File
System". Use Disk Utility to create a disk image and then erase it
(again, using Disk Utility) and put UFS on it. You'll find that "touch
foo FOO" will create two files.
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x27;exit: (.*?)', a)
> In [4]: b.group(0)
> Out[4]: 'exit: '
>
> In [5]: b.group(1)
> Out[5]: ''
>
> In [6]: b.group(2)
> IndexError: no such group
The ? tells (.*?) to match as little as possible and that is nothing.
If you change it to (.*) it should
> dash. This is much nicer than in C or Python having to get rid of """ or
> > /* and */. Of course, the IDE can compensate. But it's still neat :)
>
> python:
>
> """
> print 10
> """
>
> and
>
> #"
does? In other words, I want a
> pattern like this:
>
> >>> re.findall(".+", "foo") # not what I want
> ['foo']
> >>> re.findall("something", "foo") # what I want
> ['f', 'oo']
How's this?
iven by
f(n+1) = f(n) * 2^(1/12)
so by the time you go all 12 notes in an octave you have doubled the
frequency. There is nothing here involving base 12 or pi.
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, ['T'], ['A', 'G']]
How about this?
import re
s = "ATT/GATA/G"
result1 = re.findall(r"./.|.", s)
consensus = [c.split("/") for c in result1]
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, ['T'], ['A', 'G']]
How about this?
import re
s = "ATT/GATA/G"
result1 = re.findall(r"./.|.", s)
consensus = [c.split("/") for c in result1]
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Doug Schwarz
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, ['T'], ['A', 'G']]
How about this?
import re
s = "ATT/GATA/G"
result1 = re.findall(r"./.|.", s)
consensus = [c.split("/") for c in result1]
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Doug Schwarz
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In article <[EMAIL PROTECTED]>,
Reinhold Birkenfeld <[EMAIL PROTECTED]> wrote:
> Doug Schwarz wrote:
>
> > Dave,
> >
> > I think eval might be what you're looking for:
> >
> > f = eval('len')
> > length = f([1,2,3])
>
nt 'bar'
>
>
> i'd really appreciate any help the 'group' has to offer.
>
>
> thanks
> dave
Dave,
I think eval might be what you're looking for:
f = eval('len')
length = f([1,2,3])
By the way, are you the Dave Ekhaus I used to work with at Kodak?
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