Re: What's an elegant way to test for list index existing?

2018-09-29 Thread Glen D souza
i have a approach, it may not be best fld = [ ] for data in shlex.split(ln): fld.append(data) On Sat, 29 Sep 2018 at 07:52, wrote: > On Friday, September 28, 2018 at 11:03:17 AM UTC-7, Chris Green wrote: > > I have a list created by:- > > > > fld = shlex.split(ln) > > > > It may

Re: What's an elegant way to test for list index existing?

2018-09-29 Thread Glen D souza
fld = [ ] data = shlex.split(ln) for item in data: fld.append(item) fld = fld + [0] * (5 - len(data)) On Sat, 29 Sep 2018 at 11:03, Glen D souza wrote: > i have a approach, it may not be best > > fld = [ ] > for data in shlex.split(ln): >fld.append(data) > &g