Sorry,
how can i convert a string like 10, 20, 30 to a list [10, 20, 30]
what i can do is:
s = 10, 20, 30
tmp = '[' + s + ']'
l = eval(tmp)
but in my opinion this is not a nice solution
daniel
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On 23 Nov 2006 03:13:10 -0800, Daniel Austria [EMAIL PROTECTED] wrote:
Sorry,
how can i convert a string like 10, 20, 30 to a list [10, 20, 30]
what i can do is:
s = 10, 20, 30
tmp = '[' + s + ']'
l = eval(tmp)
but in my opinion this is not a nice solution
Not nice, especially if you
Daniel Austria a écrit :
Sorry,
how can i convert a string like 10, 20, 30 to a list [10, 20, 30]
what i can do is:
s = 10, 20, 30
tmp = '[' + s + ']'
l = eval(tmp)
but in my opinion this is not a nice solution
daniel
If you're sure that there's only ints
l = [int(item
On Thu, 23 Nov 2006 03:13:10 -0800, Daniel Austria wrote:
Sorry,
how can i convert a string like 10, 20, 30 to a list [10, 20, 30]
what i can do is:
s = 10, 20, 30
tmp = '[' + s + ']'
l = eval(tmp)
but in my opinion this is not a nice solution
It is a dangerous solution if your
Daniel Austria wrote:
Sorry,
how can i convert a string like 10, 20, 30 to a list [10, 20, 30]
what i can do is:
s = 10, 20, 30
tmp = '[' + s + ']'
l = eval(tmp)
but in my opinion this is not a nice solution
Most people share your opinion. Try this:
| strg = 10, 20, 30
| [int(x
On 23/11/06, Steven D'Aprano [EMAIL PROTECTED] wrote:
On Thu, 23 Nov 2006 03:13:10 -0800, Daniel Austria wrote:
Sorry,
how can i convert a string like 10, 20, 30 to a list [10, 20, 30]
what i can do is:
s = 10, 20, 30
tmp = '[' + s + ']'
l = eval(tmp)
but in my opinion
Tim Williams wrote:
It is a dangerous solution if your data is coming from an untrusted source.
s = 10, 20, 30
L = [x.strip() for x in s.split(',')]
L
['10', '20', '30']
L = [int(x) for x in L]
L
[10, 20, 30]
Or, as a one liner: [int(x.strip()) for x in s.split(',')]
You don't
On 23/11/06, Fredrik Lundh [EMAIL PROTECTED] wrote:
Tim Williams wrote:
and the use of a list comprehension is pretty silly to, given that you want
to apply the same *function* to all items, and don't really need to look
it up for every item:
map(int, s.split(','))
Haha, thanks
