nt to check wether one string is a substring of an other, use the in
>operator.
>>> '.' in '020914A' and len('020914A') > 10
False
>>> len('020914A') > 10 and '.' in '020914A'
False
Thank you Diez and Antoon for demystifing this problem. I see where I've
been going wrong.
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;
> and it's just returned by the and.
>
> in python, and is implemented like this (strict evaluation
> nonwithstanding):
>
> def and(x, y):
> if bool(x) == True:
>return y
> return x
>
> Diez
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>
>
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On 2007-05-09, Greg Corradini <[EMAIL PROTECTED]> wrote:
>
> Hello all,
> I'm having trouble understanding why the following code evaluates as it
> does:
>
string.find('020914A','.') and len('020914A') > 10
> True
len('020914A') > 10 and string.find('020914A','.')
> -1
>
>
Greg Corradini wrote:
>
> Hello all,
> I'm having trouble understanding why the following code evaluates as it
> does:
>
string.find('020914A','.') and len('020914A') > 10
> True
len('020914A') > 10 and string.find('020914A','.')
> -1
>
> In the 2.4 Python Reference Ma
d."
Based on what is said above, shouldn't my first expression (
string.find('020914A','.') and len('020914A') > 10) evaluate to
false b/c my 'x' is false? And shouldn't the second expression evaluate to
True?
Thanks for your help
Gr
