lstOne = [ 'A', 'B', 'C', 'C' ]
dct = {}
for item in lstOne:
if dct.has_key(item):
dct[item] += 1
else: dct[item] = 1
On Thu, Mar 27, 2008 at 10:51 PM, Kelly Greer [EMAIL PROTECTED] wrote:
I'm in Python 2.4.4
And it works for me in the Python Shell like you just
did. Let me
On Mar 25, 4:30 pm, kellygreer1 [EMAIL PROTECTED] wrote:
What is the best way to filter a Python list to its unique members?
I tried some method using Set but got some unhashable error.
lstone = [ 1, 2, 3, 3, 4, 5, 5, 6 ]
# how do i reduce this to
lsttwo = [ 1, 2, 3, 4, 5, 6 ]
If the
On 26 мар, 02:30, kellygreer1 [EMAIL PROTECTED] wrote:
What is the best way to filter a Python list to its unique members?
I tried some method using Set but got some unhashable error.
lstone = [ 1, 2, 3, 3, 4, 5, 5, 6 ]
# how do i reduce this to
lsttwo = [ 1, 2, 3, 4, 5, 6 ]
Is there a
On Mar 26, 5:45 am, hellt [EMAIL PROTECTED] wrote:
On 26 ÍÁÒ, 02:30,kellygreer1[EMAIL PROTECTED] wrote:
What is the best way to filter a Python list to its unique members?
I tried some method using Set but got some unhashable error.
lstone = [ 1, 2, 3, 3, 4, 5, 5, 6 ]
# how do i reduce
On Wed, Mar 26, 2008 at 2:50 PM, kellygreer1 [EMAIL PROTECTED] wrote:
How come the Set() thing seems to work for some people and I get the
'unhashable' error?
How do you test for 'membership' on a dictionary?
# where tmp is the non-unique list
# dct is a dictionary where each unique
En Wed, 26 Mar 2008 15:50:30 -0300, kellygreer1 [EMAIL PROTECTED]
escribió:
On Mar 26, 5:45 am, hellt [EMAIL PROTECTED] wrote:
On 26 ÍÁÒ, 02:30,kellygreer1[EMAIL PROTECTED] wrote:
What is the best way to filter a Python list to its unique members?
How come the Set() thing seems to work
What is the best way to filter a Python list to its unique members?
I tried some method using Set but got some unhashable error.
lstone = [ 1, 2, 3, 3, 4, 5, 5, 6 ]
# how do i reduce this to
lsttwo = [ 1, 2, 3, 4, 5, 6 ]
Is there a page on this in the Python in a Nutshell or the Python
Cookbook?
Kelly Greer:
What is the best way to filter a Python list to its unique members?
If Python is batteries included, then an industrial-strength
unique() seems one of the most requested 'batteries' that's not
included :-) I feel that it's coming in Python 2.6/3.x. In the
meantime:
set(lstone)
works fine in python 2.5.1
Python 2.5.1 (r251:54863, Apr 18 2007, 08:51:08) [MSC v.1310 32 bit (Intel)]
on
win32
Type help, copyright, credits or license for more information.
lstone = [ 1, 2, 3, 3, 4, 5, 5, 6 ]
set(lstone)
set([1, 2, 3, 4, 5, 6])
On 3/26/08, kellygreer1 [EMAIL
On Mar 25, 6:30 pm, kellygreer1 [EMAIL PROTECTED] wrote:
What is the best way to filter a Python list to its unique members?
I tried some method using Set but got some unhashable error.
lstone = [ 1, 2, 3, 3, 4, 5, 5, 6 ]
# how do i reduce this to
lsttwo = [ 1, 2, 3, 4, 5, 6 ]
Is there a
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