lstOne = [ 'A', 'B', 'C', 'C' ]
dct = {}
for item in lstOne:
if dct.has_key(item):
dct[item] += 1
else: dct[item] = 1
On Thu, Mar 27, 2008 at 10:51 PM, Kelly Greer <[EMAIL PROTECTED]> wrote:
> I'm in Python 2.4.4
>
> And it works for me in the Python Shell like you just
> did. Let
En Wed, 26 Mar 2008 15:50:30 -0300, kellygreer1 <[EMAIL PROTECTED]>
escribió:
> On Mar 26, 5:45 am, hellt <[EMAIL PROTECTED]> wrote:
>> On 26 ÍÁÒ, 02:30,kellygreer1<[EMAIL PROTECTED]> wrote:
>>
>> > What is the best way to filter a Python list to its unique members?
> How come the Set() thing s
On Wed, Mar 26, 2008 at 2:50 PM, kellygreer1 <[EMAIL PROTECTED]> wrote:
> How come the Set() thing seems to work for some people and I get the
> 'unhashable' error?
>
> How do you test for 'membership' on a dictionary?
>
> # where tmp is the non-unique list
> # dct is a dictionary where each u
On Mar 26, 5:45 am, hellt <[EMAIL PROTECTED]> wrote:
> On 26 ÍÁÒ, 02:30,kellygreer1<[EMAIL PROTECTED]> wrote:
>
> > What is the best way to filter a Python list to its unique members?
> > I tried some method using Set but got some "unhashable" error.
>
> > lstone = [ 1, 2, 3, 3, 4, 5, 5, 6 ]
> > #
On 26 мар, 02:30, kellygreer1 <[EMAIL PROTECTED]> wrote:
> What is the best way to filter a Python list to its unique members?
> I tried some method using Set but got some "unhashable" error.
>
> lstone = [ 1, 2, 3, 3, 4, 5, 5, 6 ]
> # how do i reduce this to
> lsttwo = [ 1, 2, 3, 4, 5, 6 ]
>
> Is
On Mar 25, 4:30 pm, kellygreer1 <[EMAIL PROTECTED]> wrote:
> What is the best way to filter a Python list to its unique members?
> I tried some method using Set but got some "unhashable" error.
>
> lstone = [ 1, 2, 3, 3, 4, 5, 5, 6 ]
> # how do i reduce this to
> lsttwo = [ 1, 2, 3, 4, 5, 6 ]
If t
On Mar 25, 6:30 pm, kellygreer1 <[EMAIL PROTECTED]> wrote:
> What is the best way to filter a Python list to its unique members?
> I tried some method using Set but got some "unhashable" error.
>
> lstone = [ 1, 2, 3, 3, 4, 5, 5, 6 ]
> # how do i reduce this to
> lsttwo = [ 1, 2, 3, 4, 5, 6 ]
>
> I
set(lstone)
works fine in python 2.5.1
Python 2.5.1 (r251:54863, Apr 18 2007, 08:51:08) [MSC v.1310 32 bit (Intel)]
on
win32
Type "help", "copyright", "credits" or "license" for more information.
>>> lstone = [ 1, 2, 3, 3, 4, 5, 5, 6 ]
>>> set(lstone)
set([1, 2, 3, 4, 5, 6])
On 3/26/08, kellygr
Kelly Greer:
> What is the best way to filter a Python list to its unique members?
If Python is "batteries included", then an industrial-strength
unique() seems one of the most requested 'batteries' that's not
included :-) I feel that it's coming in Python 2.6/3.x. In the
meantime:
http://aspn.act
What is the best way to filter a Python list to its unique members?
I tried some method using Set but got some "unhashable" error.
lstone = [ 1, 2, 3, 3, 4, 5, 5, 6 ]
# how do i reduce this to
lsttwo = [ 1, 2, 3, 4, 5, 6 ]
Is there a page on this in the Python in a Nutshell or the Python
Cookbook
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