On Monday, August 17, 2015 at 7:32:08 PM UTC+5:30, Владислав wrote:
> # first: works fine
> x = [1, 2, 4, 2, 1, 3]
> x = list(set(x))
> x.sort()
> print(x) # output: 1, 2, 3, 4
>
> # second: why x became None ??
> x = [1, 2, 4, 2, 1, 3]
> x = list(set(x)).sort()
> print(x) # output: None
> I kno
On 17/08/2015 12:42, Владислав wrote:
# first: works fine
x = [1, 2, 4, 2, 1, 3]
x = list(set(x))
x.sort()
print(x) /# output: 1, 2, 3, 4
/# second: why x became None ??
x = [1, 2, 4, 2, 1, 3]
x = list(set(x)).sort()
print(x) /# output: None/
I know that sort() returns None, but I guess that
On 08/17/2015 01:42 PM, Владислав wrote:
x = [1, 2, 4, 2, 1, 3]
x = list(set(x)).sort()
print(x) /# output: None/
I know that sort() returns None, but I guess that it would be returned x
that was sorted. Why so?
If sort() returns None, than the following:
x = list(set(x)).sort()
is equivalen
>
> I know that sort() returns None, but I guess that it would be returned x
> that was sorted. Why so?
if it returned a sorted list it might lead some people to believe it
did not modify the oridinal list which would lead to a ton of
confusion for new users.
--
https://mail.python.org/mailman/li
# first: works fine
x = [1, 2, 4, 2, 1, 3]
x = list(set(x))
x.sort()
print(x) # output: 1, 2, 3, 4
# second: why x became None ??
x = [1, 2, 4, 2, 1, 3]
x = list(set(x)).sort()
print(x) # output: None
I know that sort() returns None, but I guess that it would be returned x
that was sorted. Wh
