Tim Chase wrote:
1. This method was suggested by Cameron Laird:
os.system("start %s" % URL)
It works. But, if the URL contains character &, it will fail. For
As an aside, the START command is a bit picky regarding quotes. You have
to use this horrible contortion
os.system('start "
1. This method was suggested by Cameron Laird:
os.system("start %s" % URL)
It works. But, if the URL contains character &, it will fail. For
As an aside, the START command is a bit picky regarding quotes.
You have to use this horrible contortion
os.system('start "title" "%s"' % URL
En Wed, 28 Jan 2009 20:49:14 -0200, Muddy Coder
escribió:
My previous post got a many helps from the people, and I tested what
they suggested. Since this topic maybe needed in future, so I drop
these lines below to help the future programmers. The methods worked
as below:
1. This method was
In article ,
MRAB wrote:
>Muddy Coder wrote:
.
.
.
>You could put quotes around the URL:
>
>os.startfile('"%s"' % URL)
>
>or:
>
>os.system('start "%s"' % URL)
>
>if "&" has a special meaning to the command-line.
In fact, no,
On Wed, 28 Jan 2009 23:14:59 +, MRAB wrote:
Muddy Coder wrote:
Hi Folks,
My previous post got a many helps from the people, and I tested what
they suggested. Since this topic maybe needed in future, so I drop
these lines below to help the future programmers. The methods worked
as below:
1
Muddy Coder wrote:
Hi Folks,
My previous post got a many helps from the people, and I tested what
they suggested. Since this topic maybe needed in future, so I drop
these lines below to help the future programmers. The methods worked
as below:
1. This method was suggested by Cameron Laird:
Hi Folks,
My previous post got a many helps from the people, and I tested what
they suggested. Since this topic maybe needed in future, so I drop
these lines below to help the future programmers. The methods worked
as below:
1. This method was suggested by Cameron Laird:
os.system("start %