CJ <[EMAIL PROTECTED]> wrote in
news:[EMAIL PROTECTED]:
Thanks! I think I've nailed it. I appreciate all the input!
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On Wed, 05 Oct 2005 06:48:59 +, CJ wrote:
>
>Hey, I'm new to the Python world, but I do have experience in several
> other languages. I've been running through a tutorial, and I decided that
> I'd make a program that runs through a list, finds if there are any
> duplicates. The progra
On Wed, 05 Oct 2005 00:10:12 -0700, [EMAIL PROTECTED] wrote:
> hi,
>
> to get howmany element list appear you can code:
> ttllst=[4,3,45,3]
> for x in ttllst:
> print x, ttllst.count(x)
> pass
>
> to get non duplicate element list you can code:
> ttllst=[4,3,45,3]
>
The specific error in your code, is that when cnto == len(ttllst), then
doing ttllst[cnto] will give you that error.
The list is indexed from 0 to len-1, which means that doing
list[len(list)] will give that error.
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"CJ" wrote:
>What does worry me, is that I can't seem to get the program by a
> certain spot. It keeps giving me the same error, and I don't know why.
quite often, exception messages means exactly what they say; if
you get an index error, it's because you're trying to fetch an item
that doesn
hi,
to get howmany element list appear you can code:
ttllst=[4,3,45,3]
for x in ttllst:
print x, ttllst.count(x)
pass
to get non duplicate element list you can code:
ttllst=[4,3,45,3]
print list(set(ttllst))
Cheers,
pujo
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Hey, I'm new to the Python world, but I do have experience in several
other languages. I've been running through a tutorial, and I decided that
I'd make a program that runs through a list, finds if there are any
duplicates. The program, doesn't work, but since its a first build I
wasn't to
