Please explain the arguments of send_request. What exactly are the
connection, handler and request_body? It will be really helpful if you give
an example of how do i call send_request
On Thu, Sep 11, 2008 at 7:18 AM, Fredrik Lundh [EMAIL PROTECTED]wrote:
Usman Ajmal wrote:
And i also fount
Usman Ajmal wrote:
Please explain the arguments of send_request. What exactly are the
connection, handler and request_body? It will be really helpful if you
give an example of how do i call send_request
you don't call send_request. you should pass the SecureTransport
instance as an
Where exactly should i call ServerProxy? Following is the code from my
client.py
t = SecureTransport()
t.set_authorization(ustring, text_ucert)
server = xmlrpclib.Server('http://localhost:8000/',transport=t)
print server.s()
Note: Full code for client is here at
Usman Ajmal wrote:
Where exactly should i call ServerProxy? Following is the code from my
client.py
ServerProxy is the preferred name. Server is an old alias for the same
class.
t = SecureTransport()
t.set_authorization(ustring, text_ucert)
server =
Problem is that when i start client (while the server is already running), i
get an error i.e.
Error 500 Internal Server Error
On Sat, Sep 13, 2008 at 3:58 PM, Fredrik Lundh [EMAIL PROTECTED]wrote:
Usman Ajmal wrote:
Where exactly should i call ServerProxy? Following is the code from my
Usman Ajmal wrote:
Problem is that when i start client (while the server is already
running), i get an error i.e.
Error 500 Internal Server Error
that's a server error, not a client error. check the server logs (e.g.
error.log or similar).
/F
--
Yeah right but i don't see something wrong in my server's code. Following is
my server's simple code
import SimpleXMLRPCServer
#server = ServerProxy(http://betty.userland.com;)
class AuthenticationFunctions:
def s(self):
print something...
server =
Hi everyone,
I am trying to call a function named system.auth at the server side running
at localhost:8080 but at the same time i want to set the http header. I
found that header can be set by
h.putheader(AUTHORIZATION,
Basic %s%encodestring(%s:%s % (ustring,text_ucert)))
Usman Ajmal wrote:
And i also fount that a typical system.auth call will look like:
POST /xmlrpc/clarens_server.py HTTP/1.0
Host: localhost
User-Agent: xmlrpclib.py/0.9.9 (by www.pythonware.com
http://www.pythonware.com)
Content-Type: text/xml
Content-Length: 105
AUTHORIZATION: Basic
Thanks for ur help. But now i am getting an error
xmlrpclib.ProtocolError: ProtocolError for localhost:8000/RPC2: 500
Internal Server Error
Here is my code at http://privatepaste.com/d81Kut9AFj
Any idea what wrong am i doing?
On Thu, Sep 11, 2008 at 7:18 AM, Fredrik Lundh [EMAIL
Hi,
I tried to take the Monkey Shell script
(http://www.sharp-ideas.net/archives/2005/03/monkey_shell_us.html) and
make it into an executable. I am making an executable for the server
piece (monkey_shelld.py). So my setup.py looks like this
# setup.py
from distutils.core import setup
import
update to this. I generated an exe for the client and server. They
both run fine, except, when i send a command from the client to server,
the cleint spits out this..
xmlrpclib.ProtocolError: ProtocolError for 10.50.20.5:80/RPC2: -1
When I run the .py's by themselves I do not get this. This
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