On Oct 6, 6:06 pm, Kitlbast wrote:
>
> grouped acc: 61
> grouped acc: 64
> grouped acc: 61
>
> am I doing something wrong?
sort first, then groupby.
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Kitlbast wrote:
On Oct 7, 3:04 am, Raymond Hettinger wrote:
On Oct 6, 4:06 pm, Kitlbast wrote:
Hi there,
the code below on Python 2.5.2:
from itertools import groupby
info_list =
{'profile': 'http://somesite.com/profile1', 'account': 61L},
{'profile'
On Oct 7, 3:04 am, Raymond Hettinger wrote:
> On Oct 6, 4:06 pm, Kitlbast wrote:
>
>
>
>
>
> > Hi there,
>
> > the code below on Python 2.5.2:
>
> > from itertools import groupby
>
> > info_list = [
> > {'profile': 'http://somesite.com/profile1', 'account': 61L},
> > {'profile': 'http://s
On Oct 6, 4:06 pm, Kitlbast wrote:
> Hi there,
>
> the code below on Python 2.5.2:
>
> from itertools import groupby
>
> info_list = [
> {'profile': 'http://somesite.com/profile1', 'account': 61L},
> {'profile': 'http://somesite.com/profile2', 'account': 64L},
> {'profile': 'http://som
Thanks guys!
Miss sorting when reading docs.. (
However, I just create simple "groupby":
def groupby(_list, key_func):
res = {}
for i in _list:
k = key_func(i)
if k not in res:
res[k] = [i]
else:
res[k].append(i)
return res
and it work
On Wed, 07 Oct 2009 00:06:43 +0100, Kitlbast
wrote:
Hi there,
the code below on Python 2.5.2:
from itertools import groupby
info_list = [
{'profile': 'http://somesite.com/profile1', 'account': 61L},
{'profile': 'http://somesite.com/profile2', 'account': 64L},
{'profile': 'http:
Kitlbast schrieb:
Hi there,
the code below on Python 2.5.2:
from itertools import groupby
info_list = [
{'profile': 'http://somesite.com/profile1', 'account': 61L},
{'profile': 'http://somesite.com/profile2', 'account': 64L},
{'profile': 'http://somesite.com/profile3', 'account': 6
Hi there,
the code below on Python 2.5.2:
from itertools import groupby
info_list = [
{'profile': 'http://somesite.com/profile1', 'account': 61L},
{'profile': 'http://somesite.com/profile2', 'account': 64L},
{'profile': 'http://somesite.com/profile3', 'account': 61L},
]
grouped_by_a
