alex goretoy wrote:
> v should have ['3','4','1'] sorry if I made it confusing.
> [...]
Aah, I see I was giving you incorrect advice. I now realise that you
want to flatten the lists as well.
Don't try to do this with a list comprehension. It won't work without
creating an unnecessary list of lis
alex goretoy wrote:
> Thank you Steve and MRAB,
>
> This is what I was looking for:
>
> [[v.append(j) for j in i if j != 0] for i in self.value]
>
No, it wasn't. You should *not* be modifying v in the list comprehension!
> the value is actually stored as a string so I would need to check if it
On Jan 2, 8:43�pm, "alex goretoy" wrote:
> rather, how do I suppress the output of the list with all None in it?
>
> >>> l=[['3'], ['0', '4'], ['0', '1'], ['0']]
> >>> v=[]
> >>> [[v.append(j)for j in i if j != "0"] for i in l]
>
> [[None], [None], [None], []]
>
> >>> v
> ['39', '32', '1']
>
Assi
alex goretoy wrote:
Thank you Steve and MRAB,
This is what I was looking for:
[[v.append(j) for j in i if j != 0] for i in self.value]
the value is actually stored as a string so I would need to check if it
is "0". I do have one more question about list comprehension though.
After doing thi
rather, how do I suppress the output of the list with all None in it?
>>> l=[['3'], ['0', '4'], ['0', '1'], ['0']]
>>> v=[]
>>> [[v.append(j)for j in i if j != "0"] for i in l]
[[None], [None], [None], []]
>>> v
['39', '32', '1']
>>>
On Sat, Jan 3, 2009 at 2:38 AM, alex goretoy wrote:
> Thank yo
On Sat, 03 Jan 2009 01:52:04 +, alex goretoy wrote:
> Hello All,
>
> I'm doing this in my code
>
> [[v.append(j) for j in i] for i in self.value]
>
> if works and all,
Replacing "self.value" with a list of lists of ints:
>>> list_of_lists = [[1, 2, 3], [2, 4, 6]]
>>> v = []
>>> output = [
v should have ['3','4','1'] sorry if I made it confusing.
On Sat, Jan 3, 2009 at 2:43 AM, alex goretoy wrote:
> rather, how do I suppress the output of the list with all None in it?
>
> >>> l=[['3'], ['0', '4'], ['0', '1'], ['0']]
> >>> v=[]
> >>> [[v.append(j)for j in i if j != "0"] for i in l]
Thank you Steve and MRAB,
This is what I was looking for:
[[v.append(j) for j in i if j != 0] for i in self.value]
the value is actually stored as a string so I would need to check if it is
"0". I do have one more question about list comprehension though. After
doing this I get an unwanted list
alex goretoy wrote:
> Hello All,
>
> I'm doing this in my code
>
> [[v.append(j) for j in i] for i in self.value]
>
> if works and all, but I need to add a if statement in the mix. Can't
> seem to remember the syntax to do so and everything I've tried seems to
> fail. How do I add a check to see
alex goretoy wrote:
Hello All,
I'm doing this in my code
[[v.append(j) for j in i] for i in self.value]
if works and all, but I need to add a if statement in the mix. Can't
seem to remember the syntax to do so and everything I've tried seems to
fail. How do I add a check to see if j is not i
Hello All,
I'm doing this in my code
[[v.append(j) for j in i] for i in self.value]
if works and all, but I need to add a if statement in the mix. Can't seem to
remember the syntax to do so and everything I've tried seems to fail. How do
I add a check to see if j is not int("0") then append to v
11 matches
Mail list logo
