Helmut Jarausch writes:
> On Mon, 13 Aug 2012 15:43:31 +, Grant Edwards wrote:
>
>> On 2012-08-13, Helmut Jarausch wrote:
>>> Hi,
>>>
>>> for tracing purposes I have added some print outs like
>>>
>>> print('+++ before calling foo',file=sys.stderr)
>>> x=foo(..)
>>> print('--- after calling
On Mon, Aug 13, 2012 at 11:16 AM, Helmut Jarausch wrote:
> Now, when executing this, I always get
>
> +++ before calling foo
> --- after calling foo
entering foo ...
Can you give us a piece of code we can run that produces this output
for you? You gave us an outline in your original post,
On Mon, 13 Aug 2012 15:43:31 +, Grant Edwards wrote:
> On 2012-08-13, Helmut Jarausch wrote:
>> Hi,
>>
>> for tracing purposes I have added some print outs like
>>
>> print('+++ before calling foo',file=sys.stderr)
>> x=foo(..)
>> print('--- after calling foo',
Sorry, this is a cut'n paste
On 2012-08-13, Helmut Jarausch wrote:
> Hi,
>
> for tracing purposes I have added some print outs like
>
> print('+++ before calling foo',file=sys.stderr)
> x=foo(..)
> print('--- after calling foo',
>
> and within 'foo'
> print('>>> entering foo ...',file=sys.stderr)
>
> Now, when executing this
As far as I know,
stdout is usually buffered (not necessary) in both C++ and Python
stderr is non-buffered in both C++ and Python (I can't imagine the point of
stderr if it were buffered)
Even with this, stdout usually come immediately - the situation you have
shouldn't happen.
Are you using an IDE
Hi,
for tracing purposes I have added some print outs like
print('+++ before calling foo',file=sys.stderr)
x=foo(..)
print('--- after calling foo',
and within 'foo'
print('>>> entering foo ...',file=sys.stderr)
Now, when executing this, I always get
+++ before calling foo
--- after calling f
