Hi,
It seems like your multivariate regression works for groups A and B. For group
C, values are calculated using an interaction between x1 and x2. Try to include
it in the regression model to find the right coeffs:
y ~ grp:x1:x2 + grp:x1 + grp:x2 + grp - 1
It works for me. Notice in summary()
You need both the name of the dataframe and the variable in the
dataframe.
dfCorTFandPCA[order(dfCorTFandPCA$PC1)]
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature
and Forest
Hi all,
I use "write.csv" and "write.table" to write a data frame in a file like
following:
write.csv2(allRandomTestCase_XDroped, "allRandomTestCase.csv")
But in the created file "allRandomTestCase.csv" an additional column with
consecutive numbers is automatically added to the column of the data
Hi,
Is there a mean to automatically choose one version of the 'rbind' function ?
By default, R chose the 'rbind' from {base}, i would lke to use the one from
{IRanges}...
Is it possible to set that using 'par' ?
> ?rbind
Help on topic 'rbind' was found in the following packages:
Package
See
help("::")
help("attachNamespace")
and perhaps
help("search")
Allan.
On 18/06/09 09:39, Martial Sankar wrote:
> Hi,
>
> Is there a mean to automatically choose one version of the 'rbind' function ?
> By default, R chose the 'rbind' from {base}, i would lke to use the one from
> {IRanges}
Dear List,
R 2.8.0
JRI 0.4-1
OS WinXP Pro
Java 1.6
I am calling R from Java through JRI.
My process runs an iteration endlessly, and (supposedly) cleans up
after each turn :
rm(list=ls(all=TRUE)
gc(reset=TRUE)
In Java:
rengine.eval("rm(list=ls(all=TRUE)); gc(reset=TRUE)");
S
On 6/18/09, Martial Sankar wrote:
> Is there a mean to automatically choose one version of the 'rbind' function
> ? By default, R chose the 'rbind' from {base}, i would lke to use the one
> from {IRanges}...
>
I am usually solving these issues with:
base::rbind() or IRanges::rbind().
Liviu
___
Hi,
I have the following dataset (shown only part of it):
WFPSsampling dayslurry depth replicates N2O (mg/m2/h)
1 1 1 3 1 0.007
1 1 1 3 2 0.022
1 1 1 3 3 0.015
1 1 2 3
On 17 Jun 2009, at 18:15, Dirk Eddelbuettel wrote:
On Wed, Jun 17, 2009 at 05:29:26PM +0100, Federico Calboli wrote:
Hello all,
a friend has a problem with tiff() which I was unable to help
about. I
searched the error messages to no avail. When he tries:
tiff(filename = "FedeWhyDoesntThisB
Hi the list
I write a function MyFunc. To optimize it, I write a C function MyFuncC
then a function MyFunc2 that call .C(“MyFuncC”,….)
The two functions MyFunc and MyFunc2 seem to behave exactly the same way
(they give the same results). But when I test MyFunc2 several times
(around 20), R cra
Please ask questions about Bioconductor packages on the Bioconductor
mailing list
https://stat.ethz.ch/mailman/listinfo/bioconductor
Martin
Aaron Wolen writes:
> I'm trying to identify the positions of all genes within a specific
> chromosomal region using biomart. When using the current bio
Dear Lavri,
Take a look at the row.names argument in ?write.table.
HTH,
Jorge
On Thu, Jun 18, 2009 at 4:09 AM, Lavri Labi wrote:
> Hi all,
>
> I use "write.csv" and "write.table" to write a data frame in a file like
> following:
> write.csv2(allRandomTestCase_XDroped, "allRandomTestCase.csv")
Thanks,
> Date: Thu, 18 Jun 2009 11:21:29 +0200
> Subject: Re: [R] R function founRd in two packages !
> From: landronim...@gmail.com
> To: martial100...@hotmail.com
> CC: r-help@r-project.org
>
> On 6/18/09, Martial Sankar wrote:
> > Is there a mean to automatically choose one version of the
Martial Sankar writes:
> Hi,
>
> Is there a mean to automatically choose one version of the 'rbind' function ?
> By default, R chose the 'rbind' from {base}, i would lke to use the one from
> {IRanges}...
> Is it possible to set that using 'par' ?
Are you asking how to find help on IRanges::rb
Dear all,
I 'm implementing the koenker procedure for quantile fixed effects. I
would like also to apply weights to the procedure, so that to give
more weight to the observation that better represent my original
sample (much larger than it is possible to use in R). Do you know if
it is possible? H
Dear Jorge,
thank you for the quick answer. But I am afraid you didn´t understand my
problem. I want to write the following data frame "exampleDataframe" in a
csv2-file.
"a";"b";"c";"d"
1 ; 2 ; 3 ; 4
5 ; 6 ; 7 ; 8
9 ; 0 ; 1 ; 2
After sending the command:
write.csv2(exampleDataframe,file="exa
Hi Sorn,
thanks for your code. I guess I didn't really made myself very clear.
What I sort of looking for is a xyplot with both the x axis at the bottom
and y axis at the
left going through 0, but continuing in the positive and negative area
(forming a kind of cross
like e.g.
http://upload.wikime
Hi there,
sorry for troubling everybody once again, I've got a problem rewriting
Sarkar's function for
rewriting the tick locations in a logaritmic way (s.
http://lmdvr.r-forge.r-project.org/code/Chapter08.R):
His example works for log 2 but I need log e (natural logarithm). My
problem is that if
Hi Jim,
thanks, that sounds like a good idea!
The only problem is that axis and pos are a far as I know not for
lattice or at least I
cannot find an appropriate function and way to do this in lattice.
Maybe I have to keep on searching for how to realize that with lattice...
Best wishes,
I checked on the affected computer and both tiff and cairo
capabiliies
return FALSE. How that is I would not know, it's a bog standard R
installation on windows XP.
The 2.9.0 Windows install does not have TIFF capability. Try png() or
something else.
I don't know about that, but R is definit
On 18/6/09 9:52 AM, Stephanie Januchowski wrote:
Hello List,
My question is an elementary one. I have run a fuzzy kmeans cluster using
FANNY to group freshwater fish assemblages. I then went in the field to
validate that classification and have retrieved new assemblage data for a
new suite of st
Hi Axel,
Both error messages indicate that a regression equation is singular.
The error message of systemfit() indicates that the singularity
appears in the first stage of the two-stage procedure. Hence, it seems
that your instruments are linearly dependent. Please check this and
remove some of th
Hi,
It sounds like the first column that is "added" is actually the row names.
That's why a previous answer pointed this argumented. Default for write.csv is
to write the row names along with the data. So, this should work:
write.csv2(exampleDataframe,file="exampleDataframe.csv", row.names=FALSE
use 'findInterval'
> x
X1 X2 X3 X4 X5 X6 X8 X13 X14 X17 X40
2 4 6 7 9 11 13 14 15 16 17
> findInterval(4.25, x)
[1] 2
> names(x)[2]
[1] "X2"
>
On Wed, Jun 17, 2009 at 10:19 PM, Germán Bonilla wrote:
> Hi all,
>
> I've got object *cumsumtab, *where the first row
> (1,2,3,
pasting reply by Xavier into this thread for the sake of others who might
come across it in their R travels. Thanks Xavier
Hi,
It seems like your multivariate regression works for groups A and B. For
group C, values are calculated using an interaction between x1 and x2. Try
to include it in the
Write.table will give you all the control you need to get exactly what you
want. Bryan
On 6/18/09 7:50 AM, "xavier.char...@free.fr" wrote:
> Hi,
It sounds like the first column that is "added" is actually the row
> names. That's why a previous answer pointed this argumented. Default for
> wri
Thanks Xavier. That's exactly the solution.
xavier.chardon wrote:
>
> Hi,
>
> It seems like your multivariate regression works for groups A and B. For
> group C, values are calculated using an interaction between x1 and x2. Try
> to include it in the regression model to find the right coeffs
Hello,
i get some memory problems using RWeka and i'm wondering because i have
only ~ 400MB in RObjects without a high memory consuming
operation when a crash occur. Look into hs_err_pid.log , it seems that
the VM max heap size is only 512 mb.
VM Arguments:
jvm_args: -Xmx512m vfprintf exi
Hi Xavier,
thanks for your suggestion. It´s run!
Lavri
> Hi,
>
> It sounds like the first column that is "added" is actually the row names.
> That's why a previous answer pointed this argumented. Default for
> write.csv is to write the row names along with the data. So, this should
> work:
> wr
Dear list,
given is the following data frame df():
Number Place Start End
1 218024740787 HHO 5 263 2008-01-02 00:21:14 2008-01-03 15:25:16
2 218024740787 HHO 5 263 2008-01-02 00:21:14 2008-01-02 00:21:14
3 318039091794 HHO 5 263 20
Take a look at the function
?aggregate
andydol...@gmail.com
2009/6/18 René Schönemann
> Dear list,
>
> given is the following data frame df():
>
>Number Place Start End
> 1 218024740787 HHO 5 263 2008-01-02 00:21:14 2008-01-03 15:25:16
HI Thanks!
This worked:
dfCorTFandPCA[order(dfCorTFandPCA$PC1),]
Ony
milton ruser wrote:
>
> Hi Ony,
>
> If you got a data.frame with dfCorTFandPCA=as.data.frame(corTFandPCA)
> so you can try something like:
>
> orderedCorTFandPCA=dfCorTFandPCA[order(dfCorTFandPCA$PC1),]
>
> May be you can a
Hi list,
I want to place a plot (eg "plot(1:10)") and a xyplot side by side in
one figure. The two columns should have different widths. If I'm not
missing something, this rules out the standard way: par(mfcol=n).
I tried layout(), but it doesn't seem to like it when grid scribbles
into it
From: Duncan Murdoch
>
> Liaw, Andy wrote:
> > A colleague and I were trying to understand all the
> possible things one
> > can do with for loops in R, and found some surprises. I think we've
> > done sufficient detective work to have a good guess as to
> what's going
> > on "underneath", but
Hi,
There is a problem installing R. I am using windows vista home
basic.
After installation and when i'm trying to access it, it shows "Fatal error:
cannot mkdir R_Tempdir"
and after pressing ok, it closes.
Can anyone help me out?
Regards,
Harish
[[alternative HTML versio
Hi all,
I have written a function
cluster_compare(myfile, mclfile)
I called it giving names of files in the working directory (I see them with
dir()). I get
Error in file("myfile", "r") : cannot open the connection
In addition: Warning message:
In file("myfile", "r") :
cannot open file 'myf
Dear list,
given is the following data frame df():
Number Place Start End
1 218024740787 HHO 5 263 2008-01-02 00:21:14 2008-01-03 15:25:16
2 218024740787 HHO 5 263 2008-01-02 00:21:14 2008-01-02 00:21:14
3 318039091794 HHO 5 263 20
Hi all,
I recently discovered how great win.metafile is for getting high resolution
graphics into word.
Having problems with specifying families though...
#pdf works fine
pdf("test.pdf",width=14,height=9)
par(family="Helvetica")
plot(1:10)
text(4,4,"trial")
dev.off()
windows
2
#metafil
I am currently trying to access a SOAP web service (hosted on a JBoss5
server and defined as a J2EE-ws service) via the SSOAP R-package. But
all I can get is a NULL answer. The web service seems to work as it can
be accessed using a general web-service tester.
The web service wsdl is here: htt
1) What is the rest of your code ... e.g. that part which sets up the
file names and at least the parameters and file access parts of the
function cluster_compare?
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, rep
Hi all,
Suppose I have a vector like this:
[1] "STAT1" "STAT1" "STAT1" "STAT1" "GAPDH" "GAPDH" "GAPDH" "ACTB"
"ACTB"
[10] "ACTB" "DDR1" "RFC2" "HSPA6" "PAX8" "GUCA1A" "UBE1L" "THRA"
"PTPN21"
[19] "CCL5" "CYP2E1" "STAT1" "THRA" "PAX8"
I would like to produce a vector
I think you can then use merge() to merge them back together
n<- merge(n, df, by.x = c("m.values"), by.y = c("Start"), all.x = F, all.y =
F)
also see ?aggregate for a more efficient solution.
HTH, Si.
- Original Message -
From: "Schönemann, Rene"
To:
Sent: Thursday, June 18, 2009
On Jun 18, 2009, at 9:28 AM, njhuang86 wrote:
Hi all,
Suppose I have a vector like this:
[1] "STAT1" "STAT1" "STAT1" "STAT1" "GAPDH" "GAPDH" "GAPDH"
"ACTB"
"ACTB"
[10] "ACTB" "DDR1" "RFC2" "HSPA6" "PAX8" "GUCA1A" "UBE1L"
"THRA"
"PTPN21"
[19] "CCL5" "CYP2E1" "STAT1"
Hi all,
How do I add an asterisk representing a significant difference to a barplot?
Cheers,
Gil
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the postin
On Jun 18, 2009, at 5:01 AM, alessia matano wrote:
Dear all,
I 'm implementing the koenker procedure for quantile fixed effects.
Who he? Wuz 'dat?
I would like also to apply weights to the procedure, so that to give
more weight to the observation that better represent my original
sample (
Here is a way of determining where the dups are:
> vec <- scan(textConnection(' "STAT1" "STAT1" "STAT1" "STAT1" "GAPDH"
"GAPDH" "GAPDH"
+
+ "ACTB" "ACTB" "ACTB" "DDR1" "RFC2" "HSPA6" "PAX8"
+ "GUCA1A" "UBE1L" "THRA" "PTPN21" "CCL5" "CYP2E1" "STAT1"
+ "THRA" "PAX8"'), what=
Where did you get the idea that Helvetica was a Windows font family
name? (It is a Linotype trademark font name.) It is rarely seen on
Windows, so attempts to use it almost always end up with a font
substitution, often to Arial which is already the default family in
win.metafile(). That will
Thank you. One question, though. In the case where I have closed form
formulæ for the Hessian, or the functions are parseable by "deriv3", would
it be better to use that than the approximation?
--Avraham
"
Hi!
I have a dataset with some 300+ variables and 2000+ records. I'd like to grind
through a bunch of analyses on the variables by using a script, but can't
figure out how to refer to variable names properly. For some of the simpler
stuff I use various "apply" functions, but for others (like t-tes
David Winsemius' solution:
> apply(data.matrix(df), 1, I)
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
x12345678910
y13456789 10 2
For y and [,2] above the value is 3. Why is the value not 2?
It look
If I understand correctly, you can try something about like this:
x <- c(1, 4, 5, 10)
bp <- barplot(x, ylim = c(0, max(x) + 2))
text(bp, x,
labels = symnum(x, cutpoints = c(1, 5, 10),
symbols = c("*", "**")), pos = 3)
On Thu, Jun 18, 2009 at 12:40 PM, Gilad wrote:
> Hi all,
>
> How
Hello!
I want to estimate strength and correlation of RandomForest, but in package
"randomForest" there is not an interface to get it. I think I must to change
the source code. Is there any advise?
Thanks,
Li
[[alternative HTML version deleted]]
Hello,
This is a newbee question. I would simply like to write in a text file the
headers of the summary function along with the computed data.
write(summary(x), file="out.txt")
gives only the data.
I have not found a solution on the forum.
Thank you for any help.
--
View this message in con
It's not a solution. Unfortunately data.matrix is no different with
respect to factors than other functions. Note what str(df) produced
for df$y.
--
David.
On Jun 18, 2009, at 10:59 AM,
wrote:
David Winsemius' solution:
> apply(data.matrix(df), 1, I)
[,1] [,2] [,3] [,4] [,5] [,6]
Look at the gridBase package.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of Titus v. d. Malsburg
> Sent: Thu
Thanks! I did not look at the output of str(df) closely. Since y is
defined as a character variable when df is created (but stored as a
factor), it looks like str(df) is sorting the factors, at least when it
is displayed to the screen.
Jude
-Original Message-
From: David Winsemius [mailto
The word "merge" in the context of R suggests the use of the merge()
function, but I don't think that's the right tool for what you want.
The merge() function is for relational database type merges, which
for your data would have a many to many merge. Not good.
In terms of the R language, you'
Hi,
perhaps that is what you want?
> df <- as.data.frame(matrix(runif(100),ncol=10))
> form <- as.formula(paste(names(df)[length(df)], "~ ."))
> lm(form,data=df)
Call:
lm(formula = form, data = df)
Coefficients:
(Intercept) V1 V2 V3 V4
-1.367 -
On Jun 18, 2009, at 10:05 AM, nmset wrote:
Hello,
This is a newbee question. I would simply like to write in a text
file the
headers of the summary function along with the computed data.
write(summary(x), file="out.txt")
gives only the data.
I have not found a solution on the forum.
Tha
Hi all,
Do you know of any good resources for learning how S3 works? I've
some how become familiar with it by reading many small pieces, but now
that I'm teaching it to students I'm wondering if there are any good
resources that describe it completely, especially in a reader-friendly
way. So far
Gilad wrote:
Hi all,
How do I add an asterisk representing a significant difference to a barplot?
Cheers,
Gil
Bar plots are dreadful ways to present information (see
http://biostat.mc.vanderbilt.edu/DynamitePlots). Don't make them worse
by adding arbitrary declarations of 'significance.
Greetings:
I created an R group on Linkedin. It has a discussion board but a bit less
about programming and more about networking including jobs but also relevant
web sites. Please join us.
Regards,
Ajit
http://www.linkedin.com/groups?about=&gid=77616&trk=anet_ug_grppro
http://www.linkedin.c
There is a section on Object Orientation in MASS (I have 2nd ed).
On Thu, Jun 18, 2009 at 12:06 PM, Hadley Wickham wrote:
> Hi all,
>
> Do you know of any good resources for learning how S3 works? I've
> some how become familiar with it by reading many small pieces, but now
> that I'm teaching it
Not a suggestion on documentation, but to ease S3 coding and hiding
some of the details, you might want to consider the R.methodsS3
package. It basically provides some S3 code generators and makes it
clear what class of objects a method is dispatched on. From the
example code:
setMethodS3("foo",
Of course, closed form hessian is great, but I would still check it using
deriv3 or hessian() from numDeriv.
It should be noted that hessian() is so accurate that it can be a surrogate for
the exact hessian. It is computationally demanding, but it is tolerable when
you are computing it only
-- or Chapter 4 in S PROGRAMMING? (you'll need to determine if it's "reader
friendly")
Bert Gunter
Genentech Nonclinical Biostatistics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Gabor Grothendieck
Sent: Thursday, June 18, 2009
Greg is absolutely right: Generally base and grid graphics(which is what
lattice plots are based on) don't play well together, and gridBase is meant
to address this.
However...
The problem here is specifically that the print.trellis (or synonymous
plot.trellis) function that is silently invoked to
Folks,
If I have a vector such as the following:
x <- c(0, -1, -1, -1, 0, 0, 1, -1, 1, 0)
and I want to replace the zeroes by the nearest non-zero number to the
left, is there a more elegant way to do this than the following loop?
y <- x
for (i in 2 : length(x))
{
if (y[i] == 0) {
This code works for me,
subset(merge(x1, x2, by = c("category", "id"), all = T), select=-id)
category rnorm.10..5..2. rnorm.10..8..2.
1 1 NA7.810377
2 16.4932819.002411
3 16.4932818.397378
4 12.757321
I think I remember reading that some time back and finding it
confusing because it described the ideal implementation in S, rather
than the actual implementation in R. I'll look at it again.
Hadley
On Thu, Jun 18, 2009 at 11:36 AM, Bert Gunter wrote:
> -- or Chapter 4 in S PROGRAMMING? (you'll n
On 18 June 2009 at 09:36, Bert Gunter wrote:
| -- or Chapter 4 in S PROGRAMMING? (you'll need to determine if it's "reader
| friendly")
+1
It helped me a lot too back in the day. But I am wondering if there are good
current alternatives. Hadley: if you could, please send a summary back to
the
Hello:
My problem is that I have a data frame of means, and a data frame of standard
deviations which match up to each mean. I have been trying to create 500
random numbers in a given dataset for each mean/sd combination, but I am only
able to generate the last value in each data set to creat
use na.locf in zoo:
> x
[1] 0 -1 -1 -1 0 0 1 -1 1 0
> # replace 0 with NA so na.locf works
> is.na(x) <- x == 0
> x
[1] NA -1 -1 -1 NA NA 1 -1 1 NA
> na.locf(x, na.rm=FALSE)
[1] NA -1 -1 -1 -1 -1 1 -1 1 1
>
You can then go back and replace NAs with 0
On Thu, Jun 18, 2009 at 12:47
Hi,
I installed biOps on my XP, and installed the required dll packages,
jpeg62.dll, libfftw3-3.dll, and libtiff3.dll, as suggested by this forum.
Then it worked perfectly for about one week till this afternoon. When I
tried to load biOps again, I got the following error message again
Error in i
The zoo package has na.locf which replaces NAs with the last non-NA.
So, first replace 0's with NA's, apply na.locf and then replace NAs with 0's.
> library(zoo)
> x.na <- replace(x, x == 0, NA)
> x0 <- na.locf(x.na, na.rm = FALSE)
> replace(x0, is.na(x0), 0)
[1] 0 -1 -1 -1 -1 -1 1 1 1 1
On
I develop quite a bit of R code that I tend to distribute, or let
other people embed in their software. One of the things I'd really
like to do is find a way to load an R library I've developed, and call
one function with arguments.
Currently, I achieve that by building a separate R client
approx() almost does what you want, but you have to patch
up its output to account for a possible initial run of 0's in the
input:
> x <- c(0, -1, -1, -1, 0, 0, 1, -1, 1, 0)
> y <- approx(seq_along(x)[x!=0], x[x!=0], xout=seq_along(x),
method="const", f=0, rule=2)$y
> y
[1] -1 -1 -1 -1 -1 -1 1 -1
try this:
>
a1<-c(178.07,178.28,178.08,177.74,177.04,178.17,177.58,57.71,59.6,60.92,59.48,59.32,61.59,59.94,28.9,29.82,30.73,25.68,27.93,28.98,29.76,123.48,127.27,127.8,127.2,127.13,126.71,125.5)
>
a2<-c(1.69,1.3,1,.18,1.53,1.31,1.35,1.83,1.56,1.12,.74,1.48,1.67,1.53,.95,.87,0.03,1.12,1.95,1.22,1.
See the getopt R package and have a look at ?Rscript
Also on Windows see Rscript.bat and #Rscript.bat in
http://batchfiles.googlecode.com
and on Linux see:
http://dirk.eddelbuettel.com/code/littler.html
On Thu, Jun 18, 2009 at 1:25 PM, Jim Nemesh wrote:
> I develop quite a bit of R code that I t
Try this also:
a <- expand.grid(a1, a2)
x <- mapply(rnorm, n = 500, mean = a[,1], sd = a[,2])
On Thu, Jun 18, 2009 at 2:10 PM, Alexandre Lockhart <
alexandre_geor...@hotmail.com> wrote:
>
> Hello:
>
> My problem is that I have a data frame of means, and a data frame of
> standard deviations whic
I did look at ?Rscript. My question there was:
Unfortunately, it looks like each expression is evaluated separately.
Is there a way to evaluate multiple expressions in the same
environment to make the above work?
I could write an Rscript client file, but it's still poor CLI support
compared
On Thu, Jun 18, 2009 at 1:54 PM, Jim Nemesh wrote:
> I did look at ?Rscript. My question there was:
>>>
>>> Unfortunately, it looks like each expression is evaluated separately.
>>> Is there a way to evaluate multiple expressions in the same
>>> environment to make the above work?
>
> I could writ
Actually, I'm going to take by my comments.
You can use Rscript with multiple -e arguments to do what I was
looking for:
Rscript -e 'library(broadgap.hapmaptools)' -e 'processAllFiles(dir="/
humgen/cnp04/sandbox/steve/1m/hapmap3/genotypes/ftp.hapmap.org/genotypes/2008-07_phaseIII/hapmap_form
hi,
How can I compute a regression between x and y adding a covariate z?
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commente
Alexandre did say 28 datasets, not 784 (28 * 28)
Thus, either:
mapply(rnorm, n = 500, mean = a1, sd = a2)
or
apply(cbind(a1, a2), 1, function(x) rnorm(500, x[1], x[2]))
HTH,
Marc Schwartz
On Jun 18, 2009, at 12:51 PM, Henrique Dallazuanna wrote:
Try this also:
a <- expand.grid(a
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf Of Henrique Dallazuanna
> Sent: Thursday, June 18, 2009 10:52 AM
> To: Alexandre Lockhart
> Cc: r-help@r-project.org
> Subject: Re: [R] Random number datasets help
>
> Try this also:
Hi,
take a look at the following manual pages:
?lm
?longley
In general, you would use Wilkinson-Rogers notation for linear models:
y ~ x + z, etc.
Some nice examples here:
http://data.princeton.edu/R/linearmodels.html
Cheers,
Dylan
On Thu, Jun 18, 2009 at 11:04 AM, Martin
Batholdy wrote:
>
Dear R-users,
I am trying to modify the mfp() function in the mfp package to model
Weibull survival using fractional polynomials approach. However, I keep
getting into trouble when mfp.fit and other "hidden" functions can't be
found. I did find some of them in Splus but it's getting nowhere.
On Jun 18, 2009, at 1:10 PM, Alexandre Lockhart wrote:
Hello:
My problem is that I have a data frame of means, and a data frame of
standard deviations which match up to each mean. I have been trying
to create 500 random numbers in a given dataset for each mean/sd
combination, but I am
On 18 June 2009 at 14:02, Jim Nemesh wrote:
| Actually, I'm going to take by my comments.
|
| You can use Rscript with multiple -e arguments to do what I was
| looking for:
|
| Rscript -e 'library(broadgap.hapmaptools)' -e 'processAllFiles(dir="/
|
humgen/cnp04/sandbox/steve/1m/hapmap3/genot
Hi all,
I apologize for this off-topic question but I need your help -- I know
there are lots of experts here.
As a lover and student of statistics, I am thinking of building a tree
of various branches of statistics and keeping track of the greatest
historical inventions/discoveries in statistics
I am calling on the R-help crew once again. The CD4Per for each subject should
be the same for each subject based on a 90 day window either side of the known
value. For example, ID 2931 should have a CD4Per of 36 at 0, 34, and 62
DaysEnrolled. Any ideas how to do this without a loop?
ID
With help from my colleague, I found the problem. After I put another library
dll, zlib1.dll, at the folder, biOps is working again now. Though it's still
amazing to me why biOps worked for about one week before I had zlib1.dll.
I hope message could also help people who have the same problem.
Th
Hello,
I would like to build rectangles in a plot and use color and different type
of hatching for filling rectangles. I don't find the way to draw hatchings.
I'm thinking to build segment by segment inside each rectangle but I'm sure
that exists a better way to do that. I didn't find any document
Hi all,
I am currently trying to compare different plant occurrence prediction
maps generated in R and exported into GRASS. One of these maps was
generated from a glm fitted to some data, and subsequently applying this
glm model to a wider region using predict.glm. The outcome here was a
prob
On Jun 18, 2009, at 3:23 PM, Anke Konrad wrote:
Hi all,
I am currently trying to compare different plant occurrence
prediction maps generated in R and exported into GRASS. One of these
maps was generated from a glm fitted to some data, and subsequently
applying this glm model to a wider
That is not what his 'for' loops are doing. He is iterating through all
combinations and would have created 784. So his problem statement did not
match the code that he sent.
On Thu, Jun 18, 2009 at 2:12 PM, Marc Schwartz wrote:
> Alexandre did say 28 datasets, not 784 (28 * 28)
>
> Thus,
Ben Bolker ufl.edu> writes:
> > In the Sweave output for summary for several types
> > of model objects and also for the comparison of models
> > with anova, I find that that the display of the call(s)
> > or formula does not obey the width option, even with
> > keep.source=TRUE set, so that a lon
For the mean() example, I believe this should work (untested)
for (var in names(Dataset)) print( mean( Dataset[[var]] , na.rm=TRUE ) )
or
for (var in names(Dataset)) print( mean( Dataset[,var] , na.rm=TRUE ) )
But it's harder with lm, glm, and friends. For them I think maybe you
can do i
agresti's book ( forget which one. there are two ) has an appendix about the
history of categorical data that i remember being quite interesting. that's
the only one i know of.
On Jun 18, 2009, Michael wrote:
Hi all,
I apologize for this off-topic question but I need your
1 - 100 of 142 matches
Mail list logo
