My point is your problem is not entirely related to this package in
particular but more "should I trust additional R packages", ie should I
use package cron when R can handle date objects, should I use ggplot
when i could do it all in grid, ...
operators comes with unit tests that allow me to
Dear R-User,
Is it possible to simulate Impulsive differential equation using R?
If yes, please let me know how?
Thanking you,
Best Regards,
Mini Ghosh
See the Web's breaking stories, chosen by people like you. Check out
Yahoo! Buzz. http://in.buzz.yahoo.com/
2009/7/2 Peter Dalgaard :
> Mark Wardle wrote:
>> [...]
>> Otherwise, it sounds like a recipe for obfuscation! What are you
>> trying to do really?
>
> Not really obfuscation, there are legitimate reasons to want this sort of
> behaviour. See demo(scoping) for a related example
> [...]
I would hav
If the daya set is not "too big", I believe the easiest will be:
stepAIC
from the MASS package...
On Thu, Jul 2, 2009 at 11:21 PM, Angela Radulescu <
angela.radule...@gmail.com> wrote:
> Hi,
>
> I have performed a binary logistic regression using the glm ( family =
> binomial("logit") )comm
Hi
Also see http://www.stat.auckland.ac.nz/~paul/R/CM/CMR.html
Paul
(Ted Harding) wrote:
On 02-Jul-09 09:06:44, Mr Derik wrote:
I am trying to use computer modern fonts in postscript files
for a latex document. Ultimately I want to automate this through
sweave. I've read the documentation an
Hi
There's now a fix in the development version of R.
Paul
Paul Murrell wrote:
Hi
It is indeed a bug.
Should have a fix soon.
Thanks for the report!
Paul
baptiste auguie wrote:
Thanks for the info.
It does look like a bug to me, but it's always best to try and
identify the
cause befor
On Jul 2, 2009, at 11:24 PM, David Winsemius wrote:
On Jul 2, 2009, at 10:20 PM, Ivo Shterev wrote:
a = list(diag(3), diag(3), diag(3))
a = list(diag(3), diag(3), diag(3))
> sum(unlist(a))
[1] 9
Also:
> sum(sapply(a,I))
[1] 9
David Winsemius, MD
Heritage Laboratories
West Hartford,
On Jul 2, 2009, at 10:20 PM, Ivo Shterev wrote:
a = list(diag(3), diag(3), diag(3))
a = list(diag(3), diag(3), diag(3))
> sum(unlist(a))
[1] 9
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
__
R-help@r-project.org mailing list
https
I think you are asking for Reduce
> Reduce(`+`, a)
[,1] [,2] [,3]
[1,]300
[2,]030
[3,]003
>
You might be asking for do.call with some function's name as its first
argument.
> do.call("sum", a)
[1] 9
>
__
R-h
Damned, I did tried as.list but not list...
Thanks Hadley and Duncan for your quick replies
> On Thu, Jul 2, 2009 at 3:34 PM, Sebastien
> Bihorel wrote:
>> Dear R-users,
>>
>> I would like to know how expressions could be passed as arguments to
>> do.call
>> functions. As illustrated in the short
Dear All,
Is there an automatic way to sum the elements of a list?
For example given a = list(diag(3), diag(3), diag(3)) to obtain
b=a[1]+a[2]+a[3].
Thanks
Ivo
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE d
Hi folks,
I'm just learning how to use maps. As an initial foray, I'm mapping the
states that have "duty to retreat" (blue) and "stand your ground" (red)
self-defense standards. Here is my extremely naive script:
dtr <- c('alabama', 'arizona', 'conneticut', 'delaware', 'dist of columbia'
, 'hawa
As I said, I am new to R after spending far too many years using SAS. I'm
slowly getting the hang of R and like it very much.
Thanks for your insights and help.
Murray M Cooper, Ph.D.
Richland Statistics
9800 N 24th St
Richland, MI, USA 49083
Mail: richs...@earthlink.net
__
On 7/2/09, Rolf Turner wrote:
>
> On 3/07/2009, at 11:29 AM, Hongwei Dong wrote:
>
>
> > Hi, I'm trying to plot two variables in one graph. One ranges between 0
> and
> > 1, while the other ranges between 50 and 500. Can I plot them in one graph
> > with similar scale?
> >
>
> Yes you can, but D
On 3/07/2009, at 11:29 AM, Hongwei Dong wrote:
Hi, I'm trying to plot two variables in one graph. One ranges
between 0 and
1, while the other ranges between 50 and 500. Can I plot them in
one graph
with similar scale?
Yes you can, but DON'T!!! Such graphs are terribly misleading and
co
On Thu, Jul 2, 2009 at 10:11 AM, Robert A. LaBudde wrote:
> I don't seem to be able to put any syntax into identify() that gets it to
> work with "lattice" cloud() graph:
>
> layout(1)
> require('lattice')
> cloud(g3 ~ g1 + g2, data=gapp, col = "blue",
> xlab='G1 Score', ylab='G2 Score',
> zlab='
On Wed, Jul 1, 2009 at 10:38 PM, jlfmssm wrote:
> I have a data set like this
>
> ID=c("A","A","A","A","A","A","A","B","B","B","B","B","B","B")
> s=c(1.1,2.2,1.3,1.1,3.1,4.1,4.2,1.1,2.2,1.3,1.1,3.1,4.1,4.2)
> d=c(1,2,3,4,5,6,7,1,2,3,4,5,6,7)
> t=c(-3,-1,0,1,2,3,4,-3,-2,-1,0,1,2,3)
>
> mydata<-data.
I have been plotting the same charts using png on a Windows machine
and on a Mac OSX and the quality of the resulting images, particularly
in relation to the fonts, look far superior in the plots produced on
the Mac. Is there any way I can enhance the quality of the plots
produced on the Windows ma
The proto package generalizes this to an OO approach based
on the prototype or object-based model of OO.
This corresponds to the previous code:
library(proto)
p <- proto(c = 1, foo = function(.) print(.$c))
p$foo() # 1
# but now we can also create q which overrides c
# while inheriting foo from
Works very well for me! Very thanks!
2009/7/2 Henrique Dallazuanna
> Try something about like this:
>
> bp <- boxplot(x ~ id, data = DF)
> text(bp$group, bp$out, labels = "Teste", pos = 3)
>
>
> On Thu, Jul 2, 2009 at 7:40 PM, Raphael Saldanha <
> saldanha.plan...@gmail.com> wrote:
>
>> Hi!
>>
>
Try something about like this:
bp <- boxplot(x ~ id, data = DF)
text(bp$group, bp$out, labels = "Teste", pos = 3)
On Thu, Jul 2, 2009 at 7:40 PM, Raphael Saldanha wrote:
> Hi!
>
> How can I add labels in the outliers inside a boxplot.
>
> Here is my code, at now:
>
> mun <- as.data.frame(read.
Alan,
Doesn't Peter Dalgaard's response get you what you originally asked for? You
said you wanted something like:
> if (1) { c <- 1; foo <- function () print(c); }
>c <- 2
>foo()
Based on Peter's email you could do
> c <- 1
> foo <- local({x <- c; function() print(x) })
> foo()
[1] 1
> c <-
Hi, I'm trying to plot two variables in one graph. One ranges between 0 and
1, while the other ranges between 50 and 500. Can I plot them in one graph
with similar scale?
Thanks
Harry
[[alternative HTML version deleted]]
__
R-help@r-project.o
Thanks for replying, Francois.
To directly answer your question, the difference between using base R
functions and a library comes down to code correctness and stability, as
well as future support. Portions of the language, whether in base or in
packages, which have been around a long time, o
Hi!
How can I add labels in the outliers inside a boxplot.
Here is my code, at now:
mun <- as.data.frame(read.csv2("consolidada_v3.csv"))
micro <- mun$nmicro
medprop <- mun$medprop
mimedprop <- split(medprop, micro)
boxplot(mimedprop, col="chartreuse3", main="Área média das propriedades
rurai
How is this different to dependency on regular functions ?
On 07/02/2009 10:29 PM, seeliger.c...@epamail.epa.gov wrote:
Folks,
In brief -- how many of you have found the 'operators' package to be
valuable in their work?
Not that I lack respect for the amount of work involved in creating and
ma
From: Allan Engelhardt [mailto:all...@cybaea.com]
Sent: Thursday, July 02, 2009 11:12 AM
To: William Dunlap
Cc: r-help@r-project.org
Subject: Re: [R] How to use current value of variable in
function definition?
I don't know any direct way. ?sink perhaps and then load into Word.
You might want to have a look at R2HTML as well.
Alternatively have a look at Sweave for output in pdf or OOo formats.
--- On Thu, 7/2/09, Suyan Tian wrote:
> From: Suyan Tian
> Subject: [R] save the result into a word f
On Thu, Jul 2, 2009 at 3:34 PM, Sebastien
Bihorel wrote:
> Dear R-users,
>
> I would like to know how expressions could be passed as arguments to do.call
> functions. As illustrated in the short example below, concatenating lists
> objects and an expression creates an expression object, which is no
From the CRAN task view on natural language processing:
(package) tm provides a comprehensive text mining framework for R.
The Journal of Statistical Software article Text Mining
Infrastructure in R gives a detailed overview and presents
techniques for count-based analysis methods, text c
On 7/2/2009 4:34 PM, Sebastien Bihorel wrote:
Dear R-users,
I would like to know how expressions could be passed as arguments to
do.call functions. As illustrated in the short example below,
concatenating lists objects and an expression creates an expression
object, which is not an acceptable
An errratum to my previous email:
In your problem, you can do as follows:
f <- function(par, data, lambda1, lambda2) loglik(par, data) - lambda1 *
(sum(Ai))^2 - lambda2 * (sum(Di))^2
Note the correct negative signs in front of the penalty terms.
Ravi.
---
Hi,
I have performed a binary logistic regression using the glm ( family =
binomial("logit") )command on 6 IV's and one DV. I would like to now repeat
the regression in backward fashion. What is the easiest way to do so in R?
Thanks in advance!
Best,
Angela
[[alternative HTML version de
Mark Wardle wrote:
Hi.
I've stared at your code for a number of minutes and can't understand
what you're trying to achieve here. It looks as if you're fighting
scope - it may be worth refactoring your approach to simplify matters.
Otherwise, it sounds like a recipe for obfuscation! What are you
Dear R-users,
I would like to know how expressions could be passed as arguments to
do.call functions. As illustrated in the short example below,
concatenating lists objects and an expression creates an expression
object, which is not an acceptable argument for do.call. Is there a way
to avoid
On 7/2/2009 3:33 PM, Mark Knecht wrote:
On 7/2/09, Don MacQueen wrote:
Use
deparse(substitute(df))
Example from ?deparse:
function(x, y) {
plot(x, y, xlab=deparse(substitute(x)),
ylab=deparse(substitute(y)))
}
-Don
Now that's interesting... deparsed mean
> I’m trying to export a file from R to excel using the xlsReadWritePro
> function and I keep getting the error below.
POSIXt is not currently supported (neither in data.frames nor vectors)
and must be converted to other types (see ?write.xls). I almost never
use POSIXlt/ct myself but it would pr
On 7/2/2009 2:17 PM, Steve Lianoglou wrote:
Hi,
I was wondering if I could get R to warn me, or give me a rude
awakening somehow, if I'm accessing a variable that is out of my
function's scope.
For example, often times I'm creating a function as I'm testing it in
the REPL, copying and pa
Sorry. Of course, I meant the DIFFERENCE of two non-negative
variables. So, for example, write b1 = b1p - b1n, where both b1p and
b1n are non-negative.
On Thu, Jul 2, 2009 at 4:18 PM, Rob Helpert wrote:
> Hi Alicia,
>
> I think the trick may be to split b1 into the sum of two non-negative
> varia
Folks,
In brief -- how many of you have found the 'operators' package to be
valuable in their work?
Not that I lack respect for the amount of work involved in creating and
maintaining a package, but I am unsure about the utility of these new
operators. Several of the operators appear to offer
On 02/07/09 21:02, Mark Wardle wrote:
Hi.
I've stared at your code for a number of minutes and can't understand
what you're trying to achieve here. It looks as if you're fighting
scope - it may be worth refactoring your approach to simplify matters.
Otherwise, it sounds like a recipe for obfusca
Hi Alicia,
I think the trick may be to split b1 into the sum of two non-negative
variables. You will then also have to alter your constraints and
objective to include the two new variables with negative values in
appropriate places, but I believe that this will solve the problem.
On Thu, Jul 2,
Hi.
I've stared at your code for a number of minutes and can't understand
what you're trying to achieve here. It looks as if you're fighting
scope - it may be worth refactoring your approach to simplify matters.
Otherwise, it sounds like a recipe for obfuscation! What are you
trying to do really?
On 7/2/09, Mark Knecht wrote:
> For kicks I tried JGR yesterday. In the Rgui console, or sourcing, my
> code runs fine. In JGR it crashed with messages about stack
> imbalances.
>
Perhaps report the exact issue to
stats-rosuda-de...@listserv.uni-augsburg.de; the JGR devels may be
interested in f
WinXP, R-2.9.1
LS.,
I have been trying to solve a (for me) tricky issue. No matter what I've
tried, I just can't find a way to do this.
This is the issue:
I have a text file (ansi text) "titles.txt" with lines of text; here is
an example of such a file:
>
a brief history of polio vaccines
On 7/2/09, Don MacQueen wrote:
> Use
> deparse(substitute(df))
>
> Example from ?deparse:
>
> function(x, y) {
> plot(x, y, xlab=deparse(substitute(x)),
> ylab=deparse(substitute(y)))
> }
>
> -Don
>
Now that's interesting... deparsed means ?? de-analyze ?? I'm n
Try this:
which(x %in% max(x))
Then yuo can use, max or tail for get the last value.
On Thu, Jul 2, 2009 at 4:30 PM, Kenny D'Amica wrote:
> Hello,
>
>
>
> I'm currently writing a program to analyze economic indicators, and need
> to identify the indices of peaks and troughs in certain interval
Hi,
I know nothing about neither your model nor the Skellam distribution. I
will assume that it is a sensible model and that the parameters are
identifiable from the data.
Here is a toy example showing how to impose equality constraints:
# To maximize x1 + x2, subject to x1^2 + x2^2 = 1
#
f <-
Hello,
I'm currently writing a program to analyze economic indicators, and need
to identify the indices of peaks and troughs in certain intervals
(business cycles) of my time series. I am using which.max() for this,
which gives me the index of the first max in the interval. However, I
need a f
As indicated in some off-list mail by Frank E. Harrell Jr.,
the announcement of the availability of package
%-
SweaveListingUtils
%-
on CRAN, mingled into mail "New versions for the distr-family of
packages" t
Dear Specialists in R,
May be somebody has experiment in using pakage for the book Quantitative
Risk Management by McNeil?
This package is writen in R.
I have run this package for fitting the data to Nornal Inverse Gaussian
distribution and fased with following problem.
> Return<-read.csv("data
On 7/2/09, Ted Harding wrote:
> On 02-Jul-09 19:00:44, Mark Knecht wrote:
> > I've passed a data.frame as an input into a function which does some
> > plotting on a 4x4 matrix of certain parameters within in the
> > data.frame. I'd like to add a small header on top of each plot with
> > the na
Perfect! Thanks!
Cheers,
Mark
On 7/2/09, Phil Spector wrote:
> Mark -
>Take a look at the help file for substitute.
> For example:
>
>
> > zz = function(x)print(substitute(x))
> > zz(variablename)
> >
> variablename
>
> - Phil
>
>
>
> On Thu, 2 Jul
Use
deparse(substitute(df))
Example from ?deparse:
function(x, y) {
plot(x, y, xlab=deparse(substitute(x)),
ylab=deparse(substitute(y)))
}
-Don
At 12:00 PM -0700 7/2/09, Mark Knecht wrote:
I've passed a data.frame as an input into a function which does some
pl
On 02-Jul-09 19:00:44, Mark Knecht wrote:
> I've passed a data.frame as an input into a function which does some
> plotting on a 4x4 matrix of certain parameters within in the
> data.frame. I'd like to add a small header on top of each plot with
> the name of the data.frame so that it's clear as I
Your example is not self-contained, which makes it more difficult
to answer your question.
However, I believe you should be able to answer the question by
studying the examples on the help pages for "gnls" and possibly
"corCompSymm", using the following additional commands:
# T
I've passed a data.frame as an input into a function which does some
plotting on a 4x4 matrix of certain parameters within in the
data.frame. I'd like to add a small header on top of each plot with
the name of the data.frame so that it's clear as I compare these 16
things where each on came from.
Hi, everyone:
I am running logistic regression on a bunch of variables using apply
command. But an error occurs, the whole process stops. I am wondering
if anyone knows how to skip this error and to continue the
regression for the rest of variable.
What I did is that first confine a func
Dear Chris,
Perhaps the WriteXLS package (see [1]) by Marc Schwartz might be useful for
your proposes.
HTH,
Jorge
[1] http://cran.r-project.org/web/packages/WriteXLS/index.html
On Thu, Jul 2, 2009 at 2:12 PM, Chris Anderson wrote:
> Is there a way to export multiple datasets into multiple exc
Ping-Hsun Hsieh wrote:
Dear R- experts,
I am trying to superimpose two or more scatterplot matrices generated by
pairs() to visualize the differences over each datasets, but have not been very
successful. Two data frames, df1 and df2 for example, each has the same five
variables in column
Hi,
I was wondering if I could get R to warn me, or give me a rude
awakening somehow, if I'm accessing a variable that is out of my
function's scope.
For example, often times I'm creating a function as I'm testing it in
the REPL, copying and pasting between both.
As a simple example, I
Is there a way to export multiple datasets into multiple excel spreadsheets
using xlsReadWritePro or with xlsReadWrite?
Chris Anderson
707.315.8486
www.sassydeals4u.com
Turn any room into a work of art. Click now for beautiful oriental
Thanks for the pointer to substitute(), William. This seems to work and
is a little shorter than yours:
a <- 1; foo <- eval(substitute(function () print(a), env=list(a=a)))
a <- 2; foo()
# [1] 1
Not the clearest code I have ever seen, especially as 'foo' still shows 'a':
print(foo)
# function
Dear R-users,
I'm currently having trouble with the implementation of a groupedData
object in the lme() function.
Executing the following function
applyScalingSimp <- function(input.population)
{
## GA is a time value
varInOrder <- c("GA","weight","grouping","sex")
mod
Try changing "sample_file.xls" to normalizePath("sample_file.xls")
so you are passing an absolute file path to Excel.
Bill Dunlap
TIBCO Software Inc - Spotfire Division
wdunlap tibco.com
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] O
Thanks, it did not work but this worked:
xl$Workbooks()$Open("\\sample_file.xls")$Sheets()$Count()
Cheers,
Lauri
2009/7/2 Henrique Dallazuanna :
> Try this:
>
> xl$Workbooks()$Open("/sample_file.xls")$Sheets()$Count()
>
> On Thu, Jul 2, 2009 at 2:23 PM, Lauri Nikkinen
> wrote:
>>
>> Thanks, I t
Dear R- experts,
I am trying to superimpose two or more scatterplot matrices generated by
pairs() to visualize the differences over each datasets, but have not been very
successful. Two data frames, df1 and df2 for example, each has the same five
variables in columns.
My goal is to paint ea
Try this:
xl$Workbooks()$Open("/sample_file.xls")$Sheets()$Count()
On Thu, Jul 2, 2009 at 2:23 PM, Lauri Nikkinen wrote:
> Thanks, I tried and got this error:
>
> > setwd("C:/")
> > list.files(pattern=".xls")
> [1] "sample_file.xls"
> > library(RDCOMClient)
> > xl <- COMCreate("Excel.Application
Hi, everyone:
I forget on how to save a result from R as a word document. For
example, if I run the linear regression and want to save the result:
summary(lm(y~x)
in a word file. So I can show it later to my clients. Any idea on
how to do this?
Thanks a lot,
Suyan
___
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Allan Engelhardt
> Sent: Thursday, July 02, 2009 9:47 AM
> To: r-help@r-project.org
> Subject: [R] How to use current value of variable in function
> definition?
>
> Must be the heat or something but I can'
Thanks, I tried and got this error:
> setwd("C:/")
> list.files(pattern=".xls")
[1] "sample_file.xls"
> library(RDCOMClient)
> xl <- COMCreate("Excel.Application")
> xl$Workbooks()$Open("sample_file.xls")$Sheets()$Count()
Error in .COM(x, name, ...) :
'sample_file.xls' could not be found. Check
Please tell us about the actual problem that you are trying to solve,
because the "answer" would very much depend on that.
Are your constraints really sum(par) = 0? If so, you can just eliminate one
of the parameters and solve the optimization problems with (p-1) parameters.
If you have other c
I don't seem to be able to put any syntax into identify() that gets
it to work with "lattice" cloud() graph:
layout(1)
require('lattice')
cloud(g3 ~ g1 + g2, data=gapp, col = "blue",
xlab='G1 Score', ylab='G2 Score',
zlab='G3 Score', main='3D Plot for Applicants')
identify(gapp[,2:4], labels
Kristian Karlson wrote:
Hi,
I am working with -poLCA- which uses the package -scatterplot3d- in
order to work. However, I work on a restricted server that is not
online. The R-version installed there is 2.6. However, running
library(poLCA) after installing the most recent -scatterplot3d- on th
Dear Martin,
Thank you for the propmt and highly informative reply!
In my experiments, I compared (a) smooth.spline (with both GCV and CV for
automatic bw selection), (b) spm() in "SemiPar", which implements penalized
splines smoothing with REML estimation of penalty, (c) glkerns() in
"lokern", w
Thank you Rich,
it looks very nice and seems to be the better solution.
Udo
Quoting "Richard M. Heiberger" :
I would do this as a lattice plot. Continuing with your data:
tmp <- data.frame(sapply(data, tapply, data[1:2], mean))
tmp$time <- factor(tmp$time)
xyplot(thanaa+thalcho+thalino+pona
Hi Henrique,
This works perfectly!. Thanks so much for your help.
Best regards,
Peter
Henrique Dallazuanna wrote:
>
> Peter,
>
> Try this:
>
> apply(do.call(merge, c(loadfiles, by = "Time"))[2:3], 1, mean)
>
> On Thu, Jul 2, 2009 at 10:39 AM, Peter Perez wrote:
>
>>
>> Hi,
>>
>> Thanks t
Dear all,
I am interested in solving a MIP problem with binary outcomes and
continuous variables, which ARE NOT RESTRICTED TO BE NEGATIVE. In
particular,
Max {z1,z2,z3,b1} z1 + z2 + z3
(s.t.)
# 7 z1 + 0 z2 + 0 z3 + b1 <= 5
# 0 z1 + 8 z2 + 0 z3 - b1 <= 5
# 0 z1 + 0 z2 + 6 z3 + b1 <=
Must be the heat or something but I can't get my brain into gear and
figure out how to get something like
if (1) { c <- 1; foo <- function () print(c); }
c <- 2
foo()
to print 1, not 2. (The real life example is a little more complex, but
you get the idea. I don't want the variable c in the
> "RV" == Ravi Varadhan
> on Thu, 2 Jul 2009 10:51:03 -0400 writes:
RV> Dear Martin, I have been playing a lot with the
RV> glkerns() function in the "lokern" package for
RV> "automatic" smoothing of time-series data. This kernel
RV> smoothing approach of Gasser and M
Hi,
I am working with -poLCA- which uses the package -scatterplot3d- in
order to work. However, I work on a restricted server that is not
online. The R-version installed there is 2.6. However, running
library(poLCA) after installing the most recent -scatterplot3d- on the
server leaves me with R te
A second possibility (not as automated but very simple to do)
is to read the first sheet with verbose = TRUE:
DF <- read.xls("test.xls", sheet = 1, verbose = TRUE)
and it will display the number of sheets in a message.
You can then read them in in a loop.
On Thu, Jul 2, 2009 at 11:05 AM, Gabor
i want to estimate parameters with maximum likelihood method with contraints
(contant numbers).
for example
sum(Ai)=0 and sum(Bi)=0
i have done it without the constraints but i realised that i have to use the
contraints.
Without constraints(just a part-not complete):
skellamreg_LL=function(pa
Hello! Just want to get some suggestions on which R package is good
for analyzing time course microarray data. Thank you so much for your
input!
Sincerely,
Allen
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ht
Hi,
On Jul 2, 2009, at 11:13 AM, barbara.r...@uniroma1.it wrote:
Is there a command as "mat.or.vec(nr,nc)" to create an array that I
must calculate with more cicle?
I'm not sure your question is very clear: what do you mean by
"calculate with more cicle"?
Could you give an example of wh
On 7/2/09, Dirk Eddelbuettel wrote:
>
> On 2 July 2009 at 11:14, Steve Lianoglou wrote:
> | On Jul 2, 2009, at 10:39 AM, Mark Knecht wrote:
>
> | > 2) The closest example of the second would be a multi-study chart sort
> | > of like is typical in a lot of stock charting programs. Here's (I
> |
On 7/1/09, seeliger.c...@epamail.epa.gov wrote:
> > ... I saw my friend has a R Console window which has automatic syntax
> > reminder when he types in the first a few letters of R command. ...
>
> You might be thinking of JGR (Jaguar) at
> http://jgr.markushelbig.org/JGR.html . This editor als
Hi,
On Jul 2, 2009, at 11:26 AM, Mark Knecht wrote:
On 7/2/09, Steve Lianoglou wrote:
[snip]
One thing you could do is to peruse the R Graph Gallery to see what
people
can do:
http://addictedtor.free.fr/graphiques/
In particular, the graph below looks *somehow* similar to the chart
you
plot.zoo and xyplot.zoo in the zoo package both produce
multipanel plots with one panel per series (or optionally
all on one panel or a mixture).
library(zoo)
example(plot.zoo)
example(xyplot.zoo)
and see the three zoo vignettes.
The quantmod package has charting specifically oriented to
securit
Dear R users,
I 'm working on a dataset consisting of 4 different dataframes with
tree, leaf, fruit and seed measurements made on 300 trees, coming from
10 provenances (30 trees per provenance, 10 leaves/fruits/seeds per
tree). Provenances are fixed effects (they were not randomly chosen),
but
On 2 July 2009 at 11:14, Steve Lianoglou wrote:
| On Jul 2, 2009, at 10:39 AM, Mark Knecht wrote:
| > 2) The closest example of the second would be a multi-study chart sort
| > of like is typical in a lot of stock charting programs. Here's (I
| > hope) a simple example:
| >
| > http://stockcharts.
On 7/2/09, Mark Knecht wrote:
> On 7/2/09, Steve Lianoglou wrote:
> >
> > In particular, the graph below looks *somehow* similar to the chart you
> > link to.
> >
> > http://addictedtor.free.fr/graphiques/RGraphGallery.php?graph=109
>
> What a great site! Thanks!
>
> The chart you point
On 7/2/2009 10:53 AM, Bert Gunter wrote:
-- (The Windows GUI does have syntax completion
using TAB, but not the hints.)
I never knew that! Where is this documented? -- i.e. where are all the
features of the Windows GUI documented (as there may well be others I don't
know about).
The CHA
Is there a command as "mat.or.vec(nr,nc)" to create an array that I must
calculate with more cicle?
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
If you are on Windows and have Excel on the same machine
then the code here:
http://tolstoy.newcastle.edu.au/R/e6/help/09/03/7736.html
will return the number of worksheets as well as a vector of
the worksheet names.
It seems that the email has somehow caused some of the
lines to wrap so you will
On Jul 2, 2009, at 11:26 AM, Mark Knecht wrote:
On 7/2/09, Steve Lianoglou wrote:
Hi,
On Jul 2, 2009, at 10:39 AM, Mark Knecht wrote:
Hi,
So far my plotting needs have been sort of ignored as I got
acquainted with R this week, but now that I have the basics in place
for the program I want
I have recently discovered the "playwith" library, which is great for
creating complex lattice objects.
If you start with a simple lattice plot then modify it using playwith, you
can export the code to produce the spiffed up plot.
I noticed this function at the bottom of the xyplot documentation i
On 7/2/09, Steve Lianoglou wrote:
> Hi,
>
> On Jul 2, 2009, at 10:39 AM, Mark Knecht wrote:
>
>
> > Hi,
> > So far my plotting needs have been sort of ignored as I got
> > acquainted with R this week, but now that I have the basics in place
> > for the program I wanted to write it's time for me
Try
hf$hour <- as.POSIXlt(hf$date)$hour
hf$month <- as.POSIXlt(hf$date)$mon+1
To see why, use the man pages to study the structure of POSIXlt objects. Try:
tmp <- strptime("20/2/06 11:16:16.683", "%d/%m/%y %H:%M:%OS")
unclass(tmp)
For example:
tmp <- strptime("20/2/06 11:16:16.6
Hi,
On Jul 2, 2009, at 10:39 AM, Mark Knecht wrote:
Hi,
So far my plotting needs have been sort of ignored as I got
acquainted with R this week, but now that I have the basics in place
for the program I wanted to write it's time for me to start learning
about how to make output that better s
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