Philip A. Viton wrote:
Is it possible to change the behavior of RGui/RConsole under MS
Windows so that, if you submit a bunch of commands from a script
window, when they've finished, focus is given to the Console, and not
(as now) to the script?
That's normally the job of the
Hi, R users,
I have a problem about how to generate random sample interval from a duration.
For example, during a time duration 0-70s, I want to generate a sample which
last 10s.
the sample could be 0-10 or 30-40s or 25-35s etc
How could I do it in R`??
Thanks a lot.
Tammy
Hi
r-help-boun...@r-project.org napsal dne 23.08.2009 05:00:11:
Hi,
It is easy to understand the types vector and frame.
But I am wondering why the type factor is designed in R. What is the
advantage of factor compare with other data types in R? Can somebody
give an example in which
Hi
r-help-boun...@r-project.org napsal dne 23.08.2009 17:29:48:
On 8/23/2009 9:58 AM, David Winsemius wrote:
I still have problems with this statement. As I understand R, this
should be impossible. I have looked at both you postings and neither of
them clarify the issues. How can you have
I need a simple algorithm to generate random ranges.
From: metal_lical...@live.com
To: r-help@r-project.org
Date: Mon, 24 Aug 2009 09:55:35 +0300
Subject: [R] Generate random sample interval
Hi, R users,
I have a problem about how to generate random sample interval from a duration.
On Aug 24, 2009, at 2:55 AM, Tammy Ma wrote:
Hi, R users,
I have a problem about how to generate random sample interval from a
duration.
For example, during a time duration 0-70s, I want to generate a
sample which last 10s.
the sample could be 0-10 or 30-40s or 25-35s etc
How could I
Dear R-help listers,
I want to add 95% confidential interval as vertical lines to x
axe in density plot. I have found the library(hdrcde) can do this
work, but I do not know
how to handle functions of this library when I used ggplot2 to draw the graph.
Thank you in advance.
The data and codes
Hi:
I've installed the precompiled binary for Windows. I need to use an existing
function, but I want to introduce some slight changes to it.
1. Is there a way for me to find the source files through windows explorer?
I know I can see it using edit(object name) but I want to know if I can see
it
1. Just enter
arima
at the R console to see its source code (without comments). The source
tar.gz for R is found by googling for R, clicking on CRAN in left column
and choosing mirror. Or to view it online or get it via svn:
https://svn.r-project.org/R/
2. You want myarima's free variables
I've rolled up R-2.9.2.tar.gz a short while ago.
This is a maintenance release and fixes a number of mostly minor issues.
See the full list of changes below.
You can get it from
http://cran.r-project.org/src/base/R-2/R-2.9.2.tar.gz
or wait for it to be mirrored at a CRAN site nearer to you.
I have a gnuplot script:
plot 'gp.dat' using 1:2 with line
pause mouse
and would like to have R CMD BATCH script that works similarily...
x-read.table(gp.dat)
options(device=windows)
plot(x[,1],x[,2])
what I am looking for now is an R functions which behaves like pause mouse
in gnuplot, i.e.
Show us how you extract the confidence interval from the functions in
the hdrcde library and then we might be able to help you.
HTH,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research
# Hi all,
# I want to increase the line width of the plotted lines
# in a xy-lattice plot. My own attempts were all in vain.
# Without the group option the line width is modified -
# with the option it is funnily enough not.
# Please have a look at my syntax.
#
# Many thanks in advance
# Udo
On 8/24/2009 4:47 AM, ukoe...@med.uni-marburg.de wrote:
# Hi all,
# I want to increase the line width of the plotted lines
# in a xy-lattice plot. My own attempts were all in vain.
# Without the group option the line width is modified -
# with the option it is funnily enough not.
# Please
Now it works.
Many thanks, Chuck!
Quoting Chuck Cleland cclel...@optonline.net:
On 8/24/2009 4:47 AM, ukoe...@med.uni-marburg.de wrote:
# Hi all,
# I want to increase the line width of the plotted lines
# in a xy-lattice plot. My own attempts were all in vain.
# Without the group option the
You haven't given quite enough information to be sure, but I would guess that
this is not really a problem, but rather the interesting proporty of GLMs
fitted with a canonical link described in e.g. section 2.1.8 of Wood (2006)
Generalized additive models: and introduction with R, or at the
How to NATURAL sort a vector or data frame* by row* , in ascending order ?
V1 V2V3 V4
i1 5.00e-01 1.036197e-17 4.825338e+16 0.
i104.001692e-18 1.365740e-17 2.930053e-01 0.76973827
i12 -1.052843e-17
On 23 Aug 2009, at 20:26, Uwe Ligges wrote:
Since it looks like nobody answered so far:
Your code is not reproducible, we do not have rfc, y, zVals nor
NoCols.
It's much easier to reproduce: just type in the first example from the
image help page
x - y - seq(-4*pi, 4*pi,
Hi all,
I've a trivial question. If (q) is a continous variable,actually a vector of
1000 values. how to calculate the probability that q is greater than a specific
value, i.e. P(q45)??
Thanks
Maram
[[alternative HTML version deleted]]
Hi! I'm a beginner with this webpage so, I don't know if I'm sending my
question to the correct site. Anyway, I'm working with R and I need to import
and export ENVI files, (*.HDR files). A colleague told me that there is a
package to import/export envi files but I haven't found that package,
Hello, I plan to use R with my cluster with OpenMPI.
I need the packaged 'snow' and 'Rmpi' for that, however, I get an error
while downloading and installing them:
When I do a:
install.packages(Rmpi, dependencies=T)
I get this error:
checking for mpi.h... no
Try to find libmpi.so or
Hi there,
I am currently working on something that uses hdf5 library. I think
hdf5 is a great data format, I've used it somewhat extensively in
python via PyTables. I was looking for something similar to that in R.
The closest I can get is this library: hdf5. While it does not work
the same way
Dear sir,
I am fitting a glm with default identity link:
model-glm(timetoacceptsecs~maleage*maletub*relweight*malemobtrue*femmobtrue)
the model is overdisperesed and plot model shows a low level of linearity of
the residuals. The overdispersion and linearity of residulas on the normal Q-Q
Hi there,
a text Window is supposed to map the shortcuts for copying and pasting
(Ctrl-C, Ctrl-V) automatically.
I'm working under Mac OS X and my text window doesn't really map these
functions automatically - it works fine under Windows. Is there an
easy way to map copypaste functions to
hi every one,
i have a excel sheet like this
labels starts ends
1 first task 1-Jan-04 3-Mar-04
2 second task 2-Feb-04 5-May-04
3 third task 3-Mar-04 6-Jun-04
4 fourth task 4-Apr-04 8-Aug-04
5 fifth task 5-May-04 9-Sep-04
now i converted this excel sheet into csv file and i read
Dear all,
i want to display a text in a barplot.
Actual I simply work with the following lines:
text(0.3,0.2,substring(teammembers.paint,1,140),cex=0.45,pos=4,srt=90)
text(0.48,0.2,substring(teammembers.paint,141,1000),cex=0.45,pos=4,srt=90)
The problem is, that teammembers.paint could be very
?strwrap
On Mon, Aug 24, 2009 at 3:53 AM, kojjens.k...@gmx.li wrote:
Dear all,
i want to display a text in a barplot.
Actual I simply work with the following lines:
text(0.3,0.2,substring(teammembers.paint,1,140),cex=0.45,pos=4,srt=90)
Beatriz Yannicelli wrote:
Dear all:
Is it possible to conduct a discriminant analysis in R with categorical and
continuous variables as predictors?
Beatriz
Beatriz,
Simply doing this in the R console:
RSiteSearch(discriminant)
yields many promising links. In particular, check documentation
Stefan Evert wrote:
On 23 Aug 2009, at 20:26, Uwe Ligges wrote:
Since it looks like nobody answered so far:
Your code is not reproducible, we do not have rfc, y, zVals nor NoCols.
It's much easier to reproduce: just type in the first example from the
image help page
x - y -
Thanks Baptiste
The eval(parse()) combination is just what I need.
baptiste auguie wrote:
Try this,
mystr -c==1
subset(foo, eval(parse(text = mystr)) )
library(fortunes)
fortune(parse) # try several times
# I prefer this, but there is probably a better way
mycond- quote(c==1)
subset(foo,
maram salem wrote:
Hi all,
I've a trivial question. If (q) is a continous variable,actually a vector of 1000
values. how to calculate the probability that q is greater than a specific value,
i.e. P(q45)??
Do you want to estimate any distribution or do you just want the
empirical
On Aug 24, 2009, at 8:11 AM, maram salem wrote:
Hi all,
I've a trivial question. If (q) is a continous variable,actually a
vector of 1000 values. how to calculate the probability that q is
greater than a specific value, i.e. P(q45)??
sum(q45)/1000 # if no NA's in vector
sum(q45,
Moumita Das ha scritto:
How to NATURAL sort a vector or data frame* by row* , in ascending order ?
V1 V2V3 V4
i1 5.00e-01 1.036197e-17 4.825338e+16 0.
i104.001692e-18 1.365740e-17 2.930053e-01 0.76973827
On Aug 24, 2009, at 8:21 AM, Anne Skoeries wrote:
Hi there,
a text Window is supposed to map the shortcuts for copying and
pasting (Ctrl-C, Ctrl-V) automatically.
I'm working under Mac OS X and my text window doesn't really map
these functions automatically - it works fine under Windows.
Hello r-help,
I am using lme with two specs for the variance func
varComb(varFixed(~1/n)),varPower(~Age))
this produces worse forecasts than the lm model with simple
weights=n
I think due to the fact that the lme spec works on variance inside the group. I
need to show it that 1/n scales the
Your code is not reproducible, we do not have rfc, y, zVals nor
NoCols.
It's much easier to reproduce: just type in the first example from
the image help page
x - y - seq(-4*pi, 4*pi, len=27)
r - sqrt(outer(x^2, y^2, +))
image(z = z - cos(r^2)*exp(-r/6), col=gray((0:32)/32))
then
2009/8/24 Lucas Sevilla García luckocto...@hotmail.com:
Hi! I'm a beginner with this webpage so, I don't know if I'm sending my
question to the correct site. Anyway, I'm working with R and I need to import
and export ENVI files, (*.HDR files). A colleague told me that there is a
package to
Clarification:
Lm is much better than the base forecast from lme level=0,
Level=1 produces a much tighter fit than lm.
I was expecting that level=0 would produce something very close to lm, but it
does not.
[[alternative HTML version deleted]]
On Aug 24, 2009, at 8:22 AM, rajclinasia wrote:
hi every one,
i have a excel sheet like this
labels starts ends
1 first task 1-Jan-04 3-Mar-04
2 second task 2-Feb-04 5-May-04
3 third task 3-Mar-04 6-Jun-04
4 fourth task 4-Apr-04 8-Aug-04
5 fifth task 5-May-04 9-Sep-04
now i
Dear all,
I have encountered a weird behaviour in R
survival package which seems to me to be a bug.
The weird behaviour happens when I am using
100 variables in the ridge function when calling
coxph with following formula Surv(time = futime,
event = fustat, type = right) ~ ridge(X1, X2,
On Mon, Aug 24, 2009 at 2:20 PM, polemon pole...@gmail.com wrote:
Hello, I plan to use R with my cluster with OpenMPI.
I need the packaged 'snow' and 'Rmpi' for that, however, I get an error
while downloading and installing them:
When I do a:
install.packages(Rmpi, dependencies=T)
I
On 8/24/2009 2:06 AM, Petr PIKAL wrote:
Hi
r-help-boun...@r-project.org napsal dne 23.08.2009 17:29:48:
On 8/23/2009 9:58 AM, David Winsemius wrote:
I still have problems with this statement. As I understand R, this
should be impossible. I have looked at both you postings and neither of
To drop empty factor levels from a subset, I use the following:
a.subset - subset(dataset, Color!='BLUE')
ifac - sapply(a.subset,is.factor)
a.subset[ifac] - lapply(a.subset[ifac],factor)
Mike
dataset
Color Score
1 RED10
2 RED13
3 RED12
4 WHITE22
5 WHITE27
6 WHITE
On Mon, 24 Aug 2009 05:22:17 -0700 (PDT) rajclinasia r...@clinasia.com
wrote:
R my.gantt.info-read.csv(C:/Documents and
R Settings/balakrishna/Desktop/one.csv).
R
R and for create gantt chart i used below code.
R
R gantt.chart(my.gantt.info).
This again is why others have pointed you first to
CRAN (and crantastic) updates this week
New packages
Updated packages
New reviews
---
This email provided as a service for the R community by
http://crantastic.org.
Like it? Hate it? Please let us know: crana...@gmail.com.
Sorry, we had some problems with the initial sending of our weekly digest
which resulted in a rather empty email. Here is the correct version:
CRAN (and crantastic) updates this week
New packages
* atm (0.1.0)
Charlotte Maia
http://crantastic.org/packages/atm
An R package for
I like it. Thanks.
2009/8/24 hadley wickham crana...@gmail.com:
Sorry, we had some problems with the initial sending of our weekly digest
which resulted in a rather empty email. Here is the correct version:
CRAN (and crantastic) updates this week
New packages
* atm (0.1.0)
Hello,
I'm trying to tackle a problem that would require the implementation of a
recurrent NN. However, even though the CRAN is very big, I can’t seem to
find a package for this. Does anybody here know if one exits?
BR,
John
--
View this message in context:
Great idea - thx!
On Mon, Aug 24, 2009 at 9:30 AM, hadley wickham crana...@gmail.com wrote:
Sorry, we had some problems with the initial sending of our weekly digest
which resulted in a rather empty email. Here is the correct version:
CRAN (and crantastic) updates this week
New packages
First of all, thanks to everyone who answers these questions - it's
most helpful.
I'm new to R and despite searching have not found an example of what I
want to do (there are some good beginner's guides and a lot of complex
plots, but I haven't found this).
I would like to plot two variables
Hi,
Being a R-newbie I am wondering how to calculate a correlation
coefficient (preferably with an associated p-value) for data like:
d[,1]
[1] 25.5 25.3 25.1 NA 23.3 21.5 23.8 23.2 24.2 22.7 27.6 24.2 ...
d[,2]
[1] 0.0 11.1 0.0 NA 0.0 10.1 10.6 9.5 0.0 57.9 0.0 0.0 ...
On 24-Aug-09 14:47:02, Christian Meesters wrote:
Hi,
Being a R-newbie I am wondering how to calculate a correlation
coefficient (preferably with an associated p-value) for data like:
d[,1]
[1] 25.5 25.3 25.1 NA 23.3 21.5 23.8 23.2 24.2 22.7 27.6 24.2 ...
d[,2]
[1] 0.0 11.1 0.0 NA
On Aug 24, 2009, at 11:26 AM, (Ted Harding) wrote:
On 24-Aug-09 14:47:02, Christian Meesters wrote:
Hi,
Being a R-newbie I am wondering how to calculate a correlation
coefficient (preferably with an associated p-value) for data like:
d[,1]
[1] 25.5 25.3 25.1 NA 23.3 21.5 23.8 23.2 24.2
On Aug 24, 2009, at 11:38 AM, David Winsemius wrote:
On Aug 24, 2009, at 11:26 AM, (Ted Harding) wrote:
On 24-Aug-09 14:47:02, Christian Meesters wrote:
Hi,
Being a R-newbie I am wondering how to calculate a correlation
coefficient (preferably with an associated p-value) for data like:
I apologize for what seems like it should be a straighforward query.
I am trying to multiply a list by a numeric and thought there would be a
straightforward way to do this, but the best solution I found so far has a
for loop.
Everything else I try seems to throw an error non-numeric argument to
Mcdonald, Grant wrote:
Dear sir,
I am fitting a glm with default identity link:
model-glm(timetoacceptsecs~maleage*maletub*relweight*malemobtrue*femmobtrue)
the model is overdisperesed and plot model shows a low level of linearity
of the residuals.
I don't see how the
hi,
i want to use the function table to build a table not of frequence (number of
time the vareable is repeated in a list or a data frame!!) but in function of
classes
I don t find a clear explnation in examples of ?table !!!
example
x y z
1 0 100
5 1 1500
6
Inline below.
Bert Gunter
Genentech Nonclinical Biostatisics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of David Winsemius
Sent: Monday, August 24, 2009 8:53 AM
To: David Winsemius
Cc: r-help@r-project.org Help;
On Aug 24, 2009, at 10:58 AM, Brigid Mooney wrote:
I apologize for what seems like it should be a straighforward query.
I am trying to multiply a list by a numeric and thought there would
be a
straightforward way to do this, but the best solution I found so far
has a
for loop.
Everything
Try
lapply(abc, function(x) x*3)
Peter Ehlers
Brigid Mooney wrote:
I apologize for what seems like it should be a straighforward query.
I am trying to multiply a list by a numeric and thought there would be a
straightforward way to do this, but the best solution I found so far has a
for
If I have two matrices like
x - matrix(rep(c(1,2,3),3),3)
y - matrix(rep(c(4,5,6),3),3)
How can I combine them to get ?
1 1 1 4 4 4
1 1 1 5 5 5
1 1 1 6 6 6
2 2 2 4 4 4
2 2 2 5 5 5
2 2 2 6 6 6
3 3 3 4 4 4
3 3 3 5 5 5
3 3 3 6 6 6
The number of rows and the actual numbers above are unimportant,
Hello, I am sorry, I have this problem before and Uwe send me the answer but I
misplaced it and can not find it.
writing a model for BRugs
library(BRugs)
Loading required package: coda
Loading required package: lattice
Welcome to BRugs running on OpenBUGS version 3.0.3
setwd(c:/tmp)
Error in
You need to create a factor that indicates which group the values in 'z' belong
to. The easiest way to do that based on your situation is to use the 'cut'
function to construct the factor, and then call 'table' using the result
created by 'cut'. See ?cut and ?factor
-Original
On Aug 24, 2009, at 10:59 AM, Inchallah Yarab wrote:
hi,
i want to use the function table to build a table not of frequence
(number of time the vareable is repeated in a list or a data
frame!!) but in function of classes
I don t find a clear explnation in examples of ?table !!!
example
Inchallah Yarab wrote:
i want to do a table summerizing the number of variable where z is in
[0-1000],],[1000-3000], [ 3000]
You can use cut to create a new vector of labels and tabulate the result.
Options control closed/open endpoints (see ?cut):
z -
[Note R-Devel is the wrong list for such questions. R-Help is where this
should have been directed - redirected there now]
On Mon, 2009-08-24 at 17:02 +0100, Corrado wrote:
Dear R-experts,
I have a question on the formulas used in the gam function of the mgcv
package.
I am trying to
Try this;
do.call(rbind, lapply(split(x, seq(nrow(x))), cbind, y))
On Mon, Aug 24, 2009 at 1:16 PM, Daniel Nordlund djnordl...@verizon.netwrote:
If I have two matrices like
x - matrix(rep(c(1,2,3),3),3)
y - matrix(rep(c(4,5,6),3),3)
How can I combine them to get ?
1 1 1 4 4 4
1 1 1 5
Your question is a little vague. Do you just want to know how often z falls
in one the three classes? If so, you could either code an indicator variable
(e.g. z.cat) that expresses the three categories and then do table(z.cat).
Alternatively, you could just do
sum(z0z1000)
sum(z1z3000)
ogbos okike schreef:
Hi,
I am trying to use the image function to do a color plot. My matrix columns
are labeled y and x. I tried image(y, x) but I had error message (Error in
image.default(y, x) : increasing 'x' and 'y' values expected).
Could anybody please tell me how to add these increasing
have you tried:
fits - lm(a~b)
fstat - sapply(summary(fits), function(x) x[[fstatistic]][[value]])
it takes 3secs for 100K columns on my machine (running on batt)
b
On Aug 23, 2009, at 9:55 PM, big permie wrote:
Dear R users,
I have a matrix a and a classification vector b such that
On Aug 24, 2009, at 11:16 AM, Daniel Nordlund wrote:
If I have two matrices like
x - matrix(rep(c(1,2,3),3),3)
y - matrix(rep(c(4,5,6),3),3)
How can I combine them to get ?
1 1 1 4 4 4
1 1 1 5 5 5
1 1 1 6 6 6
2 2 2 4 4 4
2 2 2 5 5 5
2 2 2 6 6 6
3 3 3 4 4 4
3 3 3 5 5 5
3 3 3 6 6 6
The
jlwoodard wrote:
Each of the above lines successfully excludes the BLUE subjects, but the
BLUE category is still present in my data set; that is, if I try
table(Color) I get
RED WHITE BLUE
82 151 0
How can I eliminate the BLUE category completely so I can do a t-test
Hi all,
Is there a quick way to display or recall data points from a specific region
on the plot? For example I want the points from x5 and y5?
Thank you very much!
--
Edward Chen
[[alternative HTML version deleted]]
__
R-help@r-project.org
On Aug 24, 2009, at 11:46 AM, Marc Schwartz wrote:
On Aug 24, 2009, at 11:16 AM, Daniel Nordlund wrote:
If I have two matrices like
x - matrix(rep(c(1,2,3),3),3)
y - matrix(rep(c(4,5,6),3),3)
How can I combine them to get ?
1 1 1 4 4 4
1 1 1 5 5 5
1 1 1 6 6 6
2 2 2 4 4 4
2 2 2 5 5 5
2 2
I may be misunderstanding the question but would
cor(d1, use='complete.obs') or some other variant of use help?
--- On Mon, 8/24/09, Christian Meesters meest...@imbie.uni-bonn.de wrote:
From: Christian Meesters meest...@imbie.uni-bonn.de
Subject: [R] robust method to obtain a correlation
Try this:
kronecker(cbind(x, y), rep(1, 3))
On Mon, Aug 24, 2009 at 12:16 PM, Daniel Nordlunddjnordl...@verizon.net wrote:
If I have two matrices like
x - matrix(rep(c(1,2,3),3),3)
y - matrix(rep(c(4,5,6),3),3)
How can I combine them to get ?
1 1 1 4 4 4
1 1 1 5 5 5
1 1 1 6 6 6
2 2
-Original Message-
From: Marc Schwartz [mailto:marc_schwa...@me.com]
Sent: Monday, August 24, 2009 9:57 AM
To: Daniel Nordlund
Cc: r help
Subject: Re: [R] Combining matrices
On Aug 24, 2009, at 11:46 AM, Marc Schwartz wrote:
On Aug 24, 2009, at 11:16 AM, Daniel Nordlund
I am assuming that you want to desplay all the data and highlight the subset.
Set up a vector to indicate the breakdown of the data and you can do it fairly
easily in ggplot2 if you treat the vector as a factor.
library(ggplot)
mydata - data.frame(x=1:21, y= -10:10)
z - ifelse(mydata[,1]5
whizvast wrote:
Hi, Adrian-
If you use overwrite=T parameter, you will overwrite the entire table,
not each record. this is the essence of my problem and i still haven't
found out right solution. i am thinking of writing my own MySQLwriteTable
function...
Thank you for your answer
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Budi Mulyono
Sent: Monday, August 24, 2009 3:38 AM
To: r-help@r-project.org
Subject: [R] hdf5 package segfault when processing large data
Hi there,
I am currently working
Dear Mike:
I don't know.
1. What specific error message do you get?
2. Your example is too long for me to parse, especially with
the color being stripped before I saw it.
3. Have you tried using debug(cro.etest.grab), then
walking through
On Aug 24, 2009, at 12:55 PM, Edward Chen wrote:
Hi all,
Is there a quick way to display or recall data points from a
specific region
on the plot? For example I want the points from x5 and y5?
Thank you very much!
Your question is pretty light on specifics but assuming that you have
Hello folks,
I have some data where spatial autocorrelation seems to be a serious
problem, and I'm unclear on how to deal with it in R. I've tried to do my
homework - read through 'The R Book,' use the online help in R, search the
internet, etc. - and I still have some unanswered questions. I'd
Hello everyone, when I run the unique command on my data frame, it deletes
the majority of duplicate rows, but not all of them. Here is a sample of my
data. How do I get it to delete all the rows?
6 -115.38 32.894 195 162.94 D 8419 D
7 -115.432 32.864 115 208.91 D 8419 D
8 -115.447 32.773
I really don't think this is the issue. I think the issue is that some columns
of the data.frame, specifically V1, V2, and V4 should be checked versus R FAQ
7.31.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Don McKenzie
Have you looked at the Spatial task view on CRAN? That would seem to me
the logical first place to go.
Bert Gunter
Genentech Nonclinical Biostatisics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of timothy_hand...@nps.gov
Sent:
Duplicated did not work, I agree with Erik. Is there any way I can specify a
tolerance limit and then delete?
On Mon, Aug 24, 2009 at 11:41 AM, Erik Iverson eiver...@nmdp.org wrote:
I really don't think this is the issue. I think the issue is that some
columns of the data.frame, specifically
Hi Emma,
R gives you the tools to work this out.
## Example
set.seed(7)
TDat - data.frame(response = c(rnorm(100, 5, 2), rnorm(100, 20, 2)))
TDat$group - gl(2, 100, labels=c(A,B))
with(TDat, boxplot(split(response, group)))
summary(aov(response ~ group, data=TDat))
Regards, Mark.
emj83
Hi;
assume i-10
how can i create a list having key=10 and value=11
list(i=11) generates a list with
'i'
[1] 11
and not
10
[1] 11
any help?
Thanks
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Bert Gunter
Genentech Nonclinical Biostatisics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Mehdi Khan
Sent: Monday, August 24, 2009 11:52 AM
To: Erik Iverson
Cc: r-help@r-project.org
Subject: Re: [R] Unique command not
duplicated()
test.df
V1 V2 V3 V4 V5 V6 V7
1 -115.380 32.894 195 162.940 D 8419 D
2 -115.432 32.864 115 208.910 D 8419 D
3 -115.447 32.773 1170 264.570 D 8419 D
4 -115.447 32.773 1170 264.570 D 8419 D
5 -115.447 32.773 1170 264.570 D 8419 D
6 -115.447 32.773 1170
Bert -
I took a look at that page just now, and I'd classify my problem as
spatial regression. Unfortunately, I don't think the spdep library fits my
needs. Or at least, I can't figure out how to use it for this problem. The
examples I have seen all use spdep with networks. They build a graph,
Try this:
l - list(i + 1)
names(l) - i
On Mon, Aug 24, 2009 at 4:01 PM, rami jiossy sra...@hotmail.com wrote:
Hi;
assume i-10
how can i create a list having key=10 and value=11
list(i=11) generates a list with
'i'
[1] 11
and not
10
[1] 11
any help?
Thanks
Yep;
great thanks :)
Date: Mon, 24 Aug 2009 16:11:20 -0300
Subject: Re: [R] create list entry from variable
From: www...@gmail.com
To: sra...@hotmail.com
CC: r-help@r-project.org
Try this:
l - list(i + 1)
names(l) - i
On Mon, Aug 24, 2009 at 4:01 PM, rami jiossy sra...@hotmail.com wrote:
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of rami jiossy
Sent: Monday, August 24, 2009 12:01 PM
To: R-Help
Subject: [R] create list entry from variable
Hi;
assume i-10
how can i create a list having key=10 and
On Mon, 24-Aug-2009 at 08:00AM -0700, Rick wrote:
First of all, thanks to everyone who answers these questions - it's
most helpful.
I'm new to R and despite searching have not found an example of what I
want to do (there are some good beginner's guides and a lot of complex
plots, but I
David: Well, e.g. the first row has 2 ones in your output while there
were no rows with 2 ones in the original matrix. Since the row and
column sums can't be changed by sorting them, the output matrix can't be
equivalent to the original one. But that means nothing, maybe it's
intended and just
I am trying to come up with a way of shading-in a grid for a simple pattern
So far I can draw a square where I want but I cannot seem to draw a complete
grid. I am just drawing them along the diagonal!!
Clearly I am missing something simple but what?
Any suggestions gratefully accepted.
On Aug 24, 2009, at 11:00 AM, Rick wrote:
First of all, thanks to everyone who answers these questions - it's
most helpful.
I'm new to R and despite searching have not found an example of what I
want to do (there are some good beginner's guides and a lot of complex
plots, but I haven't
On Aug 24, 2009, at 4:01 PM, Michael Kogan wrote:
David: Well, e.g. the first row has 2 ones in your output while
there were no rows with 2 ones in the original matrix. Since the row
and column sums can't be changed by sorting them, the output matrix
can't be equivalent to the original
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