Hi
r-help-boun...@r-project.org napsal dne 03.03.2010 22:50:59:
> I'm trying to get started with R, on Ubuntu. I worked through the
> tutorial, and have made a small tab-delimited subset of my data to try
> out (10 cases with about a dozens variables). But I can't seem to figure
> out how to actu
Hi Jim, and thanks for your solution. I figured one out for myself
about a minute after I posted this, and here it is if anyone else can
find it valuable:
subsetData<- bigData[,grep(partialName, colnames(bigData))]
This is smaller than your solution, but similar I think.
Cheers,
Sarah
On Thu
Sarah Henderson wrote:
>
>
> I think my Python brain is missing something crucial about string
> operations in R, but I cannot figure this out.
>
> I have a large data frame with several groups of similar variables.
> Similar variables are named according to their group, and I am now
> writing
On 03/04/2010 05:51 PM, Sarah Henderson wrote:
Hi all --
I think my Python brain is missing something crucial about string
operations in R, but I cannot figure this out.
I have a large data frame with several groups of similar variables.
Similar variables are named according to their group, and
Hi all --
I think my Python brain is missing something crucial about string
operations in R, but I cannot figure this out.
I have a large data frame with several groups of similar variables.
Similar variables are named according to their group, and I am now
writing a function to check correlation
Hi,
Looking for a function in R that can help me calculate a parameter that
maximizes the likelihood over groups of observations.
The general formula is:
p = exp(xb) / sum(exp(xb))
So, according to the formulas I've seen published, to do this "by group" is
product(p = exp(x_i * b_i) / sum(exp(
John,
I felt a short, somewhat strong reply was in order. One of the inherent
aspects of the language is that R demands more of an understanding from
users about what is taking place. Model formulae, for example, are close to
what one would use if they were to write the model on paper. I consider
Do your own homework!
It looks pretty trivial; what's your problem?
cheers,
Rolf Turner
On 4/03/2010, at 2:39 PM, Pitmaster wrote:
>
> Hi guys... I have problem with this excersise...
>
> Consider the pressure data frame again.
>
> (a) Plot pressure against temper
Hi guys... I have problem with this excersise...
Consider the pressure data frame again.
(a) Plot pressure against temperature, and use the following
command to pass a curve through these data:
> curve((0.168 + 0.007*x)ˆ(20/3), from=0, to=400, add=TRUE)
(b) Now, apply the power transformation
Dear list members,
I have been using R to create a heatmap where my data has continous
variables from 0 to 100.
When I create the heatmap, although the branches are correct, they do not
order themselves so that the row with the most zeros is at one end and the
row with the most 100s is at the othe
Hello.
I want to use conditional logistic regression to calculate the probability
of winning one of three players in golf. I was able to calculate these
probabilities in Stata10, and I now want to transfer the code in the R
Project, because it is can get data directly form MySQL. Unfortunately, I'
Toby -
Thanks for the reproducible example!
I think this will do what you want:
both = merge(test1,test2)
subset(both,time >= rise & time <= set)
- Phil Spector
Statistical Computing Facility
Dear R helpers,
I have a dataframe (test1) containing the time of sunrise and sunset for each
day of the year
for 3 years. I have another dataframe (test2) containing measurements that are
taken every
15 minutes, 24/7. I would like to extract all rows from test2 that occur
between sunrise an
Albyn -
That's a very important fact that I overlooked in my
original response. Thanks for pointing it out.
- Phil
On Wed, 3 Mar 2010, Albyn Jones wrote:
Note: this procedure assumes that all clusters have the same covariance matrix.
alby
Hello Everyone,
Can anyone show me how to use discrete choice data to estimate marginal
willingness to pay? I've searched for simple information or code on how to do
this but haven't found much.
The closest I've come is a paper titled "Introduction to Choice Experiments
using R." The paper s
x <- rep(c("A","B"),c(4,3))
table(x)['A']
Capiche?
Bert Gunter
Genentech Nonclinical Biostatistics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Randall Wrong
Sent: Wednesday, March 03, 2010 3:03 PM
To: Nutter, Benjamin; Henri
On 03/03/2010 5:25 PM, DarioAustralia wrote:
Ah yes sorry about that it was a vague posting.
What I'd like to see when I do a R CMD check on the package and it gets to
the part where it runs the test script, I'd like to show to the user on the
screen the progress of the testing. What happens now
Hello I have a time series object which I created from the following code
Fechas<-Datos[,1]
dat<-Datos[,2:ncol(Datos)]
datTS<-timeSeries(dat,Fechas)
I am trying to do know basic arithmethic operations on it as the following
datTS[3708,1]*2
Error en e1 * e2 : argumento no-numérico para operador bin
sorry, it should say "I copied the model from the car manual.."
more precise, I did the same as there in doing the lm(cbind()) call first an
then the av.ok, etc.
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Sent from the R h
On Thu, 4 Mar 2010, Rebecca Lawrence wrote:
Hi all,
I am running the following model:
glm89.nb <- glm.nb(AvGUD ~ Year*Trt*Micro)
where Year has 3 levels, Trt has 2 levels and Micro has 3 levels.
However when I run it has a zero inflated negative binomial (as I have lots
of zeros) I get the
I've never had any trouble using R and screen with a remote connection.
You're detaching it first, right? (Just to start with the obvious question.)
What exactly are you doing, and what happens?
Sarah
On Wed, Mar 3, 2010 at 5:43 PM, Jonathan Greenberg
wrote:
> I'm having a mixed experience with
On 03/04/2010 08:20 AM, David Winsemius wrote:
...
Perhaps the print methods for data.frame and matrix
should announce the class of the object being printed.
Yes! An enthusiastic vote for highlighting this fundamental distinction.
There is already quite enough conflation of these two very diss
Thanks to all of you !
(Benjamin Nutter, Henrique Dallazuanna, Tobias Verbeke, Jorge Ivan Velez,
David Reinke and Gavin Simpson)
x <- c(1, 1, 1, NA, NA, 2, 1, NA)
> table(x)["1"]
1
4
Why do I get two numbers ?
Thanks,
Randall
2010/2/26 Nutter, Benjamin
> But if x has any missing values:
>
Note: this procedure assumes that all clusters have the same covariance matrix.
albyn
On Wed, Mar 03, 2010 at 01:23:37PM -0800, Phil Spector wrote:
> The manhattan distance and the Mahalanobis distances are quite different.
> One of the main differences is that a covariance matrix is necessary
Hi all,
I have this data set:
## Empirical copula
## dt1 = ranking
## dt2 = observed uniform data associated with the ranking
Sample data,
> dt1
S_i R_i
[1,] 7.0 10.0
[2,] 232.5 440.5
[3,] 143.0 141.5
[4,] 272.5 222.0
[5,] 46.0 34.0
[6,] 527.0 483.0
[7,] 420.5 563.5
[8,]
I'm having a mixed experience with using R and UNIX's screen function
-- sometimes when I close a connection that used screen, the R process
is killed (which, in theory, it shouldn't be -- it should be running
in the background). Does anyone have any ideas on how well (or not) R
behaves with scree
Ah yes sorry about that it was a vague posting.
What I'd like to see when I do a R CMD check on the package and it gets to
the part where it runs the test script, I'd like to show to the user on the
screen the progress of the testing. What happens now is none of the
cat("Test X was successful. \n
On 4/03/2010, at 10:50 AM, Steven DeRose wrote:
> I'm trying to get started with R, on Ubuntu. I worked through the
> tutorial, and have made a small tab-delimited subset of my data to try
> out (10 cases with about a dozens variables). But I can't seem to figure
> out how to actually refer to va
Hi Steve,
I think the problem is just that those variables are in the con
data.frame. If so you have several options:
1) with(con, plot(rel, len))
2) plot(con$rel, con$len)
3) attach(con); plot(rel, len)
Best,
Ista
On Wed, Mar 3, 2010 at 4:50 PM, Steven DeRose
wrote:
> I'm trying to get starte
Hi all,
I am running the following model:
> glm89.nb <- glm.nb(AvGUD ~ Year*Trt*Micro)
where Year has 3 levels, Trt has 2 levels and Micro has 3 levels.
However when I run it has a zero inflated negative binomial (as I have lots
of zeros) I get the below error message:
> Zinb <- zeroinfl(AvGU
The following code takes a combination of type n over k represented by an
increasing sequence
as input an produces the lexicographically next combinations.
So you can single step through all possible combinations and apply your filter
criteria
before you produce the next combination.
next.combi
I'm trying to get started with R, on Ubuntu. I worked through the
tutorial, and have made a small tab-delimited subset of my data to try
out (10 cases with about a dozens variables). But I can't seem to figure
out how to actually refer to variables. I presume I'm missing something
very simple, but
"The manhattan distance and the Mahalanobis distances are quite different. "
This ought to be a candidate for "fortunes".
The way distances are perceived in New York city is very different from that in
Calcutta (which is where Professor Prasant Chandra Mahalanobis lived)!
Ravi.
On Mar 3, 2010, at 12:35 PM, Herm Walsh wrote:
Thanks David for the thoughts. The challenge I have with this
approach is that the criteria I have is defined by a series of
tests--which I do not think I could substitute in in place of the
logical indexing.
In the combinations code I was
On Mar 3, 2010, at 12:15 PM, William Dunlap wrote:
If R made
matrix$columnName
mean the same as
matrix[, "columnName"]
(a vector) so matrices looked more like data.frames,
would we also want the following to work
as they do with data.frames?
with(matrix, log(columnName)) # log of that col
The manhattan distance and the Mahalanobis distances are
quite different. One of the main differences is that
a covariance matrix is necessary to calculate the Mahalanobis
distance, so it's not easily accomodated by dist. There
is a function in base R which does calculate the Mahalanobis
dist
I'm making some 3D plots with contour3d from misc3d and wireframe from lattice.
I want to view them from below; i.e. the negative z-axis. I can't figure out
how to do so. I would like my point of view looking up from below, with the z,
y, and x axes positive going away. Can anyone tell me th
I am sorry,
After further inspection I fear my last answer was not correct, please
ignore it - and let's wait for other responders.
Tal
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili
when you create the distance function to put into the hclust, use:
dist(x, method = "manhattan")
Tal
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatisti
How can I perform cluster analysis using the mahalanobis distance instead of
the euclidean distance?
thank you
Naama Wolf
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___
I need to create a line and bar panel chart with two different axes. I tried
in lattice but couldn't get it worked. Here is my code:
data(barley)
barchart(yield ~ variety | site, data = barley,
groups = year, layout = c(1,6), stack = F,
auto.key = list(points = FALSE,
On Mar 3, 2010, at 9:04 AM, Newbie19_02 wrote:
Thanks again for the help but what I am having trouble with is that
I get:
1012 CAO0103166 01/04/1999 I200
1016 CAO0103166 03/05/2000 I200
1024 CAO0103166 20/06/1997 I209
1025 CAO0103166 25/02/
Bill,
The points you make are well taken; one needs to know when to stop.
I would suggest standardizing the methods used to refer to elements of a matrix
and a dataframe and going no further. Why do I say this? A beginner, even a
more experienced R users, probably envisions a dataframe and a ma
You can try this also:
plot(m <- matrix(v, ncol = 2, byrow = TRUE))
polygon(m)
On Wed, Mar 3, 2010 at 4:49 PM, sylvain willart
wrote:
> SOLVED,
>
> example from the "Nord-Pas-de-Calais" region:
>
>
> v <-
> c(237,55,236,58,229,57,214,57,203,55,197,54
You are using a random function to generate this values(runif).
So, in each replication, the value is not equal.
On Wed, Mar 3, 2010 at 4:50 PM, Val wrote:
> Thank you Henrique,
>
> However,
>
> F1<-sum(!findInterval(colMeans(replicate(100, z1(100, 4))), 0.2:0.3))
> F2<-sum(findInterval(colMean
Tena koe Anna
The following appears to do what you want (anna is a dataframe
containing the data you provided):
anna$Test <- anna$Signals
anna[duplicated(paste(anna$Dates, anna$Signals)),'Test'] <- 0
anna
Dates Signals Filtered.Signal Test
1 02-11-06 0 00
2 02-11-0
Try this:
f$Filtered <- unlist(sapply(unstack(f, Signals ~ Dates),
function(.x)tabulate(which(as.logical(.x))[1], length(.x
On Wed, Mar 3, 2010 at 4:20 PM, anna wrote:
>
> Hello R lovers,
> I have a vector of dates and signals. I want to filter the signals per day
> in a way that only the f
ifelse(ave(signals, dates , FUN=cumsum) = 1, 1, 0)
-
Anna Lippel
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__
R-help@r-project
Thank you Henrique,
However,
F1<-sum(!findInterval(colMeans(replicate(100, z1(100, 4))), 0.2:0.3))
F2<-sum(findInterval(colMeans(replicate(100, z1(100, 4))), 0.2:0.3))
the sum of the two (F1+F2) = number of replicates (in this case 100).
Sometimes I do not get that sum. Do you know why?
Val
SOLVED,
example from the "Nord-Pas-de-Calais" region:
v <-
c(237,55,236,58,229,57,214,57,203,55,197,54,187,48,179,46,179,35,180,31,184,26,197,23,201,24,202,31,207,34,213,31,216,37,219,41,228,46,234,47,237,55)
seqx <- seq(1,length(v),by=2)
seqy <- seq
Try this:
sum(!findInterval(colMeans(replicate(1000, z1(100, 4))), 0.2:0.3))
On Wed, Mar 3, 2010 at 4:15 PM, Val wrote:
> Hi all,
>
> Assume the following function that generate a random number.
>
> z1<-function (n, eta)
> {
> wv <- runif(n)
> wz <- (-1/eta) * log(wv)
> wz
>
Hello R lovers,
I have a vector of dates and signals. I want to filter the signals per day
in a way that only the first signal of the day remains like this:
Dates Signals Filtered Signal
2006-11-02 00
2006-11-02 11
2006-11
Thanks David for the thoughts. The challenge I have with this approach is that
the criteria I have is defined by a series of tests--which I do not think I
could substitute in in place of the logical indexing.
In the combinations code I was hoping there is a step where, each new
combination is
May doing a cumsum restricted on each date could help, I remember I read
someone doing this on a post...because once i do this i will be able to
discriminate the numbers different from 1.
-
Anna Lippel
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Dear R users,
I am trying to read a huge file in R. For some reason, only a part of the
file is read. When I further investigated, I found that in one of my
non-numeric columns, there is one odd character responsible for this, which
I reproduce bellow:
In case you cannot see it, it looks like a
Can anybody explain to me how to calculate Eigen values for linear
discriminants, which have been identified in the scaling matrix of a LDA
analysis [lda()].
cheers
~~
Robert Lonsinger
Wildlife Grad. Research Assistant
New Mexico State University
Dept. of Fish, Wildlife
Hi all,
Assume the following function that generate a random number.
z1<-function (n, eta)
{
wv <- runif(n)
wz <- (-1/eta) * log(wv)
wz
}
y <- z1(100,4)
mean(y)
I want to run this function say 1000 times and I want to count if
the mean(y) outside the following range 0.
I find myself loading the TeachingDemos package most often, though in my case
there may be one of those chicken/egg things going on.
I also use MASS and rms quite a bit (if we are limited to 3, but I also use
survival, Hmisc, and splines, but they are loaded with rms).
The package that I really
If R made
matrix$columnName
mean the same as
matrix[, "columnName"]
(a vector) so matrices looked more like data.frames,
would we also want the following to work
as they do with data.frames?
with(matrix, log(columnName)) # log of that column as a vector
matrix["columnName"] # 1-column m
azman wrote:
>
> i'am is new in R software.i have try to make a function but it can't give
> what it should.i dunno what have to do next.
> Can somebody help me to solve it.i'll very appreciate...
>
>
Your example is nice, because it is self-contained (even if there is a
buglet). When I run i
Dieter,
One way to check if a package is active, is by looking on r-forge. If you
are referring to data.table you would have found it is actually very active
at the moment and is far from abandoned.
What you may be referring to is a warning, not an error, with v1.2 on
R2.10+. That was fixed m
I use rms, lme4, ggplot2 frequently (also lattice and MASS).
On Tue, Mar 2, 2010 at 3:13 PM, Ralf B wrote:
> Hi R-fans,
>
> I would like put out a question to all R users on this list and hope
> it will create some feedback and discussion.
>
> 1) What are your 3 most useful R package? and
>
> 2)
Chuck and John,
Thank you both for your help. I figured that my problem was trying to work
through a new area for me, and trying to learn a new package for that area at
the same time. You have both provided examples that clarified things that I
either didn't understand about SEM in general or
Correct.
Ralf
---
Ralf Bierig
Post-Doctoral Associate
School of Communication and Information
Rutgers University
New Brunswick, NJ 08901-1071, USA
On Wed, Mar 3, 2010 at 4:16 AM, Philippe Grosjean
wrote:
>
>
> On 03/03/10 09:26, Karl Ove Hufthammer wrote:
>>
>> On Tue, 2 Mar 2010 15:13:54 -05
The simRasch function in MiscPsycho package simulates person abilities using
N(mu, sigma^2) and items from U(-x,x), which is not what you're asking for.
But, I also am not sure how you would manipulate the other moments. However,
item parameters tend not to be normally distributed in operational
to simulate from IRT models have a look at function rmvlogis() from
package ltm.
I hope it helps.
Best,
Dimitris
On 3/3/2010 6:05 PM, Stuart Luppescu wrote:
On Wed, 2010-03-03 at 09:45 -0600, Helen Lisman wrote:
hello R,
This is about simulation in psychomtrics in IRT in R. I want to simul
On Wed, 2010-03-03 at 09:45 -0600, Helen Lisman wrote:
> hello R,
> This is about simulation in psychomtrics in IRT in R. I want to simulate b
> parameters(item difficulty) with moments of fixed values of mean, st.d,
> skewness and kurtosis. Is there any specific IRT package in R with those
> funct
Others answered your question. I would however suggest that you asked the
wrong question.
If you really feel the need for your future self to serve some serious penance
for past or near future misdeeds, then continuing with this strategy is one way
to do that (just please don't inflict your su
Hi,
I have an issue with the write.table command:
I have a dataset, with many rows and 3 columns. I give a row example:
"alexia""roger","delphine" "roger","bruno","sandra"
I fist process the data to be able to process the column entries as vectors:
mo<-readLines("c:\\data.txt",n=
What is your entire dataset and the code used to do this?
On Wed, Mar 3, 2010 at 12:04 PM, Newbie19_02 wrote:
>
> Thanks again for the help but what I am having trouble with is that I get:
>
> 1012 CAO0103166 01/04/1999 I200
> 1016 CAO0103166 03/05/2000 I200
> 1024
Dear John,
Thanks very much for your message. I should have looked at the help
page for sem() more closely. Thanks again for your excellent work on
the package.
Regards,
Chuck
On 3/3/2010 10:18 AM, John Fox wrote:
> Dear Chuck and Daniel,
>
> First, thanks Chuck for fielding the question,
On Mar 3, 2010, at 7:24 AM, BioStudent wrote:
>
> Thanks!
>
> I'm just trying to do it now but having issues with memory...
>
> test <- merge(file1, file2, by.x = "col1")
>
> will this give me the output I was hoping for
>
> ID VALUE1 VALUE2
>
> ?
>
> Thanks
If you are going to use 'by.x'
I think Brian and Josh the two powerhouses behind quantmod and other finance
related packages are working on a package called 'blotter' which is on
r-forge which may be able to help you with keeping track and doing some
testing of trading strategies.
regards,
cj
On 3/3/201
Hi
r-help-boun...@r-project.org napsal dne 01.03.2010 16:36:27:
>
> Hi Petr,
>
> Thanks again for trying again with these data, I really appreciate it.
>
> Your script works perfectly, but the problem I'm having is how to store
the
> model results so after your script I would do:
>
>
Thanks!
I'm just trying to do it now but having issues with memory...
test <- merge(file1, file2, by.x = "col1")
will this give me the output I was hoping for
ID VALUE1 VALUE2
?
Thanks
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Unfortunately its complaining that 'by.x' and 'by.y' specify different
numbers of columns'.
I don't really see why that matters if your matching tbh...
I'm having a few problems. Merge is definitely what I want but my files are
way too big and i'm having memory trouble. Plus I figures out the I
Hi,
are your dataframes really called file1 and file2? Then, it will be
something like this:
test
Links:
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[2]
(link removed) =
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other than " base" :
1. XML & Rcurl2. lattice3. Hmisc
> On Tue, Mar 2, 2010 at 10:13 PM, Ralf B wrote:
>
> > Hi R-fans,
> >
> > I would like put out a question to all R users on this list and hope
> > it will create some feedback and discussion.
> >
> > 1) What are your 3
hello R,
This is about simulation in psychomtrics in IRT in R. I want to simulate b
parameters(item difficulty) with moments of fixed values of mean, st.d,
skewness and kurtosis. Is there any specific IRT package in R with those
functions to control those moments? I have seen other programs that ca
Hi
r-help-boun...@r-project.org napsal dne 03.03.2010 08:27:27:
> Hello,
>
> I'm trying to learn R (for fun!), and I've tried to find any previous
> discussion of this problem (or something like it) and haven't found one.
>
> When I run the following command, R seems to simply stop. I get no e
Hi
that is why I consider matrix is just a vector with dimensions and
data.frame is a rectangular structure similar to Excel table. That saved
me a lot of surprises.
But I must admit I am not a real beginner nowadays although I still learn
when using R, reading help list and trying sometimes
On Mar 3, 2010, at 7:45 , wrote:
Actually the problem exists only if I use JGR.
Make sure you upgrade JGR. You need JGR 1.7 or higher to work with R
2.10. If you have any questions, please use the JGR mailing list stats-
rosuda-devel.
Thanks,
Simon
If I launch R from a terminal win
Petr,
On the other hand . . .
> mat<-matrix(1:12, 3,4)
> dat<-as.data.frame(mat)
> mat
[,1] [,2] [,3] [,4]
[1,]147 10
[2,]258 11
[3,]369 12
> dat
V1 V2 V3 V4
1 1 4 7 10
2 2 5 8 11
3 3 6 9 12
What you are demonstrating by your example is th
Dear Chuck and Daniel,
First, thanks Chuck for fielding the question, which I didn't notice in
r-help.
I can get solutions for models A, B, and C using the automatic start values
along with the argument par.size="startvalues" to sem() (as recommended in
?sem if there are convergence problems). Fo
1) quantmod, zoo, xts, TTR in no particular order, the first requires the
others, so I can't really separate them.
2) There are plenty of packages for my needs (using R as a hobbyist), but my
biggest concern is that they lack active support. A package for complex testing
of trading strategies
Thanks again for the help but what I am having trouble with is that I get:
1012 CAO0103166 01/04/1999 I200
1016 CAO0103166 03/05/2000 I200
1024 CAO0103166 20/06/1997 I209
1025 CAO0103166 25/02/1999 I209
1027 CAO0103166 27/08/1999
Then:
subset(x, grepl('410|I25', main_condition))
On Wed, Mar 3, 2010 at 11:59 AM, Newbie19_02 wrote:
>
> Hi,
>
> That was a good suggestion but I should have been more specific,
> PROCHI Date_admission main_condition
> CAO3121534 15/08/2006 I501
> 2
I am attempting Anova analysis to compare results from four groups (Samp1-4)
which are lists of intensities from the experiment. I am doing this by first
creating a structured list of the data and then conducting the ANOVA (Script
provided below). Im an R beginner so am not sure if I am using th
Hi,
That was a good suggestion but I should have been more specific,
PROCHIDate_admission main_condition
CAO3121534 15/08/2006 I501
28394 CAO3121534 18/04/1999 I251
28395 CAO3121534 18/10/1993 4109
28396 CAO3121534 1
Hi,
On Wed, Mar 3, 2010 at 4:08 AM, Häring, Tim (LWF)
wrote:
> (...)
>
>> While you're sending your bug report to David, perhaps you can try the
>> SVM from kernlab.
>>
>> It relies on code from libsvm, too, but ... you never know. It can't
>> hurt to try.
>
> Hi Steve,
>
> thanks for that hint.
"John Sorkin" napsal dne 01.03.2010
15:19:10:
> If it looks like a duck and quacks like a duck, it ought to behave like
a duck.
>
> To the user a matrix and a dataframe look alike . . . except a dataframe
can
Well, matrix looks like a data.frame only on the first sight.
mat<-matrix(1:12, 3
Try this:
subset(x, grepl('411', Main_condition))
On Wed, Mar 3, 2010 at 11:33 AM, Newbie19_02 wrote:
>
> Hi everyone,
>
> I would like to subset a data.frame using partial values.
>
> For example I have the following data.frame:
>
> PROCHI Main_condition
> 1234 411
> 1235 4110
> 1236
That in itself is a question for the maintainer, off r-help. When the
posting guide says "contact the package maintainer first" it means it
literally and applies even to questions about the existence of a mailing
list for the package. So what I'm supposed to do now is tell you how the
posting
DarioAustralia wrote:
>
> In the .R file I put in the tests directory, I have a number of cat("My
> text here") type statements, that explain when a certain test completed
> successfully but everything I tried so far (like putting sink(NULL) at the
> top of the .R file) hasn't worked. Does someo
Hi everyone,
I would like to subset a data.frame using partial values.
For example I have the following data.frame:
PROCHI Main_condition
1234 411
1235 4110
1236 4111
1237 I20
1238I201
1239I202
Now let's say that I use the Subset function. Ordinarily I would use it a
Rob Forler wrote:
>
> And data.table because it does aggregation about 50x times faster than
> plyr
> (which I used to use a lot).
>
>
This is correct, from the error message its spits out one has to conclude
that is was abandoned at R-version 2.4.x
Dieter
--
View this message in contex
Hello I have 2000 univariate timeSeries of about 20 observations each, as
the following, I would like to store all of them in one object, sort of a
data frame or something similar. Do you know how can I do this. Thank you
Felipe Parra
GMT
2009-10-12
2009-10-12 0.002346171
2009-10-14
On 3/2/2010 1:43 AM, Daniel Nordlund wrote:
> I have been working through the book "Applied longitudinal data analysis:
> modeling change and event occurrence" by Judith D. Singer and John B.
> Willett. I have been working examples using SAS and also using it as an
> opportunity for learning to
3 most used packages:
1)spdep (for spatial regression/statistics)
2)car
3)survival (which is recommended, so)
3.5) survey (for analysis of complex survey samples)
Best to all,
Corey
-
Corey Sparks, PhD
Assistant Professor
Department of Demography and Organization Studies
University of Texas
Hi Frederik,
There is no need for the double for loop:
b[,5] <- sin(runif(5,0,2*pi))
As to your question, check the values i and k take. In the first
iteration of the second loop k == 0, and R does not support an index
equal to 0. The problem is in 1:n-1, this gives 0- 4, in stead do
1:(n-1)
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