Hi!
Well, I actually have no idea how to do it.
But here a few more tips to get answers:
- write a specific subject to your email
- explain what you want to do, what you already did, what did not work, etc.
- provide a reproducible example, that's really important so that people
can know what y
Hi,
I have to zoo real valued time series "a" and "b" same length.
is index(a)<-index(b) same as time(a)<-time(b)?
Which one is better?
Best,
Costas
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PLEASE do read th
Just to add to the confusion, for (nearly) all practical purposes they are the
same:
> all.equal(df1, df2)
[1] TRUE
> do.call(paste, df1)
[1] "1 4" "2 5" "3 6"
> do.call(paste, df2)
[1] "1 4" "2 5" "3 6"
>
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r
On 08/01/2010 08:48 PM, thmsfuller...@gmail.com wrote:
Hi,
The following two 'df's should be the same, although their
constructions are different.
But they aren't the same.
df1 <- data.frame(X=c(1, 2, 3), Y=c(4, 5, 6))
df2 <- data.frame(X=1:3, Y=4:6)
identical(df1, df2)
yields FALSE
See
st
Hi, R-helpers,
I am working on a problem of measurement error modeling. (I am new to this
filed)
The model I am dealing with is simple. Consider a linear regression y= beta0
+ beta1 * x + error, in which x is measured with errors. (the variance of
errors are known. )
I looked up the package simex
Hi John,
Here is my code practicing. Please give me some advises. Thank you.
Wu Gong
# Extract the function string
f.str <- sub("y~","",exprtext)
# Get arglist from the text
sp1 <- paste("\\",c(getGroupMembers(Arith),"(",")"),sep="")
sp2 <- getGroupMembers(Math)
sps <- paste(c(sp1,sp2),sep="",c
Hi,
The following two 'df's should be the same, although their
constructions are different. But the results of paste() are different.
I don't see this is explained in ?paste. Could you help me understand
why it is like this?
> df=data.frame(X=c(1, 2, 3), Y=c(4, 5, 6))
> df
X Y
1 1 4
2 2 5
3 3 6
Hi,
But i didn't understand why you did it like this qnorm(40/200)??
I already found the answer qnorm(.20,181,7.3) and qnorm(.80,181,7.3)
Thanks.
On Mon, Aug 2, 2010 at 12:33 AM, Arun.stat wrote:
>
> try
> qnorm(40/200)
> --
> View this message in context:
> http://r.789695.n4.nabble.com/He
Dear List,
I am using R 2.11.1 and R2HTML 2.1. I am able to write output to an HTML
file but after every line of output I get a line saying NULL. R2HTML seems
to be including NULL after each entry.
Here is an example of my R code and the source of the HTML...
HTMLStart(outdir=OutPath, file="M
Hi list,
As title, under windows, the methord of ~/.inputrc won't work, dunno how
to let Rterm can be vi style?
--
Regards,
Yue Wu
Key Laboratory of Modern Chinese Medicines
Department of Traditional Chinese Medicine
China Pharmaceutical University
No.24, Tongjia Xiang Street, Nanjing 210009
Would this be suitable?
http://en.wikipedia.org/wiki/File:Rlogo.png
[[alternative HTML version deleted]]
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Also note that you can 'switch' tails via the argument lower.tail. By
default, it is TRUE.
> qnorm(p = .20, mean = 181, sd = 7.3, lower.tail = TRUE)
[1] 174.8562
> qnorm(p = .20, mean = 181, sd = 7.3, lower.tail = FALSE)
[1] 187.1438
Cheers,
Josh
On Sun, Aug 1, 2010 at 4:04 PM, Arun Kumar Saha
On Sun, Aug 1, 2010 at 6:06 PM, Erin Hodgess wrote:
> Dear R People:
>
> I'm trying to convert a daily zoo object to a weekly zoo object:
>
>
> xdate <- seq(as.Date("2002-01-01"),as.Date("2010-07-10"),by="day")
> library(zoo)
> length(xdate)
> xt <- zoo(rnorm(3113),order=xdate)
> xdat2 <- seq(i
CRAN (and crantastic) updates this week
New packages
* alabama (2010.7-1)
Ravi Varadhan
http://crantastic.org/packages/alabama
Augmented Lagrangian Adaptive Barrier Minimization Algorithm for
optimizing smooth nonlinear objective functions with constraints.
Linear or nonli
I gave you hint only, however whatever you done is correct.
On Mon, Aug 2, 2010 at 4:30 AM, n.a.s wrote:
> Hi,
>
> But i didn't understand why you did it like this qnorm(40/200)??
>
> I already found the answer qnorm(.20,181,7.3) and qnorm(.80,181,7.3)
>
>
> Thanks.
>
>
> On Mon, Aug 2, 2010 a
Dear all,
many thanks, great work. Here is the feature which Peter suggested (it also
includes a string containing the variable name):
DD <- function(f, var.string="x", order=1){
res <- f
body.res <- body(f)
i <- 1
while(i <= order){
body.res <- D(
Dear R People:
I'm trying to convert a daily zoo object to a weekly zoo object:
xdate <- seq(as.Date("2002-01-01"),as.Date("2010-07-10"),by="day")
library(zoo)
length(xdate)
xt <- zoo(rnorm(3113),order=xdate)
xdat2 <- seq(index(xt)[1],index(xt)[3113],by="week")
xt.w <- aggregate(xt,by=xdat2,
I tried several ways:
1. I used the scan() function, it can read the 6GB file into the memory
without difficulty, just took some time. But just read into the memory was
definitely not enough, when I did the next step, which was to plot() and
then tried to build the nonlinear regression model, it
n.a.s gmail.com> writes:
>
> Hi , can any one help in this problem
>
> According to some study, the height for Northern European adult males is
> normally distributed with an average of 181 centimeter and a standard
> deviation of 7.3 centimeter. Suppose such an adult male is randomly chosen.
>
try
qnorm(40/200)
--
View this message in context:
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Sent from the R help mailing list archive at Nabble.com.
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Hi , can any one help in this problem
According to some study, the height for Northern European adult males is
normally distributed with an average of 181 centimeter and a standard
deviation of 7.3 centimeter. Suppose such an adult male is randomly chosen.
Let X be height of that person. The nex
>
> Anyone knows if there is a way to connect R with the ERP SAP?
Very big question.
An ERP is an accounting system typically for a large business or
governmental entity (ERP = "Enterprise Resource Planning" system). Modern
ERPs are typically built on top of (multi-user) relational data base
mana
Hhi there.
Here's the example.
pdf(file="C:/Users/Modelisation/Desktop/BubblePlot.pdf", width = 15, height
= 15, family = "Times", pointsize = 25);
par(mfcol = c(3,3), mar = c(3,3,3,3), oma = c(0,0,0,0));
for (i in 5:33)
{
print(bubble(temp,i, col = "cornflowerblue"));
Hi, is there any way to say: "this class 'x' is a S3 class?" For example what
is the type of class "data.frame"? Is it a S3 class or S4?
How can I get a complete list of all S3 classes currently available?
Thanks,
__
R-help@r-project.org mailing list
Yes, they are just a file that as many processes as you want to access
them; just be careful if you do update the file unless you are somehow
locking it.
On Sun, Aug 1, 2010 at 10:00 AM, 顾小波 wrote:
> Especially for large ff objects.
>
>
>
>
>
> Xiaobo.Gu
>
>
>
>
> [[alternative HTML versio
Dear All,
I have come across a very surprising result as I have started to learn how
to use R to pull data from the web for analysis.
I am trying to isolate that table headers for the quarterly income
statement (qtrinc) that I pulled from Google finance. I executed the
following commands after i
Ron,
In arithmetic, '-' and '+' are binary _and_ unary operators. That is,
both -1 and 1-1 are valid arithmetic expressions, the former negates its
argument, and the latter subtracts the second from the first. Since much
of R is designed do arithmetic, R honors the unary _and_ binary versions
of '
On Sun, Aug 1, 2010 at 7:56 AM, Ron Michael wrote:
> Hi friends, I am aware of the function "-"() which acts as minus in ordinary
> computations. For example:
>
>> "-"(3, 1)
> [1] 2
>
> However what is the meaning of
>> "-"(3)
> [1] -3
This seems quite functionally useful; consider the behavior
well
"*"(3,2) works but "*"(3,2,3) does not. You should now be able to
figure out the logic. It is related to the number of arguments that
make sense.
Nikhil Kaza
Asst. Professor,
City and Regional Planning
University of North Carolina
nikhil.l...@gmail.com
On Aug 1, 2010, at 10:56 AM, R
It would be helpful if you give a sample data to illustrate the problem. I
really can't understand what you want:)
-
A R learner.
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Sent from
On Sun, 1 Aug 2010, ted.hard...@manchester.ac.uk wrote:
On 01-Aug-10 10:59:03, Tims Corbett wrote:
Hi, What does it mean to say Lognormal distribution with a mean of
1.03E-6 with a range factor of 100 ? How can I find the lognormal
distribution paramters from this information?
Thanks, Tims
I
Hi,
Can rattle utilize parallel processing mechanisms such as foreach?
Can rattle analyze ff objects ?
Xiaobo.Gu
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Especially for large ff objects.
Xiaobo.Gu
[[alternative HTML version deleted]]
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.
Hi friends, I am aware of the function "-"() which acts as minus in ordinary
computations. For example:
> "-"(3, 1)
[1] 2
However what is the meaning of
> "-"(3)
[1] -3
I was expecting R to generate some error as it does for "*"(3). What is the
logic for that calculation?
Thanks,
Hi,
Can the plenty of analytical functions provided by base R and
contributed packages be called with ff objects as parameters directly, or do we
have to write special version of the functions for ff objects? If it is the
latter case, is there a list of functions which support ff objec
Hi,
After reading the slices from ff project site I know ff can be used with
snowfall to achieve parallel processing, I want to know is it the only way, can
we combine package foreach and ff, especially in a SMP server, with doMC and
multicore behind foreach.
Xiaobo.Gu
[[altern
Hello everybody,
when I create an object of class boot with the function tsboot() from the
package boot and try to compute several types of confidence intervals with
boot.ci("object of class boot created with tsboot") I obtain the warning
message, that "BCa-intervals are not defined for time-se
Thanks for confirming my suspicions! And yes, I (clearly) don't understand
how namespaces work in R. I've only been able to find bits and pieces on the
web (and the Intro to R). Most of these have been confused and don't tell
you much. The Intro to R states: "Namespaces prevent the user's definitio
-- Forwarded message --
From: Ambikesh Jayal
Date: Sun, Aug 1, 2010 at 2:24 PM
Subject: Re: [R] Using R for Multiple Regression
To: ted.hard...@manchester.ac.uk
Hi Ted,
Thanks to all those who have replied. It was very helpful.
As there can be multiple solutions, is there a way
Hi
Does anybody know how to create ff objects with data reading from stream
objects, such as data reading from PostgreSQL database through RPostgreSQL. For
this purpose although we can save the data to a csv file through external tools
and then read it through csv readers, but it requires one m
I failed many times until Gabor gave his solution. The magic tick!
PART1 <- 'TEXT'
PART2 <- '^'
PART3 <- '`\u00ae`'
ARG <- paste(PART1, PART2, PART3)
text(2,8, parse(text=str))
-
A R learner.
--
View this message in context:
http://r.789695.n4.nabble.com/Constructing-arguments-for-plotmat
On Sun, Aug 1, 2010 at 11:03 AM, Dennis Fisher wrote:
> Colleagues,
>
> I am encountering difficulty adding formatted text to a graphic.
> Specifically, I want to add a superscript in the middle of a text string but
> I would like to format the text string on the fly. The commands:
> pl
On Aug 1, 2010, at 11:03 AM, Dennis Fisher wrote:
Colleagues,
I am encountering difficulty adding formatted text to a graphic.
Specifically, I want to add a superscript in the middle of a text
string but I would like to format the text string on the fly. The
commands:
plot(1,1
Thanks Ted,
> I came across this "range factor" in the context of Bayesian analysis:
>
> The range factor of the lognormal distribution was fixed to 100 which
> provides a very broad distribution and might be regarded as slightly
> informative prior.
>
> This is all I have about the jargon.
> Tims
Colleagues,
I am encountering difficulty adding formatted text to a graphic. Specifically,
I want to add a superscript in the middle of a text string but I would like to
format the text string on the fly. The commands:
plot(1,1)
ARG <- bquote('TEXT'^'\u00ae')
mtext(
Peter Dalgaard gmail.com> writes:
> Issue #2 is stickier. I think I must say that the idelology of mle() is
> that the user passes a likelihood function. If the likelihood function
> depends on global data, and the user changes the global data, the user
> deserves what he or she gets... It is pre
?replicate
?apply
?sapply
Nikhil Kaza
Asst. Professor,
City and Regional Planning
University of North Carolina
nikhil.l...@gmail.com
On Aug 1, 2010, at 2:42 AM, leepama wrote:
hi!! imade many codes during these days..
I study Statistics
please one more question!!
ex1<-function(n,p,rho){
pdb philbrierley.com> writes:
>
>
> Hi,
>
> Here is what I need to generate...
>
> 1 x
> 2 z
> 3 z
> 4 y
>
> Any pointers would be appreciated.
>
> Regards,
>
this should work, probably other options are possible
a <- data.frame(x = rnorm(4), y = rnorm(4), z = rnorm(4))
z<-apply(a,
a <- data.frame(x = rnorm(4), y = rnorm(4), z = rnorm(4))
> names(a)[apply(a, 1, which.max)]
[1] "y" "z" "z" "y"
> a
x y z
1 -0.8839957 -0.8824065 -0.9343157
2 0.3918695 1.4246880 1.6401349
3 -0.4020719 0.1342691 0.8041808
4 0.1500775 0.8966310 -0.2204660
HTH,
D
Hi,
I want to know if there is any package in R to do relableing algorithm for
solving lable switching problem in bayesian inferences
I would be so glad if you help me
thank you in anticipation
[[alternative HTML version deleted]]
__
R-help@r-p
On 01-Aug-10 10:59:03, Tims Corbett wrote:
> Hi, What does it mean to say Lognormal distribution with a mean of
> 1.03E-6 with a range factor of 100 ? How can I find the lognormal
> distribution paramters from this information?
>
> Thanks, Tims
If you can, please say what is meant by "range facto
Hi, What does it mean to say Lognormal distribution with a mean of 1.03E-6
with a range factor of 100 ? How can I find the lognormal distribution
paramters from this information?
Thanks, Tims
[[alternative HTML version deleted]]
__
R-help@r-pro
Hi,
Hopefully someone can point me in the right direction on how I would go
about solving the following.
I have some data and need to find the column name of the maximum value in
each row.
This could be the data...
> a <- data.frame(x = rnorm(4), y = rnorm(4), z = rnorm(4))
> a
x
On 08/01/2010 05:27 PM, MELOSHINI NAICKER wrote:
Please help. I have installed R commander. I am currently running Windows 7.
Everytime I type library(Rcmdr), it reads "Error in library(Rcmdr) : there
is no package called 'Rcmdr
what can I do to rectify this problem. I am currently a student at
Please help. I have installed R commander. I am currently running Windows 7.
Everytime I type library(Rcmdr), it reads "Error in library(Rcmdr) : there
is no package called 'Rcmdr
what can I do to rectify this problem. I am currently a student at UQ in
Australia and followed their instructions for
Arnaud Le Rouzic wrote:
> Hi the list,
>
> I am experiencing several issues with profile.mle (and consequently with
> confint.mle) (stat4 version 2.9.2), and I have to spend a lot of time to
> find workarounds to what looks like interface bugs. I would be glad to
> get feedback from experienced
hi!! imade many codes during these days..
I study Statistics
please one more question!!
ex1<-function(n,p,rho){
muvec1=zeros(1,p)
A=eye(p)
for(i in 1:p){
for(j in 1:p){
A[i,j]=rho^(abs(i-j))
X=mvrnorm(n,muvec1,A)}}
return(X)
}
this code generates design matrix in linare regr
Hello All,
Suppose that I have a sequence of letters (e.g., A..Z). I want to
permute the sequence to generate random sequences, such that the local
density of any letter with a window (say of length L) doesn't change
much before and after permutation.
One way that I can thing of is to require tha
Dear All,
I have imported an HTML document to R (called tables) and wish to select
certain pieces of it for processing. The first few lines of the object
appear as follows:
> tables
[[1]]
In Millions of USD (except for per share items)
3 months ending 2010-06-30
3 months ending 2010
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