Re: [R] Reading in .aux (ESRI raster files) into R

2010-09-27 Thread JoH
Thank you Barry -- View this message in context: http://r.789695.n4.nabble.com/Reading-in-aux-ESRI-raster-files-into-R-tp2553544p2715015.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list

[R] textplot

2010-09-27 Thread trb1
Hi all, Please can you help me to add text to a plot. I would like 5 graphical plots and 1 text plot. I use par(mfrow=c(2,3)) then textplot() I would like to add various pieces of information to the text plot, i.e. some individual values, a table of statistics, some sentences. Is there any

Re: [R] a very basic question: calling c function from R

2010-09-27 Thread teetee
Hi, Duncan Murdoch... i m facing same pro here.. n i m a very new user for R... i m just start using it now for my final year project... i wan to know how to run outside R??? i have no idea about it... can u help me??? appreciate for your helping... -- View this message in context:

[R] Odp: Object Browser

2010-09-27 Thread Petr PIKAL
Hi I noticed that nobody answered your question yet so here is my try. If you want to see what objects are in your environment you can use ls() but its output is only names of objects. Here is a function I use a long time for checking what objects are there, their type, size and possibly rows

Re: [R] textplot

2010-09-27 Thread Tal Galili
Have a look at ?textplot From the gplots package: http://cran.r-project.org/web/packages/gplots/index.html Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) |

Re: [R] Uncertainty propagation

2010-09-27 Thread Maayt
Thanks for the help, I start to get reasonable errors on the model... I finally turned to the simpler lm() fitting. As my data from which I fit has only 8 points in each case, I guess it does not make much sense to downweight outliers and use rlm() in this case. -- View this message in

[R] Fitting with error on data

2010-09-27 Thread Maayt
As this forum proved to be very helpful, I got another question... I'd like to fit data points on which I have an error, dx and dy, on each x and y. What would be the common procedure to fit this data by a linear model taking into account uncertainty on each point? Would weighting each point by

Re: [R] Some questions about string processing

2010-09-27 Thread Michael Hopkins
Thanks Phil, very helpful and works as advertised. Any thoughts on the second question? (P.S. for anyone digging this up in the future, there's a comma missing after the formula in lm()) On 24 Sep 2010, at 18:16, Phil Spector wrote: Michael - You're doing too much work half the time,

[R] store matrix in an arrary

2010-09-27 Thread wesley mathew
Dear All I want to store matrix in an array Suppose s-array(0,4) for(i in 1:4) s[i] - read_matrix(a,2,2) But the error - number of items to replace is not a multiple of replacement length. Can you suggest me any alternative method for storing a matrix in an array. Thanks In advance. Kind Regards

Re: [R] store matrix in an arrary

2010-09-27 Thread Edwin Groot
On Mon, 27 Sep 2010 11:12:26 +0100 wesley mathew wesleycmat...@gmail.com wrote: Dear All I want to store matrix in an array Suppose s-array(0,4) for(i in 1:4) s[i] - read_matrix(a,2,2) But the error - number of items to replace is not a multiple of replacement length. Can you suggest

Re: [R] store matrix in an arrary

2010-09-27 Thread Jorge Ivan Velez
Hi Wesley, Try this (untested): s - array(0, dim = c(2, 2, 4)) for(i in 1:4) s[, ,i] - read_matrix(a, 2, 2) Another (untested) option wold be s0 - lapply(1:4, function(i) read_matrix(a, 2, 2)) s0 HTH, Jorge On Mon, Sep 27, 2010 at 6:12 AM, wesley mathew wrote: Dear All I want to

Re: [R] a very basic question: calling c function from R

2010-09-27 Thread Duncan Murdoch
On 27/09/2010 2:45 AM, teetee wrote: Hi, Duncan Murdoch... i m facing same pro here.. n i m a very new user for R... i m just start using it now for my final year project... i wan to know how to run outside R??? i have no idea about it... can u help me??? appreciate for your helping... You

[R] Fitting problem

2010-09-27 Thread pj-uk
Hi, I have a function that generates a set of data but I am having problems determining the parameters using the nls fitting procedure. MH-function(field,diameter,mu=10e-7,sig=0.1,Ms=100,chi=0){ #variables mu, sig, chi, Ms #input: field and diameter #all in CGS rho - 5 kb - 1.38e-16 t -

Re: [R] legend

2010-09-27 Thread threshold
Thanks David, works fine! robert -- View this message in context: http://r.789695.n4.nabble.com/legend-tp2550747p2715250.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list

[R] Data frame self-join with no duplicates

2010-09-27 Thread Xin Zhang
Suppose I have the following data frame (df): YearPrice --- 200110 200220 200330 I would like to produce another data frame like this: a.Yeara.Priceb.Yearb.Price 200220200110 200330

[R] Odp: Fitting problem

2010-09-27 Thread Petr PIKAL
Hi r-help-boun...@r-project.org napsal dne 27.09.2010 13:13:28: Hi, I have a function that generates a set of data but I am having problems determining the parameters using the nls fitting procedure. MH-function(field,diameter,mu=10e-7,sig=0.1,Ms=100,chi=0){ #variables mu,

Re: [R] Fitting problem

2010-09-27 Thread pj-uk
Oops I forgot to add another line to the code (see below)!! You could add some noise if you want to. Generating the data from the function was merely a way to test if the fitting procedure works - I have experimental data that should allow me to calculate the parameters mu, sig, chi and Ms

Re: [R] Data frame self-join with no duplicates

2010-09-27 Thread Dennis Murphy
Hi: One option is to read your data frame into R and then use your SQL code in conjunction with the sqldf package. It uses SQLite as its engine. HTH, Dennis On Mon, Sep 27, 2010 at 4:29 AM, Xin Zhang xin.zh...@gmail.com wrote: Suppose I have the following data frame (df): YearPrice

Re: [R] cluster analysis and supervised classification: an alternative to knn1?

2010-09-27 Thread abanero
Hi Ulrich, I'm studying the principles of Affinity Propagation and I'm really glad to use your package (apcluster) in order to cluster my data. I have just an issue to solve.. If I apply the funcion: apcluster(sim) where sim is the matrix of dissimilarities, sometimes I encounter the warning

Re: [R] Data frame self-join with no duplicates

2010-09-27 Thread Xin Zhang
Thanks Dennis. I will explore that. On Mon, Sep 27, 2010 at 7:45 AM, Dennis Murphy djmu...@gmail.com wrote: Hi: One option is to read your data frame into R and then use your SQL code in conjunction with the sqldf package. It uses SQLite as its engine. HTH, Dennis On Mon, Sep 27, 2010

Re: [R] Fitting problem

2010-09-27 Thread Petr PIKAL
r-help-boun...@r-project.org napsal dne 27.09.2010 13:36:51: Oops I forgot to add another line to the code (see below)!! You could add I do not have the previous code, I do not keep mails. some noise if you want to. Generating the data from the function was merely You want to add some

Re: [R] Problem with unlist

2010-09-27 Thread Ben Bolker
Luis Felipe Parra felipe.parra at quantil.com.co writes: Hello, I am trying to unlist a list, which is attached, and I am having the problem that when I unlist it the number of elements changes from 5065 to 5084 x - lapply(SumaPluvi, FUN=[, 1); n - sapply(x, FUN=length);

Re: [R] 95% CI of Kaplan-Meier survival in package survival

2010-09-27 Thread Terry Therneau
My result using Kaplan-Meier estimate in survival package was inconsistent with that from Minitab. The survival probabilities are same, but their 95% are different. Confidence intervals for a survival curve may be calcualted on the linear (poor performance), log (good), log-log (good), or

[R] Output Graphics GIF

2010-09-27 Thread Nilza BARROS
Dear R users, How could I managed graphics in GIF format? What I have been doing is graphics in *.ps or *.eps and after I convert them using CONVERT (from ImageMagick) but the output quality is not good. Since these graphics will be use for other users they must have a better image quality. I

[R] Output Graphics GIF

2010-09-27 Thread Nilza BARROS
Dear R users, How could I managed graphics in GIF format? What I have been doing is graphics in *.ps or *.eps and after I convert them using CONVERT (from ImageMagick) but the output quality is not good. Since these graphics will be use for other users they must have a better image quality. I

Re: [R] Fitting problem

2010-09-27 Thread pj-uk
Updated! MH-function(field,diameter,mu=10e-7,sig=0.1,Ms=100,chi=0){ #variables mu, sig, chi, Ms #input: field and diameter #all in CGS rho - 5 kb - 1.38e-16 t - 300 length.d-length(diameter) length.H-length(field) M-double(length.H) for (i in 1:length.H){ S1-0

Re: [R] Data frame self-join with no duplicates

2010-09-27 Thread jim holtman
try sqldf: require(sqldf) x - read.table(textConnection(YearPrice + 200110 + 200220 + 200330), as.is=TRUE, header=TRUE) sqldf(select a.*, b.* + from x as a, x as b + where a.Year b.Year, method='raw') Year Price Year Price 1 200220 200110 2 200330 2001

[R] Date/Time format

2010-09-27 Thread Costas
Hello, Is it possible to instruct (permanently) R to write on csv (and read from csv) time series, where the time stamp has a particular format: say: -mm-dd i.e., as in format(Sys.Date(), %Y-%m-%d) Many thanks in advance, Costas __

[R] conditional assignment of colors in xyplot()

2010-09-27 Thread nathan pellegrin
# Dear R Community, # I have this data frame: df1 - data.frame( F1 = factor( c( rep(D1,12),rep(D2,12),rep(D3,12) ) ), F2 = factor( rep( rep( paste(O,1:6,sep=), rep(2,6) ), 3) ), F3 = factor( rep( c(V1,V2), 18 ) ), S1 =

Re: [R] Output Graphics GIF

2010-09-27 Thread Barry Rowlingson
On Mon, Sep 27, 2010 at 1:39 PM, Nilza BARROS nilzabar...@gmail.com wrote: Dear R users, How could I managed graphics in GIF  format? What I have been doing is graphics in *.ps or *.eps and after I convert them using CONVERT (from ImageMagick) but the output quality is not good.  Since these

Re: [R] plotting multiple animal tracks against Date/Time

2010-09-27 Thread Gabor Grothendieck
On Mon, Sep 27, 2010 at 10:01 AM, Struve, Juliane j.str...@imperial.ac.uk wrote: Hi, I am sorry that my question wasn not very clearly formulated.  My real data comes in 47 .csv files, one for each of 47 individual, for example: ,Fish_ID,Date,R2sqrt 1,1646,2006-08-18 08:48:59,0

Re: [R] Output Graphics GIF

2010-09-27 Thread Tal Galili
I am guessing you are saving the plot using the menu system. If that is the case, have a look at: ?pdf ?png Generally, I like saving my graphics to pdf since it is vectorized. Cheers, Tal Contact Details:--- Contact me:

Re: [R] plotting multiple animal tracks against Date/Time

2010-09-27 Thread Struve, Juliane
Hi, I am sorry that my question wasn not very clearly formulated. My real data comes in 47 .csv files, one for each of 47 individual, for example: ,Fish_ID,Date,R2sqrt 1,1646,2006-08-18 08:48:59,0 2,1646,2006-08-18 09:53:20,100 I would like to read the data for all individuals in the for loop

[R] Modify the vertex label

2010-09-27 Thread anderson nuel
Dear r-help, I create a graph of my baysian network. I use the package igraph. The names of vertex are within the circle, I would leave them outside the circle? E(g)$color - black tkplot(g, ,vertex.label=names,layout=layout.kamada.kawai, edge.color=E(g)$color) Best Regards

[R] name ONLY one column

2010-09-27 Thread Lorenzo Cattarino
Hi R-users I can not change the name of one column only of my matrix. my_matrix - matrix (1:12,ncol=3) colnames(my_matrix)[1] - 'myname' Error in dimnames(x) - dn : length of 'dimnames' [2] not equal to array extent thank you for your help Lorenzo

[R] make changes in existing vector with the apply function?

2010-09-27 Thread Jonas Sundberg
Hi, I'm trying to make some changes in a vector according to some conditions. It takes too long time however with vector length 10 and I guess a better way would be using the apply function. I cannot sort out how, however.  As a for/if loop: for (i in 1:length(PrH)) { if (is.finite(PrH[i])

[R] max length of a factor variable

2010-09-27 Thread Richard Mott
Hi Is there a maximum length for the character string representing a level of a factor? I have a set of several million variables, each a factor of length 19. Each factor level is a character string which in some cases can be many thousands of characters long. I am trying to find out why

Re: [R] efficient equivalent to read.csv / write.csv

2010-09-27 Thread statquant2
thank you very much for this sql package, the thing is that thoses table I read are loaded into memory once and for all, and then we work with the data.frames... Do you think then that this is going to be quicker (as I would have thougth that building the SQL DB from the flat file would already

Re: [R] Basis functions of cubic regression spline in mgcv

2010-09-27 Thread sw283
The functional form is given in chapter 4 of my book: Wood S.N. (2006) Generalized Additive Models: An Introduction with R. Chapman and Hall/CRC Press. (reserve your copy now for christmas) ... but note that by default mgcv reparameterises so that the identifiability constraints on the

[R] bwplot superpose panel.points from another dataframe

2010-09-27 Thread Christophe Bouffioux
Hi everybody, using bwplot for producing panel boxplot with 3 dimensions i want to add a mark on each boxplot representing one individual (on all its dimensions) till now, i didn't succeed getting the desired solution I want as well to keep the median symbols as a line Many thanks for your help

Re: [R] Good documentation about Sweave

2010-09-27 Thread statquant2
Thank you all for those great links, I will look at those. Thanks again Colin -- View this message in context: http://r.789695.n4.nabble.com/Good-documentation-about-Sweave-tp2714326p2715280.html Sent from the R help mailing list archive at Nabble.com.

[R] pairs and mfrow

2010-09-27 Thread Mike Harwood
Is there an alternative to par(mfrow=c(2,1)) to get stacked scatterplot matrixes generated with pairs? I am using version 2.11.1 on Windows XP. The logic I am using follows, and the second pairs plot replaces the first plot in the current graphics device, which is not what I expected (or

Re: [R] name ONLY one column

2010-09-27 Thread Ista Zahn
Hi Lorenzo, The problem is that my_matrix does not have dimnames. See below. my_matrix - matrix (1:12,ncol=3) str(my_matrix) ## does not have dimnames dimnames(my_matrix) ## dimnames is NULL colnames(my_matrix) - myname # fails because you are trying to alter the value of something that does not

Re: [R] name ONLY one column

2010-09-27 Thread Pedersen Jon
Hi, It is because the column names do not exist. If you cast the matrix as a data frame your code would work. jon -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Lorenzo Cattarino Sent: 27. september 2010 10:27 To:

Re: [R] name ONLY one column

2010-09-27 Thread Ivan Calandra
Hi, I'm not sure it's even possible (and if it is I don't know how, but I'm no expert). But I think it doesn't make much sense to have only one named column. Just give it a vector: vect_names - c(myname1, myname2, myname3) colnames(my_matrix) - vect_names HTH, Ivan Le 9/27/2010 10:26,

Re: [R] efficient equivalent to read.csv / write.csv

2010-09-27 Thread Gabor Grothendieck
On Mon, Sep 27, 2010 at 7:49 AM, statquant2 statqu...@gmail.com wrote: thank you very much for this sql package, the thing is that thoses table I read are loaded into memory once and for all, and then we work with the data.frames... Do you think then that this is going to be quicker (as I

Re: [R] Modify the vertex label

2010-09-27 Thread Gábor Csárdi
Hi, set the 'vertex.label.dist' parameter: g - graph.ring(10) tkplot(g, vertex.label.dist=1, layout=layout.circle) See ?igraph.plotting for details. Best, Gabor On Mon, Sep 27, 2010 at 11:18 AM, anderson nuel anderson@gmail.com wrote: Dear r-help, I create a graph of my baysian

[R] smooth contour lines

2010-09-27 Thread Czerminski, Ryszard
Is there an easy way to control smoothness of the contour lines? In the plot I am working on due to the undersampling the contour lines I am getting are jugged, but it is clear by eye these should be basically straight lines. In maps package I found smooth.map function, but maybe there is a more

[R] rimage package problems

2010-09-27 Thread Ralf B
Hi all, I tried to install the rimage in order to get to the function ?read.jpeg. However, I get this error, independent what mirror I choose: install.packages(rimage) --- Please select a CRAN mirror for use in this session --- Warning message: In getDependencies(pkgs, dependencies, available,

[R] hcluster with linkage median

2010-09-27 Thread Kennedy
Hi, I want to perform a hierarchical clustering using the median as linkage metric. As I understand it the function hcluster in package amap have this option but it does not produce the results that I expect. In the example below M is a matrix of similarities that is transformed into a matrix

Re: [R] smooth contour lines

2010-09-27 Thread Duncan Murdoch
On 27/09/2010 11:11 AM, Czerminski, Ryszard wrote: Is there an easy way to control smoothness of the contour lines? In the plot I am working on due to the undersampling the contour lines I am getting are jugged, but it is clear by eye these should be basically straight lines. Straight lines

Re: [R] hcluster with linkage median

2010-09-27 Thread Peter Langfelder
On Mon, Sep 27, 2010 at 8:22 AM, Kennedy henrik.aldb...@gmail.com wrote: Hi, I want to perform a hierarchical clustering using the median as linkage metric. As I understand it the function hcluster in package amap have this option but it does not produce the results that I expect. In the

Re: [R] Newbie Correspondence Analysis Question

2010-09-27 Thread Gavin Simpson
On Sun, 2010-09-26 at 09:41 -0700, Vik Rubenfeld wrote: I'm experienced in statistics, but I am a first-time R user. I would like to use R for correspondence analysis. I have installed R (Mac OSX). I have used the package installer to install the CA package. I have run the following line

Re: [R] hcluster with linkage median

2010-09-27 Thread Peter Langfelder
On Mon, Sep 27, 2010 at 8:22 AM, Kennedy henrik.aldb...@gmail.com wrote: Hi, I want to perform a hierarchical clustering using the median as linkage metric. As I understand it the function hcluster in package amap have this option but it does not produce the results that I expect. Also, if

[R] Issue increasing DPI on a png output of a plot

2010-09-27 Thread Justin Fincher
Howdy, I have created a set of plots, but I wish to increase the dpi to 300 (instead of the default 72). From the documentation, I thought that the res parameter to png should accomplish this, but it appears to greatly alter the appearance of my plot. (plot area becomes smaller, plot lines

[R] Issue increasing DPI on a png output of a plot

2010-09-27 Thread Justin Fincher
Howdy, I have created a set of plots, but I wish to increase the dpi to 300 (instead of the default 72). From the documentation, I thought that the res parameter to png should accomplish this, but it appears to greatly alter the appearance of my plot. (plot area becomes smaller, plot lines

[R] Regular expressions: offsets of groups

2010-09-27 Thread Titus von der Malsburg
Dear list! gregexpr(a+(b+), abcdaabbc) [[1]] [1] 1 5 attr(,match.length) [1] 2 4 What I want is the offsets of the matches for the group (b+), i.e. 2 and 7, not the offsets of the complete matches. Is there a way in R to get that? I know about gsubgn and strapply, but they only give me the

[R] stacked area chart

2010-09-27 Thread Dimitri Liakhovitski
Dear R-ers! Asking for your help with building the stacked area chart for the following simple data (several variables - with date on the X axis): ### Creating a data set my.data-data.frame(date=c(20080301,20080402,20080503,20090301,20090402,20090503,20100301,20100402,20100503),

Re: [R] Issue increasing DPI on a png output of a plot

2010-09-27 Thread Peter Langfelder
On Mon, Sep 27, 2010 at 8:48 AM, Justin Fincher finc...@cs.fsu.edu wrote: Howdy,  I have created a set of plots, but I wish to increase the dpi to 300 (instead of the default 72).  From the documentation, I thought that the res parameter to png should accomplish this, but it appears to

Re: [R] Normalizing Vector with Negative Numbers

2010-09-27 Thread Greg Snow
You can use the scale function, just use the minimum instead of the mean and the range instead of the standard deviation. -- Gregory (Greg) L. Snow Ph.D. Statistical Data Center Intermountain Healthcare greg.s...@imail.org 801.408.8111 -Original Message- From:

Re: [R] make changes in existing vector with the apply function?

2010-09-27 Thread William Dunlap
-Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Jonas Sundberg Sent: Monday, September 27, 2010 1:43 AM To: r-help@r-project.org Subject: [R] make changes in existing vector with the apply function? Hi, I'm trying to make

Re: [R] bwplot superpose panel.points from another dataframe

2010-09-27 Thread Peter Ehlers
On 2010-09-27 4:54, Christophe Bouffioux wrote: bwplot(v2 ~ v1 | z, data = ex3, layout=c(3,2), pch = |, par.settings = list( plot.symbol = list(alpha = 1, col = transparent,cex = 1,pch = 20)), panel = function(x, y){ panel.bwplot(x, y) X-

Re: [R] rimage package problems

2010-09-27 Thread Greg Snow
The rimage package appears to have been abandoned. One option is the EBImage package from Bioconductor. -- Gregory (Greg) L. Snow Ph.D. Statistical Data Center Intermountain Healthcare greg.s...@imail.org 801.408.8111 -Original Message- From: r-help-boun...@r-project.org

Re: [R] pairs and mfrow

2010-09-27 Thread Greg Snow
Why do you want 2 pairs plots on the same device? There may be a better approach to what you want to do. You could use splom from the lattice package along with the print.trellis function to put 2 on the same page. -- Gregory (Greg) L. Snow Ph.D. Statistical Data Center Intermountain

[R] calculating mean and s.d. from a two-column table

2010-09-27 Thread Jonas Josefsson
I have a two-column table as follows where age is in the 1st column and the number of individuals is in the 2nd. age;no 1;21 2;31 3;9 4;12 5;6 Can I use mean() and sd() to calculate the mean and standard deviation from this or do I have to manually multiplicate 21*1+31*2 etc. / N?

Re: [R] calculating mean and s.d. from a two-column table

2010-09-27 Thread Peter Langfelder
On Mon, Sep 27, 2010 at 9:34 AM, Jonas Josefsson jo...@runtimerecords.net wrote: I have a two-column table as follows where age is in the 1st column and the number of individuals is in the 2nd. age;no 1;21 2;31 3;9 4;12 5;6 You can use the following trick: x = rep(age, no) This repeats

Re: [R] Regular expressions: offsets of groups

2010-09-27 Thread jim holtman
try this: x - gregexpr(a+(b+), abcdaabbcaaacaaab) justA - gregexpr(a+, abcdaabbcaaacaaab) # find matches in 'x' for 'justA' indx - which(justA[[1]] %in% x[[1]]) # now determine where 'b' starts justA[[1]][indx] + attr(justA[[1]], 'match.length')[indx] [1] 2 7 17 On Mon, Sep 27, 2010

Re: [R] Regular expressions: offsets of groups

2010-09-27 Thread Titus von der Malsburg
Thank you Jim, but just as the solution that I discussed, your proposal involves deconstructing the pattern and searching several times. I'm looking for a general and efficient solution. Internally, the regexpr engine has all necessary information after one pass through the string. What I need

Re: [R] Regular expressions: offsets of groups

2010-09-27 Thread Titus von der Malsburg
On Mon, Sep 27, 2010 at 7:16 PM, Henrique Dallazuanna www...@gmail.com wrote: You've tried: gregexpr(b+, abcdaabbc) But this would match the third occurrence of b+ in abcdaabbcbb. But in this example I'm only interested in b+ if it's preceded by a+. Titus

Re: [R] Regular expressions: offsets of groups

2010-09-27 Thread Gabor Grothendieck
On Mon, Sep 27, 2010 at 11:48 AM, Titus von der Malsburg malsb...@gmail.com wrote: Dear list! gregexpr(a+(b+), abcdaabbc) [[1]] [1] 1 5 attr(,match.length) [1] 2 4 What I want is the offsets of the matches for the group (b+), i.e. 2 and 7, not the offsets of the complete matches.  Is

Re: [R] Regular expressions: offsets of groups

2010-09-27 Thread Titus von der Malsburg
On Mon, Sep 27, 2010 at 7:29 PM, Gabor Grothendieck ggrothendi...@gmail.com wrote: Try this zero width negative look behind expression: gregexpr((?!a+)(b+), abcdaabbc, perl = TRUE) [[1]] [1] 2 7 attr(,match.length) [1] 1 2 Thanks Gabor, but this gives me the same result as gregexpr(b+,

Re: [R] Regular expressions: offsets of groups

2010-09-27 Thread Henrique Dallazuanna
You could do this: gregexpr(ab+, abcdaabbcbb)[[1]] + 1 On Mon, Sep 27, 2010 at 2:25 PM, Titus von der Malsburg malsb...@gmail.comwrote: On Mon, Sep 27, 2010 at 7:16 PM, Henrique Dallazuanna www...@gmail.com wrote: You've tried: gregexpr(b+, abcdaabbc) But this would match the third

[R] [R-pkgs] Bayesian Fractional Polynomials package bfp on CRAN

2010-09-27 Thread Daniel Sabanés Bové
Fractional polynomials (FPs) are an automatic way of fitting non-linear, parametric effects. The R-package mfp implements a frequentist inference approach for FP models. Recently, we have proposed a Bayesian inference approach for normal FP models, which is based on the quasi-default

[R] [R-pkgs] Deducer 0.4-1 and JGR 1.7-2 released

2010-09-27 Thread Ian Fellows
Hi All, I would like to announce the release of Deducer 0.4-1 and JGR 1.7-2 to CRAN. The updates should be propagating through the mirrors over the next few days. On the Deducer side we have a number of nice improvements: 1. A new Text Field Widget for plug-ins is included, which is better

Re: [R] finding big matrix size and SVD

2010-09-27 Thread Natasha Asar
I have 500,00 rows in my matrix and i was wondering whether there is any way to get its SVD without breaking it to parts because if R can only read about 1000 columns then to have a rectangular matrix (diagonal i think they are called) I will need to have only 1000 rows I want to know how i

Re: [R] Regular expressions: offsets of groups

2010-09-27 Thread Henrique Dallazuanna
You've tried: gregexpr(b+, abcdaabbc) On Mon, Sep 27, 2010 at 12:48 PM, Titus von der Malsburg malsb...@gmail.com wrote: Dear list! gregexpr(a+(b+), abcdaabbc) [[1]] [1] 1 5 attr(,match.length) [1] 2 4 What I want is the offsets of the matches for the group (b+), i.e. 2 and 7, not

Re: [R] Split-split plot design with aov function in R

2010-09-27 Thread Muhammad Yaseen
*Hello, I'm new to R and trying to do Split Split Plot Design analysis with aov function in R. Sharing any worked example and suggestion will be highly appreciated. Thanks Regards! * -- * Muhammad Yaseen * [[alternative HTML version deleted]]

Re: [R] Split-split plot design with aov function in R

2010-09-27 Thread Sunny Srivastava
http://www.amazon.com/Statistical-Design-George-Casella/dp/1441926143/ref=sr_1_1?s=gatewayie=UTF8qid=1285609902sr=8-1 Hello Mohd. Yaseen, Please check out the book by Dr. Casella and his website www.stat.ufl.edu/~casella for the relevant R codes. Chapter 5 of this book talks about Split Split

[R] compare two matrices

2010-09-27 Thread xinxin xx
Hi everyone: I have a kinda easy question but i do not know how to solve that in a simple way. I want to compare the rows of two matrices. col1 - c(1,2,3,4,5,6) col2 - c(6,5,4,3,2,1) m - cbind(col1, col2) col3 - c(1,3,2,6) col4 - c(6,3,5,1) n - cbind(col3,

Re: [R] stacked area chart

2010-09-27 Thread Dimitri Liakhovitski
I found a solution to my original question (see code below). But I have a question about cosmetics, which I always find very challenging. 1. How can I make all dates appear on the X axis (rotated at 90 degrees vs. horizontal)? 2. How can I create vertical grid lines so that at each date there is a

Re: [R] compare two matrices

2010-09-27 Thread Dimitris Rizopoulos
one way is the following: col1 - c(1,2,3,4,5,6) col2 - c(6,5,4,3,2,1) m - cbind(col1, col2) col3 - c(1,3,2,6) col4 - c(6,3,5,1) n - cbind(col3, col4) ind.n - do.call(paste, c(as.data.frame(n), sep = \r)) ind.m - do.call(paste, c(as.data.frame(m), sep = \r)) ind.n %in% ind.m I hope it helps.

Re: [R] Regular expressions: offsets of groups

2010-09-27 Thread Gabor Grothendieck
On Mon, Sep 27, 2010 at 1:34 PM, Titus von der Malsburg malsb...@gmail.com wrote: On Mon, Sep 27, 2010 at 7:29 PM, Gabor Grothendieck ggrothendi...@gmail.com wrote: Try this zero width negative look behind expression: gregexpr((?!a+)(b+), abcdaabbc, perl = TRUE) [[1]] [1] 2 7

Re: [R] Problem with unlist

2010-09-27 Thread Henrik Bengtsson
On Mon, Sep 27, 2010 at 5:27 AM, Ben Bolker bbol...@gmail.com wrote: Luis Felipe Parra felipe.parra at quantil.com.co writes:  Hello, I am trying to unlist a list, which is attached, and I am having the problem that when I unlist it the number of elements changes from 5065 to 5084   x -

[R] Ordered logit with polr won't match SPSS output

2010-09-27 Thread Ben Hunter
I am learning R via a textbook that performs analysis with SPSS and SAS. In trying to reproduce the results for an ordinal logit model, I get very similar point estimates for my cut-off points, but the parameters for the covariate q60 do not match. The estimate for q51 also matches. Is this

Re: [R] margin control in lattice package

2010-09-27 Thread Jonathan Flowers
Hi Peter, Thank you for your thoughtful reply. I am tweaking the setting print settings you suggested. It looks like this is going to solve my problem. Thanks very much for help. Jonathan On Sat, Sep 25, 2010 at 6:00 PM, Peter Ehlers ehl...@ucalgary.ca wrote: On 2010-09-25 8:59, Jonathan

[R] scientific vs. fixed notation in xyplot()

2010-09-27 Thread array chip
Hi I am using xyplot() to plot on the log scale by using scale=list(log=T) argument. For example: xyplot(1:10~1:10, scales=list(log=T)) But the axis labels are printed as scientific notation (10^0.0, etc), instead of fixed notation. How can I change that to fixed notation? options(scipen=4)

[R] Sample size estimation for non-inferiority log-rank and Wilcoxon rank-sum tests

2010-09-27 Thread Paul Miller
Hello Everyone,   I'm trying to conduct a couple of power analyses and was hoping someone might be able to help. I want to estimate the sample size that would be necessary to adequately power a couple of non-inferiority tests. The first would be a log-rank test and the second would be a

Re: [R] scientific vs. fixed notation in xyplot()

2010-09-27 Thread Henrique Dallazuanna
Try this: xyplot(1:10~1:10, scales=list(log = T, labels = round(log(1:10), 4))) On Mon, Sep 27, 2010 at 4:10 PM, array chip arrayprof...@yahoo.com wrote: Hi I am using xyplot() to plot on the log scale by using scale=list(log=T) argument. For example: xyplot(1:10~1:10, scales=list(log=T))

[R] Percentages and lattice

2010-09-27 Thread Mark Noworolski
What I'm trying to do is to figure out how to create lattice charts of %right by region, or alternatively, by date from a dataset of observations that looks something like this: date,location,region,correct 2010-09-10,a,r1,yes 2010-09-10,a,r1,yes 2010-09-10,a,r1,no 2010-09-11,a,r1,yes

Re: [R] Percentages and lattice

2010-09-27 Thread Phil Spector
Mark - Here's one way to get the percentages you want. Suppose your data frame is called df: correct = subset(as.data.frame(with(df,table(date,region,correct))), correct=='yes') all = as.data.frame(with(df,table(date,region))) names(all)[3] = 'Total' both =

Re: [R] scientific vs. fixed notation in xyplot()

2010-09-27 Thread array chip
Thanks for the suggestion. But my example is just an example, I would prefer to have some generalized solution, like what options(scipen=4) does in general graphics, which usually gave pretty axis labels as well. Any suggestions? Thanks John From: Henrique

Re: [R] Sample size estimation for non-inferiority log-rank and Wilcoxon rank-sum tests

2010-09-27 Thread Andrew Miles
I haven't done much with the type of data you're working with, but here is a post that lists a few packages for doing sample size calculations in R. Perhaps one of them will be helpful. https://stat.ethz.ch/pipermail/r-help/2008-February/154223.html Andrew Miles On Sep 27, 2010, at 2:09

[R] Variation of predictor of linear model

2010-09-27 Thread Yi Du
Hi folks, I use lm to run regression and I don't know how to predict dependent variable based on the model. I used predict.lm(model, newdata=80), but it gave me warnings. Also, how can I get the variance of dependent variable based on model. Thanks. [[alternative HTML version deleted]]

Re: [R] scientific vs. fixed notation in xyplot()

2010-09-27 Thread Don McKenzie
This is quite elegant (thanks) and brings up a problem I could not solve awhile back, although Dr. Sarkar did his best to help. How do I do the same thing in a panel plot? e.g., toy example temp.df - data.frame(X=seq(1,100,by=1),Y=seq(1,50.5,by=.5),class=rep (c(A,B),each=50)) xyplot(Y ~ X |

[R] Alphabetical sequence of data along the x-axis in a box plot

2010-09-27 Thread Hughes, Ed
Hello All, I noticed when I generated some boxplots, the data is presented in alphabetical order along the x-axis (the data in this case was the four quandrants of a sample area (NE,NW, SE, SW) that was my first column of data). Is there a way to have R plot the data in a different order? I

Re: [R] plot single part of the country using gadm map

2010-09-27 Thread Paul Murrell
Hi carolina plescia wrote: Dear all, in GADM map there are three levels (nation, province and precinct) for each country of the world but for all of them you are never able to plot only one part of a chosen country. The Spatial object you get when you read in the shapefile has convenient

Re: [R] Variation of predictor of linear model

2010-09-27 Thread Joshua Wiley
Hi, Try this: # using the iris dataset mydat - iris mymodel - lm(Sepal.Length ~ Petal.Length + Species, data = mydat) summary(mymodel) newdat - data.frame(Petal.Length = seq(1, 10, by = .1), Species = factor(rep(virginica, 91))) results - predict(object = mymodel, newdata =

Re: [R] Alphabetical sequence of data along the x-axis in a box plot

2010-09-27 Thread Joshua Wiley
Hi Eddie, I've been on a role with the iris data, so I figure why stop. Assuming that one variable is a factor, you can easily reverse it, and if you want fine tuned control, then just reorder the levels. Here is an example: dat - iris boxplot(Sepal.Length ~ Species, data = dat)

Re: [R] Alphabetical sequence of data along the x-axis in a box plot

2010-09-27 Thread Peter Alspach
Tena koe Eddie One way: eddie - data.frame(grp=rep(c('small','medium','large','very large'), each=20), wgt=rnorm(80, 100, 10)) with(eddie, plot(grp, wgt)) eddie$grp - factor(eddie$grp, levels=c('small','medium','large','very large')) with(eddie, plot(grp, wgt)) HTH ... Peter Alspach

[R] spplot cuts

2010-09-27 Thread emorway
Hello- After looking through ?spplot, I would expect that I could specify the values of the cuts: ...‘cuts’ number of cuts or the actual cuts to use... So in the following command, spplot(lzm.krige.dir[var1.pred], scales=list(draw=TRUE), xlab=Easting,ylab=Northing,

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