Hello,
I'm trying to run a lagsarlm (maximum likelihood estimation of a spatial lag
model) in the spdep library ; but R gives following error message:
Error in solve.default(inf, tol = tol.solve) :
system is computationally singular: reciprocal condition number = 4.20137e-12
I get
Eik Vettorazzi wrote:
... and so the following is from scratch, not from memory.
fun-function(x,...){
mthd-list(...)
lapply(mthd,function(m) do.call(m,list(x)))
}
fun(3.14, mode, typeof, class)
there is no error-catching for non-existing functions, no naming of
results and so on, but
On 03.02.2011 22:06, Dimitri Liakhovitski wrote:
Just a small correction: the package snow does install. But once I
try to load it:
library(snow),
I get an error:
Error: package 'snow' was built before R 2.10.0: please re-install it
Dimitri
On Thu, Feb 3, 2011 at 3:57 PM, Dimitri Liakhovitski
Hi:
This is FAQ 7.22 (Why do lattice/trellis graphics not work?)
You need to print() the plot, as in
print(xyplot(a ~ b))
This problem also extends to ggplot2 graphics.
(BTW, the legend statement after xyplot() won't work because the legend()
function is meant for use in base graphics. Lattice
Feiming Chen feimingc...@yahoo.com
on Thu, 3 Feb 2011 12:03:05 -0800 (PST) writes:
Hello:
I found the hubers function in MASS library is NOT working on the
following
data:
a -
Hi Jie Tang,
You could try my Friendly Beginners' R Course. Online resource at:
http://www.R-project.org/ → Documentation/Other (left-hand panel) →
Contributed Documentation (middle of screen) → (scroll down a little)
which is a quick intro to what R can do in 14 pages with lots of links for
Hello R
Currently I am using the sciplot function to draw error bars on my bar charts,
but this uses standard error of a mean SEM, is there an alternative variant
that
will allow me to draw error bars using least significant difference.
Than you.
[[alternative HTML version
On 02/04/2011 07:14 PM, Asan Ramzan wrote:
Hello R
Currently I am using the sciplot function to draw error bars on my bar charts,
but this uses standard error of a mean SEM, is there an alternative variant that
will allow me to draw error bars using least significant difference.
Hi Asan,
The
Jie TANG wrote:
Now I want to know how much R can do .where can i get some examples or
demo resource to study advanced function of R ?
Not really what you were thinking of, I guess, but don’t overlook the ‘demo’
function. For example, try ‘demo(graphics)’.
Type ‘demo()’ for a list of demos,
Dear all,
Using the code I got from the link (
http://www.phaget4.org/R/image_matrix.html), I obtained a nice plot that
suits me. However, adding axes labels proved difficult for me . I have
succeeded in adding a few things to the plot function so as to get what a
better plot. Other things work
Dear R community,
I can't find the way to eliminate the hclust() print at the bottom of the
dendrogram plot (plclust).
Can this be done?
J
Dr James Foadi PhD
Membrane Protein Laboratory (MPL)
Diamond Light Source Ltd
Diamond House
Harewell Science and Innovation Campus
Chilton, Didcot
Hi Danny,
it sounds to much easer than that.
Try
y - data.frame(matrix(rnorm(100),10))
nr - ncol(y)
test - lapply(y, shapiro.test)
sapply(test,function(x)c(x$statistic, x$p.value))
it should perform the required task.
Cheers,
P
On Fri, Feb 4, 2011 at 4:52 AM, DB1984 dannyb...@gmail.com
On 02/04/2011 09:14 PM, ogbos okike wrote:
Dear all,
Using the code I got from the link (
http://www.phaget4.org/R/image_matrix.html), I obtained a nice plot that
suits me. However, adding axes labels proved difficult for me . I have
succeeded in adding a few things to the plot function so as to
It isn't immediately obvious. but that's the subtitle.
You can use
plclust(myclusters, sub=Something else)
to change it, including
plclust(myclusters, sub=)
to get rid of it.
Sarah
On Fri, Feb 4, 2011 at 5:42 AM, james.fo...@diamond.ac.uk wrote:
Dear R community,
I can't find the way to
Hi,
I have a GAM quasipoisson that I'd like to run through MuMIn package
- dredge
- gettop.models
- model.avg
However, I'm having no luck with script from an example in MuMIn help file.
In MuMIn help they advise include only models with smooth OR linear term
(but not both) for each
Dear R-List,
I have a dataframe with one column name.of.report containing character
values, e.g.
df$name.of.report
jeff_2001_teamx
teamy_jeff_2002
robert_2002_teamz
mary_2002_teamz
2003_mary_teamy
...
(i.e. the bit of interest is not always at same position)
Now I want to recode the column
On Fri, 2011-02-04 at 12:31 +, Karen Moore wrote:
Hi,
snip /
My formula is
GAM-gam(Species richness (count) ~ Categorical + Continous + Continous + *
s*(Continous ) + Continous : Continous + Continous : Continous,
family=quasipoisson, data =)
Ok, I'm reasonably certain that that is
Is there a function that can shade the region between two arbitrary
curves? For example, how can I fill in the area between these two
plotted curves?
x - 1:10
y - x + rnorm(10)
z - x + 10 + rnorm(10)
plot(x, y, type = l, ylim = c(0,20))
lines(x, z)
I would appreciate any help.
David
Is there a function that can shade the region between two arbitrary
curves? For example, how can I fill in the area between these two
plotted curves?
x - 1:10
y - x + rnorm(10)
z - x + 10 + rnorm(10)
plot(x, y, type = l, ylim = c(0,20))
lines(x, z)
I would appreciate any help.
David
Is there a function that can shade the region between two arbitrary
curves? For example, how can I fill in the area between these two
plotted lines?
x - 1:10
y - x + rnorm(10)
z - x + 10 + rnorm(10)
plot(x, y, type = l, ylim = c(0,20))
lines(x, z)
I would appreciate any help.
David
Is there anything out there which replicates the functionality of
RExcel on a mac? I have Excel for mac, and would just like something
which makes its easy to put sheets into R as a dataframe etc.
__
R-help@r-project.org mailing list
Hi,
I am using the uniroot function in order to carry out a bivariate Monte
Carlo simulation using the logistics model.
I have defined the function as:
BV.FV - function(x,y,a,A)
(((x^(-a^-1)+y^(-a^-1))^(a-1))*(y^(a-1/a))*(exp(-((1^(-a^-1)+y^(-a^-1))^a)+y^-1)))-A
and the procedure is as
Hi,
I'm processing a data file with the following structure:
#index time distance
1 10 500
1 15 300
1 23 215
1 34 200
2 5400
2 13 340
2 15 210
3 10 200
3 12 150
3 16 30
etc
My intention was to generate line plots for the datapoints using their index
to group the elements.
Hello,
I would like to change the names of the sites in an ordination biplot
(resulting from the function rda in vegan). Can somebody give me some
trick?
Thank you very much
--
View this message in context:
polygon() will do it. That's a frequently-discussed topic on this list,
so there are plenty of examples in the archives, and also some on
the R Graph Gallery.
Sarah
On Fri, Feb 4, 2011 at 8:03 AM, David Bickel
davidbickel.com+rh...@gmail.com wrote:
Is there a function that can shade the region
How can I run multivariate linear regression in R (I have got 3 dependent
variables and only 1 independent variable)? I tried lm function, but it gave
different R2 and p values for every dependent variable. I need one R2 and p
value for the model.
On Feb 4, 2011, at 6:32 AM, D. Alain wrote:
Dear R-List,
I have a dataframe with one column name.of.report containing character
values, e.g.
df$name.of.report
jeff_2001_teamx
teamy_jeff_2002
robert_2002_teamz
mary_2002_teamz
2003_mary_teamy
...
(i.e. the bit of interest is
On 4 February 2011 at 07:55, David Bickel wrote:
| Is there a function that can shade the region between two arbitrary
| curves? For example, how can I fill in the area between these two
| plotted curves?
|
| x - 1:10
| y - x + rnorm(10)
| z - x + 10 + rnorm(10)
| plot(x, y, type = l, ylim =
Hi,
It's a piece of cake with ggplot,
d - read.table(textConnection(id x y
1 10 500
1 15 300
1 23 215
1 34 200
2 5400
2 13 340
2 15 210
3 10 200
3 12 150
3 16 30), head=TRUE)
str(d)
library(ggplot2)
p -
ggplot(d) +
geom_path(aes(x,y, group=id))
p ## grouping
On Fri, 2011-02-04 at 13:06 +0800, cahyo kristiono wrote:
Dear r-help
I don't want to receive againevery e-mail about [R] in my address e-mail
(cahyo_kristi...@yahoo.com), because it is cause my inbox so full quickly. So
I
need your help to stop every e-mail about [R] in my address.
Please help us help you. Follow the posting rules and send us a copy of your
code and output.
John
John Sorkin
Chief Biostatistics and Informatics
Univ. of Maryland School of Medicine
Division of Gerontology and Geriatric Medicine
jsor...@grecc.umaryland.edu
-Original Message-
From:
On Feb 4, 2011, at 4:36 AM, Clayton Coffman wrote:
Is there anything out there which replicates the functionality of
RExcel on a mac? I have Excel for mac, and would just like something
which makes its easy to put sheets into R as a dataframe etc.
On OSX, I believe that the two primary
Thanks for that Gavin - yeah you're right that was not my actual model,
which is:
GAMV2c-gam(VASCSR~ROTATION+ CANCOV +LAreaoldwood+ + s(SOILPH) +
CANCOV:LAreaoldwood +
CANCOV:SOILPH,family=quasipoisson, data =HIGHBRYOSR)
For MMI the script I use, and have used successfully with *exactly* same
On Fri, Feb 4, 2011 at 5:36 AM, Clayton Coffman
clayton.coff...@gmail.com wrote:
Is there anything out there which replicates the functionality of
RExcel on a mac? I have Excel for mac, and would just like something
which makes its easy to put sheets into R as a dataframe etc.
See:
Do you mean something like:
with(DF.new, paste(person, year, paste(team, team, sep = ), sep = _))
[1] jeff_2001_teamx jeff_2002_teamy robert_2002_teamz
[4] mary_2002_teamz mary_2003_teamy
?
See ?paste and ?with for more information, if so.
HTH,
Marc
On Feb 4, 2011, at 7:26 AM, Denis
I have a model with quant vars only and the error message does not
make sense:
Could you tell us what version of S and of the survival package you are
using? You can get this with sessionInfo(), see the posting guide for
details.
This would help me identify the issue. I was planning to
On 03/02/2011 10:27 AM, Ernest Adrogué wrote:
Hi,
Suppose a function that checks an object:
stop.if.dims- function(x) {
if (! is.null(dim(x))) {
stop(cannot handle dimensional data)
}
}
This would be used by other functions that can only work with
dimensionless objects. The problem
Dear all,
Using:
library(vegan)
data(BCI)
mod - radfit(BCI[1,])
mod
RAD models, family poisson
No. of species 93, total abundance 448
par1 par2 par3Deviance AIC BIC
Null 39.5261 315.4362 315.4362
Preemption 0.042797
Dear R people
Could you please help
I have similar but opposite question
How to reshape data from DF.new to DF from example, Mark kindly
provided?
Thank you
Denis
On Пят, 2011-02-04 at 07:09 -0600, Marc Schwartz wrote:
On Feb 4, 2011, at 6:32 AM, D. Alain wrote:
Dear R-List,
I have
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
Hi
I hava a simulation model, of which I want to do a sensitivity analysis.
I have identified a number of input variables and my response variable.
What I hava done so far:
1) I created a Latin Hypercube with the lhs package (10.000 simulations)
2)
Dear Jim,
One touch!! Thank you very much
Best regards
Ogbos
On 4 February 2011 13:47, Jim Lemon j...@bitwrit.com.au wrote:
On 02/04/2011 09:14 PM, ogbos okike wrote:
Dear all,
Using the code I got from the link (
http://www.phaget4.org/R/image_matrix.html), I obtained a nice plot
On Wed, Feb 2, 2011 at 7:59 AM, Karl Ove Hufthammer k...@huftis.org wrote:
Dear list members,
I recall seeing a convenience function for applying multiple functions to
one object (i.e., almost the opposite of 'mapply’) somewhere.
Example: If the function was named ’fun’ the output of
Hello all, kind regards,
I have imported a data.frame from SPSS using foreign:read.spss but
unfortunately it is reading dates in a way neither R nor myself can
understand.
book$DATE
[1] 13502246400 13443321600 13477795200 13472956800 13501728000 13445395200
13501382400 13502851200 13444185600
What do the dates look like in the original file?
On Fri, Feb 4, 2011 at 9:47 AM, dunner ross.du...@tcd.ie wrote:
Hello all, kind regards,
I have imported a data.frame from SPSS using foreign:read.spss but
unfortunately it is reading dates in a way neither R nor myself can
understand.
Responding to T. Therneau:
sessionInfo()
R version 2.10.1 (2009-12-14)
i386-pc-mingw32
locale:
[1] LC_COLLATE=English_United States.1252 LC_CTYPE=English_United States.1252
LC_MONETARY=English_United States.1252
[4] LC_NUMERIC=C LC_TIME=English_United
On Fri, Feb 4, 2011 at 9:47 AM, dunner ross.du...@tcd.ie wrote:
Hello all, kind regards,
I have imported a data.frame from SPSS using foreign:read.spss but
unfortunately it is reading dates in a way neither R nor myself can
understand.
book$DATE
[1] 13502246400 13443321600 13477795200
as.POSIXlt(book$DATE, origin=1582/10/14) works.
The Gregorian calendar was the kicker, thanks to ggrothendieck at gmail.com
Ross
--
View this message in context:
http://r.789695.n4.nabble.com/Importing-dates-from-SPSS-file-tp3260293p3260329.html
Sent from the R help mailing list archive at
Hi Olga,
Here is how I would approach this problem. I hope it is instructive.
library(vegan)
data(BCI)
mod - radfit(BCI[1,])
class(mod) #find out what mod is
methods(class=radfit) #find out what methods are available for
objects of this class. Nothing looks promising, so define a summary
method
Thanks Ista,
Very instructive and works like a charm!
Cheers!
Olga
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented,
Hi,
Got my issues sorted.
Error message solved:
I heard from the guy who developed MuMIn and his suggestion worked.
As for the error you get, it seems you are running an old version of MuMIn.
Please update the package first.
I did (I was only 1 version behind in both R and in MuMIn) and error
Hi
I have a list of nodes and edges.
I want to draw a graph from two different direction left and right. I
am drawing the required graph which is growing from left. Similar will be
the case that will grow from right. the one that grows from right may have
few nodes present in left subtree.
I would probably use a Dynamic Linear Model, combining seasonal
component and regression. See package dlm and its vignette for
examples.
HTH,
Giovanni
On Tue, 2011-02-01 at 11:01 +, Paolo Rossi wrote:
Hi list,
I would like to estimate and forecast the seasonal component of a series.
--- begin included message
I'm trying to do some analysis using survreg function. I need to
implement
there my own distribution with density:
lambda*exp(-lambda*y), where y = a1/(1+exp(-a2*x)).
a1, a2 are unknown parameters and x 0.
--- end inclusion --
The survreg
Hi there,
I have a problem about lapply, strsplit, and accessing list elements,
which I don't understand or cannot solve:
I have e.g. a character vector with three elements:
x = c(349/077,349/074,349/100,349/117,
340/384.2,340/513,367/139,455/128,D13/168,
On Feb 4, 2011, at 8:26 AM, Denis Kazakiewicz wrote:
Dear R people
Could you please help
I have similar but opposite question
How to reshape data from DF.new to DF from example, Mark kindly
provided?
Well, I don't think you want a random order, right? If what you are
asking is for a
# Hi all,
# I've made a function to make a formula out of a data.frame without columns
which contain a constant value.
# The function which.constant returns the indices of colums with constant
values:
which.constant - function(data.frame) { # counts the number of columns in a
data.frame which
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Dick Harray
Sent: Friday, February 04, 2011 7:37 AM
To: r-help@r-project.org
Subject: [R] lapply, strsplit, and list elements
Hi there,
I have a problem about lapply,
dpender wrote:
Hi,
I am using the uniroot function in order to carry out a bivariate Monte
Carlo simulation using the logistics model.
I have defined the function as:
BV.FV - function(x,y,a,A)
(((x^(-a^-1)+y^(-a^-1))^(a-1))*(y^(a-1/a))*(exp(-((1^(-a^-1)+y^(-a^-1))^a)+y^-1)))-A
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Duncan Murdoch
Sent: Friday, February 04, 2011 6:03 AM
To: Ernest Adrogué
Cc: r-h...@stat.math.ethz.ch
Subject: Re: [R] get caller's name
On 03/02/2011 10:27 AM, Ernest
Did you look at the help? ?formula has a whole section about why
formulas have environments and what they do.
On Fri, 4 Feb 2011, Aviad Klein wrote:
# Hi all,
# I've made a function to make a formula out of a data.frame without columns
which contain a constant value.
# The function
Dear R users?
I want to know how to use strata in survival analysis, I want to combine
multiple dataset:
Coxph(Surv(merged.time.v, merged.event.v)~merged.score+
strata(dataset.v))
So merged.time.v and merged.event.v are from multiple datasets.
How should I define dataset.v here?
I get a different set of errors than you do (what version of R are you using?).
Patrizio showed one way to do what you want. But, what is it that you are
really trying to accomplish? What do you think the result of 20,000 normality
tests (each of which may not be answering the real question
Dear All,
I used glm and then used step function for stepwise regression.
Now, I want to store the variables used in the stepwise regression.
The code is the following.
m_logistic - glm(y ~ . + M1:T + M2:T + M3:T+ M4:T +M5:T,
family=binomial(logit), data = data)
step_glm - step(m_logistic)
On Feb 4, 2011, at 11:56 AM, Soyeon Kim wrote:
Dear All,
I used glm and then used step function for stepwise regression.
Now, I want to store the variables used in the stepwise regression.
I am not sure that what you ask here is actually what you eventually
ask and will limit my answer to
Thank you. This is what I want.
I need to study about attr :).
Soyeon
On Fri, Feb 4, 2011 at 11:07 AM, David Winsemius dwinsem...@comcast.net wrote:
On Feb 4, 2011, at 11:56 AM, Soyeon Kim wrote:
Dear All,
I used glm and then used step function for stepwise regression.
Now, I want to
So you want to combine multiple columns back into a single column with the
strings pasted together? If that is correct then look at the paste and sprintf
functions (use one or the other, not both).
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
You can do this with regular expressions, since you want to extract specific
values from the string I would suggest learning about the gsubfn package, it is
a bit easier with gsubfn than with the other matching tools.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain
Hi,
I'm trying to create a function to return three dataframes for later use in
a graphic so I want the return from the function to give me dataframes and
with unique names relating to the variable they are based on.
For example.
sub-c(6-1a,6-1a,6-1a,9-2b,9-2b,9-2b,7c,7c,7c)
Dear Łukasz
Thank you very much for information
Dear R people could you please help please with following questions
Sorry for my silly questions, because I am not a mathematician.
1. Is elrm() works similar as exact regression in SAS or Stata? After
double check in Stata and R some results from
Hey,
this may be a simple question, but I am struggling to apply a list of
parameters to a function.
Say I have the following function:
test-function(a=1,b=2,c=3,d=4){a+b+c+d}
And the following list:
point-list(a=3,d=2)
Is there a way I can evaluate function test at point?
(Apart from
Hello,
I'm still trying to modify my script in order to use RODBC instead of RMySQL
(no more ready-to-use package for windows).
My new problem is the following one (not seen with RMySQL):
I'd like to copy a data.frame to a mysql table. One column is a numeric one
with big integer like :
'Aggregate multiple functions into a single function. Combine multiple
functions to a single function returning a named vector of outputs'
This is a short description of each() function from plyr package
Here is an example from help
each(min, max)(1:10)
Hope this helps
Regards
Denis
У
Thanks for the feedback Patrizio - but your function is performing the
shapiro.test on columns instead of rows...
I tried:
nt-data.frame(#a dataframe with 6 columns and 9 rows)
nr - nrow(nt)
test - apply(nt, nt[1:nr,], shapiro.test)
Error in ds[-MARGIN] : invalid subscript type 'list'
attempting to do multivariate modelling in R with known future
conditions (in this case variable 'b') using MSBVAR and hc.forecast.
The sample code (a paired down representation) does not give anywhere
near the expected results - I am assuming that a forecast 8 steps out
would approximate 'a' as
Hate to say that, but it looks like Stata is way above R, considering
exact logistic regression.
To use elrm() I have to aggregate my data,which is really time consuming
when I look for the way out through many variables. But the worst thing
is that I am not not sure if I can trust to p-values in
I'm also not an expert on this topic. I just wanted to list a couple of
ways that non-PD matrices might arise. I'll just add now a couple of
pointers:
First, I believe the term semipositive definite is considered ambiguous
because in some literature it means that the matrix the smallest
The options showWarnCalls and showErrorCalls may also help --
they can be use do enable automatic printing of a call stack
summary. From ?options:
‘showWarnCalls’, ‘showErrorCalls’: a logical. Should warning and
error messages show a summary of the call stack? By default
Hi Marianne,
The quick-and-dirty solution is to add one character and make ns global:
ns - nrow(x)
Poor practice, but OK temporarily if you're just debugging.
This is an issue of scope. You are assuming dynamic scope, whereas R uses
static scope. 'ns' was not defined when you said
1. Martin Maechler's comments should be taken as replacements
for anything I wrote where appropriate. Any apparent conflict is a
result of his superior knowledge.
2. 'eigen' returns the eigenvalue decomposition assuming the
matrix is symmetric, ignoring anything in
On Feb 4, 2011, at 10:48 AM, DB1984 wrote:
Thanks for the feedback Patrizio - but your function is performing the
shapiro.test on columns instead of rows...
I tried:
nt-data.frame(#a dataframe with 6 columns and 9 rows)
nr - nrow(nt)
test - apply(nt, nt[1:nr,], shapiro.test)
Error in
1. Martin Maechler's comments should be taken as replacements
for anything I wrote where appropriate. Any apparent conflict is a
result of his superior knowledge.
2. 'eigen' returns the eigenvalue decomposition assuming the
matrix is symmetric, ignoring anything in
(Apologies to the cc-list: I'm resending from a different address because
I didn't realize it was going to r-help.)
I'm also not an expert on this topic. I just wanted to list a couple of
ways that non-PD matrices might arise. I'll just add now a couple of
pointers:
First, I believe the
I actually have several questions revolving around the generation of
wireframe plots.
The most pressing is that which is described by the subject line.
I am trying to produce a figure with x, y, and z labels, but only tick marks
on the x, and y axes. I have supplied sample code below
Dear all,
I collected my data from the different agricultural fields every week over a
period of a month.
how can I test for spatial autocorrelation in R with data that are temporally
pseudoreplicated?
I used lme with correlation=corCompSymm(form=~Date) to model temporal
pseudoreplication.
Try this:
do.call(test, point)
On Fri, Feb 4, 2011 at 12:35 PM, Florian Burkart florian.burk...@whu.eduwrote:
Hey,
this may be a simple question, but I am struggling to apply a list of
parameters to a function.
Say I have the following function:
test-function(a=1,b=2,c=3,d=4){a+b+c+d}
Chris -
You can solve your problem by removing the print
statements and replacing them with
answer = list(org.plot[org.plot$sub %in% ex.plot,],
new.pl[new.pl$yar %in% 1991,],
new.pl[new.pl$yar %in% 1993,])
prefix = sub('-','.',ex.plot)
names(answer) =
Try this:
x - c(349/077,349/074,349/100,349/117,
+ 340/384.2,340/513,367/139,455/128,D13/168,
+ 600/437,128/903,128/904)
library(gsubfn)
out - strapply(x, '([0-9]+)(?=/)')
out
[[1]]
[1] 349 349 349 349
[[2]]
[1] 340 340 367 455 13
[[3]]
[1] 600 128 128
The strapply
Try:
do.call(test,point)
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Florian Burkart
Sent: Friday,
Of course. Thanks.
On 04/02/2011 18:32, Greg Snow wrote:
Try:
do.call(test,point)
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and
This is the qqmath example from the lattice package. I added the scales to the
example. I would like to switch the axis and not sure how? Meaning I would like
the height on the x-axis and the probability on the y-axis. Will you show me
the correct syntax for this switch thanks.
qqmath(~
Thanks David - but '1' (if I understood correctly) returns the same value for
each row, which I took to be an error.
nt
V1V2V3V4V5V6
1 24.71 23.56 24.71 23.56 24.71 23.56
2 25.64 25.06 25.64 25.06 25.64 25.06
3 21.29 20.87 21.29 20.87 21.29 20.87
4 25.92 26.92 25.92
Try this:
strsplit(x, /\\d+\\.\\d+,|/\\d+,|/\\d+)
On Fri, Feb 4, 2011 at 1:37 PM, Dick Harray tomdhar...@gmail.com wrote:
Hi there,
I have a problem about lapply, strsplit, and accessing list elements,
which I don't understand or cannot solve:
I have e.g. a character vector with three
On Feb 4, 2011, at 1:41 PM, DB1984 wrote:
Thanks David - but '1' (if I understood correctly) returns the same
value for
each row, which I took to be an error.
And exactly what were you expecting with that data?
nt
V1V2V3V4V5V6
1 24.71 23.56 24.71 23.56 24.71
Hi Greg,
In addition to the reply above, to address your questions - I fully
appreciate that my understanding of the code is basic - this is my first
attempt at putting this together...
My starting point is a data frame with numeric and text columns, but I can
cut columns to make a fully
Hello,
I have a R code for doing convolution of two functions:
convolveSlow - function(x, y) {
nx - length(x); ny - length(y)
xy - numeric(nx + ny - 1)
for(i in seq(length = nx)) {
xi - x[[i]]
for(j in seq(length = ny)) {
ij - i+j-1
xy[[ij]] -
On 4 February 2011 at 14:03, sudhir cr wrote:
| Hello,
|
| I have a R code for doing convolution of two functions:
|
| convolveSlow - function(x, y) {
| nx - length(x); ny - length(y)
| xy - numeric(nx + ny - 1)
| for(i in seq(length = nx)) {
| xi - x[[i]]
| for(j in
Hello, All,
GWAF 1.2
R.Version() is below.
system(lme.batch.imputed(
phenfile = 'phenfile.csv',
genfile = 'CARe_imputed_release.0.fhsR.gz',
pedfile='pedfile.csv',
phen='phen1',
covar=c('covar1','covar2'),
kinmat='imputed_fhs.kinship.RData',
outfile='imputed.FHS.IBC.GWAF.LME.output.0.txt'
))
On Fri, Feb 4, 2011 at 1:27 PM, Greg Snow greg.s...@imail.org wrote:
Try this:
x - c(349/077,349/074,349/100,349/117,
+ 340/384.2,340/513,367/139,455/128,D13/168,
+ 600/437,128/903,128/904)
library(gsubfn)
out - strapply(x, '([0-9]+)(?=/)')
out
[[1]]
[1] 349 349 349
On 2011-02-04 11:00, DB1984 wrote:
Hi Greg,
In addition to the reply above, to address your questions - I fully
appreciate that my understanding of the code is basic - this is my first
attempt at putting this together...
My starting point is a data frame with numeric and text columns, but I
Yes, that was dumb - I got that...
--
View this message in context:
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Sent from the R help mailing list archive at Nabble.com.
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