On Thu, Apr 14, 2011 at 7:02 PM,
wrote:
> I was able to write a very short C++ function using the Rcpp package
> that provided about a 1000-fold increase in speed relative to the best
> I could do in R. I don't have the script on this computer so I will
> post it tomorrow when I am back on the c
On Thu, Apr 14, 2011 at 7:41 PM, Marion Dumas wrote:
> Hello R-help list
> I'm trying to run 1 billion iterations of a code with calls to random
> distributions to implement a data generating process and subsequent
> computation of various estimators that are recorded for further comparison
> of
Dear All,
I would like to generate m positive real numbers c_i, I=1,...,m, such that
(1) c_1 + c_2 + ... + c_m=m,
(1) after being ordered into c_1 >= c_2 >= >=c_m>0, we have that c_m is
of the same order of m^(-1/8), when m is sufficiently large.
Thanks,
-Chee
[[alternative HTML
1. The three levels of the vector DrugPair actually represent three
genotypes, which are some randomly chosen genotypes from a population of
many genotypes. That's why I thought it was justified as random effect.
Does estimating them as random make sense then?
2. Also could you please elaborate o
Jurgens de Bruin gmail.com> writes:
>
> Hi,
>
> I do not have much R experience just the basics, so please excuse
> any obvious questions.
>
> I would like to create bubble plot that have Categorical data on the x and y
> axis and then the diameter if the bubble the value related to x and y.
>
Hello R-help list
I'm trying to run 1 billion iterations of a code with calls to random
distributions to implement a data generating process and subsequent
computation of various estimators that are recorded for further
comparison of performance. I have two question about how to achieve
th
Hello
I sympathise with you, since Beamer can quickly drive one mad.
On Fri, Apr 15, 2011 at 3:11 AM, Brett Presnell wrote:
> So, is this useful to anyone besides me? What trick(s) am I missing
> that would make it easier/better, or that would obviate altogether the
> need for such manipulation
Thanks for the reply...
with reproducible I am believe you require a dataset?
The size of the bubbles will be related to the fitvalues.
On 14 April 2011 17:57, Ben Bolker wrote:
> Jurgens de Bruin gmail.com> writes:
>
> >
> > Hi,
> >
> > I do not have much R experience just the basics, so p
Ravi:
Well, that's a challenge!
Here is a solution which is faster than Bill's as long as length(y) <<
length(x).
f3 <- function(x, y) length(y)*ecdf(y)(x)
Then using your test on my workstation, I get for f2():
> tt
[1] 0.761 1.071 1.329 1.565 1.894 3.865 11.824
and for f3():
> tt
[1]
Hi All,
I'm using RODBC to tap into MySQL on a remote server. It appears like
the connection is successful: I can see all tables and columns in my
database. However, queries return zero lines, including queries I've
verified as functional and non-empty by entering them directly in
MySQL.
I gran
not everything has to be done in R.
awk and sed are some of the best tools on a linux/unix box.
quick refs:
http://www.pement.org/awk/awk1line.txt
http://sed.sourceforge.net/sed1line.txt
-Whit
On Wed, Apr 13, 2011 at 12:07 AM, Chris Howden
wrote:
> Hi Everyone,
>
>
> I needed to parse some st
On Thu, Apr 14, 2011 at 8:19 PM, Ravi Varadhan wrote:
> Bill's code is insanely fast!
>
> f2 <- function(x, y) length(y) - findInterval(-x, rev(-sort(y)))
>
> n1 <- 1e07
> n2 <- 10^c(1,2,3,4,5,6,7)
> tt <- rep(NA, 7)
> x <- rnorm(n1)
> for (i in 1:length(n2)){
> y <- runif(n2[i])
> tt[i] <- syste
On Thu, Apr 14, 2011 at 8:28 PM, Chris Howden
wrote:
> Thanks for the suggestions, they were all exactly what I was looking for.
> (I knew that had to be a more elegant way then my brute force method)
>
> One question though.
>
> I was playing around with strsplit but couldn't get it to work, I re
Bill's code is insanely fast!
f2 <- function(x, y) length(y) - findInterval(-x, rev(-sort(y)))
n1 <- 1e07
n2 <- 10^c(1,2,3,4,5,6,7)
tt <- rep(NA, 7)
x <- rnorm(n1)
for (i in 1:length(n2)){
y <- runif(n2[i])
tt[i] <- system.time(a1 <- f2(x, y))[3]
}
> tt
[1] 0.70 0.86 1.03 1.28 1.54 4.99
I'm posting this for two reasons: one is to see if anyone has a better
way of solving the problem or suggestions for improving my existing
approach; and the other is to show what I'm currently doing in case
anyone else might find it useful.
The background is that I've been using Sweave for severa
seatales uh.edu> writes:
>
> Hello,
> I am using the following model
>
> model1=lmer(PairFrequency~MatingPair+(1|DrugPair)+(1|DrugPair:MatingPair),
> data=MateChoice, REML=F)
>
> 1. After reading around through the R help, I have learned that the above
> code is the right way to analyze a mi
> I was trying strsplit(string,"\.\.\.") as per the suggestion in Venables
> and Ripleys book to "(use '\.' to match '.')", which is in the Regular
> expressions section.
>
> I noticed that in the suggestions sent to me people used:
> strsplit(test,"\\.\\.\\.")
>
>
> Could anyone please explain why
Also fine with Kaspersky.
Ronggui
On 15 April 2011 05:37, David Freedman wrote:
> 2.13.0 looks fine with VIPRE
>
> david freedman
> atlanta
>
> --
> View this message in context:
> http://r.789695.n4.nabble.com/Trojan-in-R-2-13-0-tp3450084p3450784.html
> Sent from the R help mailing list archiv
Thanks for the suggestions, they were all exactly what I was looking for.
(I knew that had to be a more elegant way then my brute force method)
One question though.
I was playing around with strsplit but couldn't get it to work, I realised
my problem was that I was using "." as the string.
I was
Hi everyone.
I am quite frustrated that this doesn't work, as all the functions within
work fine by themselves. I'd also like any pointers to how to avoid 'for'
loops in my code. I understand it's less than desirable, but I'm still quite
new and use them a lot.
I have a few wide datasets (90 to 1
On 14 April 2011 at 19:02, Robert Wilkins wrote:
| a new language that can produce complex statistical tables far faster,
| with much less code and effort, than any previous statistical
| programming language.
|
| a version that outsources ( gives work to do ) to vilno data
| transformation and R
a new language that can produce complex statistical tables far faster,
with much less code and effort, than any previous statistical
programming language.
a version that outsources ( gives work to do ) to vilno data
transformation and R is already in beta mode, a version that
outsources to SAS/BAS
On 4/14/2011 2:04 PM, Cliff Clive wrote:
I have a vector of character strings that I would like to split in two, and
place in columns of a dataframe.
So for example, I start with this:
beatles<- c("John Lennon", "Paul McCartney", "George Harrison", "Ringo
Starr")
and I want to end up with a da
On 11-04-14 12:29 PM, Liviu Andronic wrote:
Dear all
I've just tried the brand new 'grdevice' option in Sweave but couldn't
make it work. When I declare
\SweaveOpts{grdevice=pdf}
or
\SweaveOpts{grdevice=cairo_pdf}
trying to plot something simple
<>=
plot(1:10,1:10,main='Some title')
@
would re
On 2011-04-14 12:15, Soyeon Kim wrote:
Thank you all, but I still cannot see the whole code.
Closest answer is Steve's answer R> glmnet:::predict.cv.glmnet but I
only can see a part of the code.
I am not sure whether it is protected by the programmer on purpose or
I just cannot find where it is.
On 15/04/11 09:04, Cliff Clive wrote:
I have a vector of character strings that I would like to split in two, and
place in columns of a dataframe.
So for example, I start with this:
beatles<- c("John Lennon", "Paul McCartney", "George Harrison", "Ringo
Starr")
and I want to end up with a data
You could use ?unlist:
structure(data.frame(
matrix(unlist(strsplit(beatles," ")),length(beatles),2,T)),
names=c("FirstName","LastName"))
Note that this compact code does not guard you against typos, that is
names with >2 or <2 elements.
Hope that helps,
Denes
> I have a vector of ch
Dear list,
I wish to modify programmatically only a few factor levels, according
to a named list. I came up with this function,
modify.levels <- function(f, modify=list()){
## levels that will not be changed
names.old.levels <- setdiff(levels(f), unlist(modify))
## as a named list
old.le
My colleague Sunduz Keles once mentioned a similar problem to me. She
had a large sample from a reference distribution and a test sample
(both real-valued in her case) and she wanted, for each element of the
test sample, the proportion of the reference sample that was less than
the element. It's
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Kevin Ummel
> Sent: Thursday, April 14, 2011 12:35 PM
> To: r-help@r-project.org
> Subject: [R] Find number of elements less than some number:
> Elegant/fastsolution needed
>
>
2.13.0 looks fine with VIPRE
david freedman
atlanta
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Hello All,
I am using Groovy and Grails on Eclipse. I want to use R with this language but
I am unable to configure it correctly on my mac with JRI. So can you help me
out ?
Thanks
Sonu
-
Sonu kumar
DKFZ, Heidelberg
Germany
__
R-help@r-project.org
Hi Achim,
Yes, this worked. I added the two strings
regts.start <- as.Date(regts.start)
regts.end <- as.Date(regts.end)
and changed the frequency to 1 in my zooreg call.
The window call now works perfectly.
I'm still wrapping my head around POSIXct and ISOdatetime and how they
need to be appli
I have a vector of character strings that I would like to split in two, and
place in columns of a dataframe.
So for example, I start with this:
beatles <- c("John Lennon", "Paul McCartney", "George Harrison", "Ringo
Starr")
and I want to end up with a data frame that looks like this:
> Beatles
This might be a bit quicker with larger vectors:
f <- function(x, y) sum(x > y)
vf <- Vectorize(f, "x")
vf(x, y)
On Thu, Apr 14, 2011 at 5:37 PM, Marc Schwartz wrote:
> On Apr 14, 2011, at 2:34 PM, Kevin Ummel wrote:
>
>> Take vector x and a subset y:
>>
>> x=1:10
>>
>> y=c(4,5,7,9)
>>
>> For ea
Michael McAssey gmail.com> writes:
>
> I need to include some mathematical expressions in a plot I am creating in
> R, one of which requires an underbrace, which in LaTeX would be written like
>
> \underbrace{T \cdots T}_{n times}
>
> There does not appear to be a provision for this in plotmat
On Thu, Apr 14, 2011 at 7:47 AM, 1Rnwb wrote:
> Thanks, I thought that removing the list would take care of it. the question
> is I do not see a .Rhistory file in my current working directory, so where
> it is stored. it is not visible in C:\Program files\R either. Serarching the
> C;\ and D:\ dri
[see below]
From: Frederik Lang [mailto:frederikl...@gmail.com]
Sent: Thursday, April 14, 2011 12:56 PM
To: William Dunlap
Cc: r-help@r-project.org
Subject: Re: [R] Incremental ReadLines
Hi Bill,
Thank you so much for your suggestions. I will try and alter my
code.
> I am trying to teach myself R and replicate some previous SAS analysis.
> Could someone please help me translate the following SAS code into R.
>
> Proc mixed method=ml
> Class Group Treatment Stream Time Year;
> Model Logrpk=Treatment Time Treatment*Time;
> Random Group Stream (Group Treatment)
Hi
I'm trying to forecast an zoo-object the following exempel of code::
"dynlm(y_t = 1+ L(y_t, 1:5}}"
but I cannot use predict() nor forecast() to make an forecast of the object.
Regard Serdar
[[alternative HTML version deleted]]
__
R-help@r
On Thu, 14 Apr 2011, Katrina Bennett wrote:
Hi Achim,
Yes, this worked. I added the two strings
regts.start <- as.Date(regts.start)
regts.end <- as.Date(regts.end)
and changed the frequency to 1 in my zooreg call.
The window call now works perfectly.
I'm still wrapping my head around POSIXc
I think using base graphics you would need to use numerical vectors to set the
bubble positions. However there is not reason that you could not suppress the
axis labeling and apply your own.
This code does the first part using circles. There are probably better ways to
do it but this should wo
On Apr 14, 2011, at 18:17 , rbali wrote:
> Dear list
>
> Avira said TR/ATRAPS.Gen trojan is in open.exe [C:\Program
> Files\R\R-2.13.0\bin\i386\open.exe] installed yesterday with R 2.13.0 from
>
> http://streaming.stat.iastate.edu/CRAN/bin/windows/base/R-2.13.0-win.exe
> http://cran.cnr.berkel
On Apr 14, 2011, at 2:34 PM, Kevin Ummel wrote:
> Take vector x and a subset y:
>
> x=1:10
>
> y=c(4,5,7,9)
>
> For each value in 'x', I want to know how many elements in 'y' are less than
> 'x'.
>
> An example would be:
>
> sapply(x,FUN=function(i) {length(which(y [1] 0 0 0 0 1 2 2 3 3 4
>
This is faster for small vectors
> system.time(for (i in 1:1000)
+ colSums(outer(y, x, `<`))
+ )
user system elapsed
0.110.000.11
> system.time(for (i in 1:1000)
+ sapply(x,FUN=function(i) {length(which(y
> colSums(outer(y, x, `<`))
[1] 0 0 0 0 1 2 2 3 3 4
> sapply(x,FUN=function(
hi All,
I have a matrix Ufi (x by y)
1 2 3 4 5
1 0 0 0 0 3
2 0 0 0 9 0
3 0 2 0 0 3
4 0 0 1 0 0
5 0 1 0 0 0
And I need the x and y "coordinates" of those cells with maximum values:
First:
x=4; y=2 (Value=9)
Second:
x=5; y=3 (value=3)
Any help?
THANKS!
Nic
_
On 14 April 2011 at 03:56, didu wrote:
| Hi all,
|
| I'm new to R and Rcpp, and I'm trying to learn Rcpp with the simplest code
| possible. My goal is to be able to call R functions from C++.
Just to set the record straight here for purpose of the mailing list archive:
the original poster had a s
Hello all,
I am trying to teach myself R and replicate some previous SAS analysis.
Could someone please help me translate the following SAS code into R.
Proc mixed method=ml
Class Group Treatment Stream Time Year;
Model Logrpk=Treatment Time Treatment*Time;
Random Group Stream (Group Treatment)
Same problem with Vista
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I have got the same problem. Can anybody help me why R just shuts down?
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R-help@r-project.org m
> Date: Thu, 14 Apr 2011 11:57:40 -0400
> Subject: Re: [R] Incremental ReadLines
> From: frederikl...@gmail.com
> To: marchy...@hotmail.com
> CC: r-help@r-project.org
>
> Hi Mike,
>
> Thanks for your comment.
>
> I must admit that I am very new to R and alth
To anyone that may be able to help,
First I applogize if this message ends up in your inbox twice. The first
one seemed to get stuck in a pending status so I deleted and started over.
I am relatively new to R, however I know the basics through some classes I
have taken. Unfortunately the classe
Dear list
Avira said TR/ATRAPS.Gen trojan is in open.exe [C:\Program
Files\R\R-2.13.0\bin\i386\open.exe] installed yesterday with R 2.13.0 from
http://streaming.stat.iastate.edu/CRAN/bin/windows/base/R-2.13.0-win.exe
http://cran.cnr.berkeley.edu/bin/windows/base/R-2.13.0-win.exe
Robert
--
View
Hi Bill,
Thank you so much for your suggestions. I will try and alter my code.
Regarding the even shorter solution outside the loop it looks good but my
problem is that not all observations have the same variables so that three
different observations might look like this:
Id: 1
Var1: false
Var
Hi All,
I have the following matrix Ufi (x by y):
Ufin
1 2 3 4 5 6 7 8 9 10
1 0 0 0 0 0 0 0 0 0 0
2 0 0 0 0 0 0 0 0 0 0
3 0 0 0 0 0 0 0 0 0 0
4 0 0 0 6 0 0 0 0 0 0
5 0 0 0 0 0 0 0 0 0 0
6 0 0 0 0 0 0 9 0 0 0
7 0 2 0 0 0 0 0 0 0 0
8 0 0 0 0 0 0 0 0 0 0
I need to include some mathematical expressions in a plot I am creating in
R, one of which requires an underbrace, which in LaTeX would be written like
\underbrace{T \cdots T}_{n times}
There does not appear to be a provision for this in plotmath, and I cannot
find anything on the topic in the R
Take vector x and a subset y:
x=1:10
y=c(4,5,7,9)
For each value in 'x', I want to know how many elements in 'y' are less than
'x'.
An example would be:
sapply(x,FUN=function(i) {length(which(yhttps://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.o
Yep... Hitting the up arrow key upon the next initialization shows all the
previous codes.
I.e. after q() --- Y and re opening R console the next time.
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Hi Mike,
Thanks for your comment.
I must admit that I am very new to R and although it sounds interesting what
you write I have no idea of where to start. Can you give some functions or
examples where I can see how it can be done.
I was under the impression that I had to do a loop since my block
Dear list members,
I need to fit a regression with two inequality constraints. I look up in
the literature and R archive and found some ways to do it, for example
using the ic.infer package.
However I do not know how to write in R my constraints. In the package
help, it is told that
Hi Mike,
There are some facilities for storing and manipulating small (2 bit)
integers. See here:
http://cran.r-project.org/web/packages/ff/index.html
-Matt
On 04/14/2011 01:20 PM, Mike Miller wrote:
I note that "current implementations of R use 32-bit integers for
integer vectors," but I a
Thank you all, but I still cannot see the whole code.
Closest answer is Steve's answer R> glmnet:::predict.cv.glmnet but I
only can see a part of the code.
I am not sure whether it is protected by the programmer on purpose or
I just cannot find where it is.
Soyeon
On Thu, Apr 14, 2011 at 1:18 PM,
I note that "current implementations of R use 32-bit integers for integer
vectors," but I am working with large arrays that contain integers from 0
to 3, so they could be stored as unsigned 8-bit integers. Can R do this?
(FYI -- This is for storing minor-allele counts for genetic studies.
Ther
Just type the name of your function without (). Or use fix(). Or
do you need to do something more complicated?
HTH Jannis
--- Soyeon Kim schrieb am Do, 14.4.2011:
> Von: Soyeon Kim
> Betreff: [R] How to see a R code from a package?
> An: r-help@r-project.org
> Datum: Donnerstag, 14. April, 2
On Apr 14, 2011, at 12:45 PM, Alison Callahan wrote:
> Hello all,
>
> First off, I am using R version 2.13.0 in Ubuntu.
>
> I have read previous posts in the R mailing list on saving models for
> later use, and the responses indicate using the R save() function to
> save a model and then using l
I apologize for the slow response, but I just registered with Nabble.
The duleg function in labdsv was renamed indval to be more consistent with
its use in the literature. Typing ?indval will provide more information.
As an aside, all R functions have an email for the author or maintainer
speci
Hello all,
First off, I am using R version 2.13.0 in Ubuntu.
I have read previous posts in the R mailing list on saving models for
later use, and the responses indicate using the R save() function to
save a model and then using load() to load it is one way to go.
However, when I use the save() fu
Dear Community,
this is my first programming in R and I am stuck with a problem. I
have the following code which automatically calculates Granger
causalities from a variable, say e.g. "bs" as below, to all other
variables in the data frame:
log.returns<-as.data.frame( lapply(daten, function(x) di
Hi-
Tabular data have been provided to me within .csv files. I need to transform
the data from tabular format into a dataframe with three
columns. The columns need to be the table row id, table column id, and the
tabulated variable. An example dataset can be downloaded here:
https://docs.google.co
You could also just download the source package from CRAN and look through it.
The thing is, the predict.cv.glmnet function isn't exported by the
package (via its namespace file) -- so it's somehow protected. You
could still see it using `:::`, like so:
R> glmnet:::predict.cv.glmnet
function(obje
See help for getAnywhere()
Kevin
On Thu, Apr 14, 2011 at 11:24 AM, Soyeon Kim wrote:
> Dear R users,
>
> Hi. I want know R code of a function: predict.cv.glmnet (which is
> included in glmnet package).
> Could you let me know how I can see the R code of the function?
>
> Thank you,
> Soyeon Ki
I have two suggestions to speed up your code, if you
must use a loop.
First, don't grow your output dataset at each iteration.
Instead of
cases <- 0
output <- numeric(cases)
while(length(line <- readLines(input, n=1))==1) {
cases <- cases + 1
output[cases] <- as.nume
Dear all
I've just tried the brand new 'grdevice' option in Sweave but couldn't
make it work. When I declare
\SweaveOpts{grdevice=pdf}
or
\SweaveOpts{grdevice=cairo_pdf}
trying to plot something simple
<>=
plot(1:10,1:10,main='Some title')
@
would result in an Sweave error:
18:16:47.299: 1 : te
Dear R users,
Hi. I want know R code of a function: predict.cv.glmnet (which is
included in glmnet package).
Could you let me know how I can see the R code of the function?
Thank you,
Soyeon Kim
__
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https://stat.ethz.ch
Thanks Martin, this is very helpful.
Barth
-Original Message-
From: Martin Morgan [mailto:mtmor...@fhcrc.org]
Sent: Thursday, April 14, 2011 11:04 AM
To: Barth B. Riley
Subject: Re: [R] for loop performance
On 04/14/2011 07:12 AM, Barth B. Riley wrote:
> Hi Martin
>
> Question--when vari
Jurgens de Bruin gmail.com> writes:
>
> Hi,
>
> I do not have much R experience just the basics, so please excuse
> any obvious questions.
>
> I would like to create bubble plot that have Categorical data on the x and y
> axis and then the diameter if the bubble the value related to x and y.
>
> Date: Thu, 14 Apr 2011 12:42:28 +0200
> From: r.m.k...@gmail.com
> To: marchy...@hotmail.com
> CC: r-help@r-project.org
> Subject: Re: [R] Identify period length of time series automatically?
>
> -BEGIN PGP SIGNED MESSAGE-
> Hash: SHA
Neither is the fastest method. The best way would be to vectorize func so
that it accepts and returns a vector. Many builtin R functions do this and
say so in their documentation.
The slower way would be to use one of the apply functions, such as:
?lapply
x2 <- lapply(x, func)
If you must use
ok ?c.trellis works well.
But I still have a problem.
One of my plot is a combination of two xyplot on different scales:
a<-xyplot(NDVI_P10~dek_num
| Year, type="a", data=data, xlim=c(1,37), ylim=c(0.1,0.8), as.table = TRUE,
layout =
c(13,1), aspect = 2, col="darkgrey",
col.axis="black", l
Thanks for the clarification, Jim. The terminology "previous"
was not self-explanatory!
The following implements (in a somewhat crude way, but explicit)
a solution to your question:
M <- matrix(c(1, 4, 23, 30), byrow=TRUE, ncol=2)
M
# [,1] [,2]
# [1,]14
# [2,] 23 30
f
On Apr 14, 2011, at 16:55 , Jim Silverton wrote:
> What Ted and Peter did were Fisher's exact test, To get the previous
> attainable p-value, what you do is the the fisher exact test p-values of ALL
> the possible tables with margins fixed and choose the p-value that is just
> below the one f
Dear Peter, thank you for your reply.
It works very well!
I have an additional question: what about the Wilcoxon test in case of
unequal paired samples with ties?
thank you!
net
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Hi Dirk,
On Thu, Apr 14, 2011 at 4:59 AM, dirknbr wrote:
> Which one is more efficient?
>
> x2=c()
> for (i in 1:length(x)) {
> x2=c(x2,func(x[i]))
> }
>
> or
>
> x2=x
> for (i in 1:length(x)) {
> x2=func(x[i])
> }
>
> where func is any function?
This one. Creating a [vector|matrix|dataframe]
Dear Pert,
Many thanks to your reply. Fully you are right!
Best wishes,
Helin.
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If you don't want your history, why not just do this.
>q()
Save workspace image? [y/n/c]:
>n
??
Am I missing something?
1Rnwb wrote:
>
> Thanks, I thought that removing the list would take care of it. the
> question is I do not see a .Rhistory file in my current working directory,
> so where
Dear Dr. Therneau,
Thank you for your response. Just to point out that we didn't experience any
problems with the lm() function under R version 2.12.2 (2011-02-25):
> set.seed(123)
> testdat=data.frame(y=rexp(10),event=rep(0:1,each=5),x=rnorm(10))
> testfm=as.formula('y~x')
>
> testfun=function
thank you very much for your response!
But I have now another problem: optim( ) gives me the exactly same initial
values for the 4 parameters. I have tried many initial values, and it always
didnt change them.
opt$convergence = 1. I increased the number of iterations, but the problem is
still
Thanks, I thought that removing the list would take care of it. the question
is I do not see a .Rhistory file in my current working directory, so where
it is stored. it is not visible in C:\Program files\R either. Serarching the
C;\ and D:\ drives shows some old .Rhistory files but not the recent o
Hi R-Users
I need to estimate Lyapunov exponent of my time series. After reading
description of all functions available I still don't know how to determine
time delay. My time series length is 4200. Is it possible to determine time
delay with other function's output or I can choose any random valu
I knew that the "NA's" in my data were the root cause of the trouble, but did
not find out how to get rid of them. Untill I found your another post
mentioning to use 'na.omit' to remove the lines containing 'NA's" and the
problem got fixed after that.
Thanks for the help and all the trouble you hav
Dear list,
I am running a fama macbeth regression using the lm.fit function and am
having problems extracting the rsquareds from each of the cross sectional
regressions (second stage) I have estimated.
I can obtain the coefficients using cfit = lm.fit(t(bhat[-1,]),
t(q))$coefficients
However I
Hi
I'm trying to plot several return level plots on the same axes to compare the
return levels from different data sets. To do this I am having to manually plot
the return levels for return periods. The problem is when I try to plot the
automatically calculated confidence intervals as the array
> Date: Wed, 13 Apr 2011 10:57:58 -0700
> From: frederikl...@gmail.com
> To: r-help@r-project.org
> Subject: Re: [R] Incremental ReadLines
>
> Hi there,
>
> I am having a similar problem with reading in a large text file with around
> 550.000 observatio
Hi all,
I'm new to R and Rcpp, and I'm trying to learn Rcpp with the simplest code
possible. My goal is to be able to call R functions from C++.
The code I'm trying to run is:
#include
#include
#include
#include
int main(int argc, char* argv[])
{
Rcpp::NumericVector v(1);
r
> Date: Thu, 14 Apr 2011 11:29:23 +0200
> From: r.m.k...@gmail.com
> To: r-help@r-project.org
> Subject: [R] Identify period length of time series automatically?
>
> -BEGIN PGP SIGNED MESSAGE-
> Hash: SHA1
>
> Hi
>
> I have 10.000 simulatio
thank you very much for your response!
But I have now another problem: optim( ) gives me the exactly same initial
values for the 4 parameters. I have tried many initial values, and it always
didnt change them.
opt$convergence = 1. I increased the number of iterations, but the problem is
still
Hello,
I have a contingency table showing relation between two datasets. I tried
to see association among them with the assocplot, but it shows
error. mosaicplot of the same data worked perfectly.
Can anyone please help me.
Con.table=as.matrix(Con.table)
> dim(Con.table)
[1] 27 27
> assocplot(C
Which one is more efficient?
x2=c()
for (i in 1:length(x)) {
x2=c(x2,func(x[i]))
}
or
x2=x
for (i in 1:length(x)) {
x2=func(x[i])
}
where func is any function?
Dirk
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Hi,
Just wanted to mention that this worked perfectly.
Many thanks again and best wishes,
Ranjan
On Tue, 12 Apr 2011 13:04:14 -0500 Jonathan P Daily
wrote:
> try:
>
> options(help_type = 'text')
> ?options
>
> If this works, you can create a site profile (A default is created
> automaticall
Hi,
I have to one set of inputs and their observed true values of each
input. Now I have a model takes the input and predict a value. I only
consider the ranks based on either the observed true values or the
predicted values. My question is how do I compare this two rank in R?
That is, how close t
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