Thank you, David and Bill! I'll try that.
...Tao
- Original Message -
> From: David Scott
> To: bill.venab...@csiro.au
> Cc: shida...@yahoo.com; r-help@r-project.org
> Sent: Thursday, June 23, 2011 10:11 PM
> Subject: Re: [R] extract worksheet names from an Excel file
>
> On 24/06/
Hello, I have a data set like one below.
First,
I'd like to replace the empty cells with NA, and then the one immediately
above.
I could replace NAs with the immediate one, but don't know for the empty
cells.
index <- which(is.na(data1$year))
while (any(index)) {
dummy$data1[index] <
On 24/06/11 16:55, bill.venab...@csiro.au wrote:
Package XLConnect appears to provide this kind of thing.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Shi, Tao
Sent: Friday, 24 June 2011 2:42 PM
To: r-help@r-project.org
Subjec
Use as.data.frame()
See ?ftable for details.
ftable(Titanic, row.vars = 1:3)
as.data.frame(.Last.value)
Rich
On Thu, Jun 23, 2011 at 10:58 PM, Mark Alen wrote:
> I am generating an ftable (by running ftable on the results of a xtabs
> command) and I am getting the following.
>
Package XLConnect appears to provide this kind of thing.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Shi, Tao
Sent: Friday, 24 June 2011 2:42 PM
To: r-help@r-project.org
Subject: [R] extract worksheet names from an Excel file
Hi list,
Is there a R function I can use to extract the worksheet names from an Excel
file? If no, any other automatic ways (not using R) to do this?
thanks!
...Tao
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
P
I am generating an ftable (by running ftable on the results of a xtabs command)
and I am getting the following.
Var1 Var2
date group
2007-01-01 q1
On Jun 23, 2011, at 10:40 PM, David Winsemius wrote:
On Jun 23, 2011, at 4:41 PM, jalen wrote:
http://r.789695.n4.nabble.com/file/n3620982/mbeFORUM.csv mbeFORUM.csv
I uploaded my data and one more time the script (*adjusted version*):
To get the "Block and Trt text as in the original reque
On Jun 23, 2011, at 4:41 PM, jalen wrote:
http://r.789695.n4.nabble.com/file/n3620982/mbeFORUM.csv mbeFORUM.csv
I uploaded my data and one more time the script (*adjusted version*):
Try:
pMBE<- MBE[MBE$left!=0,]
pMBE$bt<- interaction(pMBE$Block,pMBE$trt)
par(mfrow=c(3,3), oma=c(2,0,2,0))
f
Thanks Bill! Next time, I'll try literacy.
William Dunlap wrote:
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Benjamin Tyner
Sent: Thursday, June 23, 2011 5:31 PM
To: r-help@r-project.org
Subject: [R] 'Rscript -e' and stdout()
On Jun 23, 2011, at 2:00 PM, wwreith wrote:
library(xlsReadWrite)
mydata<-read.xls("file path", header=TRUE)
however if I change xls to csv it works just fine. Any ideas what
I'm doing
wrong? I have have also using the package gdata with the exact same
error.
Below is the error that pops
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Benjamin Tyner
> Sent: Thursday, June 23, 2011 5:31 PM
> To: r-help@r-project.org
> Subject: [R] 'Rscript -e' and stdout() puzzle
>
> Hello,
>
> I am curious to know why the out
>From: r-help-boun...@r-project.org [r-help-boun...@r-project.org] On Behalf Of
>Ann [trivialesc...@gmail.com]
>Subject: [R] reading the results of a within subject test
>
>Hi, I ran the following in R (on item means):
>
> aov(VAR ~(a*b)+Error(item/(a*b)), data = item)
>
>
> I'm confused...
Hello,
I am curious to know why the output of
Rscript -e "cat(R.version.string,stdout())"
includes a trailing " 1", whereas
Rscript -e "cat(R.version.string)"
does not. I have tried various mechanisms to subvert this behavior, such as
Rscript -e "invisible(con<-stdout()); cat(R.vers
Basically you need to set up a recursive relationship. I'd do this with a
2D array:
G = numeric(6*N)
dim(G) = c(6,N)
G[,1] = c(1,rep(0,5))
for (i in 2:N){G[,i]=G[,i-1]+5* c(1,rep(0,5))}
HTH,
-Steve
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.or
Gabor's answer explains the error perfectly. You might want to look at the xlsx
package as well as the RODBC package if you're on Windows. RODBC is really
fast, if you can use it.
Abhijit
On Jun 23, 2011, at 2:00 PM, wwreith wrote:
> library(xlsReadWrite)
> mydata<-read.xls("file path", head
On Jun 23, 2011, at 4:42 PM, elisheva corn wrote:
> hi all-
>
> I am doing some research, have never used R before until today and need to
> understand the following program for a project.
> if some one could PLEASE help me understand this program ASAP i would
> GREATLY appreciate it (any syntax
On Jun 23, 2011, at 4:11 PM, Adrienne Keller wrote:
> I would like to change the plot area for a figure I made with barplot2 so
> that it is rectangular (for example, 5 x 3 inches) rather than square, which
> is the default. What is the best way to do this?
>
> Thanks,
>
> Adrienne
Hi,
The s
On 2011-06-23 16:46, Steven Wolf wrote:
I am looking at the function ks.test in the stats package and trying to
figure out why it gives a different result for a p-value than does the
corresponding function in MATLAB. I am hoping for one of two responses:
1. You know about ks.tests and h
On Thu, Jun 23, 2011 at 4:46 PM, Steven Wolf wrote:
> I am looking at the function ks.test in the stats package and trying to
> figure out why it gives a different result for a p-value than does the
> corresponding function in MATLAB. I am hoping for one of two responses:
>
>
>
> 1. You kno
On Thu, Jun 23, 2011 at 2:00 PM, wwreith wrote:
> library(xlsReadWrite)
> mydata<-read.xls("file path", header=TRUE)
>
> however if I change xls to csv it works just fine. Any ideas what I'm doing
> wrong? I have have also using the package gdata with the exact same error.
>
> Below is the error t
hi all-
I am doing some research, have never used R before until today and need to
understand the following program for a project.
if some one could PLEASE help me understand this program ASAP i would
GREATLY appreciate it (any syntax/ statistic comments would be great)
PLEASE PLEASE HELP!! THAN
the answer to the missing mars data can be found on pages 176/177 of the
referenced book.
--
View this message in context:
http://r.789695.n4.nabble.com/question-about-Software-for-Data-analysis-book-tp1043713p3621277.html
Sent from the R help mailing list archive at Nabble.com.
___
The "bayesm" package does HB models for discrete choice. In practice, a hurdle
is likely to be translating your data (if it's fielded in Sawtooth Software) to
the correct format for bayesm (which uses a list format instead of a matrix,
and difference coding instead of dummy coding).
(BTW, note
http://r.789695.n4.nabble.com/file/n3620982/mbeFORUM.csv mbeFORUM.csv
I uploaded my data and one more time the script (*adjusted version*):
pMBE<- MBE[MBE$left!=0,]
pMBE$bt<- interaction(pMBE$Block,pMBE$trt)
par(mfrow=c(3,3), oma=c(2,0,2,0))
for(i in unique(pMBE$bt)){
ss <- pMBE$bt==i
plot(pMBE$
Hi
Please find attached document to see my problem that I wish you would assist
me to solve.
I want to maximise the LDV model to get alpha estimates.
I am looking forward to hearing from you soon.
Edward
Actuarial Science student
__
R-help@r-project.o
I would like to change the plot area for a figure I made with barplot2
so that it is rectangular (for example, 5 x 3 inches) rather than
square, which is the default. What is the best way to do this?
Thanks,
Adrienne
__
R-help@r-project.org mailin
library(xlsReadWrite)
mydata<-read.xls("file path", header=TRUE)
however if I change xls to csv it works just fine. Any ideas what I'm doing
wrong? I have have also using the package gdata with the exact same error.
Below is the error that pops up.
Error in findPerl(verbose = verbose) :
perl
Hi, I'm quite new to R and are stuck with the following problem.
Lets say I have a column consisting of a 1 and the rest zero's, called G0.
G0 <- c(1,rep(0,5))
Now what I would like to do is to generate G1 from G0, and G2 from G1 etc...
Just for the simplicity, let's say I need the first entry of
I am looking at the function ks.test in the stats package and trying to
figure out why it gives a different result for a p-value than does the
corresponding function in MATLAB. I am hoping for one of two responses:
1. You know about ks.tests and have a familiarity with both the R and
MAT
Mike Marchywka wrote:
>
>> I discovered a way to do repetitive tasks that can be concisely specified
>> using
>> something called a computer.
Now that's funny :)
There were not controlled tests. It was a field experiment testing the
effects that various pavement designs have on underlying soi
Hi,
is there any chance to install glmnet with gcc-4.5.2? For me it fails on
all systems with:
trying URL
'http://mirrors.softliste.de/cran/src/contrib/glmnet_1.7.tar.gz'
Content type 'application/x-gzip' length 522888 bytes (510 Kb)
opened URL
==
d
Hi all,
I'm currently working on updating an R package to run for loops in parallel
to speed up computation time. I'm using the 'foreach' package with a
foreach loop. When I run my code inside the loop, I get an error message
that a number of the functions aren't recognized (even though the func
Hi, I ran the following in R (on item means):
aov(VAR ~(a*b)+Error(item/(a*b)), data = item)
I got this result:
Error: item
Df Sum SqMean Sq F value Pr(>F)
a 1 7.7249e+13 7.7249e+13 11.329 0.003934 **
Residuals 16 1.0910e+14 6.8187e+12
---
Signif
There is a problem passing x in the ... arguments to fit.mult.impute when the
function has a formal argument starting with "x" (xtrans). To get around
this specify xtrans=a to fit.mult.impute instead of just listing a.
Frank
Lina Hellström wrote:
>
> Hi!
> Does anyone know how to do the test fo
Is there a way to apply paste to list(form1 = EQ1, form2 = EQ2, form3 = EQ3,
form4 = EQ4) such that I don't have to write form1=EQ1 for all my models (I
might have a list of 20 or more)? I also need the EQs to read the formulas
associated with them.
For example, below, I was able to automate
Thanks for the suggestion. Those functions only provide part of the
functionality I want.
After a great deal more of drawing the internet, I've concluded that the
correct answer to my question is dredge() from the package MuMIn. It
seems to use the same AIC algorithm as AIC, which is perfect f
On Thu, Jun 23, 2011 at 11:19 AM, Estefania Ruiz Vargas wrote:
> I am using the function cutreeHybrid from the package dynamic Tree Cut and I
> need a list of the resulting clusters but I do not know how to get it.
Hi,
I'm the author of the package. The function returns a list whose
component '
Alexandra,
Have a look at add1 and drop1.
Regards,
Jan
On 06/23/2011 07:32 PM, Alexandra Thorn wrote:
Here's a more general question following up on the specific question I
asked earlier:
Can anybody recommend an R command other than mle.aic() (from the wle
package) that will give back a ran
Is there any package for computing concordance coefficient of incomplete
ranking?
If there is not, please help me to write it.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-
On Jun 23, 2011, at 1:19 PM, Adrienne Keller wrote:
> I am trying to make a two panel figure using barplot2 in gplots. When I use
> par(mfrow=c(1,2)), two panels are created but both barplots are overlaid on
> top of one another in the first panel and the second panel is left blank. Am
> I run
On Jun 23, 2011, at 1:47 PM, yf wrote:
Dear all,
How can I do the subset fucntion from the table?
What table?
I want to do the subset for
the less than 50.
I tried b8a<-subset(b8, (table(g$book)<50)==TRUE) but it didn't work.
And you neither shown us what these structures are nor posted
On Jun 23, 2011, at 1:00 PM, jalen wrote:
Hello, I have a problem with my script. I don'y know how to apply
subtitles.
I have 9 charts per page (for combination of 3 blocks and 3
treatments). I
want to have subtitles for this interaction (e.g. Block A Trt 1,
Block A Trt
2, ...)
MBE$bt<-
Hi,
I am trying to merge data similar to the example data below
> dat0
idvar1var2var3
2 1 0 1
3 1 0 1
4 0 1 1
5 0 1 1
> dat1
idvar4var5var6
2 1 0 1
3 1
Yes, that's true. On a test set, the highest probability of being in the
smaller class is about 40%. (Incidentally, accuracy on the test set is much
higher when I use the best-according-to-Kappa model instead of the
best-according-to-Accuracy model.)
It looks like the ctree() method supports weigh
Hello, I have a problem with my script. I don'y know how to apply subtitles.
I have 9 charts per page (for combination of 3 blocks and 3 treatments). I
want to have subtitles for this interaction (e.g. Block A Trt 1, Block A Trt
2, ...)
MBE$bt<- interaction(MBE$Block,MBE$trt)
par(mfrow=c(3,3))
for
Dear all,
How can I do the subset fucntion from the table? I want to do the subset for
the less than 50.
I tried b8a<-subset(b8, (table(g$book)<50)==TRUE) but it didn't work.
Thanks.
table(g$ book )
119 121 134 160 161 170 175 179 190 193 225 226 256 260
130 89 50 8774 23 8547
I am using the function cutreeHybrid from the package dynamic Tree Cut and I
need a list of the resulting clusters but I do not know how to get it.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/m
I am trying to make a two panel figure using barplot2 in gplots. When
I use par(mfrow=c(1,2)), two panels are created but both barplots are
overlaid on top of one another in the first panel and the second panel
is left blank. Am I running into problems because I of some
complexities of gpl
Here's a more general question following up on the specific question I
asked earlier:
Can anybody recommend an R command other than mle.aic() (from the wle
package) that will give back a ranked list of submodels? It seems like
a pretty basic piece of functionality, but the closest I've been able
Hi:
Try this:
merge(merge(dat0, dat1, by = 'id', all.x = TRUE, all.y = TRUE), dat2,
by = 'id', all.x = TRUE, all.y = TRUE)
Dennis
On Thu, Jun 23, 2011 at 9:53 AM, cddesjar wrote:
> Hi,
> I am trying to merge data similar to the example data below
>
>> dat0
>
> id var1 var2 var3
> 2
Hi,
> How can I best do this in R? I've looked into merge but it excludes ids that
> aren't in all 3 data sets.
You need to look a bit harder at merge(), specifically the all.x and
all.y options.
Sarah
On Thu, Jun 23, 2011 at 12:53 PM, cddesjar wrote:
> Hi,
> I am trying to merge data similar t
I have a data frame that looks as follows.
df <- data.frame(city=c("Houston", "Houston", "El Paso", "Waco", Houston",
"Plano", "Plano")
What I want to do is get a list of the city values. Currently, when I run
df$city, I get all the values.
I just want to know the four cities that appear.
So ins
Try levels(df$city) or unique(df$city) depending on if it is a factor (default)
or character string.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-hel
Hi all,
I have two questions about variables in glmnet:
1. We are doing a logistic regression with binary outcome variable using a
set of predictors that include continuous and binary predictors(coded 0 and
1). If the latter are centered and standardized, they will be transformed
into negative
My thanks to this mailing list and its members for their great help in the
past. I have yet another question per the following code and comments:
# I need individual graphs grouped by "PARLABEL" AND "Event", with "PARLABEL"
# controlling pct and lty, and "Event" controlling col (where Event==1
I think that there may be a problem with the way
bquote(), for() and savePlot() play together in
the OP's example (multiple plots on a windows device;
bquote using the loop index).
Here's a version using replayPlot():
## show mu with subscripts 4 and 9:
x11()
par(mfrow = c(2,1))
for (i in
It's very simple to do this in steps:
> # to make separate dataframes
> df <- data.frame(A=1:5, B=11:15)
> df.sample <- c(1,3,4)
> df[df.sample, ]
A B
1 1 11
3 3 13
4 4 14
> df[-df.sample, ]
A B
2 2 12
5 5 15
>
> # or a list with two components
> split(df, 1:nrow(df) %in% df.sample)
$`FALSE`
On Jun 23, 2011, at 12:05 PM, Kara Przeczek wrote:
Thank you for all your help! I did not know to use "" when searching
for help, as ?mean, etc, had always worked for me in the past.
It makes perfect sense why 'else' was causing me the trouble the way
I was using it. I think it was working i
Hi,
I seemingly have a simple problem, but I've spend hours reading guides &
posts on this forum and I can't seem to piece together what I need.
I have a dataframe where I want to divide it into two subsets: a sample, and
the remainder of the dataframe in a new frame.
I've tried this:
split(df, s
Depending on how critical the problem is, you might also want to look at the
literature on bootstrap CI's, perhaps starting from the references in boot.ci
in the boot package. The simple quantiles are not necessarily the most
appropriate. For example I seem to recall that BCa intervals were the
Thank you for all your help! I did not know to use "" when searching for help,
as ?mean, etc, had always worked for me in the past.
It makes perfect sense why 'else' was causing me the trouble the way I was
using it. I think it was working in my other code, despite the same format,
because it w
On Jun 23, 2011, at 11:57 AM, Abhisek Saha wrote:
Hi Lui, Anupam and my other R-user friends,
Thanks for your previous suggestions. As for my issue, it is clearly
RAM problem as my code is running perfectly as long as my input data
size is small and code has been refined a number of times to i
D'oh! Completely missed that. Definately a case or RTFMS (RTFM, Stupid).
My apologies for the spam.
Sincerely (with additional grovelling)
Cormac.
On 23 June 2011 15:59, Nick Sabbe wrote:
> Hello Cormac.
>
> Not having thoroughly checked whether your code actually works, the behavior
> of rle y
Thanks All,
Henrique, gave me the solution is was looking for, the indexing was a
mistake on my part.
Thanks again
On 23 June 2011 16:37, David Winsemius wrote:
>
> On Jun 23, 2011, at 11:19 AM, Uwe Ligges wrote:
>
>
>>
>> On 23.06.2011 16:39, Michael Pearmain wrote:
>>
>>> Hi All,
>>>
>>> I'v
Hi Lui, Anupam and my other R-user friends,
Thanks for your previous suggestions. As for my issue, it is clearly
RAM problem as my code is running perfectly as long as my input data
size is small and code has been refined a number of times to increase
efficiency [ by using matrix more in the conte
On 6/22/2011 11:02 PM, Idris Raja wrote:
Brian,
I'm a bit confused about how the following line works, specifically, what is
happening in freq=length(x)? Is it just taking the length of x after it has
been summarized by different combinations x& y? I guess that must be the
case, because that gi
On Jun 23, 2011, at 11:19 AM, Uwe Ligges wrote:
On 23.06.2011 16:39, Michael Pearmain wrote:
Hi All,
I've been given a data file of the form:
1: 3,4,5,6
2:1,2,3
43: 5,7,8,9,5
and i want to read this data in as a list to create the form:
(guessing final look)
my.list
[[1]]
[1] 3 4 5 6
[[2]
Try this:
sapply(lapply(strsplit(l, ":"), strsplit, ","),
function(x)structure(lapply(x[2], as.numeric), .Names = x[1]))
On Thu, Jun 23, 2011 at 11:39 AM, Michael Pearmain
wrote:
> Hi All,
>
> I've been given a data file of the form:
> 1: 3,4,5,6
> 2:1,2,3
> 43: 5,7,8,9,5
>
> and i want to read
Thanks Uwe,
The list elements was a mistake on my part, i just wanted everything before
the : to be the name of the element.
Thanks for the help, i can play around with this to get what i want.
M
2011/6/23 Uwe Ligges
>
>
> On 23.06.2011 16:39, Michael Pearmain wrote:
>
>> Hi All,
>>
>> I've b
l <- readLines(textConnection("1: 3,4,5,6
2:1,2,3
43: 5,7,8,9,5"))
On Thu, Jun 23, 2011 at 12:28 PM, Henrique Dallazuanna wrote:
> Try this:
>
> sapply(lapply(strsplit(l, ":"), strsplit, ","),
> function(x)structure(lapply(x[2], as.numeric), .Names = x[1]))
>
> On Thu, Jun 23, 2011 at 11:39 AM,
Perhaps some additional clarification... (???)
>> if (length(dat2f$year)%%2==0) {
>> md <-dat2f[, list(med_year = max(year[which(abs(tot_km3y -
>> median(tot_km3y)) == min(abs(tot_km3y - median(tot_km3y ]), med_TotQ =
>> median(tot_km3y))] }
>> else {
>
> If this line is executed at a conso
On 23.06.2011 16:39, Michael Pearmain wrote:
Hi All,
I've been given a data file of the form:
1: 3,4,5,6
2:1,2,3
43: 5,7,8,9,5
and i want to read this data in as a list to create the form:
(guessing final look)
my.list
[[1]]
[1] 3 4 5 6
[[2]]
[1] 1 2 3
[[43]]
[1] 5 7 8 9 5
I can get to a s
On Thu, Jun 23, 2011 at 6:30 AM, Uwe Ligges
wrote:
> Folks,
>
> the relevant thing you have to remember is: All the stuff must be valid R
> syntax (with few additional functions as mention in the ?plotmath help
> file). Knowing that it is obvious where additional "operators" are required.
>
> Best
On Jun 23, 2011, at 10:59 AM, Kara Przeczek wrote:
Dear R users,
I have run into a problem using if...else and I hope you can shed
some light on it. I am using R version 2.2.0.1.
I have the following data frame:
head(dat2f)
year tot_km3y
[1,] 1964 0.1876854
[2,] 1965 0.1835116
[3,] 1
Hi All,
I've been given a data file of the form:
1: 3,4,5,6
2:1,2,3
43: 5,7,8,9,5
and i want to read this data in as a list to create the form:
(guessing final look)
my.list
[[1]]
[1] 3 4 5 6
[[2]]
[1] 1 2 3
[[43]]
[1] 5 7 8 9 5
I can get to a stage using scan:
scan("my.data", what = character
Dear R users,
I have run into a problem using if...else and I hope you can shed some light on
it. I am using R version 2.2.0.1.
I have the following data frame:
> head(dat2f)
year tot_km3y
[1,] 1964 0.1876854
[2,] 1965 0.1835116
[3,] 1966 0.1915012
[4,] 1967 0.1869758
[5,] 1968 0.2249865
[6
Hello Cormac.
Not having thoroughly checked whether your code actually works, the behavior
of rle you describe is the one documented (check the details of ?rle) and
makes sense as the missingness could have different reasons.
As such, changing this type of behavior would probably break a lot of
ex
On 23.06.2011 16:50, David Winsemius wrote:
On Jun 23, 2011, at 9:48 AM, Mark Finger wrote:
Have you ever run into a situation where you wanted to delete a file,
but Windows simply wouldn’t allow you to do it? Personally, these
things happen to me all the time, especially when I’m at a clien
On Jun 23, 2011, at 9:48 AM, Mark Finger wrote:
Have you ever run into a situation where you wanted to delete a file,
but Windows simply wouldn’t allow you to do it? Personally, these
things happen to me all the time, especially when I’m at a client’s
house trying to get their machine clean of
On 2011-06-23 06:44, Cormac Long wrote:
Hello there R-help,
I'm not sure if this should be posted here - so apologies if this is the case.
I've found a problem while using rle and am proposing a solution to the issue.
Description:
I ran into a niggle with rle today when working with vectors wit
Hello all,
I have a question on manova in R:
I'm using the function "manova()" from the stats package.
Is there anything like a stepwise (backward or forward) manova in R (like
there is for regression and anova).
When I enter:
step(Model1, data=Mydata)
R returns the message:
Error in drop1.
Hi all
I'm trying to match a numeric code to a vector of numeric codes:
a <- c(12345, 12346, 12347)
agrep(12349, a, max.distance=list(substitutions=1))
# [1] 1 2 3
agrep(12399, a, max.distance=list(substitutions=2))
# integer(0)
I didn't expect the latter result as substituting two characters
Hello there R-help,
I'm not sure if this should be posted here - so apologies if this is the case.
I've found a problem while using rle and am proposing a solution to the issue.
Description:
I ran into a niggle with rle today when working with vectors with NA values
(using R 2.31.0 on Windows 7 x
Dear list,
I have a matrix Y of multiple response variables and a matrix X of
predictor variables and I would like to fit a multivariate multiple
regression model and compute the R2-value to determine the overall
proportion of variance of the response matrix Y that is explained by
the predictor ma
Solved :)
Just use RBloomberg with RJava and use option_names
more in
http://www.carfield.com.hk/document/Finance/rbloomberg-manual-0-4-144.pdf
Thanks mike you did a good job :)
--
View this message in context:
http://r.789695.n4.nabble.com/RBloomberg-data-account-for-dividend-tp3614213p36198
Have you ever run into a situation where you wanted to delete a file,
but Windows simply wouldn’t allow you to do it? Personally, these
things happen to me all the time, especially when I’m at a client’s
house trying to get their machine clean of malware. Have you ever
tried deleting a locked file
On Jun 23, 2011, at 9:44 AM, Adriana Bejarano wrote:
Dear R gurus,
I have the following code, but I still not know how to estimate and
extract
confidence intervals (95%CI) from resampling.
If you have a distribution of values, say "resamp.stat", of a
statistic from a properly performed
On Thu, 2011-06-23 at 09:29 -0400, Alexandra Thorn wrote:
> Ok, here's some example code showing how I get different output for
AIC
> vs. mle.aic(). Now that I've taken another look at the independent
> variables, I'm wondering whether missing values in one of the
variables
> might be what is mes
Dear R gurus,
I have the following code, but I still not know how to estimate and extract
confidence intervals (95%CI) from resampling.
Thanks!
~Adriana
#data
penta<-c(770,729,640,486,450,410,400,340,306,283,278,260,253,242,240,229,201,198,190,186,180,170,168,151,150,148,147,125,117,110,107,104
Ok, here's some example code showing how I get different output for AIC
vs. mle.aic(). Now that I've taken another look at the independent
variables, I'm wondering whether missing values in one of the variables
might be what is messing me up. I'm going to see if the behavior
changes when I remove
On Jun 23, 2011, at 8:55 AM, Adan_Seb wrote:
Here is a self-contained example of my problem.
set.seed(100)
x = rbeta(100, 10.654, 10.439)
# So the shape parameters and the exteremes are
a = 10.654
b = 10.439
xmax = 1
xmin = 0
# Using the non-standardized form (as in my application and this
s
Dear All,
The first issue of the third volume of The R Journal is now available at
http://journal.r-project.org/current.html.
Thanks to everyone involved.
Heather
--
Editor in chief
heather.tur...@r-project.org
___
r-annou...@r-project.org mailing l
Hi!
Does anyone know how to do the test for goodness of fit of a logistic model (in
rms package) after running fit.mult.impute?
I am using the rms and Hmisc packages to do a multiple imputation followed by a
logistic regression model using lrm.
Everything works fine until I try to run the test f
The packages is wle.
I'll put together some code that shows the behavior I'm talking about,
and send it to the list.
Alexandra
On Thu, 2011-06-23 at 13:51 +0200, Rubén Roa wrote:
> I don't find the mle.aic function. Thus it does not ship with R and it's in
> some contributed package.
> What pa
Here is a self-contained example of my problem.
set.seed(100)
x = rbeta(100, 10.654, 10.439)
# So the shape parameters and the exteremes are
a = 10.654
b = 10.439
xmax = 1
xmin = 0
# Using the non-standardized form (as in my application and this shouldn't
make any difference) of the
# Beta densi
> From: rvarad...@jhmi.edu
> To: marchy...@hotmail.com; jmo...@student.canterbury.ac.nz;
> r-help@r-project.org
> Subject: RE: [R] Time-series analysis with treatment effects - statistical
> approach
> Date: Thu, 23 Jun 2011 02:59:19 +
>
> If you have any specific features of the ti
On Jun 23, 2011, at 7:26 AM, sumit gupta wrote:
Hi All,,
I am new to R and having a problem dealing with timestamps.
I have 2 columns in my table . Both of these have timestamps value in
format 06/22/11 05:34 PM .
If these are Date or DateTime objects you can use:
?difftime # with atten
Dear R-helpers,
I need to quantify dissimilarity of two minimum spanning trees,
specifically dissimilarity of their topologies. (They connect the same
objects but they are calculated from different sets of variables.)
Are you aware of any R-function doing this?
Best regards
Ondrej Mikula
_
On Jun 2, 2011, at 11:35 AM, Petr Savicky wrote:
On Thu, Jun 02, 2011 at 11:23:28AM -0400, Jim Silverton wrote:
Hi,
Can someone tell me how to remove rows of zeros from a matrix?
For example if I have the following matrix,
0 0
0 1
2 8
0 0
4 56
I should end up with
0 1
2 8
4 56
Hi.
Try the
1 - 100 of 109 matches
Mail list logo
