This is true if the original problem was with gdata::read.xls().
But xlsReadWrite was loaded, and this package doesn't use Perl to read
an xls file.
Is there a confusion somewhere?
Ivan
Le 6/24/2011 03:56, David Winsemius a écrit :
On Jun 23, 2011, at 2:00 PM, wwreith wrote:
SPAM
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
www.r-statistics.com (English)
Hi,
I have a problem with understanding what the function cast() from the package
reshape is doing. In the example below I have a 2x2x2 array which I first melt
and then cast to get the averages over the field 'strain' for every combination
of the fields 'treatement' and 'gene':
--
mdat
hi dear R crew.
may i request the script for volcano plot.
if able, pls include any tips about volcano plot.
thank you.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
Hi R users,
I'd like to draw a nomogram using a competing-risks regression (crr function
in R), rather than a cox regression. However, the nomogram function provided
in the Design package is not good for this purpose.
Do you have any suggestion.
I really appreciate your help
Many thanks
I have a list of names that look like this, with some ending in an * and
others not:
Steve Young*
Joe Montana*
Tom Brady
Daunte Culpepper
...
I want to create a variable that = 1 if the name ends in * and = 0
otherwise. Please help!
--
View this message in context:
Hi, ALL,
My name is Igor and I am a Software Developer.
Recently I wrote a program for a company using C++.
The problem I am facing right now is that this program (demo) has to
run using web interface. I.e. the potential user goes to the website,
click on the link and the program executes
Hi Sven,
Not sure if you're still having this problem, but I was as well and googled
into your post. I didn't find a great answer either, but the workaround I'm
using is some dummy points or lines with alpha=0 so they don't show up (ie
geom_hline(yintercept=0, alpha=0)). I suppose the same could
Hi,
This answer is predicated on the assumption that you are using list
in its English sense.
## character vector with the names
x - c(Steve Young*, Joe Montana*, Tom Brady, Daunte Culpepper)
## using grepl() and taking advantage of how logical data is stored to
get 0/1 data
...you should find a 64 bit Linux version here:
http://cran.r-project.org/bin/linux/
On Thu, Jun 23, 2011 at 6:04 PM, David Winsemius dwinsem...@comcast.net wrote:
On Jun 23, 2011, at 11:57 AM, Abhisek Saha wrote:
Hi Lui, Anupam and my other R-user friends,
Thanks for your previous
That problem is at least two-fold:
1. A failing heuristic in glmnet/configure.in
2. glmnet/src/glmnet/src/newGLMnet_f.f90 does not compile.
Several problems:
- gfortran does not recognise lines starting with [c|C]
comments
- starting at line 517, a
?restrict
-Ursprüngliche Nachricht-
Von: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] Im Auftrag von gizmo
Gesendet: Mittwoch, 22. Juni 2011 18:26
An: r-help@r-project.org
Betreff: [R] VAR with excluded lags
Hi,
I would like to fit a Vector Auto
Hi All,
What is the fastest way of finding if any members of vector x fall in the
range of the rows of matrix y?
I do not want to use two for loops as this will take forever.
Any help will be appreciated,
best,
salih
[[alternative HTML version deleted]]
Almost any tool can be bent to perform almost any task, but that combination
sounds like a particularly difficult way to get started. There are a variety of
purpose-built software development environments for serving
dynamically-constructed web pages, including C++ libraries.
However,
One approach is the following:
x - rnorm(5)
y - matrix(rnorm(5*2), 5, 2)
check - y - x
check[, 1] * check[, 2] 0
I hope it helps.
Best,
Dimitris
On 6/24/2011 10:57 AM, Salih Tuna wrote:
Hi All,
What is the fastest way of finding if any members of vector x fall in the
range of the rows of
Hi Dimitris,
Thanks for your reply. But this is not exactly what i am after. I want to
find the probes that falls into certain regions. In your solution it will
ignore the second probe if it falls into the same region as the first one.
Is there any vector trickb uilt in R to find whether probes
On 06/24/2011 05:16 AM, Assieh Rashidi wrote:
Is there any package for computing concordance coefficient of incomplete
ranking?
If there is not, please help me to write it.
Hi Assieh,
The muranks function in the crank package will impute missing ranks as
the mean value of all missing ranks
Hello Everybody,
The way I learn some analyses tools in R is to install the package and play
with some examples.
I am trying to see if declustering algorithm is implemented in R. I have
seen some examples examples of declustering data. However, I could not try
them as I do not know which package
Hi,
I am trying to install the network package at my work computer. I'm using R
version 2.12.0 (2010-10-15)
At home I can use the Package Installer, but at work this is blocked by our
firewall. What I usually do is download the Mac binary and copy it to
R.Framework/Resources/Library, but this
From: jdnew...@dcn.davis.ca.us
Date: Fri, 24 Jun 2011 02:13:29 -0700
To: ikoro...@gmail.com; R-help@r-project.org
Subject: Re: [R] Is R a solution to my problem?
Almost any tool can be bent to perform almost any task, but that combination
sounds like a particularly difficult way to
Dear all,
I get an error using betrag on this data set
:http://dl.dropbox.com/u/1866110/dump.csv.
I run it like this
regression f2.1=betareg(Y~X1+X2,data=dump)
summary(f2.1)
I get :
Call:
betareg(formula = Y ~ X1 + X2, data = dump)
Standardized weighted residuals 2:
Error in
The domain of the beta distribution as defined in R is 0 = x = 1 and as
shown by David Winsemius it is undefined outside [0,1]. But thats sort of
the question I have.
To elaborate, I have a variable with 0 as its natural lower limit but can
assume any positive number as an upper limit. So its
Hello,
I am having some trouble with the 'censoring-adjusted C-index' by Uno et al, in
the package survAUC. The relevant function is UnoC.
The question has to do with what happens when I specify a time point t for the
upper limit of the time range under consideration (we want to avoid using
I have a question regarding the very useful doBy package, and
specifically, the transformBy() function with the lag() and diff()
functions. It is often useful to lag or difference data within a
panel, i.e., within a by-group. Is the following code a safe use of
transformBy? Is there an
Please see the tsDyn package for implementing the Augmented Dickey
Fuller test.
Lexi
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of UnitRoot
Sent: Wednesday, June 15, 2011 9:06 AM
To: r-help@r-project.org
Subject: [R] Using ts and
On Fri, 24 Jun 2011, oyvfos wrote:
Dear all,
I get an error using betrag on this data set
:http://dl.dropbox.com/u/1866110/dump.csv.
I run it like this
regression f2.1=betareg(Y~X1+X2,data=dump)
summary(f2.1)
I get :
Call:
betareg(formula = Y ~ X1 + X2, data = dump)
Standardized weighted
I'm surprised the pdf made it through mail list but many will not open
these and I have just cleaned malware off my 'dohs system. Can you explain
what you want to do in simple text?
Subject: [R] R-help
Hi
Please assist me to code the attached pdf in R.
Your help will be greatly
On Jun 24, 2011, at 4:29 AM, thomas.chesney wrote:
Hi,
I am trying to install the network package at my work computer.
Which is a machine of what sort? (Most likely a Mac from subsequent
error messages)
I'm using R
version 2.12.0 (2010-10-15)
At home I can use the Package Installer,
This is not a homework help list.
Please read the Posting Guide before further posting.
On Jun 24, 2011, at 2:26 AM, Edward Bowora wrote:
Hi
Please assist me to code the attached pdf in R.
Your help will be greatly appreciated.
Edward
Actuarial Science Student
The Limited Dependent
Hi,
On Fri, Jun 24, 2011 at 3:15 AM, Ungku Akashah kasla...@yahoo.com wrote:
hi dear R crew.
may i request the script for volcano plot.
if able, pls include any tips about volcano plot.
Sure. What do you think a volcano plot looks like, and what kind of
data do you wish to use in constructing
Hi,
On Fri, Jun 24, 2011 at 6:09 AM, ogbos okike ogbos.ok...@gmail.com wrote:
Hello Everybody,
The way I learn some analyses tools in R is to install the package and play
with some examples.
Excellent plan.
I am trying to see if declustering algorithm is implemented in R. I have
seen some
On Thu, Jun 23, 2011 at 10:15 PM, Guy Jett gj...@itsi.com wrote:
My thanks to this mailing list and its members for their great help in the
past. I have yet another question per the following code and comments:
# I need individual graphs grouped by PARLABEL AND Event, with PARLABEL
#
Replace the Design package with the rms package. Use the ordinary linear
regression trick to predict the linear predictor from the competing risk
regression, then use nomogram on this new model (that merely represents the
fit of interest).
Frank
Firas Abdollah wrote:
Hi R users,
I'd like
Note that the original C-index is implemented in various validation options
in the rms package related to the cph function (which calls coxph in
survival).
Frank
=
Eleni Rapsomaniki-2 wrote:
Hello,
I am having some trouble with the 'censoring-adjusted C-index' by Uno et
al, in the package
Hi
Hi Dimitris,
Thanks for your reply. But this is not exactly what i am after. I want
to
find the probes that falls into certain regions. In your solution it
will
ignore the second probe if it falls into the same region as the first
one.
Is there any vector trickb uilt in R to find
Hi
Thank you for all your help! I did not know to use when searching for
help, as ?mean, etc, had always worked for me in the past.
It makes perfect sense why 'else' was causing me the trouble the way I
was
using it. I think it was working in my other code, despite the same
format,
On Fri, Jun 24, 2011 at 12:41 AM, Shi, Tao shida...@yahoo.com wrote:
Hi list,
Is there a R function I can use to extract the worksheet names from an Excel
file? If no, any other automatic ways (not using R) to do this?
thanks!
Many or all of the Excel interfaces listed here:
On Jun 24, 2011, at 7:47 AM, Petr PIKAL wrote:
Hi
Thank you for all your help! I did not know to use when
searching for
help, as ?mean, etc, had always worked for me in the past.
It makes perfect sense why 'else' was causing me the trouble the
way I
was
using it. I think it was
Hi,
I have a matrix (pwdiff in the example below) with ~48 rows and 780
columns.
For each row, I want to get the percentage of columns that have an absolute
value above a certain threshold t. I then want to allocate that percentage
to matrix 'perc' in the corresponding row. Below is my
The replication of the error did not suceed because I forgot to tell that
X2 is a factor. Sorry about that. For instance:
d[,3]=as.factor(d[,3])
This piece is just a small sample of a larger error for which I encouneter
this error many times.
Thanks
--
View this message in context:
Hey,
I am having trouble with lmer. I am looking at the presence/absence of water
shrews against habitat and other factors e.g
so I used this:
m1-lmer(Presencebsence~Habitatype*Width+(1|Sitename))summary(m1)
But i keep getting this error up
Error in mer_finalize(ans) : Downdated X'X is not
On Fri, 24 Jun 2011, oyvfos wrote:
The replication of the error did not suceed because I forgot to tell that
X2 is a factor. Sorry about that. For instance:
d[,3]=as.factor(d[,3])
This piece is just a small sample of a larger error for which I encouneter
this error many times.
You try to
Hi
Hi,
I have a matrix (pwdiff in the example below) with ~48 rows and 780
columns.
For each row, I want to get the percentage of columns that have an
absolute
value above a certain threshold t. I then want to allocate that
percentage
to matrix 'perc' in the corresponding row.
Dear list
Despite having set color settings for the console and script editing window,
when I open R and open a script file the text is black against a black
background (should be, according to the rconsole colors I saved, yellow against
black). I have tried repeatedly to reload and reapply
On Jun 24, 2011, at 9:44 AM, Barth B. Riley wrote:
Dear list
Despite having set color settings for the console and script editing
window, when I open R and open a script file the text is black
against a black background (should be, according to the rconsole
colors I saved, yellow
Hello Paul.
You could try something like
perc-apply(pwdiff, 1 function(currow){
mean(abs(currow) t, na.rm=TRUE)*100
})
I haven't tested this, as you did not provide a sample pwdiff. You should
probably check ?apply for more info.
Two suggestions: probably best not to name any variable
Dear list,
I have some data on a geneaology, here is a subset:
warmerge[1:11,c(1,6,25)]
Warrior SibID birth.year
11003793 2013 1926
4 2013 2024 1934
10943769 2024 1918
632 2747 2037 1928
176 2083 2039 1944
187 2085 2039 1949
Hey,
Here is a snippet that generated a boxplot and separates points so that
they do not overlap. I have a problem to avoir text overlapping. Any
help would be helpful.
attach(InsectSprays)
boxplot(count ~ spray, data = InsectSprays, outpch = NA)
stripchart(count ~ spray, data =
Hi:
In addition, the sos package is useful when you need to search for a function:
# install.packages('sos')
library(sos)
findFn('augmented Dickey-Fuller')
The results are sent to a Web page - this search identified the
adf.test() in the tseries package and the ur.df() function in the urca
Look at the spread.labs function in the TeachingDemos package or the
spread.labels function in the plotrix package.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of David martin
Sent: Friday, June 24, 2011 8:07 AM
To:
Hi,
I would like to know how to capture the console output from running an
algorithm for further analysis. I can capture this using capture.output() but
that yields a character vector. I would like to extract the actual numeric
values. Here is an example of what I am trying to do.
fr -
try this:
fr - function(x) { ## Rosenbrock Banana function
+on.exit(print(f))
+x1 - x[1]
+x2 - x[2]
+f - 100 * (x2 - x1 * x1)^2 + (1 - x1)^2
+f
+ }
fvals - capture.output(ans - optim(c(-1.2,1), fr))
# convert to numeric
fvals - as.numeric(sub(^.* , , fvals))
fvals
Solved it:
oldest-unlist(tapply(warmerge$birth.year, warmerge$SibID,function(x)
ifelse (x==min(x, na.rm=T)|is.na(x)==T,1,0)))
-
Corey Sparks, PhD
Assistant Professor
Department of Demography and Organization Studies
University of Texas at San Antonio
501 West Durango Blvd
Monterey
There are a couple of ways to do this. You can open a plotting window before
using barplot2. If you are running R on Windows, help(windows) for how to
change the plotting window dimensions (or help(quartz) for Mac, help(X11)
for linux).
The second method is to change the margins in the current
Dear useRs,
I am using the gamm function in the mgcv package to model a smooth relationship
between a covariate and my dependent variable, while allowing for
quantification of the subjectwise variability in the smooths. What I would
like to do is to make subjectwise predictions for plotting
One possibility involves applying a regular expression via gsub:
as.numeric(gsub(^\\[1\\] ,,fvals))
On Friday 24 June 2011 14:39:31 Ravi Varadhan wrote:
Hi,
I would like to know how to capture the console output from running an
algorithm for further analysis. I can capture this using
Hi:
In addition to Sarah's comments, perhaps this has been implemented by
someone in one of the Bioconductor packages. If you are inclined
towards genomics applications, the Bioconductor list is probably more
useful. See
http://www.bioconductor.org/help/mailing-list/
for further details.
HTH,
On Jun 24, 2011, at 10:07 AM, David martin wrote:
Hey,
Here is a snippet that generated a boxplot and separates points so
that they do not overlap. I have a problem to avoir text
overlapping. Any help would be helpful.
attach(InsectSprays)
boxplot(count ~ spray, data = InsectSprays,
Is this doing what you want? It's going from the raw data not the list
===
library(reshape2)
# sample data.frame
xx -structure(list(Warrior = c(3793L, 2013L, 3769L, 2747L, 2083L,
2085L, 2086L, 2556L, 2050L, 2158L, 3045L), SibID =
Is this doing what you want? It's going from the raw data not the list
===
library(reshape2)
# sample data.frame
xx -structure(list(Warrior = c(3793L, 2013L, 3769L, 2747L, 2083L,
2085L, 2086L, 2556L, 2050L, 2158L, 3045L), SibID =
Thank you very much, Jim. That works!
I did know that I could process the character strings using regex, but was also
wondering if there was a direct way to get this.
Suppose, in the current example I would like to obtain a 3-column matrix that
contains the parameters and the function
Hi:
That leaves open several possibilities. Could you please supply a
small, reproducible example (i.e., one that someone can copy and paste
into an R session) that illustrates the problem along with the
solution you expect?
TIA,
Dennis
On Fri, Jun 24, 2011 at 2:30 AM, Salih Tuna
Try using dput(f) instead of print(f) and
use eval(parse(text=capture.output(...))).
I would tend to use something like
OUTPUTS - list()
fr - function(x) {
on.exit(OUTPUTS[[length(OUTPUTS)+1]] - list(x=x,f=f))
... compute and return f
}
so you don't have to use
Sophie,
I'm myself quite new to linear mixed effect models, but PresenceAbsence
sounds like
a binary response variable. So wouldn't be
m1-lmer(Presencebsence~Habitatype*Width+(1|Sitename),familiy=binomial)
the first thing to try? There is also a special mailing list for linear -
mixed
Here is one approach (different from capture.output) that I believe
accomplishes what you are trying to do:
frtop - function(){
out - numeric(0)
topenv - environment()
fr - function(x) { ## Rosenbrock Banana function
x1 - x[1]
x2 - x[2]
On Jun 24, 2011, at 11:10 AM, Ravi Varadhan wrote:
Thank you very much, Jim. That works!
I did know that I could process the character strings using regex,
but was also wondering if there was a direct way to get this.
Suppose, in the current example I would like to obtain a 3-column
Ravi,
Consider using an environment (i.e. a 'reference' object) to store the
results, avoiding string manipulation, and the potential for loss of
precision:
fr - function(x, env) { ## Rosenbrock Banana function
x1 - x[1]
x2 - x[2]
f - 100 * (x2 - x1 * x1)^2 + (1 - x1)^2
http://www.r-project.org/
Manuals Introduction to R
This is not a homework forum. If you are in the middle of a problem, have a
very specific R problem and clearly have done your work come back and ask
for help
--- On Fri, 6/24/11, Edward Bowora n.bow...@gmail.com wrote:
From: Edward
Given that you don't have huge numbers of subjects you could fit the
model with `gam' rather than `gamm', using
out.gamm - gam( Y ~ Group + s(X, by=Group) + s(Subject,bs=re),
method=REML)
Then your predictions will differ by subject (see e.g. ?random.effects
for a bit more
On 2011-06-24 08:00, David Winsemius wrote:
On Jun 24, 2011, at 10:07 AM, David martin wrote:
Hey,
Here is a snippet that generated a boxplot and separates points so
that they do not overlap. I have a problem to avoir text
overlapping. Any help would be helpful.
attach(InsectSprays)
If you don't want the information as character, why are you printing it
rather than storing it in a matrix?
Why not something along the lines of this...
fr - function(x) { ## Rosenbrock Banana function
on.exit(aMatrix - rbind(aMatrix,(cbind(x1, x2, f
x1 - x[1]
x2 - x[2]
f -
I did think of this solution, Keith, but I am generally uncomfortable (may be
paranoid is a better word) with the use of `-'. Perhaps, my fear is
unjustified in this particular situation.
Thanks,
Ravi.
---
Ravi Varadhan, Ph.D.
Assistant
On Jun 24, 2011, at 11:27 AM, Matt Shotwell wrote:
Ravi,
Consider using an environment (i.e. a 'reference' object) to store the
results, avoiding string manipulation, and the potential for loss of
precision:
fr - function(x, env) { ## Rosenbrock Banana function
x1 - x[1]
x2 - x[2]
On Fri, Jun 24, 2011 at 11:10 AM, Ravi Varadhan rvarad...@jhmi.edu wrote:
Thank you very much, Jim. That works!
I did know that I could process the character strings using regex, but was
also wondering if there was a direct way to get this.
Suppose, in the current example I would like to
On Fri, 2011-06-24 at 12:09 -0400, David Winsemius wrote:
On Jun 24, 2011, at 11:27 AM, Matt Shotwell wrote:
Ravi,
Consider using an environment (i.e. a 'reference' object) to store the
results, avoiding string manipulation, and the potential for loss of
precision:
fr -
Hi guys,
let's assume i havethe following
1
x = 2
6
5
1 4
y = 3 5
8 10
i want the code to report back 1, 2 and 5 from x.
Basically it shopuld check whether each elements of x falls in the range of
each row of x. 1 and 2 falls in between 1-4 and 5 falls in
On Fri, Jun 24, 2011 at 11:16 AM, William Dunlap wdun...@tibco.com wrote:
Try using dput(f) instead of print(f) and
use eval(parse(text=capture.output(...))).
I would tend to use something like
OUTPUTS - list()
fr - function(x) {
on.exit(OUTPUTS[[length(OUTPUTS)+1]] -
Hi
I'm having some difficulty understanding my output (below) from GEE. the
person who wrote the program included some comments about the '3-th term
gives diff between hyp/ox at time..', and after created an L vector to use
for a WALD test. I was wondering if someone could help me understand
Dear R users,
I am a new R user and not very experienced in Statistics. I would like to
regress a time series variable y on several other time series variables x. I
read that the Kalman Filter would provide me with a better fit for my
estimation. However, I have no idea how to translate this
Hello,
I am using function lmodel2 to calculate RMA regression between
life-history traits in ladybirds beetles. It works well but I am not able
to plot an RMA regression line on the scatterplot of my data. I am of
course unable to plot the confidence intervals. For ordinary least square
I have taught myself R over the last few months and I learned quite a bit
from reading the PDFs that accompany each package, articles on the R Journal
(http://journal.r-project.org/) that cover similar problems to mine, and by
asking specific questions about code to this list. I also search online
Thanks, that solves/explaines the problem. It occured when running
regressions on subsets where some levels even hade zero observations. Didn't
check that.
Oyvind
--
View this message in context:
http://r.789695.n4.nabble.com/Error-using-betareg-tp3621955p3622614.html
Sent from the R help
Thanks for your reply, but that is not quite what I am looking for...I do not
want to add up all the values in the row, I want to get the number of
columns in each row that meet the criteria and then get that as a
percentage
my understanding is that the rowSums function adds up the values
Thank you for your help, David.
This is what I needed!
--
View this message in context:
http://r.789695.n4.nabble.com/help-subtitles-for-multiple-charts-tp3620453p3622926.html
Sent from the R help mailing list archive at Nabble.com.
__
On 2011-06-24 09:52, Salih Tuna wrote:
Hi guys,
let's assume i havethe following
1
x = 2
6
5
1 4
y = 3 5
8 10
i want the code to report back 1, 2 and 5 from x.
Basically it shopuld check whether each elements of x falls in the range of
each row of
Hi
I am very new to R, I am attempting to produce a monthly boxplot with the
following fish thermal telemetry data:
ID TempDate.Time Month.Year Month Week Shortdate
1 1734 4.4140 04/05/2010 11:5605,2010 May 19 04/05/2010
2 1734 4.1002 04/05/2010 12:0605,2010 May
Thank you so much for that. I now have this graphs, by using these commands
*p=ggplot(data = test, aes(x = YEAR, y = TOTAL, colour = TREATMENT)) +
geom_point() + geom_smooth(method = lm, se=FALSE) + facet_wrap(~COUNTRY)
p +scale_x_continuous(limits=c(1,4))*
This needs to be made reproducible. In other words it would be
helpful if you would use dput to share the data.
dput(Good)
copy the output to the email in this format
x - ()
with the output from dput inside the ()
then write the code for ggplot under this line so that we can then
just
Hi:
Not much different from Peter's approach, but here's another try:
v - c(1, 2, 6, 5)
w - matrix(c(1, 4, 3, 5, 8, 10), ncol = 2, byrow = TRUE)
w
[,1] [,2]
[1,]14
[2,]35
[3,]8 10
f - function(x) v[which(v = x[1] v = x[2])]
unlist(apply(w, 1, f))
[1] 1 2 5
If you
aa file isï¼
x 1 NA 2
y 1 NA 3
and r program is
aa-read.table(aa,row.names=1)
bb-cor(t(aa),method = pearson,use=pairwise.complete.obs)
bb
x y
x 1 1
y 1 1
i am confused why the pearson correlation coefficients between x and y is 1
[[alternative HTML version deleted]]
Hi,
Thanks for your speedy reply! The file is pretty big (I have 18,000
datapoints), there is not enough room on the r screen for the entire output
so I have just cut out a few lines from the end of the dput . I dont know if
that helps?
X -(12L, 12L, 12L, 12L, 12L, 12L, 12L, 12L, 12L, 12L, 12L,
On Fri, 24 Jun 2011, wang peter wrote:
aa file is：
x 1 NA 2
y 1 NA 3
and r program is
aa-read.table(aa,row.names=1)
bb-cor(t(aa),method = pearson,use=pairwise.complete.obs)
bb
x y
x 1 1
y 1 1
i am confused why the pearson correlation coefficients between x and y is 1
You have two
On Jun 24, 2011, at 1:58 PM, wang peter wrote:
aa file is：
x 1 NA 2
y 1 NA 3
and r program is
aa-read.table(aa,row.names=1)
bb-cor(t(aa),method = pearson,use=pairwise.complete.obs)
bb
x y
x 1 1
y 1 1
i am confused why the pearson correlation coefficients between x and
y is 1
Hi thanks for your patience, I understand what you mean now. I made some
dummy data;
x-(structure(list(ID = c(1734L, 1734L, 1734L, 1734L, 1734L, 1734L,
1734L, 1734L, 1734L, 1734L, 1734L, 1734L, 1734L, 1734L, 1734L,
1734L, 1734L, 1734L, 1734L, 1734L, 1734L, 1734L, 1734L, 1734L,
1734L, 1734L,
Try this out. The Date.Time variable was not a date class. str() is
your friend.
#
library(ggplot2)
x - (
structure(list(ID = c(1734L, 1734L, 1734L, 1734L, 1734L, 1734L,
1734L, 1734L, 1734L, 1734L, 1734L, 1734L, 1734L,
Dear all,
I have the following problem. I have a List of time series dataframe.I'm
trying to produce specific graph for each element of my list. The code is:
This is my list:
Lista_import-lapply(Lista_import, function(x){
x2-subset(x, select=c(ANNO,DICHIARANTE,PARTNER, quota))
x2-cast(x2,
On 6/22/2011 2:28 PM, Alexander Shenkin wrote:
On 6/22/2011 4:09 PM, Brian Diggs wrote:
On 6/22/2011 1:37 PM, Alexander Shenkin wrote:
On 6/22/2011 3:34 PM, Brian Diggs wrote:
On 6/22/2011 12:09 PM, Luke Miller wrote:
For what it's worth, I cannot reproduce this problem under a nearly
Hi:
Here are a couple of places to start:
http://www.jstatsoft.org/v39/i02/paper
http://stats.stackexchange.com/questions/4296/r-code-for-time-series-forecasting-using-kalman-filter
HTH,
Dennis
On Fri, Jun 24, 2011 at 6:24 AM, Patrick patrick88mau...@gmail.com wrote:
Dear R users,
I am a
On 06/24/2011 11:12 AM, Dennis Murphy wrote:
Hi:
Not much different from Peter's approach, but here's another try:
v- c(1, 2, 6, 5)
w- matrix(c(1, 4, 3, 5, 8, 10), ncol = 2, byrow = TRUE)
w
[,1] [,2]
[1,]14
[2,]35
[3,]8 10
f- function(x) v[which(v= x[1] v=
Passing in two dates to a sql statement (sqldf). Is returning a factor. Tried
setting back to a Date via as.Date, but get an error the error: character
string is not in a standard unambiguous format. Any thoughts appreciated.
Code/Results listed below:
summary(df.possible.combos)
Date
1 - 100 of 110 matches
Mail list logo
