AJ: This is something to learn a lesson from. A question, starved of
preparation, can't help anybody to help you.
James
On Mar 25, 2012 9:00 PM, Rolf Turner rolf.tur...@xtra.co.nz wrote:
On 26/03/12 00:18, Anjana Thampi wrote:
How do you decompose inequality in R, say by gender?
This has
Hi
I have records like like this
X1 X2 State
34 72 state1
9 63 state1
49 31 state1
60 34 state1
80 73 state1
60 20 state2
59 87 state2
88 20 state2
71 66 state2
65 56 state2
59 16
Hello helpful R folks,
I am simply trying to graph a quarter circle centered at the origin in the
first quadrant. When I set the xlim of the plot to the radius of the
circle, the plot appears correct. However, I'd like to see a slight
extension of the axes beyond the domain of the function
Another approach:
foo - function(t){
bm - ceiling(t/15)
s - cut(t,breaks=15*(0:bm),labels=1:bm)
s - as.numeric(levels(s)[s])
t^(s+1)
}
This idea can be generalised .
cheers,
Rolf Turner
On 27/03/12 15:31, R. Michael Weylandt wrote:
On Mon, Mar 26, 2012 at 07:48:07PM -0400, Aimee Jones wrote:
Dear all,
I'm aware if y has two separate functions (depending on the conditions
of x) you can use the ifelse function to separate y into two separate
functions depending on input. How do you do this if there a multiple
different
On 2012-03-26 05:09, John D. Muccigrosso wrote:
I cannot for the life of me figure this out:
What's the parameter to fill in with color circles made with
circles()? col changes the line color, but all I see in the help is a
reference to additional graphic parameters, and no examples via google.
Strassburger, Daniel Daniel_Strassburger at baylor.edu writes:
I haven't been successful in converting my colleagues to the world of R yet
they wish to share collected data
so that they may analyze it in SPSS.
I know how to write to an SPSS file and it opens fine, but my problem is that
it
Dear all,
Novice in statistics.
I have 2 experimental conditions. Each condition has ~400 points as its
response. Each condition is done in 4 repereats (so I have 2 x 400 x 4
points).
I want to compare the means of two conditions and test whether they are same
or not. Which test should I use?
Dear all,
I am novice in statistics.
I have two matrices (results from my experiments), each having ~400 point. I
want to test whether the points come from a same distribution or not.
Further, I have the results for each matrix (each experiment) in 4
replicates. What should I do?
# Repeats of
Dear Chad,
your problem is linked to (1) the function returning NaNs from x values
greater than 50, and (2) the fact that the function is estimated on a
predefined number of points.
Calling plot for a function object is basically a wrapper for curve(). Your
function g() is evaluated on the
On Mar 26, 2012, at 17:33 , David Winsemius wrote:
The usual approach to that problem is to use sapply:
x - list()
x - sapply(1:10, function(z) x[[z]] - 1:z )
Yikes!
If that works, it is only by coincidence (The pre-assignment to x only
serves the purpose of allowing the
Thank you so much, Jessica,
The specific of my case is that I have a very detailed variable 'Interests'
which may have several thousands of possible values. Usually each customer has
3-10 different interests. For example:
customer_id|...|interests
1001 |...| cycling, swimming, cooking
Hi All,
Here is the case. I want to build classification model (SVM). Some of variables
for this model are categorical attributes which represent words (usually 3-10
words - query for search in google). For example:
search_id | query_words|..| result
Thanks, I had totally missed this controversy but from quick read of summary
the impact on open source analysis was unclear.Can you explain the punchline? I
think many users of R have concluded the biggest problem in most analyses
isfirst getting the data and then verfiying any results you
Hi Agnes and Camille (and help-list),
In Ubuntu 11.10 I needed to use su permissions to copy and gzip the *.afm
files manually into /usr/lib/R/library/grDevices/afm/ to get the Arial
embedding to work in R for postscript.
Ie. after following the instructions by Agnes and Camille, I did
sudo
Dear R-help,
My dataset (which is a data frame, called 'Calender' here) includes 365
rows representing 365 days for a year. One column ('Season')contains
factor data representing seasons, e.g. spring, summer, autumn and winter.
Another column (called 'Day') contains data representing wether the
Hello Tal,
I have the same problem with the ' added to all my cells when exported into
Excel.
I can drop them manually but only one by one (the Find Replace does not
work) ... So finally the exported Excel file can actually not be used by
scientists to draw graphs or whatever!
Did you find a
Hi,
I'm working with a legacy R script which makes use of the
download.file command. We're having a problem that occasionally we get a
time out from a particular FTP site but the function that does this
doesn't pass that information back to the main function that calls it.
I'm aware that it
Dear All,
I have a dataset of eight variables with 156 records which I wish to
discretize using the MDLP algorithm. My issue is that I want to dictate the
number of bins the algorithm splits the data into (around 5), rather than
just allowing the algorithm to dictate this using the mdlp(data)
Hi HJ,
Take a look at ?; this is probably what you're looking for.
What you could also do is:
Calender[Calender$Day=='Wd' Calender$Season==Winter, ] # notice the
last comma
This will subset directly without using which(); it might be helpful to you.
HTH,
Ivan
--
Ivan CALANDRA
Université
Why not use 'split' and get all the groups at once:
result - split(Calandra, list(Calandra$Day, Calandra$Season, drop = TRUE)
On Tue, Mar 27, 2012 at 7:43 AM, Ivan Calandra
ivan.calan...@u-bourgogne.fr wrote:
Hi HJ,
Take a look at ?; this is probably what you're looking for.
What you could
I don't see any problem here; there is no data and no indication as to
the actual problem you are having that is causing a Find Replace. I
export to Excel all the time and don't have any problems. So provide
some data and an indication of the problem.
On Tue, Mar 27, 2012 at 4:37 AM, Juliette
Dear R-help,
I am using R 2.14.1 on Windows 7 with the 'gfcure' package (cure rate model).
I have included the treatment variable in the cure part of the model as shown
below:
Ø ref_treat -
Thanks Henrique...
giving it a try now, but it'll take a good while, given the file size.
Cheers,
b
On 27 March 2012 02:35, Henrique Dallazuanna www...@gmail.com wrote:
Benilton,
Try this:
read.table(textConnection(gsub(',', ',', gsub('^\|\$', ',
readLines('../teste.csv', sep = ',',
On 27/03/12 01:09, Benilton Carvalho wrote:
I need to read in csv files, created by 3rd party, with fields
containing single quotes (as shown below).
header1,header2,header3,header4
field1r1,field2r1,field3r1,field4r1
field1r2,field2r2,field3r2PartA), field3r2PartB Very Long,field4r2
Right,
I was also thinking about it, but since I have few thousands of unique words I
'm not quite sure how it will work
I just posted my question with more detailed description here:
http://stats.stackexchange.com/questions/25355/multi-value-categorical-attributes-how-r
Really interesting case
All:
I am using RSqlite and want to be able to update individual values in a
record, such as with this simple example:
library(RSQLite)
drv-dbDriver(SQLite)
con-dbConnect(drv,test.db)
my.data-data.frame(countries=c(US,UK,Canada,Australia,NewZealand),vals=c(52,36,74,10,98))
Hm.. so what you need is either
- one new feature for each activity that has a binary value
e.g.:
cust_id , cycling, swimming, cooking
1001 , 1 , 0, 1
- one new feature that has a value corresponding to a certain combination of
activities
so if you had just the
Dear R-help,
I am trying to express myself as best as I can here. If you also use Latex
to edit math reports or other languages with similar editing method,
you'll see what I'm talking about. My sincere appologies if my question is
not clear enough to some extend, as also I'm not able to provide
Hi Jim!
Thank you so much for the very helpful hints!!
I am learning 'split' now and it seems very useful..
HJ
On Tue, Mar 27, 2012 at 12:58 PM, jim holtman jholt...@gmail.com wrote:
Why not use 'split' and get all the groups at once:
result - split(Calandra, list(Calandra$Day,
Thanks guys for all the replies.
It is an urban myth that using 'apply' functions will deliver better
performance than 'for' loops. It may even worsen performance or create
obstacles when it is improperly used with dataframes. Most of the
benefits come from improving readability and
You probably want:
sql-UPDATE testtable SET vals=21 WHERE countries='NewZealand'
dbGetQuery(con, sql)
instead...
b
On 27 March 2012 14:18, Thomas Adams thomas.ad...@noaa.gov wrote:
All:
I am using RSqlite and want to be able to update individual values in a
record, such as with this
Hi, HJ,
see
?plotmath
Hth -- Gerrit
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Liebig-University Giessen
Tel: +49-(0)641-99-32104 Arndtstr.
Benilton,
*
*
*Thank you you are quite right!!*
*
*
*Regards,*
*Tom
*
On Tue, Mar 27, 2012 at 9:35 AM, Benilton Carvalho
beniltoncarva...@gmail.com wrote:
You probably want:
sql-UPDATE testtable SET vals=21 WHERE countries='NewZealand'
dbGetQuery(con, sql)
instead...
b
On 27 March
:)
yes! I agree!
On Mon, Mar 26, 2012 at 10:51:17AM -0700, Bert Gunter wrote:
Fortunes candidate?!
-- Bert
On Mon, Mar 26, 2012 at 10:24 AM, Sarah Goslee sarah.gos...@gmail.com wrote:
The OP wrote
The problem is that it gives the result that I want.
Sarah's reply: That's a new sort
No idea what a mean median histogram is but you may wish to check
out ?tapply or library(plyr), both of which are designed for this
split-apply-combine paradigm.
Michael
On Tue, Mar 27, 2012 at 12:51 AM, arunkumar akpbond...@gmail.com wrote:
Hi
I have records like like this
X1 X2
Hello,
I am new at using R.
I would like to use the following functions of the clim.pact package:
ncdfcont and retrieve.nc
I have installed the package clim.pact in Rstudio.
I have downloaded the ncdf pack from unicar (including ncdump and ncgen).
The ncdf file I'm working on is called
Hello,
I have been attempting to set up a lme and have looked at numerous posts
including 'R's lmer cheat-sheet' as well as reading a number of papers and
other resources including R help, but I am still a little confused on how to
write my model (I thought I had it).
I have asked a number of
HI all,
I am planning to get Zuur et al.'s new book when it comes out, but until
then I was wondering if anyone could suggest examples of zero inflated or
hurdle GAMMs. I have count data with many zeros, non-linear relationships,
and site as a random effect.
Thank you!
Bert Harris, University of
Thank you for the modified script! I have now tried on different datasets
and it works very well and is dramatically faster than my original script!
I really appreciate the help.
Kurinji
On Fri, Mar 23, 2012 at 1:33 PM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
Taking a look at
Hello Mike,
I don't think I did, but I fixed the issue by loading each package before
use. The second issue was solved by removing a variable that was used to
create two other categorical variables. I think it must have been
recognising this.
Thanks for the help.
--
View this message in
*I'm still a R noob, just had a couple of lectures about it in our research
master.
There is a Deal or no deal experiment where I have to write some code for.
Someone wrote a website to gather the data and write it in a .xlsx file.
These are seperate files for seperate participants so first I
Hello,
I encountered a situation similar as the one described by Tal above :
I use the RODBC library to export multiple dataframes into different sheets
of an Excel file.
My dataframes contain Character, Date and Numeric columns.
library(RODBC)
channel - odbcConnectExcel(xls.file = myXlsFile,
On Mar 27, 2012, at 3:37 AM, peter dalgaard wrote:
On Mar 26, 2012, at 17:33 , David Winsemius wrote:
The usual approach to that problem is to use sapply:
x - list()
x - sapply(1:10, function(z) x[[z]] - 1:z )
Yikes!
If that works, it is only by coincidence (The pre-assignment to
Good Afternoon,
I believe that my to the problem, the R has a more effective solution.
in place the use the loop
I have the following set of data, and needs to extract some sections.
user poscommunications source v_destine
7 1 109 2222
7 2 100 22
Hi,
I have similarity value between string pairs in a mysql database.
I need to construct the distance matrix which hclust can take and cluster
the strings. Most of the examples I came across show how to construct the
distance matrix using dist function.
How can I code to construct distance
In the package lasso2, there is a Prostate Data. To find coefficients in the
prostate cancer example we could impose L1 constraint on the parameters.
code is:
data(Prostate)
p.mean - apply(Prostate, 5,mean)
pros - sweep(Prostate, 5, p.mean, -)
p.std - apply(pros, 5, var)
pros -
On Mar 27, 2012, at 9:39 AM, Gerrit Eichner wrote:
Hi, HJ,
see
?plotmath
Hth -- Gerrit
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
On Tue, 27 Mar 2012, HJ YAN wrote:
Dear R-help,
I am
You should use mixed effects modeling to analyze data of this sort.
This is not a topic that has generally been covered by introductory
classes, so you should consult with a professional statistician on
your problem, or educate yourself well beyond the novice level (this
takes more than just
The title() function also has parameter 'line' where you can specify the
margin line in which the text should be displayed.
How many lines of margin should be around the figure region of the plot
can be specified before plotting by par(mar=c(bottom,left,top,right)),
in text lines. margin lines are
Guys, let me add my 5 coins into your interesting discussion.
I have ~10Gb txt file with train data for my model. It has about 150 millions
rows for 12 variables.
When I load it into memory (just run only one row!):
train-read.table(file=/training.txt)
while loading it takes ~28Gb of RAM (It
I realised that I removed the link to the question but forgot to remove the
text regarding it. Sorry. I am not sure if I am supposed to link to other
forums, but I can add the links as needed (as the format is clearer).
I actually have one more question though in regards to which data to use.
If
Note that you can actually drop the line defining the big list x. I
thought it would be needed, but it turns out to be unnecessary after
cleaning up the second half: cutting off that allocation might save
you even more time.
Best,
Michael
On Tue, Mar 27, 2012 at 11:14 AM, Kurinji Pandiyan
Hello,
this code, works perfectly
temp - merge(travel, city, by.x=Source, by.y=cod)
result - merge(temp, city, by.x=Destine, by.y=cod)
The problem was the construction of the data frame, had a parenthesis in
city-rbind(city,data.frame(city=Lisbon,cod=3))),
I tried to delete the post,
yet another way:
city-data.frame(city=Barcelona,cod=1)
city-rbind(city,data.frame(city=Madrid,cod=2))
city-rbind(city,data.frame(city=Lisbon,cod=3))
city-rbind(city,data.frame(city=Milan,cod=4))
city-rbind(city,data.frame(city=London,cod=5))
travel-data.frame(pos=1,Source=1,Destine=2)
Ah, thanks. I am new to R and was unaware of the from/to parameters for
the plot function. I thought xlim and ylim served that purpose. Thanks
again!
-Chad
On Tue, Mar 27, 2012 at 3:31 AM, Matthieu Dubois matth...@gmail.com wrote:
Dear Chad,
your problem is linked to (1) the function
It's really not suggested etiquette to thread-jack, but generally, the
more you can tell to read.table (particularly the colClasses, nrows,
as.is, and stringsAsFactors arguments) the faster it will be able to
read things by skipping various necessary checks.
Michael
On Tue, Mar 27, 2012 at 12:07
I'm trying to make a glmm to identify the relationship between insect
species richness with fragment size, isolation and time (different years).
I already tried to analyse it using poisson distribution error, but I
always face with the following warning:
*glm.fit: fitted probabilities numerically
Dear All,
How do I ignore an error and still getting result of next iteration.
I am trying to do wilcox.test on a loop, when the test fail, I would like to
continue doing the next iteration and getting the p-value.
I tried to do tryCatch or try but I cannot retrieve the p-value if the test is
Hi,
your code has errors: apply function only has 1 or 2 as margin.
bound is used as turning parameter for summation of absolute
coefficients. lasso runs on a grid of the turning parameter for
varying strength of shrinkage. so each turning value may yield
different sets of coefficients and
Hi,
I'm afraid that the function read.octave from package foreign has
some problems with the ASCII data format exported by new versions of
Octave (later than 3.2.X). It fails even for a simple case as:
[Octave code:]
octave:1 x=1;
octave:2 save -ascii testdata.mat x
[Now in R:]
octavedata -
Inline:
On Tue, Mar 27, 2012 at 10:00 AM, Weidong Gu anopheles...@gmail.com wrote:
Hi,
your code has errors: apply function only has 1 or 2 as margin.
FALSE. Please re-read the Help files. It works as expected with
arbitrary higher dim arrays.
-- Bert
bound is used as turning parameter
Sorry last message was not completed before sending
Please below
On Tue, Mar 27, 2012 at 5:36 PM, HJ YAN yhj...@googlemail.com wrote:
Thank you very much Gerrit, for the nice hints!
Just done some more googling and reaserches on this and trying to
answering it myself...
Below is
Hi,
I used
GDALinfo(MOD13Q1.A2001049.h13v11.005.2007002215512.250m_16_days_EVI.tif)
and
got the results:
rows10
columns 11
bands 1
origin.x150701.4
origin.y7744897
res.x 250
res.y 250
ysign -1
oblique.x 0
oblique.y 0
Hello,I am trying to install a newer version of R (R 2.14.2) from this
linkhttp://cran.r-project.org/bin/macosx/
However I am getting an error that it can not be installed on my computer. My
Mac is version 10.6.8. Can you please advise me what the problem. I need the
newer version to install
On Mar 27, 2012, at 12:56 PM, C Lin wrote:
Dear All,
How do I ignore an error and still getting result of next iteration.
I am trying to do wilcox.test on a loop, when the test fail, I would
like to continue doing the next iteration and getting the p-value.
I tried to do tryCatch or try
Hello,
I'm new here, but will try to be as specific and complete as possible. I'm
trying to use âlmâ to first estimate parameter values from a set of
calibration measurements, and then later to use those estimates to calculate
another set of values with âpredict.lmâ.
First I have a
Hi,
On Tue, Mar 27, 2012 at 10:35 AM, yx78 yangx...@gmail.com wrote:
In the package lasso2, there is a Prostate Data. To find coefficients in the
prostate cancer example we could impose L1 constraint on the parameters.
code is:
data(Prostate)
p.mean - apply(Prostate, 5,mean)
pros -
Hello to everyone.
I´m using this function to download some information from a website.
This is the URL:
http://164.77.222.61/climatologia/php/vientoMaximo8.php?IdEstacion=330007FechaIni=01-1-1980
If you go to that website you´ll find a table with meteorological
information. One column is called
Hello,
I am having trouble figuring out how to convert a Day of Year integer
back into a Date format. For example I have the following:
date -
c('2008-01-01','2008-01-02','2008-01-03','2008-01-04','2008-01-05','2008-01-06','2008-01-07',
As a matter of fact, I did read the FAQ. However, in the FAQ coef() is used to
return the coefficients of lm() if it succeeded.
I cannot find similar function for pvalue.
CC: r-help@r-project.org
From: dwinsem...@comcast.net
To: bac...@hotmail.com
Subject: Re: [R] ignore error getting
On 27-03-2012, at 19:24, Nederjaard wrote:
Hello,
I'm new here, but will try to be as specific and complete as possible. I'm
trying to use “lm“ to first estimate parameter values from a set of
calibration measurements, and then later to use those estimates to calculate
another set of
On Mar 27, 2012, at 2:18 PM, C Lin wrote:
As a matter of fact, I did read the FAQ. However, in the FAQ coef()
is used to return the coefficients of lm() if it succeeded.
I cannot find similar function for pvalue.
So your question has nothing to do with the subject line? If you are
trying
There may very well be a better solution, but this works.
format(strptime(dayofyear, format=%j), format=%m-%d)
On Tue, Mar 27, 2012 at 11:12 AM, Sam Albers tonightstheni...@gmail.comwrote:
Hello,
I am having trouble figuring out how to convert a Day of Year integer
back into a Date format.
Hi,
On Tue, Mar 27, 2012 at 1:03 PM, Heba S abehsun...@hotmail.com wrote:
Hello,I am trying to install a newer version of R (R 2.14.2) from this
linkhttp://cran.r-project.org/bin/macosx/
However I am getting an error that it can not be installed on my computer. My
Mac is version 10.6.8.
I'm sorry. I do appreciate you are trying to help. However, what I am trying to
do is not exactly the same as in FAQ.
If I do the following:
test2=list(numeric(0),c(10,20));
test1=list(c(1),c(1,2,3,4));
for (i in 1:2){
tryCatch(wilcox.test(test1[[i]],test2[[i]]),error = function(e) NULL);
}
On Mar 27, 2012, at 2:36 PM, C Lin wrote:
I'm sorry. I do appreciate you are trying to help. However, what I
am trying to do is not exactly the same as in FAQ.
If I do the following:
test2=list(numeric(0),c(10,20));
test1=list(c(1),c(1,2,3,4));
for (i in 1:2){
R tries hard to keep you from committing scientific abuse.
As stated, your problem seems to me akin to
1. Given that a man's age can be modelled as a function
of the grayness of his hair,
2. predict a man's age from the temperature in Barcelona.
Your calibration relates 'abs' and 'conc'.
Hi,
On Tue, Mar 27, 2012 at 6:05 AM, Alekseiy Beloshitskiy
abeloshits...@velti.com wrote:
Hi All,
Here is the case. I want to build classification model (SVM). Some of
variables for this model are categorical attributes which represent words
(usually 3-10 words - query for search in
FORTUNE!!!
-- Bert
On Tue, Mar 27, 2012 at 11:44 AM, Peter Ehlers ehl...@ucalgary.ca wrote:
R tries hard to keep you from committing scientific abuse.
As stated, your problem seems to me akin to
1. Given that a man's age can be modelled as a function
of the grayness of his hair,
2.
test2=list(numeric(0),c(10,20));
test1=list(c(1),c(1,2,3,4));
for (i in 1:2){
tryCatch(wilcox.test(test1[[i]],test2[[i]]),error = function(e) NULL);
}
I cannot get the p-value of the test for i=2.
You didn't store the results of wilcox.test anywhere.
First make it work for data that
R tries hard to keep you from committing scientific abuse.
As stated, your problem seems to me akin to
1. Given that a man's age can be modelled as a function
of the grayness of his hair,
2. predict a man's age from the temperature in Barcelona.
Your calibration relates 'abs' and 'conc'.
Hello,
I am modelling positive continuous data (including zeros) using the ZAGA
distribution in GAMLSS and want to use the model for predictions. My final
model includes smoothers (pb()) for the mu and nu parameter.
First, I blindly used the default options for predictions but noticed that I
I wrote in my previous message the following Octave code:
[Octave code:]
octave:1 x=1;
octave:2 save -ascii testdata.mat x
Forget the -ascii. It should be -text or nothing (-text is the
default).
By the way, read.octave() does not really fail (it does return a
value), but the result is somewhat
Hello Dr. Winsemius,
Not sure how or if the use of NAs you describe applies to my case. I'll go back
to this again when the ggplot2 book arrives. It may be that this will provide a
helpful insight then.
Thanks,
Paul
--- On Fri, 3/23/12, David Winsemius dwinsem...@comcast.net wrote:
From:
On 27/03/2012 19:30, Justin Haynes wrote:
There may very well be a better solution, but this works.
format(strptime(dayofyear, format=%j), format=%m-%d)
The answer depends on the year (think leap years), so I think you need
strptime(paste(2008, dayofyear), format=%Y %j)
Probably a better
Dear R-helpers
I am wondering if there is an option to the survplot function in the design
package that allows for drawing Kaplan-Meier plots starting from 0 instead of
1, similar like fun = 'event' in the standard plotting function used on a
survfit object.
I apologize in advance for having
hi, I'm a beginner of tcltk packages.
I'm making some gui for some function and want to change the background
color that is grey in default.
anybody who knows the way that changes the color of it plz teach me how to
do that.
Forthemore is there a nice manual for tclck?
Thanks.
--
View this
Lívia Dorneles Audino livia.audino at gmail.com writes:
I'm trying to make a glmm to identify the relationship between insect
species richness with fragment size, isolation and time (different years).
I already tried to analyse it using poisson distribution error, but I
always face with the
I believe it was 2008.
Hadley
On Mon, Mar 26, 2012 at 11:46 AM, Marina Doucerain
marinadoucer...@gmail.com wrote:
Hello,
I'm wondering what was the year (or year range) of collection for the data
included in the 'diamonds' dataset in ggplot2.
This information would be very helpful in
I solved some of my problems, but the one that remains is
that reading the two-dimensional arrays into R transposes the matrix.
The arrays I want to read are unequal interval time multi series with
the first column being the times which are converted in java from
calendar CnYrMoDaHrMnScDCMQ or
On 2012-03-27 15:11, Ben Bolker wrote:
Lívia Dorneles Audinolivia.audinoat gmail.com writes:
I'm trying to make a glmm to identify the relationship between insect
species richness with fragment size, isolation and time (different years).
I already tried to analyse it using poisson
There is a mailing list R-Sig-Geo which is more appropriate for
questions about the rgdal and related packages.
If by read the information GDType you mean to get that Int16
description you can get it by delving into the attributes of the
GDALinfo return value, for example:
f -
It is (at least for me) really unclear what the problem is, or how
it's related to mclapply.
You say
this works fine, except that what I want to get NA's in the return
positions that were not recalculated. then, I can write
newdata$y - ifelse ( is.na(olddata$y), mc.byselectrows( olddata,
Dear R-list,
I'm queering a M$ Access database with the sqlQuery function from the RODBC
library. As I cannot make a working example with a database here is an
illustrative example,
library(RODBC)
mdbConnect-odbcConnectAccess(S:/data/ ... /databse.mdb)
data - sqlQuery(mdbConnect, select id,
I wasn't thinking straight.
old.data= 11:20
recalc.please= (old.data%%2==0)
old.data[recalc.please]
[1] 12 14 16 18 20
new.data[recalc.please]= old.data[recalc.please]^2
Error in new.data[recalc.please] = old.data[recalc.please]^2 :
object 'new.data' not found
# this is where I had given
Dear R,
Thanks for helping me locate the source for the StructTS method from
stats, but I've run in to a roadblock in reverse engineering it to locate a
formula for its forecasting because it calls some compiled C code, a function
called KalmanLike. I've looked through that R library that
Bert,
Try posting on the R-sig-ME list for help with mixed models.
Cheer,
Neil
On Wed, Mar 28, 2012 at 1:16 AM, Bert Harris aramidop...@gmail.com wrote:
HI all,
I am planning to get Zuur et al.'s new book when it comes out, but until
then I was wondering if anyone could suggest examples
Hello,
my idea is to get results like this:
user, sector, source, destine, count, average
7 1 22 22 4 186.25 #
(109+100+214+322)
7 2 161 97 1 68
7 2 97 97
Could you please post a small example of your data and code which gives you
this error. Your assumed error distribution sounds reasonable. I am
interested as to why you have zeros... you have sites with species richness
==0 ??
Lívia Dorneles Audino wrote
I'm trying to make a glmm to
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