I have been using R and SAS from past 6 months and i found a interesting
thing while doing PLS in R and SAS is that when we use NO SCALE option in
SAS and scale=FALSE in R , we see the estimates are matching but if we use
scaling option in SAS and R the estimates differ to greater extent , you can
Hello:
I have so far failed to get Rprofile.site to be processed in R
2.15.0 under Windows 7 as I remember having done it in previous version
of R. For example, I've included "options(max.print=222)" in
"R_HOME/etc/Rprofile.site" (with and without the environmental variable
R_HOME set
This is the R-help list, not the do-your-work-for-you list. Please read the
Posting Guide and:
- use the approved support resources within your educational institution until
you finish your class
- use a sensible subject line
- provide a self-contained example, at least showing how far you got b
Hard to say.. your example is not reproducible. (Study the Posting Guide
mentioned at the end of every message on this list.)
A stab in the dark might be that z$dt is a factor and needs to be converted to
character first. Use the str function to study your data.
-
I forgot to say what 'rmNames' is:
rmNames <- function(x) {x[c(FALSE, x[-1]==x[-length(x)])] <- ""; x}
With
rmNames <- function(x) {x[c(FALSE, x[-1]==x[-length(x)])] <- NA; x}
the option na.blank=TRUE works as expected. Also, the two empty columns are
inserted due to "cgroup", but I don't k
On 02-05-2012, at 22:00, Alex Roth wrote:
> Hello there, I was wondering if you could help me with a quick R issue.
>
> I have a data set where one of the columns has both date and time in
> it, e.g. "12/31/11 23:45" in one cell. I want to use R to split this
> column into two new columns: date
?quantile
HTH,
Jorge.-
On Wed, May 2, 2012 at 7:42 PM, Drew Duckett <> wrote:
> Hi there I am new to R, and I was hoping you guys could help me out. I
> want to make a vector that is: vec(1,2,3,4,5,6,7,8,9,10) and i want to
> create a function called PercentileFinder, that if i plug in
> Perce
Hi Alex,
Here is one way:
s <- "12/31/11 23:45"
strsplit(s, " ")[[1]]
# [1] "12/31/11" "23:45"
*
HTH,
Jorge.-
*
On Wed, May 2, 2012 at 4:00 PM, Alex Roth <> wrote:
> Hello there, I was wondering if you could help me with a quick R issue.
>
> I have a data set where one of the columns has both
Take a look at the quantile function. You can view help by typing
?quantile at the prompt and get interactive examples by typing
example(quantile)
Michael
On Wed, May 2, 2012 at 7:42 PM, Drew Duckett wrote:
> Hi there I am new to R, and I was hoping you guys could help me out. I
> want to make
Hi Mary Ann,
Use (untested) either
# after creating F1.norm
res <- lapply(F1.norm, function(x) c(statistics = x$statistics, p =
x$p.value))
write.table(res, ...)
or
# before creating F1.norm
out <- t(apply(F1.n.mat, 1, function(x){
result <- shapiro.test(x)
c(stat = result$stati
I'd loop (possibly but not necessarily with *apply) over F1.norm and
get the results directly before returning. E.g.,
lapply(F1.norm, function(x) c(x$p.value, x$statistic))
Michael
On Wed, May 2, 2012 at 1:45 PM, Mary Ann Middleton wrote:
>
> Hello,
>
> I have applied the Shapiro test to a matr
You can run multiple regressions at once:
x <- 1:4
y <- x + 10
z <- 0:3
lm(cbind(x,y) ~ z)
Michael
On Wed, May 2, 2012 at 9:48 AM, stella wrote:
> Hi,
>
> How can a function in R handle different types of input?
> I have written a function, which should calculate the slope from several
> 3-time
Dear All,
I have a data sets as shown below A (Patient ID ), B and C are the
Concentration of drug in blood on day 1 and day 4, D is the difference in
conc. To do this in R I have written a code as follows, identified the
number of patients who have more concentration on day 4 . Here I want to
ide
So with case (6) here's the general structure of what I have:
chw = read.table("crac.csv", skip = 1, header = TRUE,
colClasses = rep(c("NULL", NA, "numeric", "NULL"),
c(3, 1, 1, 24)),
sep = ",")
chw$Time.1 = as.POSIXct(chw$Time.1, format = fmt, tz = TZ)
chw = na.omit(chw)
chw = read.zo
Hello,
Far from the "absolute fastest" but apparently portable,
big <- function(con, n, pass=5000){
if(file.exists(con)) unlink(con)
fc <- file(con, "wb")
on.exit(close(fc))
m <- n %/% pass
r <- n %% pass
replicate(m, writeBin(double(pass), fc))
Hi there I am new to R, and I was hoping you guys could help me out. I
want to make a vector that is: vec(1,2,3,4,5,6,7,8,9,10) and i want to
create a function called PercentileFinder, that if i plug in
PercentileFinder (vec, .9) it will give me 9. Creating the function is my
biggest hurdle pleas
Jonathon,
10,000 numbers is pretty small, so I don't think time will be a
big problem. You could write this using writeBin with no problems. For
larger files, why not just use a loop? The writing is pretty fast, so I
don't think you'll have too many problems.
On my machine:
> ptm <- proc
Hello,
knavero wrote
>
> case (6) - regress back to read.table apparently
>
Or to readLines.
tmp <- readLines("http://dl.dropbox.com/u/41922443/test.csv";)
# Why doesn't it work?
sapply(strsplit(tmp, ","), length)
# Don't argue with computers, they don't listen.
tmp <- tmp[-1]
tmp <- str
Hello,
I am using the plot.igraph function in the igraph package to plot a network.
How do I keep vertices from overlapping? One option would be to pass an
argument that restricts vertices to occupy the same coordinates given their
size. A second option would be to increase the area of the plot (a
case (6) - regress back to read.table apparently
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In a time series ts object, like the z1.ts below:
z1 = array(1:235)
z1.ts = ts(z1, frequency =12)
I would like to select only a certain month, for instance the "February"
data
If I transform the data to a matrix, I have the problem that 235 is not
a multiple of 12
I do not like to cut or add
blank.lines.skip is not working either...
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Actually case (4) didn't work. The issue is also with the index.."fill" only
seems to work with the dimensions/columns that contain the data associated
to the index. Dang.yeah, I need help here.
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Case (4) - use the fill argument in ?read.tablethis looks useful...guess
I answered my own question...going to delete this thread now...
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So far I see two options: (1) nrows argument to specify max number of rows to
read in or (2) go into excel, and put a bunch of NA's . Both which are
inefficient in that they're not so "automated". For case (1), I have to
wait till an error pops up each time and deal with each one individually
taki
Make that 3 options actually. In case (3) I would have to take each category
on the spreadsheet and isolate each to its own csv file using excel. Fun
stuff...
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Hello there, I was wondering if you could help me with a quick R issue.
I have a data set where one of the columns has both date and time in
it, e.g. "12/31/11 23:45" in one cell. I want to use R to split this
column into two new columns: date and time.
One of the problems with splitting here is
hello all,
I've been trying for some time to try and model a big dataset using
generalized linear models, or more precisely negative binomial regression.
Unfortunately i have too many explanatory variables and i'd like to cut
some of them off using a stepwise selection method.
i've been struggeling
I truncated and simplified my code and the read in data that I'm working with
to isolate the issue. Here is the read in data and R script respectively:
http://r.789695.n4.nabble.com/file/n4604287/test.csv test.csv
http://pastebin.com/rCdaDqPm
Here is the terminal/R shell output that I hope the
I am having a problem with stemDocuments also. I can make it work by moving
the data into a Corpus by using:
> a <- Corpus(VectorSource(df$text)) # create corpus object
> a <- tm_map(a, stemDocument, language = "english")
but it is horrably slow. I want to stem outside the Corpus object like:
Hello,
stella wrote
>
> Hi,
>
> How can a function in R handle different types of input?
> I have written a function, which should calculate the slope from several
> 3-time-point measurements by linear regression
>
> 4 three-time-point-measurements:
> x<-cbind(c(1,2,3,4),c(2,3,4,5),c(3,4,5,6
Hello,
I have applied the Shapiro test to a matrix with 26.925 rows of data using the
following
F1.norm<-apply(F1.n.mat,1,shapiro.test)
I would now like to view and export a table of the p and W values from the
Shapiro test, but I am not sure how to approach this.
I have tried the follow
That did it! Thanks very much Berend.
On Wed, May 2, 2012 at 4:19 AM, Berend Hasselman wrote:
>
> On 02-05-2012, at 07:22, Kaushik Krishnan wrote:
>
>> Hey folks
>>
>> I'm sorry for bringing what must be a very simple question to R-help,
>> but after some research I haven't been able to find a so
I'm looking for a function for the "multiple correlation" among three variables.
I have created three vectors (x, y and z) and I want to find a correlation
coefficient and evaluate its significance.
Can anyone help me?
Thanks in advance.
[[alternative HTML version deleted]]
Ey R-people
Trying to do a binary logistic regression with only
categorical(age,ballot) and binary predictors for a binary response
variable. I can model them at least at least i treat the binary
predictors as categorical with the use of as.factor(etc) and use glm
with binomial distribution
Hello,
>
> I must be missing something very obvious, but I just cannot see it.
>
The hardest to find errors.
Wrong manual calculation in t1, powers have precedence right to left and
before additions.
t1b <- 10^(params[1]-xx)^params[2]
t3b <- 1 + t1b
t4b <- t2/t3b
t5b <- params[4] + t4b
all.equal
Hello,
mpostje wrote
>
> Hi
>
> I've been trying to convert numbers from an online temperature database
> into dates and time that R recognizes. the problem is that the database
> has put a T
> between the numbers and R will not accept any conversions.
>
> this is the format that it's in now
Hi,
I have a list of data, e.g. r[[i]]
r[[1]]=
1 2
1 6
5 5
5.5 3
r[[2]]=
46
35
78
35
…
r[[500]].
In the first column, the selected values should like this:
(the later value)-(the former value)>=1
In the second column, the selected values should like this:
(the form
Hi,
How can a function in R handle different types of input?
I have written a function, which should calculate the slope from several
3-time-point measurements by linear regression
4 three-time-point-measurements:
x<-cbind(c(1,2,3,4),c(2,3,4,5),c(3,4,5,6))
time points:
time<-c(1,3,9)
function
Hi,
I am using coxph from the survival package to fit a large model
(100,000 observations, ~35 covariates) using both ridge regression (on
binary covariates) and penalized splines (for continuous covariates).
In fitting, I get a strange error:
Error in if (abs((y[nx] - target)/(y[nx - 1] -
Worked like a charm. Thanks for the help! It's really appreciated.
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On most UNIX systems this will leave a large unallocated virtual "hole" in the
file. If you are not bothered by spreading the allocation task out over the
program execution interval, this won't matter and will probably give the best
performance. However, if you wanted to benchmark your algorith
On May 2, 2012, at 6:23 PM, Jonathan Greenberg wrote:
> R-helpers:
>
> What would be the absolute fastest way to make a large "empty" file (e.g.
> filled with all zeroes) on disk, given a byte size and a given number
> number of empty values. I know I can use writeBin, but the "object" in
> thi
interactive() does not do exactly what you
ask for, but may be close enough. It returns
FALSE when run from Rscript and TRUE from
R when you have not redirected standard input.
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Message-
> From: r-help-boun...@r-project.o
Hello list
Is there a way of identifying from within R whether a script has been source(d)
from Rgui.exe or via Rscript.exe in batch mode?
For the code I have I use the commandArgs() function to pick up command line
args when running in batch mode via Rscript.exe
However I like to get the code
Thanks everyone for your helpful responses. I looked at the csv file in a
text editor and saw no spaces or non-numerical characters (other than
periods as decimals) outside of the header. str() says me that the
variables are either num or int.
David was spot-on; I was trying
> storage.mode(~miles)
Addendum to my first post:
Since I wish to understand what plm does to my data, I tried to manually
calculate the demeaned values and use OLS. See below how far I got with the
Grunfeld data; formula's are based on Greene's Econometric Analysis.
Obviously, I am missing at least one important step
It works for me with your data:
> dat<-read.table("/tmp/foo.txt",header=TRUE)
> metaplot(a$coef,a$se_coef)
It has boxes of size zero for the point estimates, but that's because
you give the standard error as zero for the second estimate, which
implies all the other boxes should be infinitely smal
Something like:
http://markus.revti.com/2007/06/creating-empty-file-with-specified-size/
Is one way I know of.
Jeff
Jeffrey Ryan|Founder|jeffrey.r...@lemnica.com
www.lemnica.com
On May 2, 2012, at 5:23 PM, Jonathan Greenberg wrote:
> R-helpers:
>
> What would be the absolu
On 12-05-02 5:20 PM, Heiko Neuhaus wrote:
Thank you very much for your suggestion.
f<- function(a,b,c) {
names<- ls(environment()) # get all the names
result<- list()
for (n in names) {
if (!do.call(missing, list(as.name(n
result[n]<- get(n)
}
result
}
I have already figured out a very si
An R solution is:
allocateFile <- function(pathname, nbrOfBytes) {
con <- file(pathname, open="wb");
on.exit(close(con));
seek(con, where=nbrOfBytes-1L, origin="start", rw="write");
writeBin(as.raw(0), con=con);
invisible(pathname);
} # allocateFile()
> allocateFile("foo.bin", nbrOfByte
Look at the man page for dd (assuming you are on *nix)
A quick google will get you a command to try. I'm not at my desk or I would as
well.
Jeff
Jeffrey Ryan|Founder|jeffrey.r...@lemnica.com
www.lemnica.com
On May 2, 2012, at 5:23 PM, Jonathan Greenberg wrote:
> R-helpers:
R-helpers:
What would be the absolute fastest way to make a large "empty" file (e.g.
filled with all zeroes) on disk, given a byte size and a given number
number of empty values. I know I can use writeBin, but the "object" in
this case may be far too large to store in main memory. I'm asking bec
Thank you very much for your suggestion.
f <- function(a,b,c) {
names <- ls(environment()) # get all the names
result <- list()
for (n in names) {
if (!do.call(missing, list(as.name(n
result[n] <- get(n)
}
result
}
I have already figured out a very similar solution using for/eval that
bas
Plot the data. You're clearly overfitting.
(If you don't know what this means or why it causes the problems you
see, try a statistical help list or consult your local statistician).
-- Bert
On Wed, May 2, 2012 at 12:32 PM, Michal Figurski
wrote:
> Dear R-Helpers,
>
> I'm working with immunoassa
Dear R-Helpers,
I'm working with immunoassay data and 5PL logistic model. I wanted to
experiment with different forms of weighting and parameter selection,
which is not possible in instrument software, so I turned to R.
I am using R 2.14.2 under Win7 64bit, and the 'nls' library to fit the
m
Dear all:
Is there a way to add text to the margins or outer margins of a mosaic plot
using the vcd package? I understand the margins argument to mosaic, but I don't
know how to add text to that.
I'd like to add a caption to a plot. If possible, I'd like to know how to set
the font and size fo
On 02/05/2012 12:59 PM, Heiko Neuhaus wrote:
Thanks a lot for your answer!
>> --
>>
>> test1<- function(a, b, c)
>> {
>> x<- as.list(environment())
>> print ("hi from test1!")
>> test2(a = a, b = b, c = c)
>
> You are rying to pass a, b, c here and hence R trie
Hi,
I'm trying to build a Forest Plot using the second and fourth columns in
the table (test.csv) below. My code is the following:
curated <- data.frame("test.csv")
tmp <- curated$coef
tmp1 <- curated$se_coef
plt <- metaplot(tmp, tmp1, xlim = c(-.45, .45))
I keep getting the following error at th
On Wed, May 02, 2012 at 11:42:27AM -0400, Rajarshi Guha wrote:
> Hi, I'm running a calculation in two ways. The first way is to employ
> vectors and evaluate a function in one go. The second way is to break
> down the function into pieces and combine the pieces to the final
> answer.
>
> Algebraic
Thanks a lot for your answer!
--
test1 <- function(a, b, c)
{
x <- as.list(environment())
print ("hi from test1!")
test2(a = a, b = b, c = c)
You are rying to pass a, b, c here and hence R tries to insert those
into the environment of test2 once it is called, you h
try this:
> x <- read.table(text = "id wtdt wt lastpk
+
+ 64050256 2010-09-18 275 2010-09-16
+
+ 64050256 2010-09-19 277 2010-09-18
+
+ 64050256 2010-09-20 272 2010-09-18
+
+ 64050256 2010-09-21 277 2010-09-18", as.is = TRUE, header = TRUE)
>
> first
On 02.05.2012 11:19, mpostje wrote:
Hi
I've been trying to convert numbers from an online temperature database
into dates and time that R recognizes. the problem is that the database has
put a T
between the numbers and R will not accept any conversions.
this is the format that it's in now
198
On 02.05.2012 02:55, Ulfa Hasanah wrote:
hi all,can you help me? index moran is very difficut for me, i have data n
neighbor as enclosure:
please help me to make the program for find index moran value each
variabel,...thank very much
Which translates to:
please help me, and note that
- I
On 5/2/2012 11:40 AM, Duncan Murdoch wrote:
> On 02/05/2012 12:26 PM, Duncan Murdoch wrote:
>> On 02/05/2012 11:00 AM, Alexander Shenkin wrote:
>> > Hi Folks,
>> >
>> > I'm trying to get rgl.Sweave to produce plots with transparency.
>> > However, it just seems to produce opaque plots when pdf
On 02/05/2012 12:26 PM, Duncan Murdoch wrote:
On 02/05/2012 11:00 AM, Alexander Shenkin wrote:
> Hi Folks,
>
> I'm trying to get rgl.Sweave to produce plots with transparency.
> However, it just seems to produce opaque plots when pdf is the output
> type. Perhaps this is a known issue? I'll
And now we have two entirely different interpretations of the question.
I think Ondřej needs to provide a more detailed explanation of the
problem and intended result.
Sarah
On Wed, May 2, 2012 at 12:23 PM, R. Michael Weylandt
wrote:
> I think readline() will do what you want. It can display a
On 01.05.2012 19:57, Heiko Neuhaus wrote:
Hi all,
I am trying to create a list of all variable/value combinations in
environment().
When a function with unset arguments is called, the method I have been
using fails with a "missing argument" error. However it should be
possible to simply skip
Hi,
In a data I have two predictors and one response variable. The response
variable is categorical and fixed. Now I want to choose which predictor
would better predict the response variable. Is there a statistical test for
that?
Best,
Jing
--
Jing Tang, PhD
Senior Researcher
Institute
You might start with par(ask=TRUE) and identify().
A reproducible example might get you actual code. Also, how do you
know they're superfluous? Perhaps that knowledge can be used to
automate identification.
Sarah
On Wed, May 2, 2012 at 12:08 PM, Ondřej Mikula wrote:
> Dear R-helpers,
> I have a
On 02/05/2012 11:00 AM, Alexander Shenkin wrote:
Hi Folks,
I'm trying to get rgl.Sweave to produce plots with transparency.
However, it just seems to produce opaque plots when pdf is the output
type. Perhaps this is a known issue? I'll just use .png in the
meantime, but wanted to see about thi
I think readline() will do what you want. It can display a message and take
user input, assigning it to a character value so you might need as.numeric()
Michael
On May 2, 2012, at 12:08 PM, Ondřej Mikula wrote:
> Dear R-helpers,
> I have a number of point configurations representing skull shap
Dear R-helpers,
I have a number of point configurations representing skull shapes, but
some of them contain superfluous points. I want to write a loop in
which each configuration is plotted and I am asked to write the
numbers of points that are superfluous. However, I don't know how to
introduce th
Your multistep approach corresponds to the following, which has one
more set of parentheses than you used
yy <- params[4] + (params[3] - params[4])/((1 + 10^(params[1]-xx))^params[2])
In R lingo, both of your approaches are vectorized and you probably won't find
a huge difference in speed betwee
Walmes, Thank you so much!!!
I am still trying to understand all of your code but it works. I have changed
it a bit so that I get upper and lower limits for the error bar, and that the
origin starts at 0 so the negative values are plotted correctly.
barchart(Change~fTreat,groups=Process,change,
Hi, I'm running a calculation in two ways. The first way is to employ
vectors and evaluate a function in one go. The second way is to break
down the function into pieces and combine the pieces to the final
answer.
Algebraically, they should give me the same result. But the final
vector differs sig
?tapply
?with is also useful here
as in (untested)
with(yourdataframe, tapply(lastpk, id, unique))
-- Bert
On Wed, May 2, 2012 at 7:58 AM, Ayyappa Chaturvedula
wrote:
> Dear Group,
>
> I am working with a large dataset where I need to select for each unique id
> the the unique lastpk row. Her
Hi Folks,
I'm trying to get rgl.Sweave to produce plots with transparency.
However, it just seems to produce opaque plots when pdf is the output
type. Perhaps this is a known issue? I'll just use .png in the
meantime, but wanted to see about this, as I didn't see it in the
documentation (though
Dear Group,
I am working with a large dataset where I need to select for each unique id
the the unique lastpk row. Here is a sample subject:
id wtdt wt lastpk
64050256 2010-09-18 275 2010-09-16
64050256 2010-09-19 277 2010-09-18
64050256 201
On May 2, 2012, at 15:48 , meredith wrote:
> Peter-
> Maybe I have not articulately my problem clearly, I have had local help
> with the statistical part just trying to figure out how to correctly program
> this test. For clarity's sake, I have months worth of data, I want to
> potentially comb
Try something like this. Convert the vector to character and grab the first 10
characters then convert to a date.
aa <- as.factor("1981-01-02T08:00I")
aa <- as.character(aa)
aa <- substr(aa, 1, 10)
class(b)
John Kane
Kingston ON Canada
> -Original Message-
> From: mayo_j...@hotmail.co
On May 2, 2012, at 6:14 AM, Johannes Radinger wrote:
Hi,
i want to plot empirical cumulative density functions for two
variables in
one plot. For better visualizing the differences in the two
cumulative curves I'd like to log-scale the axis.
So far I found 3 possible functions to plot ec
write.csv() is definitely the right way to go so you're on track
What is str(medpolish)?
>From the error message, it sounds like it's a functionIf it is,
are you sure you don't mean write.csv(medpolish( xx )) ?
Michael
On Wed, May 2, 2012 at 12:39 AM, Martin Raymond Lefebvre
wrote:
> Quick
As has been answered several times on rhelp ... the baseline hazard is
for a case with the "mean value". It's not a meaningful case with all
factor variables. There can be no cases where fidelity>3 has a
fractional value. You should be using predict() and survfit() to
display estimates for
It is not clear what you mean. Can you supply some sample data? Have a look
at ?dput for a handy way to supply data.
John Kane
Kingston ON Canada
> -Original Message-
> From: lterle...@anadolu.edu.tr
> Sent: Tue, 1 May 2012 17:55:25 +
> To: r-help@r-project.org
> Subject: [R] Arul
This might be more of a question for R-SIG-Finance and followup should
probably be there, but you might get a start with the rugarch package.
Michael
On Wed, May 2, 2012 at 4:13 AM, Ivette wrote:
> I have done the usual estimation of GARCH models, applied to my historical
> dataset (commodities
On May 1, 2012, at 8:47 PM, Eve Proper wrote:
I am a raw novice to R, playing around with a mini .csv dataset
created in
Excel. I can read it in and the data looks OK in Excel and upon
initial
inspection in R:
hikes <- read.csv("/Users/eproper/Desktop/hikes.csv", header=TRUE)
print(hikes)
Peter-
Maybe I have not articulately my problem clearly, I have had local help
with the statistical part just trying to figure out how to correctly program
this test. For clarity's sake, I have months worth of data, I want to
potentially combine those months into four, shall we say seasons, that
Please don't triple post.
Michael
On Wed, May 2, 2012 at 8:08 AM, marjolein post wrote:
>
>
>
>
> Hi, I've been trying to convert numbers from an online temperature database
> into dates and time that R recognizes. I've tried as.Date, as.POSIXlt and
> strptime the problem is that the database
Quick and dirty solution is to use sub() to change the T to a space
and then use as.POSIXct as usual.
x <- "1981-01-02T08:00"
as.POSIXct(sub("T"," ", x), format = "%Y-%m-%d %H:%M")
but it does look to me like R can work around the T if you give a good
format argument:
as.POSIXct(x, format = "%Y
I think you are looking for something like
aggregate(cbind(VPts, HPts) ~ VTm + HTm, data = NFL, sum)
but you should look at the examples for ?aggregate to tweak it to what
you need.
Michael
On Wed, May 2, 2012 at 7:45 AM, Daniel_55 wrote:
> Hello,
>
> I'm looking for what I'm sure is a quick a
On Wed, May 2, 2012 at 4:34 AM, Jim Lemon wrote:
> On 05/02/2012 10:47 AM, Eve Proper wrote:
>>
>> I am a raw novice to R, playing around with a mini .csv dataset created in
>> Excel. I can read it in and the data looks OK in Excel and upon initial
>> inspection in R:
>>
>> hikes<- read.csv("/User
On 02/05/2012 8:08 AM, marjolein post wrote:
Hi, I've been trying to convert numbers from an online temperature database
into dates and time that R recognizes. I've tried as.Date, as.POSIXlt and
strptime the problem is that the database has put a T between the numbers and
R will not accept
Meredith:
You are clearly out of your depth. Get local help. R-help is, err,
an R help list, not a resource for remote statistical consulting.
Although, I admit, there is often some overlap.
-- Bert
On Wed, May 2, 2012 at 5:58 AM, peter dalgaard wrote:
>
> On May 1, 2012, at 22:01 , meredit
Deepak,
On Wed, May 2, 2012 at 7:53 AM, deepakw wrote:
> Hi I am trying to use depmixS4 package. Based on the documentation, it
> seems
> that depmix allows one to fit an HMM model based on a training data with
> time-varying co-variates. However, I did not find any routines which can
> help tes
I have a variable :
*sim.var[,1]
*
Object of class SpatialPixelsDataFrame
Object of class SpatialPixels
Grid topology:
cellcentre.offset cellsize cells.dim
Xloc 0.3 0.0597
Yloc 0.1 0.05 117
SpatialPoints:
Xloc Yloc
[1,] 0.30 1.70
Or look for A handbook of Statistical Analyses using R. (Everitt and Holhorn)
available on line in pdf format.
John Kane
Kingston ON Canada
> -Original Message-
> From: istaz...@gmail.com
> Sent: Wed, 2 May 2012 07:01:22 -0400
> To: sydney.ver...@gmail.com
> Subject: Re: [R] How to read
Hello,
I'm looking for what I'm sure is a quick answer. I'm working with a data set
that looks like this:
Week Game.ID VTm VPts HTm HPts
Differential HomeWin
11 NFL_20050908_OAK@NE OAK 20 NE 30 10
FALSE
21 NFL_20050911
Hi, I've been trying to convert numbers from an online temperature database
into dates and time that R recognizes. I've tried as.Date, as.POSIXlt and
strptime the problem is that the database has put a T between the numbers and
R will not accept any conversions. currently it sees the date as
Hi
I've been trying to convert numbers from an online temperature database
into dates and time that R recognizes. the problem is that the database has
put a T
between the numbers and R will not accept any conversions.
this is the format that it's in now
1981-01-02T08:00
can anyone help?
cheers!
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