Hi Rui Barradas
thank you very much, that's what I searched for
result - lapply(conds, fun, DF) works, if
day - DF$day
val - DF$val
Thanks
Christof
Am 02-07-2012 20:44, schrieb Rui Barradas:
Hello,
I'm not sure if this is what you want.
#-- Make up a dataset
Hi,
I am trying to format some data (example matrix m below) for which each data
point has 2 associated values separated by a comma.
I want to replace values 3 with 0 to give the example output below.
I have got as far as:
out-lapply(strsplit(m,,),as.numeric)
Failed to identify anything along
Hello,
I did a mistake in my script:
hour - day*24; hour - c(hour[1],cumsum(hour[1:length(hour)-1]))
should be replaced by:
hour - day*24; hour - c(0,cumsum(hour[1:length(hour)-1]))
Regards
Le 05/07/2012 10:49, Pascal Oettli a écrit :
Hello,
A short code to include real monthly
Hi,
i tried with inlinedocs package function extract.docs.file. it have exactly
what i need but it return as list.
can u help me how to convert list to html documentation.
Thanks
B.Purushothaman
--
View this message in context:
Thank you Simon!
--
View this message in context:
http://r.789695.n4.nabble.com/Graph-showing-fitted-values-obtained-by-binomial-GLM-tp4635573p4635581.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
Dear R users (r-help@r-project.org),
The definition of AIC (Akaike information criterion)
for normal error models has just been changed.
Please refer to the paper below on this matter. Eq.(22) is
the new definition. The essential part is RSS(n+q+1)/(n-q-3);
it is close to GCV. The paper
sap-sapply(strsplit(m,,),as.numeric)
sap[which(sap = 3)]-0
mNew-matrix(apply(sap,2,FUN=function(x){paste(x,collapse=,)}),ncol=4)
works?
On 06.07.2012, at 08:47, Sarah Auburn wrote:
Hi,
I am trying to format some data (example matrix m below) for which each
data point has 2 associated values
Perfect, thank you!
From: Jessica Streicher j.streic...@micromata.de
To: Sarah Auburn saub...@yahoo.com
Cc: R help r-help@r-project.org
Sent: Friday, 6 July 2012, 17:48
Subject: Re: [R] function on strsplit output
sap-sapply(strsplit(m,,),as.numeric)
sap[which(sap = 3)]-0
I read there are several R functions to get the Maximum Likelihood Estimates
of a probability distribution with the available data in R. For Example...
http://stat.ethz.ch/R-manual/R-devel/library/stats4/html/mle.html mle
{stats4}
http://stat.ethz.ch/R-manual/R-devel/library/stats/html/optim.html
You have made it extraordinarily difficult to help you.
1) Using a library function without indicating which library it is from. This
is really a special case of failing to provide a reproducible example as
requested in the posting guide.
2) You provide data that does not appear to be a result
Could also do it in one apply i realized..
apply(m,1:2,FUN=function(x)
{y-as.numeric(strsplit(x,split=,)[[1]]);y[which(y =
3)]-0;paste(y,collapse=,)})
On 06.07.2012, at 10:18, Jessica Streicher wrote:
sap-sapply(strsplit(m,,),as.numeric)
sap[which(sap = 3)]-0
Hi!
I think I had some issues with the charset on the previous message, so I'm
sending this again. Sorry for the double post.
I'm using the Naive Bayes classifier provided by the e1071 package (
http://cran.r-project.org/web/packages/e1071) and I've noticed that the
predict function has a
Good morning
When I try to run an Apriori, I keep often the following message:
checking subsets of size 1Error in apriori(tr, parameter = list(supp =
3e-05, conf = 0.05, minlen = 2, :
internal error in trio library
Other time it works fine on the same data. What can be the reason for this?
Thank you guys! The solution turned out to be very simple, but I couldn't
find it anywhere (not even in the help of the function curve()). I think
there's not much difference in both methods, but with curve you can easily
adjust the amount of a values with 'n = ...' option, to make a smooth line.
Good morning,
1. What is your OS?
2. Which package do you use to perform the Apriori?
3. Without providing any reproducible code, it will probably be
complicated to answer you.
Best Regards
Le 06/07/2012 18:15, Jolinda Bartlett a écrit :
Good morning
When I try to run an Apriori, I keep
On 07/05/2012 10:37 PM, purushothaman wrote:
Hi,
i am new in R development ,
so i need help in documentation from comments in R file
for example
sample-function(filepath)
{
##title read csv file
##author Purushoth
##description this function is used to read a csv
My question is, how to compute hazard function(H(t)) after building the
coxph model. I even aware of the terminology that differs from hazard
function(H(t)) and the hazard rate(h(t)). Here onward I wish to calculate
both.
Here what I have done in two different methods;
Hi,
You could also try:
set.seed(1)
n - 1e2
DF - data.frame(year=2010 + sample(3, n, TRUE),
day=sample(365, n, TRUE),
val=sample(100, n, TRUE))
a = day 100; b = val 50; c = year == 2012
conds - list(a=a, b=b, c=c)#To check individual conditions
eval(parse(text=conds[[1]]))
My question is, how to compute hazard function(H(t)) after building the
coxph model. I even aware of the terminology that differs from hazard
function(H(t)) and the hazard rate(h(t)). Here onward I wish to calculate
both.
Here what I have done in two different methods;
i have try lasso use lars package with real data..
when i running the data and plot it (plot(lasso))..
in plot showed|beta|/max|beta, when i calculated beta from coefficient lasso
(coef(lasso))..
there are some differentiation between the calculation result and the plot..
what cause it?
must i
Mateus,
I see what you mean.
I can't figure it out.
I found a message from a few years ago that mentions the same problem.
http://tolstoy.newcastle.edu.au/R/e8/help/09/12/8165.html
This may be a bug.
Since hclust() is in the stats package, I am ccing the maintainer,
r-c...@r-project.org, on
Hello,
i am trying to understand the difference between S3 function print and
S4 method.
My main problem is that i need to count the environment (frames) (i
use /eval/() afterwards with /parent.frame/() ).
If I use a S4 method/print/, a 'hidden' environment seem to appears.
It is not the
Thank you, Jean.
Mateus
2012/7/6 Jean V Adams jvad...@usgs.gov
Mateus,
I see what you mean.
I can't figure it out.
I found a message from a few years ago that mentions the same problem.
http://tolstoy.newcastle.edu.au/R/e8/help/09/12/8165.html
This may be a bug.
Since hclust() is in
Hi all,
I am reading the MASS book but it doesn't give examples about the diagnosis
and model checking for rlm...
My data is highly non-Gaussian so I am using rlm instead of lm.
My questions are:
0. Are goodness-of-fit and model-checking using rlm completely the same as
usual regression?
On Jul 6, 2012, at 15:36 , knallg...@gmx.com wrote:
Hello there,
I just upgraded to R 2.15 (from R 2.12) on a Windows XP machine and noticed
some puzzling behaviour (that in my opinion did not exist in R 2.12).
It is possible now to call objects without spelling out the full object
On Fri, Jul 6, 2012 at 7:19 AM, Michael comtech@gmail.com wrote:
Hi all,
I am reading the MASS book but it doesn't give examples about the diagnosis
and model checking for rlm...
My data is highly non-Gaussian so I am using rlm instead of lm.
Well, rlm() is not necessarily going
This has always been how the $ operator has worked. See ?[[, and use that
operator directly if you want exact matching.
---
Jeff NewmillerThe . . Go Live...
On Jul 6, 2012, at 9:36 AM, knallg...@gmx.com wrote:
Hello there,
I just upgraded to R 2.15 (from R 2.12) on a Windows XP machine and
noticed some puzzling behaviour (that in my opinion did not exist in
R 2.12).
It is possible now to call objects without spelling out the full
object
Mateus,
Apparently I cc-ed the wrong group (see snippet below).
I think you found a bug.
I suggest you write something up and send it to r-b...@r-project.org
Follow the directions on How to report a bug
http://www.stat.ucl.ac.be/ISdidactique/Rhelp/library/base/html/bug.report.html
Jean
the study design of the data I have to analyse is simple. There is 1 control
group (CTRL) and 2 different treatment groups (TREAT_1 and TREAT_2).
The data also includes 2 covariates COV1 and COV2. I have been asked to check
if there is a linear or quadratic treatment effect in the data.
I
Hello,
I'm having some issues grouping cases for some Mann-Whitney U tests I'm
attempting to run. I'm willing to use wilcox.test if it'll work; I've also
tried wilcox_test() from the coin package. Here's the deal: for each column
(A through H), I would like to run the two-sample independent
I have my data in a table
table - table(test2$Filename, test2$PREDICT)
I need to convert this table so it keeps the same structure, but is a
different format. The current output is count data by Filename and I want to
get the max for each Filename.
Columns are:
Filename, 1, 2, 3, 4, 5, 6, 7
Hi,
I am using R's grep function to find patterns in vectors of strings. The
number of patterns I would like to match is 7,700 (of different sizes). I
noticed that I get an error message when I do the following:
data - array()
for (j in 1:length(x))
{
array[j] -
Dear everyone
I'm dealing with a problem related to Poisson Ridge Regression. If anyone
can help me in this regard by telling if any changes in the source code of
glm.fit may help
--
Regards
Umesh Khatri
[[alternative HTML version deleted]]
Hi,
Given that you can't provide a full example, please at least provide
str() on your data, more complete information on the problem, and
ideally a small toy example that demonstrates precisely what you are
doing.
For instance, you tell us that you get an error message but you
never tell us
Dear Researches,
Did anyone know where to find the following Based-Density cluster
algorithms in R or function implemented?
OPTICS (Ordering Points To Identify the Clustering Structure)
DECLUN (DENsity CLUstering)
Thanks in Advance
Gianni
[[alternative HTML version deleted]]
Hi. Here are some examples that could be useful here:
set.seed(1)
x - sample(1:2, 100, rep=T)
y - sample(1:3, 100, rep=T)
TAB - table(x,y)
#check the object class
class(TAB)
apply(TAB, 2, max)
apply(TAB[,2:3], 2, max)
apply(TAB, 1, max)
DF - as.data.frame.matrix(TAB)
class(DF)
sapply(DF, max)
I would like to import only datas of my table where DATEtoday-7days.
But my datas in Oracle are 'dates' and in R are 'characters'.
now_7-format(Sys.time()-(7*60*60*24), %Y-%m-%d 00:00:00)
How to do?
--
View this message in context:
A table is a matrix
Filename - sample(LETTERS[1:5], 50, replace=TRUE)
PREDICT - sample(1:7, 50, replace=TRUE)
To get a data frame that preserves the row/column structure of the table use
dfm - as.data.frame.matrix(tbl)
But you can do what you want on the table directly:
rowmx - apply(tbl, 1,
I managed to leave out one key line:
Filename - sample(LETTERS[1:5], 50, replace=TRUE)
PREDICT - sample(1:7, 50, replace=TRUE)
tbl - table(Filename, PREDICT) # this one.
Then the rest follows.
--
David
-Original Message-
From:
Can you describe how your data is organized. It is clear there are eight
columns, but it is not clear how the groups are represented, a Group column
or do the groups have to be assembled from information in another column (a
column with CD8.14, etc)? Create a small version of the data and use
Please hold. The r-help hive mind is attempting to probe your brain for
further details of your problem related to Poisson Ridge Regression.
--
David L Carlson
Associate Professor of Anthropology
Texas AM University
College Station, TX 77843-4352
On Fri, Jul 6, 2012 at 10:45 AM, mdvaan mathijsdev...@gmail.com wrote:
Hi,
I am using R's grep function to find patterns in vectors of strings. The
number of patterns I would like to match is 7,700 (of different sizes). I
noticed that I get an error message when I do the following:
data -
If you don't know what format your data is in, how are we supposed to know?
Have you tried looking at your data file with a text editor? Perhaps reading
your data using read.table or read.csv will help? Use the str function to learn
its structure? use dput as the posting guide recommends so we
Ding! Semantic error : problem not defined. Return to beginning of Posting
Guide mentioned at bottom of every email on this list, process contents, and
reformulate question.
---
Jeff NewmillerThe
Dear Peter;
This is an exact duplicate of a question posted on SO. Cross-posting
is deprecated on Rhelp.
--
David.
On Jul 6, 2012, at 11:06 AM, mails wrote:
the study design of the data I have to analyse is simple. There is 1
control group (CTRL) and 2 different treatment groups (TREAT_1
Thanks a lot Bert.
Yet still, I would like to know does the diagnosis and model-checking for
rlm follow the same procedure as lm ...
Thank you!
On Fri, Jul 6, 2012 at 9:27 AM, Bert Gunter gunter.ber...@gene.com wrote:
On Fri, Jul 6, 2012 at 7:19 AM, Michael comtech@gmail.com
Dear Peter,
Because your model is additive, type-II and type-III tests are identical,
and the t-tests for the linear and quadratic coefficients are interpretable.
I hope this helps,
John
John Fox
Sen. William McMaster Prof. of Social Statistics
Hi all
I have a large SAS data set, how do I get it read in R?
The data is too big (about 400,000 rows by 100 columns) to be saved as an
Excel file. How should I get it read in R? Any packages? I don't seem to
find any.
Thanks,
Mike
[[alternative HTML version deleted]]
You need to learn how to search.
RSiteSearch(SAS)
or
Google : R read SAS
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live
On 06/07/2012 1:11 PM, C W wrote:
Hi all
I have a large SAS data set, how do I get it read in R?
The data is too big (about 400,000 rows by 100 columns) to be saved as an
Excel file. How should I get it read in R? Any packages? I don't seem to
find any.
You could write it out in some plain
On Jul 6, 2012, at 10:50 AM, cindy.dol wrote:
I would like to import only datas of my table where DATEtoday-7days.
But my datas in Oracle are 'dates' and in R are 'characters'.
now_7-format(Sys.time()-(7*60*60*24), %Y-%m-%d 00:00:00)
How to do?
Huh? How are you getting the data from Oracle
On Jul 6, 2012, at 12:11 PM, C W wrote:
Hi all
I have a large SAS data set, how do I get it read in R?
The data is too big (about 400,000 rows by 100 columns) to be saved as an
Excel file. How should I get it read in R? Any packages? I don't seem to
find any.
Thanks,
Mike
Strangely
Hi everyone!
I am trying to install boot package in order to do bootstrap analysis with
R. I am trying to use the following command:
install.packages(/var/folders/++/++53BE++6+0++4RjPqRgNE+-lHI/-Tmp-//Rtmpvmc3aE/downloaded_packages)
But get the following message:
package
Whoops! Thanks to everyone and sorry for asking something so trivial and
obvious for everyone. I really hadn't noticed it before.
Cheers!
i.
- Original Message -
From: David Winsemius
Sent: 07/06/12 05:32 PM
To: knallg...@gmx.com
Subject: Re: [R] automatic completion of
Dear everyone
I'm dealing with a problem related to Poisson Ridge Regression. If
anyone can help me in this regard by telling if any changes in the
source code of glm.fit may help
--
Regards
Umesh Khatri
__
R-help@r-project.org mailing list
Thanks for the quick response. I should phrase my question differently
because everything is working fine, I am just trying to find a more
efficient approach:
1. What's the maximum size of the patterns argument in grep? Can't find it
online.
2. I am trying to match 7,700 character strings to
Fantastic, thank you so much!
--
View this message in context:
http://r.789695.n4.nabble.com/convert-a-table-tp4635615p4635627.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
Hi all,
I am wondering if the survey package has the capability to describe a
multistage survey with PPS clusters. Speficially I have a national survey
that is intially stratified by region, then by PPS cluster by locality.
I'm not sure if this needs to be done with an FPC statement or if I need
Hi,
I 'm a novice user of R statistics and my hands-on experience with it is
minimal.
I want to create a table for my MBA course assignment that looks like the
ones that SPSS and MS Excel produces ,the data that the table has to include
are the following :
table(agec)
agec
1 2 3
749 160
Hello,
Not quite understand about ur problem. Could you dput your data?
The below should be general format to convert to class date
now_7-format(Sys.time()-(7*60*60*24), %Y-%m-%d 00:00:00)
now_7
[1] 2012-06-29 00:00:00
class(now_7)
[1] character
now_7_new-as.Date(Sys.time()-(7*60*60*24),
Thanks Dennise,
Now I see what you have. It was not obvious from the original data set that
you posted that is is a time series.
I am afraid my knowledge of time series is about zero but I am sure others
here can help now that we have a good idea of what the data really looks
On Jul 6, 2012, at 10:46 AM, SergeyHC wrote:
Hi everyone!
I am trying to install boot package in order to do bootstrap analysis with
R. I am trying to use the following command:
install.packages(/var/folders/++/++53BE++6+0++4RjPqRgNE+-lHI/-Tmp-//Rtmpvmc3aE/downloaded_packages)
But
Hello,
On further thinking about the issue, I guess this may be close to what you are
looking for:
date1-c(2012-06-12,2012-06-13,2012-06-14,2012-06-27,2012-07-01,2012-07-02,2012-07-03,2012-07-04)
class(date1)
[1] character
#converting to date class
date2-as.Date(date1,format=%Y-%m-%d)
Quick question, what the memory size in R?
I converted to CSV, but only 53300 of the 1,000,000 rows were read in. Did
R run out of memory? If so, is there a work around?
Thanks,
Mike
On Fri, Jul 6, 2012 at 1:24 PM, Duncan Murdoch murdoch.dun...@gmail.comwrote:
On 06/07/2012 1:11 PM, C W
Hello All,
I am running the following code in RStudio, and I keep on getting an error
message that says: Error in plot.new() : figure margins too large
Is there something that I am doing wrong?
# Import Data
nba - read.csv(http://datasets.flowingdata.com/ppg2008.csv;, sep=,)
nba
#Sort Data
Have a look at the xtables package. I have not used it in some time but I
think it may do what you want. A google search R statistics xtables should
bring up some useful information on this.
John Kane
Kingston ON Canada
-Original Message-
From: sggk...@gmail.com
Sent: Fri, 6 Jul
Probabaly not since you do not tell us what the problem is.
Please read the posting notes at the bottom of this email
John Kane
Kingston ON Canada
-Original Message-
From: khatriumes...@gmail.com
Sent: Fri, 6 Jul 2012 21:13:32 +0530
To: r-help@r-project.org
Subject: [R] Poisson
Yes, this request is woefully incomplete, but it looked to me like the question
was how to select the data so that a limited amount of data could be imported,
rather than loading the whole table and subsetting in R. If so, the discussion
should be about constructing appropriate SQL (with or
On Jul 6, 2012, at 11:46 AM, SergeyHC wrote:
Hi everyone!
I am trying to install boot package in order to do bootstrap
analysis with
R. I am trying to use the following command:
install.packages(/var/folders/++/++53BE++6+0++4RjPqRgNE+-lHI/-Tmp-//
Rtmpvmc3aE/downloaded_packages)
But
Your code works okay in a plan R terminal. It may be an Rstudio problem or
perhaps you already have a graphics device open and are trying to draw into it?
John Kane
Kingston ON Canada
-Original Message-
From: khar...@lbl.gov
Sent: Fri, 6 Jul 2012 10:39:41 -0700
To:
I would like to know which function to use for modeling a multinomial logistic
regression model in the package survey. thanks
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
On Jul 6, 2012, at 1:39 PM, C W wrote:
Quick question, what the memory size in R?
I converted to CSV, but only 53300 of the 1,000,000 rows were read
in. Did
R run out of memory? If so, is there a work around?
You probably have mismatched quotes. Consider using quote=. Also
consider
On 06.07.2012 20:02, John Kane wrote:
Your code works okay in a plan R terminal. It may be an Rstudio problem or
perhaps you already have a graphics device open and are trying to draw into
it?
John Kane
Kingston ON Canada
-Original Message-
From: khar...@lbl.gov
Sent: Fri,
On Jul 6, 2012, at 2:49 PM, C W wrote:
Hey, David
table(count.fields()) is telling me have 11 columns, but I have way
more, more like 30 columns.
table(count.fields(persistency.csv))
1 2 3 4 5 6 7 8 9 11
439384 39617 16130 21993 12556
Has anyone read SAS file .sas7bdat into R. The above suggestions don't
work.
-M
On Fri, Jul 6, 2012 at 3:06 PM, David Winsemius dwinsem...@comcast.netwrote:
On Jul 6, 2012, at 2:49 PM, C W wrote:
Hey, David
table(count.fields()) is telling me have 11 columns, but I have way more,
more
On 06/07/2012 3:30 PM, C W wrote:
Has anyone read SAS file .sas7bdat into R. The above suggestions don't
work.
They work if you follow them.
Duncan Murdoch
-M
On Fri, Jul 6, 2012 at 3:06 PM, David Winsemius dwinsem...@comcast.netwrote:
On Jul 6, 2012, at 2:49 PM, C W wrote:
Hey,
David W. wrote
à It also looses it year labels and you may need to suppress the x-axis
à and substitute your own.
You can use plot(yourTimeSeries, type=n) to set up the usual time series axis
and then use lines() or points() to add the data. E.g.,
plot(serieONI, type=n)
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of C W
Sent: Friday, July 06, 2012 12:30 PM
To: David Winsemius
Cc: r-help help
Subject: Re: [R] How to import SAS data in R?
Has anyone read SAS file .sas7bdat into R. The
On Sat, Jul 7, 2012 at 5:50 AM, Diana Marcela Martinez Ruiz
dianamm...@hotmail.com wrote:
I would like to know which function to use for modeling a multinomial
logistic regression model in the package survey. thanks
There isn't an implementation of multinomial regression in the survey
package.
Look at the Predict.Plot and TkPredict functions in the TeachingDemos
package. These will not plot all 11 dimensions at once, but will plot
2 of the dimensions conditioned on the others. You can then change
the conditioning to see relationships.
These use base rather than ggplot graphics.
On
Dear R Users,
Could you please help me on the following issue?
I have a real large yearly data set. For each year I have
365 flow values. Some of the flow values are not known and thats why you will
see NA written in those slots. I wanted to know, is there a way that I can
estimate those
Yes, it's more like that, to limit the amout of data imported in R from Oracle.
- Mail original -
De: Jeff Newmiller jdnew...@dcn.davis.ca.us
À: Marc Schwartz marc_schwa...@me.com, cindy.dol
cindy.dolom...@insa-lyon.fr
Cc: r-help@r-project.org
Envoyé: Vendredi 6 Juillet 2012 20:00:37
Hi Rich,
So what you're faced with is that the cenros() function has no built-in
methods for grouping or subsetting -- unlike some other R methods,
especially those that work with the lattice package, or the many modeling
functions like lm() that have a subset argument or employ a conditioning
Dear Community,
I have been using two types of survival programs to analyse a data set.
The first one is an R function called aftreg. The second one an STATA
function called streg.
Both of them include the same analyisis with a weibull distribution. Yet,
results are very different.
Shouldn't
Ok, so let's say I have a logit equation outlined as Y= 2.5 + 3X1 + 2.3X2 +
4X3 + 3.6X4 + 2.2X5
So a one unit increase in X2 is associated with a 2.3 increase in Y,
regardless of what the other
predictor values are. So I guess instead of trying to plot of curve with
all the predictors accounted
On Jul 6, 2012, at 3:30 PM, C W wrote:
Has anyone read SAS file .sas7bdat into R. The above suggestions
don't work.
help(package=foreign)
And read the Import/Export Manual
--
-M
On Fri, Jul 6, 2012 at 3:06 PM, David Winsemius dwinsem...@comcast.net
wrote:
On Jul 6, 2012, at
Hi David,
Thank you for the insight: I could have sworn I added a picture of the
data, but providing the actual data is worlds easier to deal with, I'm sure.
I've never used dput(), so I entered it using the dataframe in question as
the object, and I've pasted the results below.
Essentially, I
Hello All,
I have a couple of stacked histograms which I need to compare/evaluate for
similarity or difference.
http://r.789695.n4.nabble.com/file/n4635668/Selection_011.png
I believe rather than evaluating histograms is will be east to work with
dataset used to plot these stacked histograms,
David, thanks for your helpful response.
Now i figured out that I do have boot command and do not need to install any
additional packages. With regards t R GUI, I guess I would like to use it,
but I could not figure out how to install it. For now I downloaded
R-2.15.1.pkg file, which I could
I have a class with 732 members, so using rpart.plot is giving me a tiny plot
in the middle of the window. Is there a good way to modify the plot, or
replace the long list with something like group1?
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I got this error when I tried to install the package in order to use the
logit(logit transformation) function on linux.
install.packages(car)
Error in install.packages(car) : object 'car' not found
I was using the Terminal in my macbook accessing the server in the lab. I
could successfully
Hi J,
You have not provided nearly enough information for us to evaluate
whether the results should be similar. You are talking about two
completely different packages, with no information on your data, only
a small amount of information about your model (the same analysis)
but clearly the
Install.packages needs a quoted argument -- the error message suggests
that its looking for a variable named `car` and not finding it -- in
fact, most functions taking package names do, but library() allows
some trickery, which is convenient, but occasionally leads to mishaps
like this.
Please do keep messages on list unless there's a particular reason to take them
private: it increases your visibility to the wider community and, by extension,
your chance of getting a good reply.
On Jul 6, 2012, at 10:43 PM, Chenwei Gao ga...@umich.edu wrote:
Thank you so much Michael !!
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