Greetings of Peace!
I am new in R software. I want to use the correlation dimension corrDim in
computing a map. I have installed the packages(fractal) in R. Now my problem is
this, when I tried your example in the following
site http://rgm2.lab.nig.ac.jp/RGM2/func.php?rd_id=fractal:corrDim
> l
Dear R Users,i am very new to R. I want your help on an issue regarding
distance matrix and cluster analysis
i had discharge data of 4 rivers(a,b,c,d) in 4 vectors each having 364 values
> dput(qmu)structure(list(a = c(0.26, 0.25, 0.25, 0.25, 0.24, 0.23, 0.22, 0.21,
> 0.21, 0.21, 0.2, 0.19, 0.19
Hi guys,
Thank you very much :)
It seems that both your suggestions works. I wasn't aware of the function
[[argument]], it makes the
programming procedure much easier! :)
Best regards,
Emil
--
View this message in context:
http://r.789695.n4.nabble.com/Extracting-results-from-the-VAR-outpu
hony gmail.com> writes:
>
> I need to create a software and use R engine in my software. but I don't know
> how to use R code in my software same www.revolutionanalytics.com.
> Rapid Miner has 2 section. one of them is using for application and the
> other is used for researcher for extended it.
Hi all,
When I installed rJava from source, rJava installation was failed with below
messges.
$ R CMD INSTALL rJava_0.9-4.tar.gz
...
...
...
gmake[1]: Leaving directory `/tmp/RtmpNwiCae/R.INSTALL4ebb76a3400d/rJava/jri'
installing via 'install.libs.R' to /stat/R-2.15.1/lib/R/libr
Dear R users,
I have seven regression lines I´d like to compare, in order to find out if
these are significatively different. The main problem is that these are
curves, non normal, non homogeneous data, I´ve tried to linearize them but
it has not worked. So I´d like to know if you know any comman
Hi,
I'm Wellington from Brazil and I have the following issue:
I've been working on a project a for a while, and I'm having trouble in
using the loop (for)
I need to read a column (c1), and for each value of this column, I need to
check if it's within the control limits
So, I was t
I would really like some help with understanding the panel function, in
zoo. Thank you.
R 15.1 and zoo 1.7-7.
library(zoo)
x = seq(0,3*pi,length.out=100)
y = sin(x)
zobj = zoo(y, x)
###
## EXAMPLE 1 - GLOBAL ARGUMENT
## This panel functio
Thanks a million, Michael. I really appreciated it.
Marco
-Original Message-
From: R. Michael Weylandt [mailto:michael.weyla...@gmail.com]
Sent: Sunday, July 29, 2012 5:03 PM
To: MP
Cc: r-help@r-project.org
Subject: Re: [R] Hints for the best package
It sounds like you want multiple lo
Hello,
I am not able to query Sybase IQ database from R using RODBC package.
Check the below code
R> sybaseiq.query <- function (sql, ..., as.is = FALSE)
{
connstr <- "Driver={Sybase
IQ};UID=ajadhav2;PWD=*;ServerName=PSGSESHR01A_IQ;CommLinks=SharedMemory,TCPIP{host=psgseshr01_iq.sg.cs
Hi all,
I'm trying to generate a grid of four plots. The first 2 appear
just fine, but the final 2 will not appear in the grid, instead
overwriting the first two.Any ideas on how to get them all in the
same window would be greatly appreciated.
Cheers,
Jonathan
library(fields)
par(mfrow=
Hi,
Can anyone tell me how to set Z-score according to my own requirement as
the below code is taking as per the file entries. Any help would
be appreciable.
library(gplots)
x=read.table("final.txt", header=TRUE)
mat=data.matrix(x)
heatmap.2(mat,
col=colorRampPalette(c("green","white","red"))(256
Hi,
On Sun, Jul 29, 2012 at 5:58 AM, hony wrote:
> I need to create a software and use R engine in my software. but I don't know
> how to use R code in my software same www.revolutionanalytics.com.
If your software is written in C++ perhaps the RInside package will be helpful:
http://cran.r-pro
Hi!
You're right. I was misinterpreting the way the coefficients were
calculated. Reading about the method of least squares helped me in
clarifying some of my doubts.
Thanks for your tips!
--
Joao.
On Fri, Jul 27, 2012 at 2:36 PM, Jean V Adams wrote:
> Joao,
>
> Your intuition is correct, the
Show us what you actually did. Rui's example does not generate a problem
with a log axis but it is an index plot.
This also does not generate any problems:
> set.seed(42)
> x <- runif(10)*100
> y <- runif(10)*100
> plot(x, y, xlim=c(100, 1), log="x")
You wouldn't have used xlim=c(100, 0) and the
Actually if you are looking for neighbors of neighbors you only need the
nearest neighbor for each point. The problem is that the nearest neighbor of
the nearest neighbor of point 1 is often point 1. Did you want the nearest
neighbor not counting any point twice? Sounds more like a traveling salesm
(1) Please show context; r-help is *not* nabble.
(2) You might like to investigate the revaxis() function from the
"plotrix" package.
cheers,
Rolf Turner
On 30/07/12 07:41, sappy wrote:
Thanks,
for the moment it works. But is there a possibility for a logarithmic
x-Axis? When i
Hello,
Inline
Em 29-07-2012 17:41, arun escreveu:
Hi,
As there is not much information like str() or the data, it is difficult to
comment.
But, try this (considering your x and y are factors):
x<-c("1","4","7","9","10","15")
y<-c("3","5","8","6","5","14")
dat1<-data.frame(x,y)
str(dat
It sounds like you want multiple logistic regression: I think most
people find the mlogit package quite helpful there. See also:
http://www.ats.ucla.edu/stat/r/dae/mlogit.htm
Michael
On Sun, Jul 29, 2012 at 9:02 AM, MP wrote:
> I am new to this field and I am currently studying the most basic pr
Searching markov switch on the R website gives a list of useful hints and
packages:
https://www.google.com/search?q=markov+switch&domains=r-project.org&sitesearch=r-project.org&btnG=Google+Search
If you know the cut-off between states no complicated modeling is
necessary, using something like thi
Hello,
Just reverse the xlim values, it defaults to c(min, max), use c(max, min).
x <- 1:10
plot(x)
plot(x, xlim=c(10, 1))
Hope this helps,
Rui Barradas
Em 29-07-2012 18:23, sappy escreveu:
Hello,
does anybody know, how to reverse the elements of the x-axis. At now my
x-axis for example goe
Thanks,
for the moment it works. But is there a possibility for a logarithmic
x-Axis? When i use log='x' i get only a vertical line.
Greetings
--
View this message in context:
http://r.789695.n4.nabble.com/Reverse-order-of-x-axis-tp4638275p4638282.html
Sent from the R help mailing list archiv
HI Yolande,
No problem.
I tried to get a solution to your old post yesterday after converting xts
object to dataframe. But, still I am getting the error message that the
lengths differ. I don't know how to fix that.
A.K.
From: Yolande Tra
To: arun
Thanks a lot. It Works.
--
View this message in context:
http://r.789695.n4.nabble.com/Simple-x-y-Plot-tp4638262p4638274.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/l
Hi,
As there is not much information like str() or the data, it is difficult to
comment.
But, try this (considering your x and y are factors):
x<-c("1","4","7","9","10","15")
y<-c("3","5","8","6","5","14")
dat1<-data.frame(x,y)
str(dat1)
'data.frame': 6 obs. of 2 variables:
$ x: Factor
Hello,
does anybody know, how to reverse the elements of the x-axis. At now my
x-axis for example goes from 0, 0.5, 1, 1.5, ... to 99.5, 100.0
Is there a way to change the x-axis, like this: 100.0, 99.5, 99.0, ..., 0.5,
0. The 100.0 should start at left x-axis and the 0 shold be on the right.
Gre
On Tue, Jul 24, 2012 at 09:26:49AM -0700, olemissrebs1123 wrote:
> I was wondering if there is a way in R to find k nearest neighbors of various
> orders, say order 2, 3, or 4. In otherwords neighbors of neighbors of
> neighbors. You get the idea. I know that I can use knearneigh(matrix.data,
> k)
On Sun, Jul 22, 2012 at 05:34:08PM -0700, bilelsan wrote:
> Hi,
> Thanks a lot for answer. It is what I mean.
> But the code does not seem to work (
Hi.
I am sorry for a late reply. I was on vacations one week.
Can you specify the problem?
I get
e1 <- 2
e2 <- 3
k <- 3
f <- 0
for (r
Thanks. It was very helpful.
Y
On Sun, Jul 29, 2012 at 2:45 AM, arun wrote:
> Hello,
>
> I tried to do the same thing that you have done. Without the timestamps
> as rownames (xts object), there were no errors.
>
> dat1<-read.table(text="
> dive_id datetime speciescount si
Please post on R-sig-mac (see the posting guide, footer of this email).
They will need to know how you are running R (command-line or R.app) and
your language settings.
On 29/07/2012 09:32, 肖文迪 wrote:
Dear sir/madam,
I encountered some problems when running R on my computer. To be honest, I
On 2012-07-29 08:18, sappy wrote:
Dear Community,
i have read in a table with two column from a *txt-File. What i get is a
data-frame wit two column.
After that i allocate this 2 column to x and y. Plotting this, i obtain a
picture that looks like a bar plot (something like a grid).
Is that beca
On 29.07.2012 17:18, sappy wrote:
> Dear Community,
>
> i have read in a table with two column from a *txt-File. What i get is a
> data-frame wit two column.
> After that i allocate this 2 column to x and y. Plotting this, i obtain a
> picture that looks like a bar plot (something like a grid).
>
Try this: You had some 'indexing' problems. You were accessing the
columns of the dataframe incorrectly. You are also accessing 'list'
so you might want to review the Intro to R on indexing:
> datos.mx1 <-
> read.table('http://r.789695.n4.nabble.com/file/n4638257/PETmx1.csv',head=TRUE,sep=';')
On Jul 29, 2012, at 10:32 , 肖文迪 wrote:
> Dear sir/madam,
>
> I encountered some problems when running R on my computer. To be honest, I
> am only a beginner of computer programming and I have no idea how to deal
> with it. I have tried to change the font in "system preference" but it did
> not w
Hi there,
I got a question that is both about stats and R. Imagine two alternative
stochastic processes:
a. Each subject has an exponential distribution of lifetime, with a parameter
lambda; If I simulate 100 such subjects and rank their lifetimes, they'd look
like this:
>plot(sort(rex
Hello!
Is there an implementation of the MetaCost algorithm in R?
I found a project here:
https://r-forge.r-project.org/scm/viewvc.php/src/mlrCost/metacost.r?root=mlr&view=log
But I'm not sure about its status - it seems unfinished to me.
My goal is to use MetaCost for cost-sensitive learning of
Dear Community,
i have read in a table with two column from a *txt-File. What i get is a
data-frame wit two column.
After that i allocate this 2 column to x and y. Plotting this, i obtain a
picture that looks like a bar plot (something like a grid).
Is that because x and y is in factor-formatted?
I need to create a software and use R engine in my software. but I don't know
how to use R code in my software same www.revolutionanalytics.com.
Rapid Miner has 2 section. one of them is using for application and the
other is used for researcher for extended it.
--
View this message in context:
Dear sir/madam,
I encountered some problems when running R on my computer. To be honest, I
am only a beginner of computer programming and I have no idea how to deal
with it. I have tried to change the font in "system preference" but it did
not work. Can you tell me how to get it right?
The syste
I am new to this field and I am currently studying the most basic problem of
statistics, I think.
I have an indicator that is 0 or 1 and many categorical and continuous
variables. I have to create a predictive model for the indicator.
Could anyone provide me a direction in terms of packages that
Hi there!
My question is not necessarily specific to R, bit I still hope that I
can find help here. I appreciate any suggestions; how to do/improve my
analysis, what stuff to read more on etc...
I am interested in a dependent variable A. I measured A of 10
individuals at 7 different levels of
Hello erverybody,
I have a problem with my second for-loop.
1. First i read the tables.
datos.mx1 <- read.table('PETmx1.csv',head=TRUE,sep=';')
datos.min <- read.table('PETmin.csv',head=TRUE,sep=';')
http://r.789695.n4.nabble.com/file/n4638257/PETmx1.csv PETmx1.csv
http://r.789695.n4.nabble.
On Jul 28, 2012, at 8:55 AM, stefan23 wrote:
> Dear all,
> I know that my question is somewhat special but I tried several times to
> solve the problems on my own but I am unfortunately not able to compute the
> following test statistic using the quantreg package. Well, here we go, I
> appreciate
On Sat, Jul 28, 2012 at 10:48 AM, David Romano wrote:
> Context: I'm relatively new to R and am working with very large datasets.
>
> General problem: If working on a dataset requires that I produce more than
> two objects of roughly the size of the dataset, R quickly uses up its
> available mem
Wrong list! Post on r-sig-mixed-models instead of here.
However, this is really not an R question. It appears that you are
looking for remote statistical consulting, which I consider rather
hazardous. Sort of like having a virtual thesis advisor. I believe you
would be better off talking with your
You cannot have two sets of column names in a data.frame
You can do this
rbind(X, Y)
Summary G Y R
1 Acc 12 12 13
2 Bcc 11 14 15
3 Ccc 13 15 16
4 Acc 10 11 12
5 Bcc 13 12 11
6 Ccc 11 16 20
John Kane
Kingston ON Canada
> -Original Message-
> From: saileshch
I think that first you need to tell us
:what kind of map you are using,
what mappig package(s) you are using
Why you want the colours and what data set you are drawing on to get these
colours (Note it possible provide some sample data (See ?dput as a way to do
this
And provide any code that you
Hello,
return( list(y, x, z, dy, dx) )
# or
return( list(y=y, x=x, z=z, dy=dy, dx=dx) )
That's ONE variable returned, a list. In the first case you access the
list members by number,
ret <- dgp.par(...)
ret[[ 1 ]] # 'y' value
In the second case, by number or name.
ret[[ 4 ]]
ret[[ "dy" ]]
On Jul 28, 2012, at 17:37 , Giorgio Monti wrote:
> I'm a student. I'm working on a research using the statistical program "R
> 2.15.1".
> Here's my problem: how i can do a regression considering only values over a
> certain limit?
> For example, considering the dataset "Workinghour" of the "Ecdat
Hi!
I have some questions about R function. I try to write a function for
multi-returns. The function code is as attachment.
dgp.par<-function(ai, bi, t, n)
{
t0<-t+20
y0<-matrix(0, nr=t0, nc=n)
y0[1,]<-ai/(1-bi)
for(tt in 2:t0)
{ y0[tt,]<-ai+bi*y0[tt-1,]+rnorm(n, 0, 1) }
y<-y0[21:t0,]
x<-y0[2
On Feb 18, 2011, at 14:20 , Jan wrote:
> One of the references you googled suggests that intercepts should never
> be omitted. Is this true even if I know that the physical reality behind
> the numbers suggests an intercept of zero?
No. That'll be a piece of pragmatic advice caused by the experie
On Feb 18, 2011, at 14:20 , Jan wrote:
> Hello Achim,
>
>> Not quite. Consult your statistics textbook for the correct interpretation
>> of p-values. Under the null hypothesis of a true intercept of zero, it is
>> very likely to observe an intercept as large as 13.52 or larger.
> thank you for
Hello,
I tried to do the same thing that you have done. Without the timestamps as
rownames (xts object), there were no errors.
dat1<-read.table(text="
dive_id date time species count size
1 08/06/2008 8:49:00 S.OYT 15 6
1 08/06/2008 8:49:00 S.atrovirens 1 23
",head
Hello,
Isn't the same question posted on stackoverflow
(http://stackoverflow.com/questions/11705062/generating-beta-binomial-responses-with-covariates)?
I guess you got the answer there.
In general, cross-posting is not that preferred in R.
A.K.
- Original Message -
From: Anamika C
On Jul 28, 2012, at 3:28 PM, Anamika Chaudhuri wrote:
Hi All:
I am trying to generate Beta-Binomial data with regressors using R.
I have
used the following code to generate Beta-Binomial data. Now I want
to add
a covariate to the equation. I would then like to use the simulated
data to
55 matches
Mail list logo
