The function you programed expects you to provide 7 arguments. In the first
case, you explicitly specify each of the seven arguments, i.e., you tell the
function: this is yu, this is yf, and so forth. In the second case, you only
specify 2 arguments, t and par[1,1:16]. So the function thinks that
Dear R developers:
I am a PHD candidate student in the school of public health of Peking
University and my major is genetic epidemiology. I am learning the FAM-MDR
algorithm, which is used to detect the gene-gene and gene-environment
interactions in the data of pedigree. The codes were written
Hi,
I'm currently reworking a report, originating from a MS Access database, but
should be implemented in R.
Now I'm facing the task to convert a lot of queries to postgreSQL.
What I want to do is make a function which takes the MS Access query as an
argument and returns the pgSQL version.
So:
I would like to know whether there is a faster way to do the below
operation (updating vec1).
My objective is to update the elements of a vector (vec1), where a
particular element i is dependent on the previous one. I need to do this on
vectors that are 1 million or longer and need to repeat that
Hi,
I am getting the follwoing error while installing gsubfn_0.6-4.tar.gz library
for R. R version is 2.15.1 and i am installing on Redhat linux version
2.6.18-238.9.1.el5
(mockbu...@x86-002.build.bos.redhat.commailto:mockbu...@x86-002.build.bos.redhat.com)
(gcc version 4.1.2 20080704 (Red
Hi,
I am facing an issue while installing RODBC library on Redhat Linux version
2.6.18-238.9.1.el5
(mockbu...@x86-002.build.bos.redhat.commailto:mockbu...@x86-002.build.bos.redhat.com)
(gcc version 4.1.2 20080704 (Red Hat 4.1.2-50))
Warning: invalid package
Hi,
Can someone please tell me what are the steps to follow for installing RHBASE
library for R 2.15.1.
Regards,
Divya
CAUTION - Disclaimer *
This e-mail contains PRIVILEGED AND CONFIDENTIAL INFORMATION intended solely
for the use of the addressee(s). If
Hi,
In R under cygwin I have trouble to correctly display help in text
format. One problem arises when there are single qoutes in the text like
in ?help which looks like this
helppackage:utils R Documentation
Documentation
Description:
Usage:
Hello,
try this:
x - c(SELECT [public_tblFiche].[Fichenr], [public_tblArtnr].[Artnr], SELECT
public_tblFiche.Fichenr, public_tblArtnr.Artnr)
# The square backets [ and ] should removed
x - gsub([][], , x)
# and xxx_xxx.xxx should become \xxx\.\xxx\\.\xxx\
x -
On 24-08-2012, at 06:49, Gopi Goteti wrote:
I would like to know whether there is a faster way to do the below
operation (updating vec1).
My objective is to update the elements of a vector (vec1), where a
particular element i is dependent on the previous one. I need to do this on
vectors
On Thu, Aug 23, 2012 at 09:49:33PM -0700, Gopi Goteti wrote:
I would like to know whether there is a faster way to do the below
operation (updating vec1).
My objective is to update the elements of a vector (vec1), where a
particular element i is dependent on the previous one. I need to do
Hi
Well, I am not sure if this is what you want but same result can be achieved by
vec1 - (probs=p00)*(probs=p10)
Petr
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Gopi Goteti
Sent: Friday, August 24, 2012 6:50 AM
To:
On Fri, Aug 24, 2012 at 10:34:14AM +0200, Petr Savicky wrote:
On Thu, Aug 23, 2012 at 09:49:33PM -0700, Gopi Goteti wrote:
I would like to know whether there is a faster way to do the below
operation (updating vec1).
My objective is to update the elements of a vector (vec1), where a
Hello,
Each block of probs range from p00 to p10 is last value before the block.
Example:
probs: .1 .1 .5 .5 .5 .9 .9
vec1 : 0 0 0 0 0 1 1
probs: .9 .9 .5 .5 .5 .1 .1
vec1 : 1 1 1 1 1 0 0
So you can eliminate a loop.
# modification
f5 - function () {
vec1 -
Hello,
I've put the short version here and if anyone wants to run the code with
CollocInfer, I've given the full version in the file analysis.
I come at the question of array attributes and dimnames
to try to simplify.
In a CollocInfer LS.profile analysis using this array 'Y' constructed
as
On Thu, Aug 23, 2012 at 09:49:33PM -0700, Gopi Goteti wrote:
I would like to know whether there is a faster way to do the below
operation (updating vec1).
My objective is to update the elements of a vector (vec1), where a
particular element i is dependent on the previous one. I need to do
Hi,
Shortly after my first post I posted an answer including the fix I found; which
seems to work. Through the archives I found that my code snippet got filtered
out and appended as an attachment (which was not my intent).
This was my suggestion:
for(i in seq(length(ss$name))) {
Greetings,
I would like to plot a curve (in color red) on a surface in a 3D plot.
Say
x - as.vector(seq(-1,1,0.2))
dim(x) - c(length(x),1)
y - as.vector(seq(-1,1,0.2))
dim(y) - c(1,length(y))
z - x%*%y # (x_iy_j)
# 3D plot of z(x,y)=xy:
persp(x,y,z)
I would like to plot a curve (in color red) on a surface in a 3D plot.
Perhaps trans3d would be relevant?
?persp 's examples include an example of adding a line to a 3d plot using
trans3d
S
***
This email and any attachments are
Hi,
I'm doing some easy calculations to normalize some values. This looks like
this:
x=mean(a+b+c+d ...)
a=a-x
b=b-x
c=c-x
d=d-x
...
mean(a+b+c+d ...) --- Should now be 0!
However, I'm getting results like -2.315223e-18
This is really near to 0 but not very aesthetic.
Can I prevent this? Or is
Thanks for your reply.
Does what you said by resources mean memory or something else? Inside my
loop, I removed the objects that are created but not used by the next loop
and did garbage collection as well. Do you have any idea how I should
modify my code such that the system won't kill it?
Hi,
Is there a Branch and Bound routines or library for R?.
Thanks,
David
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide
Hi,
I should preface this problem with a statement that although I am sure this
is a really easy function to write, I have tried and failed to get my head
around writing functions in R. I can use R where functions exist to do what
I want done, but have found myself completely incapable of writing
Hi,
Do you try 'RSiteSearch(Branch Bound)'?
--
Noia Raindrops
noia.raindr...@gmail.com
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and
Silje,
Thanks for reporting this. Should be fixed for version 1.7-20 (but
please let me know if not!)
best,
Simon
On 14/08/12 12:08, silje skår wrote:
Hi,
I am using the gam function in the mgcv package, I have random effects in
my model (bs=re) this has worked fine, but after I updated
On Aug 24, 2012, at 5:48 AM, Frederik Bertling
frederik.bertl...@stud.uni-due.de wrote:
Hi,
I'm doing some easy calculations to normalize some values. This looks like
this:
x=mean(a+b+c+d ...)
a=a-x
b=b-x
c=c-x
d=d-x
...
mean(a+b+c+d ...) --- Should now be 0!
However, I'm getting
Dear Duncan,
many thanks for helping. It works fine.
Cheers,
Marius
Duncan Murdoch murdoch.dun...@gmail.com writes:
On 12-08-19 3:47 PM, Marius Hofert wrote:
Dear Duncan,
I recently asked a question concerning patchDVI on r-help, see
,
|
I have never seen that before. It has been independently verified that
gsubfn works on Fedora Red Hat as you can see here:
http://cran.r-project.org/web/checks/check_results_gsubfn.html
The message about Tcl/Tk in your log suggests that there is something
wrong with your version of R itself.
Sorry, I just double checked and the options statement should be:
options(gsubfn.engine = R)
Again, I am not sure if that is sufficient given that there is clearly
something wrong with your version of R.
On Fri, Aug 24, 2012 at 8:59 AM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
I have
Hello,
This is FAQ 7.31 Why doesn't R think these numbers are equal?
As for your second question whether this behavior is desirable I think
so, we should be aware that floating-point arithmetics has limits. In
your case, a precision limit. At an R pompt run the instructions
?.Machine
Kev,
The dist() function handles more than 2 dimensions.
Using the example you provided ...
mydat - structure(list(Species = c(spA, spB, spC, spD),
x = c(2.9, 5.5, 1.4, 8.3),
y = c(34.2, 46.5, 48.6, 56.1),
z = c(0.54, 0.45, 0.84, 0.48),
n = c(15.7, 19.4, 24.8,
Yes, the resources operating systems usually kill for are memory.
No, you have not provided a reproducible example. In general, you need to do
something different, such as choose a different algorithm, run on a different
computer, or split your problem into smaller pieces.
Hello folks,
I found a strangeness while experimenting with POSIXct vectors and
lists. It seems that coerced NA's aren't real NAs, at least as
considered by is.na()?
date_vec = c(as.POSIXct(now()), as.POSIXct(now()+1),NA,b)
date_vec
[1] 2012-08-22 15:00:46 COT 2012-08-22 15:00:47 COT NA
[4]
On Fri, Aug 24, 2012 at 12:48:54PM +0200, Frederik Bertling wrote:
Hi,
I'm doing some easy calculations to normalize some values. This looks like
this:
x=mean(a+b+c+d ...)
a=a-x
b=b-x
c=c-x
d=d-x
...
mean(a+b+c+d ...) --- Should now be 0!
However, I'm getting results like
I'm very new to R and just finding my way, so be gentle!
I've hit a swift halt doing some summary statistics on a simple continuous data
field, divided into two categories. I'm getting the following error message. I
am unclear why length(names(tth$Mins.to.hospital)) is zero and how to alter
Thank you kindly for both of the replies I've received, that does indeed work
perfectly. I had been looking at the description of that function and it
reads as though it only deals with 2-dimensional data. Thanks again!
Kev
--
View this message in context:
The easiest way may be to use lmList in the nlme library:
#simulate data
d-rep(1:10,each=10)
x-rnorm(100)
e-rnorm(100)
y-2*x+e
require(nlme) #or install and load package
lmList(y~x|d)
#predicted values are obtained with:
predict(lmList(y~x|d)
HTH,
Daniel
jeff6868 wrote
Hi everybody,
Hello,
You don't need to write a function. Try the following.
nms - paste0(species, 1:4)
mat - matrix(rnorm(16), ncol=4, dimnames = list(nms, nms))
?dist
dist(mat)
dist(mat, diag = TRUE, upper = TRUE)
Hope this helps,
Rui Barradas
Em 24-08-2012 11:56, Arbuckle escreveu:
Hi,
I should
Hi everybody,
I have a question about applying a specific function (with the calculations
I want to do), on a list of elements.
Each elements are like a data.frame (with nrows and ncolumns), and have the
same structure.
At frist, I had a big data.frame that I splitted in all my elements of my
What are your expectations as to what
length(names(tth$Mins.to.hospital)) should be returning? You need
to at least provide some data so we can reproduce the error, or
'str(tth)'. My guess is that tth$Mins.to.hospital does not have any
'names' attributes and therefore your error. So what is the
On Thu, 23 Aug 2012, Gary Dong wrote:
I'm wondering if the gls function reports pseudo R. I do not see it by
summary(). If the package does not report, can I calculate it in this
way?
Adjusted pseudo R squared = 1 - [(Loglik(beta) - k ) / Loglik(null)] where
k is the number of IVs.
We've
Hello,
You must post a data example to get some help. Use
dput( head(tth, 50) ) # paste the output of this in a post
As for the warnings, they are not errors. They are telling you that it
can't make a replacement. substitute(x) is probably returning NULL and
the aggregate return value's
Or use ave() to compute the within-group ranks (reversed, so max has rank 1)
and select
the elements whose ranks are 1:
f2 - function (DATA)
{
stopifnot(is.data.frame(DATA), all(c(distance, id, month) %in%
names(DATA)))
revRanks - ave(DATA[[distance]], DATA[[id]], DATA[[month]],
Hi,
I am interested in implementing a special variant of
balloonplot. Let me
explain with an example dataset from the reference manual :
library(gplots)
data(Titanic)
dframe-as.data.frame(Titanic)
survived-dframe[dframe$Survived==Yes,]
attach(survived)
I think your first problem is the coersion done by 'c' when you are
mixing objects of various types: you have POSIXct and character. What
were your expections?
x - Sys.time()
str(x)
POSIXct[1:1], format: 2012-08-24 13:12:31
y - c(x, 'b')
str(y)
POSIXct[1:2], format: 2012-08-24 13:12:31 NA
Hello,
Your example doesn't run, lmList needs a 'data' argument.
set.seed(8109)
d - rep(1:10, each=10)
x - rnorm(100)
e - rnorm(100)
y - 2*x + e
dat - data.frame(x=x, y=y, d=d, e=e)
model - lmList(y ~ x | d, data = dat)
predict(model)
To the op: if you already have the larger data.farme
How do I read/write libsvm data into/from R?
The libsvm format is sparse data like
class/target[ attribute number:attribute value]*
e.g.,
1 10:3.4 123:0.5 34567:0.231
0.2 22:1 456:03
The foreign library does not seem to provide the necessary functionality.
Any suggestions? Code?
Thanks!
I used summary -rbind.fill(agency,prop) it worked like a charm. Thanks
everyone.
--
View this message in context:
http://r.789695.n4.nabble.com/Concatenating-data-frames-in-R-versus-SAS-tp4641138p4641219.html
Sent from the R help mailing list archive at Nabble.com.
Here's another pretty straightforward solution, using the plyr pkg:
DF - data.frame(id, month, distance, bearing)
# variables as defined in the OP
require(plyr)
DF1-ddply(DF, .(id,month), summarize,
maxdist = max(distance),
maxbearing = bearing[which.max(distance)])
Peter
Thanks for your reply, Jim.
On 8/24/2012 12:14 PM, jim holtman wrote:
I think your first problem is the coersion done by 'c' when you are
mixing objects of various types: you have POSIXct and character.
Yes, that's something I may have confounded. Still, the warning I'm
getting is In
I am new to R and I have the following SAS statements:
if otype='M' and ocond='1' and entry='a.Prop' then MOC=1;
else MOC=0;
How would I translate that into R code?
Thanks in advance
--
View this message in context:
http://r.789695.n4.nabble.com/if-then-in-R-versus-SAS-tp4641225.html
Sent
On Aug 24, 2012, at 1:03 PM, ramoss ramine.mossad...@finra.org wrote:
I am new to R and I have the following SAS statements:
if otype='M' and ocond='1' and entry='a.Prop' then MOC=1;
else MOC=0;
How would I translate that into R code?
Thanks in advance
See ?ifelse and ?Logic, both
[Redirected from R-Devel...]
Not that I recall running across such, but does R (or CRAN package)
provide something equivalent to PHP's escapeshellcmd() function
to escape shell job control, wildcards, etc?
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R-help@r-project.org mailing list
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Marc Schwartz
Sent: Friday, August 24, 2012 12:06 PM
To: ramoss
Cc: r-help@r-project.org
Subject: Re: [R] if then in R versus SAS
On Aug 24, 2012, at 1:03 PM, ramoss
Hi all,
I am encountering an RODBC problem in R 2.15.1 in windows 64 bit which I do not
encountered in the same set up in windows 32 bit (the latest binary version of
RODBC in both cases from the same depository gotten by
install.packages(RODBC), Oracle ODBC client software installed in 64
I don't know PHP, but what does escapeshellcmd() provide over and
above what system() / system2() do?
Cheers,
Michael
On Fri, Aug 24, 2012 at 2:48 PM, Roebuck,Paul L proeb...@mdanderson.org wrote:
[Redirected from R-Devel...]
Not that I recall running across such, but does R (or CRAN package)
read.matrix.csr does not close the connection:
library('SparseM')
Package SparseM (0.96) loaded.
read.matrix.csr(foo)
...
Warning message:
closing unused connection 3 (foo)
--
Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000
http://www.childpsy.net/
On 8/23/12 7:37 AM, David Lyon david_ly...@yahoo.com wrote:
Can someone show me some code to do normalization by the median of some
control genes for the example below?
Many Many Thanks in advance
This strategy selects a subset of genes (called ³control genes²) and makes the
median of
On 8/24/12 2:59 PM, R. Michael Weylandt michael.weyla...@gmail.com
wrote:
On Fri, Aug 24, 2012 at 2:48 PM, Roebuck,Paul proeb...@mdanderson.org
wrote:
[Redirected from R-Devel...]
Not that I recall running across such, but does R (or CRAN package)
provide something equivalent to PHP's
Hi R-Helpers,
I don't think I need to post a dataset for this question but if I do, I
can. Anyway, I am having a lot of trouble with the ifelse command.
Here is my code:
vn$PM.DIST_flag - ifelse( (vn$PM.EXP 0.0) (vn$PM.DIST.TOT != 1.0), 1,
0 )
And here is my output that doesn't make ANY
On Fri, Aug 24, 2012 at 3:22 PM, Jennifer Sabatier
plessthanpointohf...@gmail.com wrote:
Hi R-Helpers,
I don't think I need to post a dataset for this question but if I do, I
can. Anyway, I am having a lot of trouble with the ifelse command.
You probably should have: dput() makes it super
Oops, sorry, I thought I was in plain text. I can't tell the
difference because I use so little formatting in my emails.
Try this (a truncated version since I have to hand space everything):
PM.EXP PM.DIST.TOT PM.DIST_flag
0 00
6417 1
... and if Michael is correct, there is a lesson here: Think of how
much time and aggravation you would have saved yourself if you had
FIRST made an effort to read the docs. The FAQ's are there for a
reason. As is An Introduction to R, which also should be read before
posting on this list.
If
Another strategy is to sort by month, id, and, in reverse order,
distance and select the rows that start each month/id run. This
can be much faster than the other ways when there are lots of
month/id combinations.
f1 - function (DATA)
{
stopifnot(is.data.frame(DATA),
I looked in the archives and couldn't find anything that really
addressed my question so here it is -
Does anyone know of any web sites/environments that hosts R for free,
web-based, multi-user access to the R engine. My apologies if the
question is too simplistic for this forum. The reason I
On 2012-08-24 13:22, Jennifer Sabatier wrote:
Hi R-Helpers,
I don't think I need to post a dataset for this question but if I do, I
can. Anyway, I am having a lot of trouble with the ifelse command.
Here is my code:
vn$PM.DIST_flag - ifelse( (vn$PM.EXP 0.0) (vn$PM.DIST.TOT != 1.0), 1,
0 )
Bert,
I will thank you not to condescend to me, as I am too damn old (40) to
be treated that way. You didn't even offer a solution to my problem.
You only came to chastise me with regards to your assumptions about
me, which is very annoying.
While I am at the beginner level of R, I am not an
Hi Peter,
I'm really sorry, I thought I was in plain text. I don't use any
formatting in my emails and in Gmail the HTML looks the same as plain
text.
Anyway, I've attached the data (I didn't think we could do that but I
am frequently wrong).
I say many cases because this is just a subset of
Hello,
Michael's standard guess, FAQ 7.31, was also mine, but is wrong. The
error is in Jennifer's flag column, not the result of her ifelse. (!)
x - scan(what=character, text=
PM.EXP PM.DIST.TOT PM.DIST_flag 0 0 0 0 0 0 0 0 0 177502 1 0 31403 1
0 0 0 0 1100549 1 0 38762 1 0 0 0 0
BTW - no one else who has replied to this topic was snobby or
unfriendly and I thank you very much for trying to help me.
It's just Bert is not the first to respond to my request for help as
such. As someone looking forward to becoming an advanced R programmer
in my statistical work it is
On 8/24/12 4:02 PM, Matthew K. Hettinger mkhettin...@mathet.com wrote:
I looked in the archives and couldn't find anything that really
addressed my question so here it is -
Does anyone know of any web sites/environments that hosts R for free,
web-based, multi-user access to the R engine. My
Hi Rui,
Thanks so much for responding but I think with my HTML problem the vn
data you made must not be the same. I tried running your code on the
data (I uploaded a copy) and I got the same thing I had before.
Jen
On Fri, Aug 24, 2012 at 5:28 PM, Rui Barradas ruipbarra...@sapo.pt wrote:
Off the wall / wild guess, do you use attach() frequently? Not
entirely sure how it would come up, but it tends to make weird errors
like this occur.
M
On Fri, Aug 24, 2012 at 4:36 PM, Jennifer Sabatier
plessthanpointohf...@gmail.com wrote:
Hi Rui,
Thanks so much for responding but I think
Hi All,
has anyone run into maximum depth of nested JSON arrays in either rjson or
RJSONIO ?
I seem to be able to get up to 10 depth levels without problem, but
crossing over to 11 either causes an error or fails to load the nodes
properly.
with RJSONIO I tried:
a =
Hi Michael,
No, I never use attach(), exactly for the reasons you state. To do
due diligence I did a search of code for the function and it didn't
come up (I would have been shocked because I never us it!).
Now that real data is up, does your suggestion still apply? I am
reading it now.
No data arrived to me.
Rui Barradas
Em 24-08-2012 22:46, Jennifer Sabatier escreveu:
Hi Michael,
No, I never use attach(), exactly for the reasons you state. To do
due diligence I did a search of code for the function and it didn't
come up (I would have been shocked because I never us it!).
On Fri, Aug 24, 2012 at 4:46 PM, Jennifer Sabatier
plessthanpointohf...@gmail.com wrote:
Hi Michael,
No, I never use attach(), exactly for the reasons you state. To do
due diligence I did a search of code for the function and it didn't
come up (I would have been shocked because I never us
On Fri, Aug 24, 2012 at 4:50 PM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
On Fri, Aug 24, 2012 at 4:46 PM, Jennifer Sabatier
plessthanpointohf...@gmail.com wrote:
Hi Michael,
No, I never use attach(), exactly for the reasons you state. To do
due diligence I did a search of code
Oh, sorry, I first though you couldn't post data to the list, but then
I thought I remembered other people doing so, so I tried to post it.
Here is a copy.
Thanks,
Jen
On Fri, Aug 24, 2012 at 5:49 PM, Rui Barradas ruipbarra...@sapo.pt wrote:
No data arrived to me.
Rui Barradas
Em
Hi Michael,
Thanks for letting me know how to post data. I will try to upload it
that way in a second.
I can usually use code to make a reproducible dataset but this time
with the ifelse behaving strangely (perhaps, it's probably me) I
didn't think I could do it easily so I figured I would just
Hi there,
I'm using presence-absence data in a gam (i.e. 0 or 1 as values)
I am trying to run a gam with 'dummy covariates' i.e. 1~1
unfortunately my model:
*
model-gam(1~1, data=bats, family=negbin)*
keeps putting out:
*
Error in gam(1 ~ 1, data = bats, family = negbin) :
Not enough
Hi,
You missed a close bracket.
node4:{
...
nodeDef:{
node4:{
...
# need a close bracket here
}
},
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Noia Raindrops
noia.raindr...@gmail.com
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I see that you got other responses while I was composing an answer.
Your 'example.csv' did come through for me, but I still can't
replicate your PM.DIST_flag variable. Specifically, observations
30, 33, 36 and 40 are wrong.
I agree with Rui, that there's something else going on. The data
you've
Sam,
Thanks for pointing this out, but I have to point out in turn that this isn't
a SparseM function,
it is part of the package e1071, maintained by David Meyer.
Roger
Roger Koenker
rkoen...@illinois.edu
On Aug 24, 2012, at 3:07 PM, Sam Steingold wrote:
read.matrix.csr does not close
AHHH I GOT IT!!
And I *think* I understand about floating point arithmetic..
In this case vn$PM.DIST.TOT is the sum of proportions. So, it should
be anywhere 0 and 1.
In our case, if it's anything other than 1 when vn$PM.EXP is greater
than 0 then it means something is wrong
On Fri, Aug 24, 2012 at 7:29 PM, Jennifer Sabatier
plessthanpointohf...@gmail.com wrote:
AHHH I GOT IT!!
And I *think* I understand about floating point arithmetic..
Well then you're doing much better than the rest of us: it's quite a
difficult subject and only gets trickier as
Hah - I guess I didn't mean I understood it in full as I expect I will
run into it again without anticipating it.
But, now that I know the old adage I will look there first when I
run into a problem.
Also, I used the square root of machine precision instead - thanks for
that, too.
Thank you,
You probably mean shQuote().
Regards,
Yihui
--
Yihui Xie xieyi...@gmail.com
Phone: 515-294-2465 Web: http://yihui.name
Department of Statistics, Iowa State University
2215 Snedecor Hall, Ames, IA
On Fri, Aug 24, 2012 at 3:17 PM, Roebuck,Paul L proeb...@mdanderson.org wrote:
On 8/24/12 2:59 PM,
Hi,
I have dates as follows:
1/4/2006 0:00:00 AM
It is a factor at present.
How do I find out the day of the week from this? How do I convert to Julian
date format?
Thanks.
Chetty
--
Professor of Family Medicine
Boston University
Tel: 617-414-6221, Fax:617-414-3345
emails:
Three steps:
1) as.character to get character representation
2) as.POSIXct to convert to time
3) julian() or strptime() to get Julian date.
Read the docs (esp on part 2 and 3) to get the format strings just right.
Cheers,
Michael
On Aug 24, 2012, at 10:30 PM, Veerappa Chetty
On Aug 24, 2012, at 2:34 AM, Michael Meyer wrote:
Greetings,
I would like to plot a curve (in color red) on a surface in a 3D plot.
Say
x - as.vector(seq(-1,1,0.2))
dim(x) - c(length(x),1)
y - as.vector(seq(-1,1,0.2))
dim(y) - c(1,length(y))
z - x%*%y #
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