Somebody just might be able to help if you read the Posting Guide mentioned in
the email footer, post using plain text, and make a reproducible example [1].
[1]
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
I have so many gz files of the type (filename.nc.gz) where nc stands for
netcdf file.
I used the following commands :
path=C:/Documents and settings/AER/NorthAmerica-West/zipedfiles/ #
examples of zipped files
files - list.files(path, recursive=TRUE, full.names=TRUE)
files - grep(.*\\.gz$,
Hi Borja,
You may issue:
attach(data)
which results in adding your column names to the search path of R for name
resolving.
Pierrick Bruneau
CRP Gabriel Lippmann
On Wed, Mar 20, 2013 at 11:17 PM, Borja . borjalato...@outlook.com wrote:
Good day.
I create a data frame like this:
thanks for your answers and sorry that I didnt explain the
problem/question sufficiently in the first place. here it comes:
the problem is that when I create a formula inside a function and some
large objects exist there too, then saving the output of the formula
will save the in this case large
On Mar 21, 2013, at 7:39, Pierrick Bruneau pbrun...@gmail.com wrote:
Hi Borja,
You may issue:
attach(data)
No -- bad idea -- dangerous -- confusing statefulness, etc. (See explanations
in the archives as to why)
which results in adding your column names to the search path of R for
Or simply
subset(dat, a 0)
HTH,
Jorge.-
On Thu, Mar 21, 2013 at 6:58 PM, Michael Weylandt wrote:
On Mar 21, 2013, at 7:39, Pierrick Bruneau pbrun...@gmail.com wrote:
Hi Borja,
You may issue:
attach(data)
No -- bad idea -- dangerous -- confusing statefulness, etc. (See
OK, I just had a look at the Good Practice section of ?attach, it indeed
looks bad...
Maybe this danger should be emphasized in ?attach, or the function even
deprecated (why maintaining ugly patterns when better solutions exist?)
On Thu, Mar 21, 2013 at 8:58 AM, Michael Weylandt
Hi,
It must be an easy question but how to boxplot a subset of data:
data = read.table(my_data.txt, header = T)
boxplot(data$var1[data$loc == nice]~data$loc_type[data$loc == nice])
#in this case, i want to display only the boxplot loc == nice
#doesn't display the boxplot of only loc == nice. It
Hi
as David pointed out e is probably slightly bigger than 0. Easiest way is
probably
if (round(e) 0) { res -bugs(list(); k -5+2 }
Regards
Petr
From: Andras Farkas [mailto:motyoc...@yahoo.com]
Sent: Wednesday, March 20, 2013 3:53 PM
To: PIKAL Petr; Robert Baer
Cc: r-help@r-project.org
Hi
in interactive sessions it is convenient way to call data frame columns and
repeatedly use them in calculations.
You just have to be careful with some functions as they can be useful but
dangerous.
rm(something) removes an object from environment without warning.
It is usually not a fault
On 03/21/2013 07:40 PM, carol white wrote:
Hi,
It must be an easy question but how to boxplot a subset of data:
data = read.table(my_data.txt, header = T)
boxplot(data$var1[data$loc == nice]~data$loc_type[data$loc == nice])
#in this case, i want to display only the boxplot loc == nice
#doesn't
Dear all,
I would like to have all unique combinations in the following matrix
TimeIndex- rbind (c(1,Week_of_21_07-29_03),
c(2,Thursday_21_03),
c(3,Friday_22_03),
c(4,Saturday_23_03),
c(5,Sunday_24_03),
c(6,Monday_25_03),
Hello,
I am using function princomp from the package psych.
I have my principle component object mypc:
mypc - princomp(covmat=mycor)
plot(mypc) # shows me a screeplot
Question: how could I actually see the values displayed in the screeplot. I
don't mean on the graph - I just want to know the
It isn't entirely clear to me if you want to remove duplicates or expand your
matrix. Check ?unique or ?expand.grid. Here are some guesses of what you may
want to do.
unique(TimeIndex)
expand.grid(as.data.frame(TimeIndex))
expand.grid(as.data.frame(unique(TimeIndex)))
TimeIndex2 -
The plot shows the variation for each component and mypc$sdev gives you the
standard deviation.
If you want to know the variation, use mypc$sdev^2.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Dimitri Liakhovitski
Sent:
Hi,
I try to run the Iramuteq software with R, on Windows 7 professional
(latest version of Iramuteq, and I tried with the three latest versions of
R). I properly installed the packages and coded the texts, but anytime I
want to run the analysis, I receive this error message : Erreur R None1
None
Dear R software faculty:
      There is a question bothering me. That is why we can not set the
property of row.names=false when we output csv data. But there exists that
parameter in R help. Hoping for your reply!
Best regards!
                          Â
Data? Code?
https://github.com/hadley/devtools/wiki/Reproducibility
John Kane
Kingston ON Canada
-Original Message-
From: aborr...@ulb.ac.be
Sent: Thu, 21 Mar 2013 12:10:13 +0100
To: r-help@r-project.org
Subject: [R] Compatibility problem Iramuteq / R : help !!!
Hi,
I try to
If I remember correctly this was possible a few versions ago but was dropped.
To do it now you need to use write.table and set row.names = FALSE.
John Kane
Kingston ON Canada
-Original Message-
From: lina...@pku.edu.cn
Sent: Thu, 21 Mar 2013 16:27:18 +0800 (CST)
To:
Thank you very much!
On Thu, Mar 21, 2013 at 8:16 AM, Blaser Nello nbla...@ispm.unibe.ch wrote:
The plot shows the variation for each component and mypc$sdev gives you
the standard deviation.
If you want to know the variation, use mypc$sdev^2.
-Original Message-
From:
On 03/21/2013 08:38 AM, John Kane wrote:
If I remember correctly this was possible a few versions ago but was dropped.
To do it now you need to use write.table and set row.names = FALSE.
John Kane
Kingston ON Canada
I used write.csv with row.names=FALSE yesterday with no issues at all in
Hello Rui,
This also works!
Thanks so much!
Cheers,
Rebecca
-Original Message-
From: Rui Barradas [mailto:ruipbarra...@sapo.pt]
Sent: Wednesday, March 20, 2013 3:34 PM
To: Yuan, Rebecca
Cc: 'R help'
Subject: Re: [R] How to look at the source code for predict()
Hello,
In the case of
I could have sworn I could not to this in 2.10 or something like that.
Thanks for saying it is still there.
John Kane
Kingston ON Canada
-Original Message-
From: kevin.tho...@utoronto.ca
Sent: Thu, 21 Mar 2013 08:52:17 -0400
To: jrkrid...@inbox.com
Subject: Re: [R] Excuse me
I have two indicator variables ABS and DEFF. I want to create another
indicator variable which will take value 1 if either ABS=1 or DEFF=1.
Otherwise, it will take value 0. How can I make that?
[[alternative HTML version deleted]]
__
I am going to use clara for gene expression analysis, so tried to play around
with the examples from R document:
http://127.0.0.1:10699/library/cluster/html/clara.html
Everything looked fine until I tried to plot the results:
it says: waiting to confirm page change...
I waited for more
Try
ifelse(ABS ==1 | DEFF == 1, 1, 0)
HTH,
Jorge.-
On Fri, Mar 22, 2013 at 12:02 AM, Tasnuva Tabassum t.tasn...@gmail.comwrote:
I have two indicator variables ABS and DEFF. I want to create another
indicator variable which will take value 1 if either ABS=1 or DEFF=1.
Otherwise, it will
Hi
I went through some extensive search to find suitable method (package,
function) to fit multiple peaks. The best I found is ALS package but it
requires rather complicated input structure probably resulting from GC-MS
experimental data and seems to be an overkill to my problem.
I have
Your variable loc_type combines information from two variables (loc and
type). Since you are subsetting on loc, why not just plot by type?
boxplot(var1~type, data[data$loc==nice,])
--
David L Carlson
Associate Professor of Anthropology
Texas AM
Hello,
I have a data frame
mdl.summary
est.coef std.errt.stat
intercept 0.0011625517 0.0002671437 4.351784
aa -0.0813727439 0.0163727943 -4.969997
dummy1 -0.0002534873 0.0001204000 -2.105376
Hello all,
I use the arima to get a model, i.e.
fit = arima(x,order=c(1,0,0))
and I know I can get the following from fit via
est.coef = coef(fig)
est.aic = fit$aic
std.err = sqrt(diag(vcov(fit)))
t.stat = est.coef/std.err
Well, you might start by reading ?pdf, where you will find that it is for
storing **graphics** not data!
Then read ?write.table -- but this will be a text file, not a pdf.
-- Bert
On Thu, Mar 21, 2013 at 6:20 AM, Yuan, Rebecca
rebecca.y...@bankofamerica.com wrote:
Hello,
I have a data
Here is one way of doing it:
x
est.coef std.errt.stat
intercept 0.0011625517 0.0002671437 4.351784
aa-0.0813727439 0.0163727943 -4.969997
dummy1-0.0002534873 0.0001204000 -2.105376
dummy2-0.0007784864 0.0001437537 -5.415417
bb-0.0002856727
Hello Jim,
I tried the following as you mentioned, but I still do not have the error while
opening the pdf file.
pdf(file = result2, paper = a4r)
mdl.summary.out-capture.output(mdl.summary)
plot.new()
Hello,
I cannot find it in ?arima, does someone know how to specify no interception
term in arima?
Thanks,
Rebecca
--
This message, and any attachments, is for the intended r...{{dropped:5}}
Here is the script I ran to get PDF output which is attached:
x
# capture the output as a string vector
xo - capture.output(x)
pdf('/temp/output.pdf')
plot.new() # new page
# now add text to plot
text(0
, 0.5
, paste(xo, collapse = '\n')
, family = 'mono'
, cex = 0.6
, adj =
On 03/21/2013 02:08 PM, Jorge I Velez wrote:
Try
ifelse(ABS ==1 | DEFF == 1, 1, 0)
or
as.numeric(ABS | DEFF)
(faster?)
Göran
HTH,
Jorge.-
On Fri, Mar 22, 2013 at 12:02 AM, Tasnuva Tabassum t.tasn...@gmail.comwrote:
I have two indicator variables ABS and DEFF. I want to create
OK, did a test where I did both - wrote a ~6Mx58 double matrix as a .txt file
(write.big.matrix), but also left the backing file + descriptor file as-is
(rather than deleting it as I usually do). Opened a different R session.
Compared contents of first 100 rows of both, they seem identical.
Hello Jim,
This graphics.off() helps me to release the previous pdf file that was had the
error message. Thanks again for your help!
Cheers,
Rebecca
From: jim holtman [mailto:jholt...@gmail.com]
Sent: Thursday, March 21, 2013 10:07 AM
To: Yuan, Rebecca
Cc: R help
Subject: Re: [R] How to store
Hello Jim,
Thanks very much!
This time I am able to get the pdf file.
Best regards,
Rebecca
From: jim holtman [mailto:jholt...@gmail.com]
Sent: Thursday, March 21, 2013 10:04 AM
To: Yuan, Rebecca
Cc: R help
Subject: Re: [R] How to store data frames into pdf file and csv file.
Here is the
If you are getting an error when trying to open the PDF file, then you may
of had a error writing out a previous file. I always issue the following
command to clear out any pending graphic output:
graphics.off()
On Thu, Mar 21, 2013 at 9:49 AM, Yuan, Rebecca
rebecca.y...@bankofamerica.com
HeLLo,
I'm new in R, I would like to use it for diagnostics with bayesian network,
I want to know how can I calculate inference and if can I enter my
probability tables like logical or arithmetic equation,
Thanks.
--
View this message in context:
I am getting error messages while installing R package lme4. Please advice
thanks
Pramod
trying URL 'http://cran.mtu.edu/src/contrib/lme4_0.99-0.tar.gz'
Content type 'application/x-gzip' length 1074142 bytes (1.0 Mb)
opened URL
==
I would use a logical variable, with values TRUE and FALSE, instead
of a numeric indicator. E.g., I find the following easier to follow
bL - ABS==1 | DEFF==1
if (any(bL)) { do.this() }
than
bN - ifelse(ABS == 1 | DEFF == 1, 1, 0)
if (any(bN == 1)) { do.this() }
The latter leaves
Hi,
I am using the function nomogram in the rms package for survival analysis.
How is the order in which variables determined and how can I change it? I use
it with a cph() model.
Many Thanks
Eleni Rapsomaniki
Clinical Epidemiology Group
Department of Epidemiology and Public Health
University
According to ?ros, one of the arguments is:
reverseT: A name of a function to use for reversing the transformation
after performing the ROS fit. Defaults to 'exp'.
And in the Details section:
By default, 'ros' performs a log transformation prior to, and
after operations over the
Hi all,
it seems that there is problem with function adaptIntegrate,
when the integration limits is infinity.
Please see the code below. The second integration does not
seem to work.
Can anyone familiar with this give some help?
Thank you with much.
Hanna
library(mnormt)
Hello,
Is there a better way to use paste such as:
a =
paste(colnames(list.indep)[1],colnames(list.indep)[2],colnames(list.indep)[3],colnames(list.indep)[4],colnames(list.indep)[5],sep=+)
a
[1] aa+dummy1+dummy2+bb+cc
I tried
a = paste(colnames(list.indep)[1:5],sep=+)
a
[1] aa
It looks like you want collapse rather than sep:
list.indep - data.frame(aa=1:4, dummy1=1:4, dummy2=1:4, bb=1:4, cc=1:4)
paste(colnames(list.indep), collapse=+)
[1] aa+dummy1+dummy2+bb+cc
On Thu, Mar 21, 2013 at 11:15 AM, Yuan, Rebecca
rebecca.y...@bankofamerica.com wrote:
Hello,
Is there a
Under ?adaptIntegrate, you will find the link to
http://ab-initio.mit.edu/wiki/index.php/Cubature#Infinite_intervals, where it
says that Integrals over infinite or semi-infinite intervals is possible by a
change of variables.
-Original Message-
From: r-help-boun...@r-project.org
dat2-as.data.frame(matrix(1:20,ncol=5))
colnames(dat2)- c(aa,dummy1,dummy2,bb,cc)
paste(colnames(dat2),collapse=+)
#[1] aa+dummy1+dummy2+bb+cc
A.K.
- Original Message -
From: Yuan, Rebecca rebecca.y...@bankofamerica.com
To: R help r-help@r-project.org
Cc:
Sent: Thursday, March 21,
Sorry, I am not sure I understand your question.
You have 5 boxplots(if I remember correctly) on a single page and these 5
boxplots have titles a1,a2,c1,c2,t1 (or something like that).
Could you try:
par(mfcol(c(3,2)) and see if that helps. (not tested)
A.K.
Pikal and Robert,
sorry for previous email, indeed, the code is working just fine!
Thanks for the pointer David Winsemius, you were right, I was getting a
character as numeric(0), which the system did not recognize as the number 0,
thus the openBUGS run was called.
Thanks for the help
You might want to start by reading the Bayesian task view at
http://probability.ca/cran/
John Kane
Kingston ON Canada
-Original Message-
From: s_zerm...@esi.dz
Sent: Thu, 21 Mar 2013 07:06:40 -0700 (PDT)
To: r-help@r-project.org
Subject: [R] Bayesian network
HeLLo,
I'm new in
Got it. Thank you very much!
library(mnormt)
library(cubature)
ff - function(x, rho){
mu - rep(0,3)
Sigma -(1-rho)*diag(3)+matrix(rho,3,3)
f - dmnorm(x/(1-x^2), mu, Sigma)*((1+x^2)/(1-x^2)^2)
f
}
On Mar 21, 2013, at 8:30 AM, Andras Farkas wrote:
Pikal and Robert,
sorry for previous email, indeed, the code is working just fine!
Thanks for the pointer David Winsemius, you were right, I was getting a
character as numeric(0), which the system did not recognize as the number
0,
Hello Sarah,
Yes, that is what I want.
Thanks!
Cheers,
Rebecca
-Original Message-
From: Sarah Goslee [mailto:sarah.gos...@gmail.com]
Sent: Thursday, March 21, 2013 11:21 AM
To: Yuan, Rebecca
Cc: R help
Subject: Re: [R] easy way of paste
It looks like you want collapse rather than
Hello A.K.,
Thanks! I use collapse instead of sep and get the answer.
Cheers,
Rebecca
-Original Message-
From: arun [mailto:smartpink...@yahoo.com]
Sent: Thursday, March 21, 2013 11:21 AM
To: Yuan, Rebecca
Cc: R help
Subject: Re: [R] easy way of paste
i'm having trouble using rJava on ubuntu 11.10 amd 64-bit.
when i try to source my code that uses rJava, i get the following error:
Error : .onLoad failed in loadNamespace() for 'rJava', details:
call: dyn.load(file, DLLpath = DLLpath, ...)
error: unable to load shared object
Pramod Anugu pramod.r.anugu at jsums.edu writes:
I am getting error messages while installing R package lme4. Please advice
This would be better on the r-sig-mixed-mod...@r-project.org list.
You haven't told us, but I'm guess from what you've pasted below
that you're on a Unix system, and
Hi,
Try this:
directory- /home/arunksa111/dados
GetFileList - function(directory,number){
setwd(directory)
filelist1-dir()[file.info(dir())$isdir]
direct-dir(directory,pattern = paste(MSMS_,number,PepInfo.txt,sep=),
full.names = FALSE, recursive = TRUE)
direct-lapply(direct,function(x)
Given an arbitrary set of character vectors:
myvect1 - c(abc,3,4)
myvect2 - c(2,3,4)
I would like to develop a function that will convert any vectors that can
be PROPERLY converted to a numeric (myvect2) into a numeric, but leaves
character vectors which cannot be converted (myvect1) alone. Is
On 21/03/2013 18:20, Jonathan Greenberg wrote:
Given an arbitrary set of character vectors:
myvect1 - c(abc,3,4)
myvect2 - c(2,3,4)
I would like to develop a function that will convert any vectors that can
be PROPERLY converted to a numeric (myvect2) into a numeric, but leaves
character
Using capital letters does not improve clarity... it just offends people.
Does read.table and friends not do this to your satisfaction already with
as.is=TRUE? If not, shouldn't coercing it and checking for NA serve?
---
Hello,
In fact, it's written there, in ?arima:
Further, if include.mean is true (the default for an ARMA model), this
formula applies to X - m rather than X.
So, use include.mean = FALSE
Hope this helps,
Rui Barradas
Em 21-03-2013 13:56, Yuan, Rebecca escreveu:
Hello,
I cannot find it
Hi Arun, thank you. I will look through that later on today when I get a
chance. I have to complete another part of this project now.
Irucka
-Original Message-
From: arun kirshna [via R] [ml-node+s789695n4661145...@n4.nabble.com]
Sent: 3/12/2013 10:35:39 PM
To: iruc...@mail2world.com
Hi Arun, thank-you very much! The 2nd option worked perfectly. That was
what I wanted.
Now, I have another question. I am using the R packages dataRetrieval
and EGRET from https://github.com/USGS-CIDA/WRTDS.
I have 2 objects Daily and Sample that have the naming convention (Names
=
Hi A.K
This is working
layout(matrix(c(1,2,3,4), 4, 1, byrow = TRUE))
plot(sin, -pi, 10*pi)
plot(sin, -pi, 20*pi)
plot(sin, -pi, 30*pi)
plot(sin, -pi, 40*pi)
dev.off()
but if I add this line
png(filename = fname.png, width = 900, height = 600, units = 'px')
no plot is generated.
where is the
Yes, thanks but with package for the Bayesians networks ?
--
View this message in context:
http://r.789695.n4.nabble.com/Bayesian-network-tp4662059p4662085.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing
I am teaching myself R for use in Psych research. I don't understand the error
message I am getting or how to fix it. Any suggestions will be greatly
appreciated
df1=read.table(fastfood.txt, header=TRUE); df1
c(t(as.matrix(df1)))
r = c(t(as.matrix(df1))) # response data
r
you are welcome!
On Thu, Mar 14, 2013 at 6:01 PM, susieboyce [via R]
ml-node+s789695n4661296...@n4.nabble.com wrote:
Thank you for your reply. I have found the pdflatex file. I was able to
solve my 'Sweave.sty not found' error by coping the Sweave.sty file and
pasting it into the working
Hello,
I am attempting to use nlme to model the response of 19 groups. I am able to
get a reasonable fit of all of the groups to the observed data using an
exponential decay model (a*exp-x*b). The problem is that when I plot the
fitted values to residuals, it demonstrates a pattern of
The pdflatex is the an excutable programe located in your MiKTexâ bin
folder, I guess you have not add your MikTex bin folder into your Windows
PATH environment
On Thu, Mar 14, 2013 at 12:55 AM, susieboyce [via R]
ml-node+s789695n4661220...@n4.nabble.com wrote:
I have located my Sweave.sty
Yep, type.convert was exactly what I was looking for (with as.is=TRUE).
Thanks!
On Thu, Mar 21, 2013 at 1:31 PM, Prof Brian Ripley rip...@stats.ox.ac.ukwrote:
On 21/03/2013 18:20, Jonathan Greenberg wrote:
Given an arbitrary set of character vectors:
myvect1 - c(abc,3,4)
myvect2 -
Hi,
So when you run the code suggested:
png(filename = fname.png, width = 900, height = 600, units = 'px')
layout(matrix(c(1,2,3,4), 4, 1, byrow = TRUE))
plot(sin, -pi, 10*pi)
plot(sin, -pi, 20*pi)
plot(sin, -pi, 30*pi)
plot(sin, -pi, 40*pi)
dev.off()
exactly like that, you do not get a file
Hello Rui,
Thanks! I get it now. Should have read the documentation carefully!
Cheers,
Rebecca
-Original Message-
From: Rui Barradas [mailto:ruipbarra...@sapo.pt]
Sent: Thursday, March 21, 2013 2:46 PM
To: Yuan, Rebecca
Cc: R help
Subject: Re: [R] How could I specify no interception
Hi,
I am not sure about the problem.
I am able to generate the pdf.
with the codes:
png(filename = fname.png, width = 900, height = 600, units = 'px')
layout(matrix(c(1,2,3,4), 4, 1, byrow = TRUE))
plot(sin, -pi, 10*pi)
plot(sin, -pi, 20*pi)
plot(sin, -pi, 30*pi)
plot(sin, -pi, 40*pi)
dev.off()
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Rodinsky, Dr Harold R.
Sent: Thursday, March 21, 2013 11:32 AM
To: 'r-help@r-project.org'
Subject: Re: [R] Error Message During ANOVA
I am teaching myself R for use in Psych
Hello,
Inline.
Em 21-03-2013 13:34, Yuan, Rebecca escreveu:
Hello all,
I use the arima to get a model, i.e.
fit = arima(x,order=c(1,0,0))
and I know I can get the following from fit via
est.coef = coef(fig)
est.aic = fit$aic
std.err =
Hi,
set.seed(45)
test1-data.frame(columnA=rnorm(7,45),columnB=rnorm(7,10)) #used an example
probably similar to your actual data
apply(test1,2,function(x) sprintf(%.1f,median(x)))
#columnA columnB
# 44.5 10.2
par(mfrow=c(1,2))
lapply(test1,function(x) {b-
Hi Guys,
Using the PGLMM function in Picante it is theoretically possible to
generate other models (than the 5 flagged ones indicated) by
differently structuring the independent variable (Y), dependent
variables (X), and covariance matrices (VV). I was wondering anyone
could give me some advice
Hi everyone,I would like to test a mediation model, that has several control
variables. More specifically, I would like to test the indirect effect with
bootstrapping. However, all the packages I have found so far (e.g. MBESS) only
allow testing a simple mediation model (One independent, one
Hi all,
Is there an R function that computes the probabilty or quantiles of
order statistics of multivariate normal?
Thank you.
Hanna
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Hi,
Just about anything can be bootstrapped, that's one of the things that
makes bootstrapping great! Use e.g., the boot package, and bootstrap
the product of the coefficients.
Alternatively the mediation package
(http://cran.r-project.org/web/packages/mediation/index.html) might
help, though
Dear List,
I'm getting an error in mgcv, and I can't figure out where it comes
from. The setup is the following: I've got a fitted GAM object called
MI, and a vector of prediction data (with default values for
predictors). I feed this into predict.gam(object, newdata = whatever)
via the
On Mar 21, 2013, at 1:44 PM, li li wrote:
Hi all,
Is there an R function that computes the probabilty or quantiles of
order statistics of multivariate normal?
Thank you.
There is an mvtnorm package. I don't know what you mean by quantiles of order
statistics of multivariate normal,
Frank Burbrink burbrink666 at gmail.com writes:
Using the PGLMM function in Picante it is theoretically possible to
generate other models (than the 5 flagged ones indicated) by
differently structuring the independent variable (Y), dependent
variables (X), and covariance matrices (VV). I was
nomogram does not have an option for specifying a new order for the
variables. With some exceptions you should be able to reorder the variables
in the model formula to achieve the desired result.
Frank
Eleni Rapsomaniki-3 wrote
Hi,
I am using the function nomogram in the rms package for
R^n for n 1 is not an ordered set.
albyn
On Thu, Mar 21, 2013 at 02:32:44PM -0700, David Winsemius wrote:
On Mar 21, 2013, at 1:44 PM, li li wrote:
Hi all,
Is there an R function that computes the probabilty or quantiles of
order statistics of multivariate normal?
Thank you.
Dear Ista and F.Doerwald,
F.Doerwald could also fit a model using sem() in the sem package, and then use
deltaMethod() in the car package to get the estimated value and standard error
of any function of model coefficients that he or she chooses.
Sorry, I didn't read the original posting.
I
Petr,
You could use nonlinear regression to fit two Guassian peaks. For example,
fit - nls(sig ~ d + a1*exp(-0.5*((time-c1)/b1)^2) +
a2*exp(-0.5*((time-c2)/b2)^2),
start=list(a1=15, b1=20, c1=315, a2=4, b2=50, c2=465, d=1.5), data=temp)
plot(temp, type=l)
lines(temp$time, predict(fit), lty=2,
Hi,
con-file(Rout1112.text)
Lines1- readLines(con)
close(con)
indx-rep(rep(c(TRUE,FALSE),each=2),2)
Lines2-Lines1[!grepl([A-Za-z],Lines1)]
res-read.table(text=paste(gsub(^\\d+\\s+,,Lines2[indx]),gsub(^\\d+\\s+,,Lines2[!indx])),sep=,header=FALSE)
nm1-unlist(strsplit(gsub(^
Well, yeah ... but it doesn't necessarily follow that the result converges
to what you want. Bootstrapping extreme order statistics is an example.
-- Bert
On Thu, Mar 21, 2013 at 1:49 PM, Ista Zahn istaz...@gmail.com wrote:
Hi,
Just about anything can be bootstrapped, that's one of the
Hello,
Em 21-03-2013 21:42, Albyn Jones escreveu:
R^n for n 1 is not an ordered set.
Theorem. All sets are well ordered.
(This theorem is equivalent to the Axiom of Choice.)
Rui Barradas
albyn
On Thu, Mar 21, 2013 at 02:32:44PM -0700, David Winsemius wrote:
On Mar 21, 2013, at 1:44
Hello:
I am using R raster package to replace ArcGIS when processing multiple shp
files. However, when I export R raster back to ArcGIS, it couldn't recognize R
raster file correctly. For example, I used {raster} package and got a
RasterLayer as followed.
class : RasterLayer
I have a 3D field of a scalar variable (x, y, z, value). Is there a way to
generate a vector field from this data--gradient at defined points? I found
the rasterVis package for 2D data, but as yet nothing for 3D data.
Thanks,
Scott Waichler
Pacific Northwest National Laboratory
Richland, WA
On Mar 21, 2013, at 4:40 PM, Waichler, Scott R wrote:
I have a 3D field of a scalar variable (x, y, z, value). Is there a way to
generate a vector field from this data--gradient at defined points? I found
the rasterVis package for 2D data, but as yet nothing for 3D data.
Can't you just
Hello,
I have a large data.frame of 80,000 rows where each row is a record. Each
record is indexed by a unique ID in the first column.
I need to update values for a column for *some* of the records. I was given a
data.frame with about 10,000 rows and two columns. The first is the record ID,
indx - match(main.df$id, key$id, nomatch = 0)
main.df$value[indx != 0] - key$value[indx]
Sent from my iPad
On Mar 21, 2013, at 20:57, Noah Silverman noahsilver...@ucla.edu wrote:
Hello,
I have a large data.frame of 80,000 rows where each row is a record. Each
record is indexed by a
Jim,
That's perfect. Thanks.
Also tried Neal's method, but it wound up be MUCH slower to build the index.
Thanks,
--
Noah Silverman, M.S.
UCLA Department of Statistics
8117 Math Sciences Building
Los Angeles, CA 90095
On Mar 21, 2013, at 6:07 PM, Jim Holtman jholt...@gmail.com wrote:
Hello Don, Jeff,
Thanks a lot for the comments and suggestions.
Best
Janh
On Thu, Mar 21, 2013 at 10:57 AM, MacQueen, Don macque...@llnl.gov wrote:
According to ?ros, one of the arguments is:
reverseT: A name of a function to use for reversing the transformation
after
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