I want to use the glht function.
In the linfct argument, I provide my linear functions to be tested.
I provide contrasts there, such as (for example)
c(Group1 - Group2 = 0, Group1 - Group3 = 0)
to compare group no 1 against the other groups.
I want to do Tukey's test in this fashion. Is it
Hi,
When I use any value greater than 2 for cex.main in title, I get
title(myTitle, cex.main= 5)
Error in title(myTitle, cex.main = 5) :
X11 font -adobe-helvetica-%s-%s-*-*-%d-*-*-*-*-*-*-*, face 2 at size 60 could
not be loaded
How to fix it?
Thanks
Carol
[[alternative HTML
Hi, every R user,
I wanna output names of objects, I googled codes from website, but it
was not what I wanted.
the codes are as following:
f - function (...)
{
unevaluatedArgs - substitute(...())
evaluatedArgs - list(...)
stopifnot(length(unevaluatedArgs) == length(evaluatedArgs))
# I have a daily series of count of transactions data i want to decompose
and forecast.
d-c(723, 772, 967, 897, 621, 684, 722, 764, 856, 819,
678, 708, 698, 832, 928, 834, 649, 676, 635, 729, 778, 817, 616,
598, 605, 851, 822, 791, 678, 703, 716, 834, 872, 831, 641, 610,
699, 840, 901, 789, 620,
mgcv:gam automatically imposes sum-to-zero constraints on the smooths in
a model (even if there is only one smooth). This is to avoid lack of
identifiability with the intercept. The constraint removes one
coefficient and shifts the curve...
best,
Simon
On 17/06/14 15:40, Alexander Engelhardt
I think it didn't converge. The warning message is for the whole fitting
iteration, whereas mod07.3.BASE.bam5.1$converged indicates whether
smoothing parameter selection converged at the final step of the iteration.
best,
Simon
On 17/06/14 19:10, Trevor Davies wrote:
I'm running some spatial
On 18-06-2014, at 10:50, Charles Thuo tcmui...@gmail.com wrote:
# I have a daily series of count of transactions data i want to decompose
and forecast.
d-c(723, 772, 967, 897, 621, 684, 722, 764, 856, 819,
678, 708, 698, 832, 928, 834, 649, 676, 635, 729, 778, 817, 616,
598, 605, 851,
On 18/06/2014 08:14, carol white wrote:
Hi,
When I use any value greater than 2 for cex.main in title, I get
title(myTitle, cex.main= 5)
Error in title(myTitle, cex.main = 5) :
X11 font -adobe-helvetica-%s-%s-*-*-%d-*-*-*-*-*-*-*, face 2 at size 60
could not be loaded
How to fix it?
On Mon, Jun 16, 2014 at 7:04 AM, Costas Vorlow costas.vor...@gmail.com wrote:
Dear Joshua,
Thanks for your reply. As I see, the solution you suggest aligns the time
stamps as required but leaves the aggregation results as is.
Hence, the last quarter data of every hour are not aggregated
Thanks Joshua.
Your time and input is much appreciated as always. What will happen if I
pick up manually the 00' hour. I.e.,
I count ever n'th (=4 quarters in my case) and pick up this observation,
forming a new XTS object. I should not have any alignment problems then,
should I?
Example:
Am 17.06.2014 23:11, schrieb jim holtman:
You were using 'rownames' incorrectly. Here is the correct way:
library(XLConnect)
wb - loadWorkbook(writeWorksheet.xlsx, create = TRUE)
createSheet(wb, name = CO2)
writeWorksheet(wb, CO2, sheet = CO2,rownames=Row Names)
saveWorkbook(wb)
Thank you I
On Wed, 18 Jun 2014 04:24:58 PM yzh lin wrote:
Hi, every R user,
I wanna output names of objects, I googled codes from website,
but it
was not what I wanted.
the codes are as following:
f - function (...)
{
unevaluatedArgs - substitute(...())
evaluatedArgs - list(...)
On 18/06/2014 12:54, Jim Lemon wrote:
On Wed, 18 Jun 2014 04:24:58 PM yzh lin wrote:
Hi, every R user,
I wanna output names of objects, I googled codes from website,
but it
was not what I wanted.
the codes are as following:
f - function (...)
{
unevaluatedArgs - substitute(...())
Would
f - function (...)
{
sapply(substitute(list(...)),deparse)[-1]
}
f(a1=log(1:4), m1=1:4, c1=pi)
a1 m1 c1
log(1:4) 1:4 pi
be equivalent?
I find the substitute(...()) construction completely mysterious, while
substitute(list(...)) makes sense to me.
Windows 8 (and earlier versions) has a disk cleanup tool that will let you
delete temporary files that might help. At the bottom of the screen on the
taskbar, click the folder icon to bring up a windows showing your drives and
folders. On the left side click on the drive you are interested in
One program that I have found valuable in looking at the size of files on
disk is SequoiaView. It creates a 'treemap' of the sizes of the files and
lets you zoom in to specific directories and such.
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you
On 18/06/2014 15:01, Bert Gunter wrote:
Would
f - function (...)
{
sapply(substitute(list(...)),deparse)[-1]
}
f(a1=log(1:4), m1=1:4, c1=pi)
a1 m1 c1
log(1:4) 1:4 pi
be equivalent?
I find the substitute(...()) construction completely mysterious, while
Ah, yes. Much better -- that is what match.call() is for.
As always, thanks for the insight,
Best,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom.
Clifford Stoll
On Wed, Jun 18,
Hi David,
Thank you for your help. The code you supplied is working, to an
extent. However, i'm only outputting the first monthly file into my
working directory.
Apologies as I'm a relatively new to R, so please bear with my
ignorance, have I not set up a loop correctly? Also, what is the
Hi,
I wanted to plot two different density profiles. My code looks like:
x1 - rnorm(100,mean=0,sd=1)
x2 - rnorm(100,mean=1,sd=1)
plot(density(x1),xlab=,col=red,main=)
par(new=T)
plot(density(x2),xlab=,col=blue,main=)
However, the x-axis values don't match up for the two plots. Is there a way
On 17 Jun 2014, at 16:38 , Therneau, Terry M., Ph.D. thern...@mayo.edu wrote:
As Peter D said, the clogit function simply sets up a special data set and
then calls coxph, and is based on an identity that the likelihood for the
conditional logistic is identical to the likelihood of a Cox
Try reading the docs!
?plot.default
... and note the xllim and ylim arguments.
Have you read An Introduction to R or some other R tutorial. If not,
you should do so before posting further.
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not information.
First you should do your best to forget that you ever saw the command
par(new=T), rip that page out of any book you saw it in, blacklist
any webpage etc. In general (as you see) it causes more problems than
it solves.
Now to do what you want there are a couple of options, one of the
simplest is
Dear R users,
Thank you so much for your help.
I got deleted all files in my C:\xxx\AppData\Local\Temp file and also run
suggested R codes to erase files.
I list them below as somebody may be interested in.
All in all, I got some space (1 GB) back, and compressing Stata data, I
achieved what
You probably want:
write.table(x, file = as.character(x$mon[1L]))
because 'input$mon[1]' will always pick the same month (first one in
'input')
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
On Wed, Jun
Thanks Greg!
On Wed, Jun 18, 2014 at 11:15 AM, Greg Snow 538...@gmail.com wrote:
First you should do your best to forget that you ever saw the command
par(new=T), rip that page out of any book you saw it in, blacklist
any webpage etc. In general (as you see) it causes more problems than
it
Dear Users,
This, substitute(paste(z,sigma)), small code doesn¡¦t work properly with text()
within a loop z in ¡V3:3, except if i don¡¦t use print(z) while plotting. What
may be the problem? This code is used in a user defined function. It was
running in older versions.
Thanks in advance.
Hi Greg and Jim.
In the end I solved by modifying the function.
I was just wondering if there is some function similar to Matlab's subplot,
which let you change the active plot.
Next time I will run in the same issue I will try the split.screen
function proposed by Jim.
Thanks a lot for the
On my system (see info at the end) the plot succeeds.
Can you plot other objects of class im?
(see ?im for examples)
Has it even been determined if the problem is with (a) the plotting
process, or (b) the structure of the object being plotted?
To check the structure of the object, you might
Dear R-users,
I have a 3200 by 3200 matrix that was build from a data frame that had
180 observations, with variables: x, y, blocks (6 blocks) and
treatments (values range from 1 to 180) I am working on. I build other
functions that seem to work well. However, I have one function that has
There is a subplot function in the TeachingDemos package, but its
purpose is to put a small plot somewhere inside of a large plot. You
can use it to position 2 plots on a blank plot. It does return the
information that you need to then go back and modify the individual
plots. However, it does
Thanks, Jim, but I also tried with this recourse, and can't reach to the
outcome I wanted...
Cleber Chaves
On Tue, Jun 17, 2014 at 9:22 PM, Jim Lemon j...@bitwrit.com.au wrote:
On Tue, 17 Jun 2014 08:58:12 PM Cleber Chaves wrote:
Dear all,
has a long time that I unsuccessfully try to
Hello Simon,
thanks for your response!
I incorporated the intercept, i.e. coef(my_gam)[1] into the spline. That
is, my B-spline coefficients are the intercept for the first one, and
for all others I added the intercept to them (see the code below if I'm
not clear)
Now I *almost* reproduce
Hi R-users,
### reproducible example:
library(gmp)
library(matlab)
library(Matrix)
library(foreach)
library(MASS)
library(mvtnorm)
#
## A function to create a field experiment
## Returns a data frame, called matdf
##
Hi all,
I have quite a specific problem with producing 300ppi plots in tiff format
for publication. I have found ggsave to work beautifully with a single
plot, which can then be exported to GIMP to compress the resulting large
tiff file. However, it seems to run into trouble when plotting two
I noticed a missing line in the code associated with my question. I've
re-supplied the question now with that line.
Sorry for the trouble,
Adam
I have a dataset of peptide 15N/14N ratios from four experiments (where
cells are grown under different conditions and were fed either
I have a dataset of peptide 15N/14N ratios from four experiments (where
cells are grown under different conditions and were fed either 15N or 14N
nitrate aka plant food if you are interested) and I want to normalize each
of these ratios to the median 15N/14N value from all 6000 peptides from
each
Dear Rolf,
The problem persists with the function plot.im(), or plot (density ()),
similar to with(bei.extra, plot (elev)). This problem occurs only with my
personal machine, to another machine this problem does not occur. However,
when I use another function, such kde2d () in the MASS package
I don't feel any need to help you if you won't read the Posting Guide and
follow its guidance... specifically you provide explanation (good) but not a
reproducible example (see e.g. [1]) and you are posting in HTML which often
corrupts your code (and is definitely not a
First order of business, without looking in detail at the code, is to avoid
the use of dataframes. If all your values are numerics, then use a matrix.
It will be faster execution.
I did see the following statements:
newmatdf-Des[[i]]
Des[[i]]-newmatdf
why are you just putting
Hi Jim. If I avoid the dataframe, how can use the function model.matrix() to
build the incident matrices X, And Z? I tried saving the design as matrix
but ghen I got the wrong design matrix.
Thanks.
Laz
Sent from my LG Optimus G™, an ATT 4G LTE smartphone
-- Original
Adam Hayward a.hayward at sheffield.ac.uk writes:
Hi all,
I have quite a specific problem with producing 300ppi plots in tiff format
for publication. I have found ggsave to work beautifully with a single
plot, which can then be exported to GIMP to compress the resulting large
tiff file.
Don,
Pablo and I have been through all that. The structure of the im
object was fine. I had no problem at all plotting the image on my
system. Pablo could get nothing but blank plots on his system. The
problem arose, as he said in a post just now, only on his personal machine.
The
On 19/06/14 01:36, Pablo Ramón wrote:
Dear Rolf,
The problem persists with the function plot.im http://plot.im(), or
plot (density ()), similar to with(bei.extra, plot (elev)). This problem
occurs only with my personal machine, to another machine this problem
does not occur. However, when I use
One of the other things to do is to use Rprof to see where time is being
spent. This will help focus on what has to be changed. This may point out
how much time is being spent manipulating dataframes.
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what
See this?
`[[alternative HTML version deleted]]`
Means your efforts at including data have been sabotaged by failing to read the
Posting guide and send plain text.
Then this line:median[i] = median(normHL)
Gets you:
Error in median[i] = median(normHL) :
object of type
Hi,
I'm trying to solve simple problem. How to pass arguments to specific search
method in RWeka package using BayesNet classifier. Here is code example:
BNet - make_Weka_classifier(weka/classifiers/bayes/BayesNet)
K2=weka.classifiers.bayes.net.search.local.K2
wcontrol -
Let me just say that the expertise and support on this List is amazing,
and I'm very grateful. I'm learning a lot from your discussions.
I will not be at my problematic machine again until Friday 20 June. I
will take these steps then, and try to provide as many details about the
system as I can.
My suggestion is not entirely satisfactory, but it's got me out
of a few jams.
When I can't get the RWeka syntax to work, I resort to using
direct weka code in a system call. One such example looks like
this and will make sense if you know how Weka does things.
system(java
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