Dear colleagues,
This is to inform you that Version 1.3.5 of the R package apclusterhas
been released on CRAN last Friday. This version is a quick fix of a
larger update (Version 1.3.4) that was released one day earlier. The
update to Version 1.3.4 included several internal and user-visible
Hi There!
I have a time series data for 13 years with freqency of 23 per year. I have
plot the curve on R.
Is it possible to refer to the point inbetween the nodes...
eg. say the time series ts1 has ts1[1] 0.25 and ts1[2]=0.4. is it possible
to get the time when ts1 reach to 0.3??
--
View this
Hi
Not much to cook from. Maybe
?approx
Regards
Petr
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of So
Sent: Monday, June 30, 2014 7:05 AM
To: r-help@r-project.org
Subject: [R] Time series
Hi There!
I have a time
On 30 June 2014 02:44, Ira Sharenow irasharenow...@yahoo.com wrote:
I wish to query tables that are NOT in the default SQL Server 2012 database.
Now for the problem. I also want to read in the table dbo.sports. That
table is in the database sportsDB. I did not see any way to do so from
within
Hi,
How do I document an S3 class with roxygen2?
I create the class at the end of the method with:
class(res) - myclass
but how do I create an documentation entry for this class, where I can
describe the fields of the class (in case of myclass these are just
list entries)?
regards
--
Good morning,
for my data I've perform a Quasi-Poisson distribution and now I want to
perform a Double Poisson distribution
Could someone tell me if it is possible and how do it in R
I attach below my data
Tanks for help, best regards
Roberta Marino
intdata-
Hi everybody,
I`m Mark and I do my PhD in biology. I try using R to calculate a population
growth rate of animals grown on different types of food. Our workgroup has a
R-skript to do so, but sadly nobody, who knows how this works. I`ve never
used R before, but got some stuff
hi. Writing R Extensions provides a simple routine getListElement(),
said to be based on a similar routine in the package stats, for C code
to call to find a named element of a list . however, it doesn't work
for the argument list passed to a .External(), as that is a PairList
rather than a
Hallo!
I have this matrix:
SampleID, Day, Species1, Species2,Species3,...,Speciesn
1,Monday,abundance values
2,Monday,abundance values
11,Tuesday,abundance values
12,Tuesday,abundance values
21,Wednesday,abundance values
22,Wednesday,abundance values
I would like to plot the Days on the
Hi Jorge,
You may try:
library(dplyr)
library(tidyr)
#Looks like this is faster than the other methods.
system.time({wide1 - x2%%
select(-rate) %%
mutate(variable=factor(variable, levels=unique(variable)),id=factor(id,
levels=unique(id))) %%
Hi, I am running some rather complex mixtures of beta regressions using the
betamix() command from the betareg package (V. 3.0-4). If I am doing
exploratory regressions with only one random starting value (nstart=1) I
obtain results which converge after about 100 iterations. However, if I run
Rolf,
I hear you.
But, after reflection, ie I looked at my situation again, it is great :-)-O
el
Sent from Dr Lisse's iPad mini
On Jun 30, 2014, at 0:48, Rolf Turner r.tur...@auckland.ac.nz wrote:
On 30/06/14 10:32, Dr Eberhard W Lisse wrote:
Thanks,
I then set NA to 0, and can
Your script is failing at the first hurdle because you data are not being
imported properly. You should include
header=TRUE. sep=;
In the call to read.table.
Cheers.
Simon.
Sent from my iPhone
Sent from my iPhone
On 30 Jun 2014, at 7:10 pm, Mark Christjani m_christj...@gmx.de wrote:
Dear R-helpers,
I have 3 thermometers measuring soil temperature at 3 levels every 10
minutes. I want to determine the soil diffusivity, by solving the heat
equation. The heat equation is a partial differential equation. In my case,
the initial values are know and the boundary conditions are
On Mon, 30 Jun 2014 10:42:28 AM Tim Richter-Heitmann wrote:
Hallo!
I have this matrix:
SampleID, Day, Species1, Species2,Species3,...,Speciesn
1,Monday,abundance values
2,Monday,abundance values
11,Tuesday,abundance values
12,Tuesday,abundance values
21,Wednesday,abundance values
Hmm. Try setting extendInt=yes in the call to uniroot. You should also look
at the help page for uniroot. help(uniroot) May give you a clue. It's difficult
for me to debug code on my iphone. Well, more difficult than usual.
Best,
Simon.
Sent from my iPhone
On 30 Jun 2014, at 8:53 pm, Mark
Mark - good on you for jumping into R with both feet.
In addition to Simon's advice, the error message you are getting means
that the two endpoints (r.range in your case) do not give function
values that are of the opposite sign and so either the function has no
roots on the interval or has
There may be something wrong with your data: in all but one case you have lx=1
and mx=0. Uniroot may be having difficulty because of this.
Simon.
Sent from my iPhone
On 30 Jun 2014, at 9:09 pm, Simon Blomberg s.blombe...@uq.edu.au wrote:
Hmm. Try setting extendInt=yes in the call to
Thank you, Simon, for your input.
Data import works fine now, but the final equation still won`t work.
Console reads now:
setwd(c:/Mark)
table - read.table(r-TCO-Scene-Kontrolle.csv, header=TRUE, sep=;)
table
x lx mx
1 1 1.0 0.0
2 2 1.0 0.0
3
1. The computations behind the scenes produce the variance of the cumulative hazard.
This is true for both an ordinary Kaplan-Meier and a Cox model. Transformations to other
scales are done using simple Taylor series.
H = cumulative hazard = log(S); S=survival
var(H) = var(log(S)) = the
Hi all,
I have managed, with the help of glob2rx() to get two parts of a text
manipulation working. I have successfully gotten rid of the first and
second bits, but I have hit the wall trying to get rid of the last bit. Here's
an example:
initString-
\Delete this\:value1,\Delete this
Thank you Simon and David for your suggestions. They were most helpful. The
Skript is now working as it was originally planed.
Greetings
Mark
Gesendet: Montag, 30. Juni 2014 um 13:06 Uhr
Von: Simon Blomberg s.blombe...@uq.edu.au
An: Mark Christjani m_christj...@gmx.de
Hi, Bill
Thank you so much for your kind explanation. It's very clear too for someone
like me.
I should've remember this but somehow forgot that [] have a special meaning in
regular expression.
Lin
From: wdun...@tibco.com
Date: Sun, 29 Jun 2014
Hi Jim
What about trying to use what you want to keep
m=gregexpr('\\:value[12]+[}]?,', initString)
regmatches(initString, m)
[[1]]
[1] \:value1, \:value2},
Duncan
Duncan Mackay
Department of Agronomy and Soil Science
University of New England
Armidale NSW 2351
Email: home:
If everything Regular Expressions could do could be done with globbing then RE
would likely not exist.
I have interpreted your problem as:
Start at the beginning of the string (^)
match stuff that is not a colon ([^:])
match a colon (:')
keep stuff that is not a comma (([^,]*))
match a comma
Thanks for everyoneâs feedback.
library(RODBC)
con = odbcConnect(SQLServer2012)
orders1 = sqlFetch(con,dbo.orders)
odbcClose(con)
Allowed me to close the connection properly. Thanks.
However, I still cannot figure out how to connect to the second database
and table.
library(RODBC)
con2
Please post here using the plain text option in your email software because the
HTML is not coming through undamaged.
The first argument to the odbcConnect function is never SQL syntax... for SQL
Server it is always a Data Source Name (DSN) that has been predefined in the
ODBC administration
Hi
I can see that you do have troubles understanding how all this works using the
RODBC package. Peter wasn't really being helpful to you.
This is something that is quite difficult to help with not sitting beside you.
Do you not having some local help from e.g. the IT department?
However for
You are also missing the fact that loops are often not required in R. In this
case print() has a method for printing data frames and that method is
automatically used when you simply type the data.frame name or if you
explicitly call it with print(stockList):
stockList -
Hello,
I was hoping someone could point me in the direction towards a package
where I can use delaunay triangulation to create a polygon set where the
inside of the triangles are tagged with an estimate of a mean value of the
points making up the points of the triangle. This is fisheries trawl
Hi,
I'm working with tips data from reshape package.
library(reshape2)
I'm saving my plots as pdf and I was wondering whether it was possible
to print a different pdf for each 'wrapped' plot. Using the code below
as an example, I'd like to get 8 independent pdf files for each sex ~
day
If you really want to mix base and grid graphics (they don't play
nicely together as you have noticed) then you should really use the
gridBase package. There is at least one package for doing maps using
grid (ggmap or ggMaps or something similar) and there is the regular
text function for adding
I think the easiest most straight forward way would be to just throw it
into a loop and subset the data on each loop around (untested code below
but I'm sure you get the gist). ~Trevor
sex1-unique(tips$sex)
day1-unique(tips$day)
for (i in 1:length(sex1)){
for (j in 1:length(day1)){
Thank you Terry for the explanation!
John
From: Therneau, Terry M., Ph.D. thern...@mayo.edu
Sent: Monday, June 30, 2014 6:04 AM
Subject: Re: standard error of survfit.coxph()
1. The computations behind the scenes produce the variance of the cumulative
Hi, Greg: Thanks. Just what I asked. Spencer
On 6/30/2014 10:24 AM, Greg Snow wrote:
If you really want to mix base and grid graphics (they don't play
nicely together as you have noticed) then you should really use the
gridBase package. There is at least one package for doing maps using
One place to start would be the Spatial task view on CRAN.
The other would be to ask on R-sig-geo, where people who specialize in
spatial data hang out.
Delaunay triangulation is available in several packages. A simple search
for delaunay on the CRAN packages page will easily find at least one.
Hi Jim,
May be this helps:
library(stringr)
paste(str_extract_all(initString,
perl('(?=\\:)[[:alnum:]]+,?'))[[1]],collapse=)
#[1] value1,value2
A.K.
On Monday, June 30, 2014 9:58 AM, Jim Lemon j...@bitwrit.com.au wrote:
Hi all,
I have managed, with the help of glob2rx() to get two parts of a
kindly guide me on how i can delete and replace an element from a matrix t below
for example delete first element in column one and replace it with 50, third
element in column 2 by 90 and fifth element in column 3 by 100
t1-c(1,2,3,4,5)
t2-c(6,7,8,9,10)
t3-c(11,12,13,14,15)
t-cbind(t1,t2,t3)
Hello everybody,
I Would like to get some help to plot together, Principal Components
Analysis (PCA) and clusters.
I am handling environmental data from 25 locations spread across 5
different ecosystems.When grouped into 5 clusters, locations from different
ecosystems are arranged in the same
When I run code in R, my R console output stops before all the code has
complied. There are no error messages, but there must be an error
somewhere. Thanks in advance for any guidance.
[[alternative HTML version deleted]]
__
t[1, 1] - 50
t[3, 2] - 90
t[5, 3] - 100
Jean
On Mon, Jun 30, 2014 at 10:27 AM, IZHAK shabsogh ishaqb...@yahoo.com
wrote:
kindly guide me on how i can delete and replace an element from a matrix t
below
for example delete first element in column one and replace it with 50,
third element
What do you mean by stops? Can you at least show what was on the
console. Can you continue to enter commands? It is not clear what you are
talking about.
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
This is a long way from being a reproducible example with no data. You also
don't mention that you are using package vegan. I'll use the dune, dune.env
data included in that package:
library(vegan)
mydata.pca - rda(dune)
mydata.w - hclust(dist(dune), ward)
plot(mydata.w, hang=-1)
Insert
data(dune)
data(dune.env)
after library(vegan)
David C.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of David L Carlson
Sent: Monday, June 30, 2014 4:47 PM
To: Jackson Rodrigues; r-help@r-project.org
Subject: Re: [R] How
On 01/07/14 04:31, Trevor Davies wrote:
Hello,
I was hoping someone could point me in the direction towards a package
where I can use delaunay triangulation to create a polygon set where the
inside of the triangles are tagged with an estimate of a mean value of the
points making up the points
Hello,
I am new to R progaming and have just started using this program since last
week. What i want to achieve is to use R to determine patterns in sales/
customer complaint etc. information located in a mysql database. I am not sure
how to approach this or which technique i should use to do
On Mon, 30 Jun 2014 11:13:18 PM Jim Lemon wrote:
Hi all,
I have managed, with the help of glob2rx() to get two parts of a text
manipulation working. I have successfully gotten rid of the first and
second bits, but I have hit the wall trying to get rid of the last bit.
Here's an example:
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Shanae Clarke
Sent: Monday, June 30, 2014 1:58 PM
To: r-help@r-project.org
Subject: [R] Getting data from Table in RStudio
Hello,
I am new to R progaming and have just
Hi Arun,
Thank you very much for your suggestion.
While running some tests, I came across the following:
# sample data
n - 2000
p - 1000
x2 - data.frame(variable = rep(paste0('x', 1:p), each = n), id =
rep(paste0('p', 1:p), n), outcome = sample(0:2, n*p, TRUE), rate =
runif(n*p, 0.5, 1))
Here's a simple example:
setClass(foo, contains=numeric)
x - new(foo, 4)
# Division by scalar works
x / 2
An object of class foo
[1] 2
# Division by array blows up
y - array(2, c(2, 2))
x / y
Error in getDataPart(c(2, 2, 2, 2)) : node stack overflow
# Not sure I understand the error message,
Estimados, como puedo poner un super indice en la etiqueta de los ejes
de un grafico hecho con lattice ?? tengo que poner.
Specific growth rate (d-1)
y el -1 debe ir como superindice, no he podido encontrar esto.
Gracias, eric.
--
Forest Engineer
Master in Environmental and Natural
Con un ejemplo siempre se entiende mejor, algo como lo que sigue es lo que
buscas?
datos - data.frame( x = rnorm(25), y = rnorm(25))
library(lattice)
xyplot(datos$x ~ datos$y,
xlab= expression(Specific Growth Rate (d^-1)),
ylab= expression(y [+1]))
Espero te
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