Huh
and what is the result of e.g.
data$Rain[indicNAs[1]]
I bet that you will see
[1] NA
and your if question askes if (NA eqals 60) which results in NA and "if" is
telling you that it expects TRUE or FALSE but not NA.
I do not see how much clearer the error message shall be.
Cheers
Petr
>
On Nov 26, 2014, at 1:27 AM, Frederic Ntirenganya wrote:
> The error seems to be starnge to me because i access the indices of NAs.
No you don't. You access the contents of the cell via an index for which you
have previously determined that the contents is NA. Then you compare that
contents w
Hi PIKAL,
The error seems to be starnge to me because i access the indices of NAs.
Indices can't be non-applicable.
This is the output of indecs having the NA in my dataset. my dataset is
very big that's why I did not provide it.
> indicNAs <- which(data$Rain %in% NA)
> indicNAs
[1] 426 792
On Tue, Nov 25, 2014 at 1:15 PM, Martin Morgan wrote:
> On 11/25/2014 04:11 AM, Scott Kostyshak wrote:
>>
>> On Mon, Nov 24, 2014 at 12:34 PM, Sarah Goslee
>> wrote:
>>>
>>> I took a look at apparent gender among list participants a few years ago:
>>> https://stat.ethz.ch/pipermail/r-help/2011-Ju
On Tue, Nov 25, 2014 at 8:24 AM, Maarten Blaauw
wrote:
> Nice graph, Scott, thanks!
>
> Based on your code I plotted not the absolute numbers but the ratios, which
> show slowly increasing relative participation of female Rhelpers over time
> (red = women, blue=men, black=unknown). After a c. 5% f
Thanks! That worked
From: William Dunlap mailto:wdun...@tibco.com>>
Date: Tuesday, November 25, 2014 12:53 PM
To: Rolf Turner mailto:r.tur...@auckland.ac.nz>>
Cc: Michael Mason
mailto:mma...@benaroyaresearch.org>>, R help
mailto:R-help@r-project.org>>
Subject: Re: [R] plot.hclust point to older
On 26/11/14 15:49, Bert Gunter wrote:
Yes, Rolf -- she seems to think that covariates must be categorical
and predictors categorical -- or maybe it's vice-versa.
You of course meant "... covariates must be categorical
and predictors numerical -- or maybe it's vice-versa."
(I can't help persis
Yes, Rolf -- she seems to think that covariates must be categorical
and predictors categorical -- or maybe it's vice-versa. Anyway, she
apparently has not done any homework (e.g. by reading an Intro to R)
and so doesn't understand the use of modeling formulas in lm() and
thus does not understand th
On 26/11/14 13:57, Kristi Glover wrote:
Hi,
I am wondering how I can separate whether it is covariate or predictor in the
ANOVA analysis. For example
A<-structure(list(Machine = c(1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L,
2L, 3L, 3L, 3L, 3L, 3L), Diameter = c(20L, 25L, 24L, 25L, 32L,
22L, 28L, 22L,
Hi,
I am wondering how I can separate whether it is covariate or predictor in the
ANOVA analysis. For example
A<-structure(list(Machine = c(1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L,
2L, 3L, 3L, 3L, 3L, 3L), Diameter = c(20L, 25L, 24L, 25L, 32L,
22L, 28L, 22L, 30L, 28L, 21L, 23L, 26L, 21L, 15L), Stre
Pebbles in sand are also an alternative to Excel, but that doesn't mean people
want to switch to abaci. Horse, meet water.
If you use LaTeX (or Rmarkdown-to-pdf in RStudio), then you can obtain much
better looking tables using latex.tabular(). Unfortunately, LaTeX is just too
scary for some peo
Thanks Duncan,
Dropping the extra columns might be the way forward. I'm sure I can work
out how to embed latex into a markdown document ;-)
On Tue, Nov 25, 2014 at 4:37 PM, Duncan Murdoch
wrote:
> On 25/11/2014 3:12 PM, Tom Wright wrote:
>
>> Hi,
>> This problem has me stumped so I thought I'd a
On 25/11/2014 3:12 PM, Tom Wright wrote:
Hi,
This problem has me stumped so I thought I'd ask the experts. I'm trying
to create a pretty summary table of some data (which patients have had
what tests at what times). Ideally I'd like to knitr this into a pretty
PDF for presentation.
If anyone has
Hi Mark,
It is the underscores that are my issue, I'd prefer multiple level row
titles:
|ID1 |ID2
|Time1 |Time2 |Time1 |Time2
|OD |OS |OD |OS|OD |OS |OD |OS
Height | 1| 1 | 1 | 1 | 1 | 1 | 1 | 1
Weight| 1| 1 | 1 | 1 | 1
You probably have a local copy of an old version of plot.hclust or
plot.dendrogram in your global environmenet or another package that masks
the one in package:stats. E.g., I fired up R-2.14.2 and copied those 2
plot methods to .GlobalEnv and then saved by workspace when quitting R. I
then fired
Tom,
If you are wanting PDF as your output, are you wanting to use LaTeX or Markdown
with knitr. LaTeX will give you more options. You have not shown an attempt to
use either for your table construction. Can you define what you mean by pretty?
Is it the underscores in the column names that are
On 26/11/14 08:53, Michael Mason wrote:
Here you are. I expect most folks won't get the error.
N = 100; M = 1000
mat = matrix(1:(N*M) + rnorm(N*M,0,.5),N,M)
h = hclust(as.dist(1-cor(mat)))
plot(h)
Error in .Internal(dend.window(n, merge, height2, hang, labels, ...)) :
there is no .Intern
On 11/25/2014 12:01 PM, Mark Sharp wrote:
> Have you tried the current version of R, 3.1.2?
I have not. I haven't had many issues in the past using what was in the
EPEL repos. Let me take one of my dev boxes and give it a try.
I will post back what I find.
Thanks!
signature.asc
Description:
On 11/25/2014 12:09 PM, Berend Hasselman wrote:
>
> If SL is Snow Leopard (no system mentioned by you) this belongs on R-SIG-Mac.
Actually, I did mention it:
"My OS: Scientific Linux 6.6"
> But this is really for RStudio support. If RStudio needs fixing the RStudio
> people will have to do that
Hi,
This problem has me stumped so I thought I'd ask the experts. I'm trying
to create a pretty summary table of some data (which patients have had
what tests at what times). Ideally I'd like to knitr this into a pretty
PDF for presentation.
If anyone has pointers I'll be grateful.
require(tables)
Reproducible example???
(I know from noddink about hclust, but I tried the example from the help
page and it plotted without any problem.)
cheers,
Rolf Turner
On 26/11/14 06:13, Michael Mason wrote:
Hello fellow R users,
I have recently updated to R 3.1.2. When trying to plot an hclust o
Counting rows is not something RODBC is supposed to do. That is a very basic
SQL query that you can use RODBC to execute:
SELECT COUNT(*) FROM yourtablename
---
Jeff NewmillerThe . .
Look at the task view for High Performance Computing (
http://cran.r-project.org/web/views/HighPerformanceComputing.html) there is
a section on packages for large memory and out-of-memory analyses. There
are also sections on parallel computing which is one way to deal with large
data if you have a
Or just modify your aggregate() command:
> TAB <- aggregate(mydata$CODE, by=list(ID=mydata$ID,
+YEAR=mydata$YEAR), FUN=paste0, collapse=", ")
> TAB
ID YEAR x
1 986 2008 GR.3.8
2 1251 2008 GR.3.1, GR.3.8
3 1801 2008 GR.3.8
411 2009 GR.3.7
5
> do.call("rbind", TAB$x)
[,1] [,2]
1 "GR.3.8" "GR.3.8"
2 "GR.3.1" "GR.3.8"
4 "GR.3.8" "GR.3.8"
5 "GR.3.7" "GR.3.7"
6 "GR.3.8" "GR.3.8"
7 "GR.3.1" "GR.3.8"
9 "GR.3.8" "GR.3.8"
10 "GR.3.7" "GR.3.7"
11 "GR.3.1" "GR.3.1"
12 "GR.3.8" "GR.3.8"
13 "GR.3.1" "GR.3.8"
15 "GR.3.8" "GR.3.8"
16
On 11/25/2014 04:11 AM, Scott Kostyshak wrote:
On Mon, Nov 24, 2014 at 12:34 PM, Sarah Goslee wrote:
I took a look at apparent gender among list participants a few years ago:
https://stat.ethz.ch/pipermail/r-help/2011-June/280272.html
Same general thing: very few regular participants on the li
> On 25-11-2014, at 00:58, Stack Kororā wrote:
>
> Greetings,
> I am having a big issue with RStudio segfaulting recently. It is
> becoming a very big problem for me. I have attached most of the
> information to the support site but no one has responded there. Can
> someone please help me fix RS
Hi,All my data is presently locked in a Microsoft access database. This has
huge data in a number of large tables. Using RODBC and connecting to it takes
too long a time, sometimes making the system to hang up.
To make things more manageable, I have tried to transfer the data to manageable
.RD
Hello fellow R users,
I have recently updated to R 3.1.2. When trying to plot an hclust object to
generate the dendrogram I get the following error:
Error in .Internal(dend.window(n, merge, height2, hang, labels, ...)) :
there is no .Internal function 'dend.window'
I am indeed using R3.1.2 b
I just saw this comment and I agree with Peter. I have occasion to ask
questions and get help on the R forum but I am not a programmer and use
programs as I need them and I suppose I must comment more often. :)
On 11/25/14, 11:28 AM, "peter dalgaard" wrote:
>
>On 24 Nov 2014, at 18:34 , Sarah Go
Dear list,
I have used the ‘polr’ function in the MASS package to run an ordinal logistic
regression for an ordinal categorical response variable with 15 continuous
explanatory variables.
I have used the code (shown below) to check that my model meets the
proportional odds assumption following
Nice graph, Scott, thanks!
Based on your code I plotted not the absolute numbers but the ratios,
which show slowly increasing relative participation of female Rhelpers
over time (red = women, blue=men, black=unknown). After a c. 5% female
contribution in 1998, this has grown to about 15% now.
Dear all,
I can't convert the result of aggregate function in a dataframe. My data
looks like:
mydata <- structure(list(ID = c(11, 11, 460, 460, 986, 986, 986, 986, 1251,
1251, 1251, 1251, 1251, 1251, 1251, 1251, 1801, 1801, 1801, 1801
), YEAR = c(2009, 2010, 2010, 2011, 2008, 2009, 2010, 2011,
Hello All,
I am working on BackTesting Strategies on stocks using daily prices.
Initially the size of data was very limited and can be easily handled using
R and SQL, but now my analysis has been extending on large set of data. Can
anyone suggest me the best packages available for handling large
Thanks for the responses so far.
> The gender ratio in R should reflect the gender ratio of the potential
> users, as this is the pool the R users / developers are coming from.
I agree with this, but then again I don't think R really has 0% female
users/developers as the R member list suggests.
Greetings,
I am having a big issue with RStudio segfaulting recently. It is
becoming a very big problem for me. I have attached most of the
information to the support site but no one has responded there. Can
someone please help me fix RStudio?
https://support.rstudio.com/hc/communities/public/ques
Hi,
I am trying to use rmvDAG in pcalg package to generate data from DAG
structure. One thing I found is that when the number of variables gets
large, there can be really large numbers in the data matrix. I played
around with different parameters and it looks like the same case.
library(pcalg)
>
On 24 Nov 2014, at 18:34 , Sarah Goslee wrote:
> I took a look at apparent gender among list participants a few years ago:
> https://stat.ethz.ch/pipermail/r-help/2011-June/280272.html
>
> Same general thing: very few regular participants on the list were
> women. I don't see any sign that that
If you do not want to use the loop, a function called 'reshape' may be
useful:
> df <- data.frame(a=1:5,b=letters[1:5],c1=1:5,c2=2:6,c3=3:7,c4=4:8)
> out2 <- reshape(data=df, direction="long", varying=list(3:6),
times=paste("c",1:4,sep=""))
> out2
a b time c1 id
1.c1 1 a c1 1 1
2.c1 2
Thanks a lot, guys!
On Tue, Nov 25, 2014 at 9:42 AM, Lee, Chel Hee wrote:
> If you do not want to use the loop, a function called 'reshape' may be
> useful:
>
>> df <- data.frame(a=1:5,b=letters[1:5],c1=1:5,c2=2:6,c3=3:7,c4=4:8)
>> out2 <- reshape(data=df, direction="long", varying=list(3:6),
>>
You do not tell us what you are trying to do but I think there is
something wrong in the logic of your thinking as on the one hand you are
selecting just precisely those elements of data$Rain which are NA and
then testing whether any of them equals 60.
On 25/11/2014 12:19, Frederic Ntirengany
Hi
Error message seems to be clear
> Error in if (data$Rain[i_NA] == 60) { :
> missing value where TRUE/FALSE needed
data$Rain[i_NA] produces probably NA
> x<-NA
> if(x==60) print(1+1) else print("Errrorrr")
Error in if (x == 60) 1 + 1 : missing value where TRUE/FALSE needed
> x<-10
> if(x==6
Dear All,
I am getting this error and don't know why it comes. can you please help ?
Error in if (data$Rain[i_NA] == 60) { :
missing value where TRUE/FALSE needed
The loop is :
indicNAs <- which(data$Rain %in% NA)
ind_nonleap = c() # NAs due to non leap years
ind_nonrecord = c() # NAs due
On Mon, Nov 24, 2014 at 12:34 PM, Sarah Goslee wrote:
> I took a look at apparent gender among list participants a few years ago:
> https://stat.ethz.ch/pipermail/r-help/2011-June/280272.html
>
> Same general thing: very few regular participants on the list were
> women. I don't see any sign that
Dear All,
i need a help on how I can create a new column on my dataset and use it as
argument inside the following function. The column i want to create and
vary is "Evapolation". It varies that'S why I need it as argument.
When I make it like this is not working:
water_blnce=function(data,capaci
Sarah Goslee writes:
> I took a look at apparent gender among list participants a few years ago:
> https://stat.ethz.ch/pipermail/r-help/2011-June/280272.html
>
> Same general thing: very few regular participants on the list were
> women. I don't see any sign that that has changed in the last thr
You appear to be using a package that are not even on CRAN, much less base R,
so you need to tell us that in your (missing) reproducible example. It is
self-described as "primitive", so don't be surprised when it acts odd.
Note that your creation of an exposed Google account in your previous thr
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