1) Wrong list... this belongs on R-sig-mixed, per the Posting Guide.
2) These lists are plain text only. HTML ends up getting corrupted. Please
figure out your email client to avoid confusion.
3) It is difficult to troubleshoot with just the output... you are requested to
make a minimal example
Hi,
The following is implemented with function named subsetAll. It calls the
function subset1. The input to subset1 is the matrix A and a vector
indicating the beginning and ending values for columns 1 and 2. Input to
subsetAll is the matrix A and a matrix that is row bind from those vectors
Hi,
Maybe I missed something. The following example works. It should not
cause any problem with the same parameter names since their scopes are
within the functions.
> function2 <- function(a,b,c,d){
+ a+b+c+d}
> function2(1:2,2:3,3:4,4:5)
[1] 10 14
> function1 <- function(a,b,c,d){
+ newb <-
Hi,
When I fit the regression model without an intercept term, R-squared tends
to much larger than the R-squared in the model with an intercept. So in this
case, what�s a more reasonable measure of the goodness of fit for the model
without an intercept?
Thanks a lot!!
Yan
[[alter
Hello, I am trying to assess weather or not my df are pseudoreplicated in my
lme model.
my study was undertaken on five fish (labeled PC) each tested in two
replicates(REP), across each combination of three treatments HOM, C18 and
CU, each of which had two levels; HOM(SON, BLD),C18 SML, BIG), CU (
Hi,
I need to run multiple iterations of a script to which I am supplying a
single numeric argument
I can open the command prompt window and enter a single command:
"C:\Program Files\R\R-3.1.0\bin\x64\Rscript.exe" myScript.R.R 18
and it runs OK and saves the outputs.
Similarly if I run the same
Hi Bill,
You solved by problem. For some reason, I thought xname was only referring
to name of the x-axis.
I remember last time I fixed it, it was something about xname, couldn't get
it right this time.
Thanks! Saved me hours from frustration.
Mike
On Thu, Jan 29, 2015 at 9:04 PM, William Du
Much thanks, Hadley!
Cheers,
Alan
On Jan 29, 2015, at 12:36 PM, Hadley Wickham wrote:
> On Thu, Jan 29, 2015 at 11:43 AM, Alan Yong wrote:
>> Much thanks to everyone for their recommendations! I agree that fishing in
>> the global environment isn't ideal & only shows my budding understanding
Does
help(curve)
talk about its 'xname' argument?
Try
curve(10*foofoo, from=0, to=17, xname="foofoo")
You will have to modify your function, since curve() will
call it once with a long vector for the independent variable
and func(rnorm(10), rnorm(10), mu=seq(0,5,len=501)) won't
work right.
Hi Rui,
Thank you for your help. That works for now, but eventually, I need to be
pass in x and y.
Is there a way to tell the curve() function, x is a fix vector, mu is a
variable!
Thanks,
Mike
On Thu, Jan 29, 2015 at 5:25 PM, Rui Barradas wrote:
> Hello,
>
> The following will work, but I
Hello:
I discovered recently that the function foreign:::writeForeignSPSS allows for
variable names longer than 8 characters and has an additional argument
varnames. Neither of these capabilities exist with write.foreign. But
according to the help file for write.foreign it seems that the latter
Hello,
The following will work, but I don't know if it's what you want. func2
will get x and y from the global environment.
func2 <- function(mu){
x + y + mu ^ 2
}
curve(func2, from = 0, to = 10)
Hope this helps,
Rui Barradas
Em 29-01-2015 21:02, C W escreveu:
Hi all,
I want to graph
Dear Krisztina,
I'm glad this worked out. I've cc'ed my response to r-help and Sandy Weisberg
so everyone following this thread can see the outcome.
Best,
John
> -Original Message-
> From: Krisztina Mosdossy [mailto:kriszmosdo...@gmail.com]
> Sent: January-29-15 4:51 PM
> To: j...@mcma
Hi S,
I did try (briefly) to work out a way to use lapply but couldn't quite
get it right. After a bit of fooling around the following does work as
a standalone command:
lapply(subsets, function(sub, x)
do.call(subset,list(x,subset=eval(parse(text=sub, x=A)
Thanks for the improvement.
Jim
Dear Krisztina,
I don't think that you mentioned that you were using Mac OS X and if you did I
missed it. Presumably allEffects() still doesn't work because you didn't
install the development version of effects.
R-Forge doesn't build binary packages for Mac OS X. If you're set up to build R
pa
Hi all,
I want to graph a curve as a function of mu, not x.
Here's the R code:
x <- rnorm(10)
y <- rnorm(10)
func <- function(x, y, mu){
x + y + mu ^ 2
}
curve(f = func(x = x, y = y, mu), from = 0, to = 10)
I know I can change variable mu to x, but is there a way to tell R that mu
is the va
Hello John,
Thank you for your prompt reply!
Unfortunately, I get the following message when trying to download the
"effects" package from R-forge (and allEffects() doesn't work):
Warning: unable to access index for repository
> http://R-Forge.R-project.org/bin/macosx/mavericks/contrib/3.1
>
On Thu, Jan 29, 2015 at 11:43 AM, Alan Yong wrote:
> Much thanks to everyone for their recommendations! I agree that fishing in
> the global environment isn't ideal & only shows my budding understanding of R.
>
> For now, I will adapt Chel Hee's "length(eval(parse(text=DFName))[,1])"
> solution
Dear Krisztina,
Thank you for your kind remarks about the effects package.
The issue is almost surely the slow computation of Kenward-Roger standard
errors for the effects, which we compute by default (KR=TRUE) for a linear
mixed model fit by lmer(). This problem is compounded by a bug in
allEffe
Hello fine R folks,
I am a big fan of the "effects" package as it enables me to visualize my
GLMM's quite nicely and with ease. I am, however, unable to find a way to
use the effect() or allEffects() functions with my recent lmer model.
I just updated R, lmerTest and effects packages the other da
Much thanks to everyone for their recommendations! I agree that fishing in the
global environment isn't ideal & only shows my budding understanding of R.
For now, I will adapt Chel Hee's "length(eval(parse(text=DFName))[,1])"
solution then fully explore Jeff's suggestion to put the data frames
Yes. I thought I was replying to a different message. Sorry.
David
-Original Message-
From: Chel Hee Lee [mailto:chl...@mail.usask.ca]
Sent: Thursday, January 29, 2015 11:33 AM
To: David L Carlson
Subject: Your personal email on the R-help mail list
Hi David,
I am not sure if you notic
That's fine, but I'm here in town if you want me to pick her up at the airport.
David
-Original Message-
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Chel Hee Lee
Sent: Thursday, January 29, 2015 9:18 AM
To: Jeff Newmiller; Alan Yong; r-help@r-project.org
Subject: Re: [
Or, you can also do the same job using 'colSums()' as shown in the below:
> colSums(status=="I")
2010 2011 2012
344
>
I hope this helps.
Chel Hee Lee
On 1/28/2015 7:31 PM, JSHuang wrote:
Hi,
I think you need quotation around I like the following:
status
2010 2011 2012
1
I like Jeff's comments on the previous post.
Regarding Alan's question, please see the following example.
> df.1 <- data.frame(v1=1:5, v2=letters[1:5])
> df.2 <- data.frame(v1=LETTERS[1:3], v2=11:13)
> DFName <- ls(pattern = glob2rx("df.*"))[1]
> DFName
[1] "df.1"
> length(DFName[,1])
Error in D
Hi all,
I'm trying to estimate a HR area for several individuals using kernelUD and
kernel.area in adehabitatHR library.
My code is:
library(adehabitatHR)
h=50
kud=kernelUD(detections[,1],h=h,grid=grid,extent=extent,kern=c("bivnorm"))
area=kernel.area(kud,percent=95,unin ="m",unout="km2
On 2015-01-29 12:42, Duncan Murdoch wrote:
On 29/01/2015 6:24 AM, Göran Broström wrote:
Hello,
A weird thing happened to me while I was playing around in the R console
with a data frame ('fert'). The finale was
-
> with(fert[fert$parity ==
On 29/01/2015 7:09 AM, Axel Urbiz wrote:
> Hello,
>
> I'm building a package on Mac OS. The build/check/install goes all ok.
> Also, the package gets loaded properly with library("my_package").
>
> However, when I call the help file for a given function in the package --
> i.e., "?my_function", I
Hello,
I'm building a package on Mac OS. The build/check/install goes all ok.
Also, the package gets loaded properly with library("my_package").
However, when I call the help file for a given function in the package --
i.e., "?my_function", I get the following error:
"Error in gzfile(file, "rb")
Thanks Thierry for your quick answer. Indeed this simplifies a lot my
method so I decided to apply it.
However I will be curious to check in which extend the coefficients
obtained with the gls function are similar to the ones obtained using
glm and whitening. It seems to me thant the method ar
On 29/01/2015 6:24 AM, Göran Broström wrote:
> Hello,
>
> A weird thing happened to me while I was playing around in the R console
> with a data frame ('fert'). The finale was
>
> -
> > with(fert[fert$parity == 4, ], table(age, event))
>
> -Original Message-
> subsets<-list(B="(A[,1] %in% c(1,2) & A[,2] %in% c(1,2)) | (A[,1] %in%
> c(3) & A[,2] %in% c(1)) | (A[,1] %in% c(4) & A[,2] %in% c(1:4))", C="(A[,1]
> %in%
> c(1:4) & A[,2] %in% c(1,2))", D="(A[,1] %in% c(1,2) & A[,2] %in% c(1:3)) |
> (A[,1]
> %in% c(3) & A[,2]
Hello,
A weird thing happened to me while I was playing around in the R console
with a data frame ('fert'). The finale was
-
> with(fert[fert$parity == 4, ], table(age, event))
event
age 0 1 2
(14,20] 0 0 0
(20,
On 29 Jan 2015, at 07:34 , Jeff Newmiller wrote:
> This approach is fraught with dangers.
>
> I recommend that you put all of those data frames into a list and have your
> function accept the list and the name and use the list indexing operator
> mylist[[DFName]] to refer to it. Having functi
34 matches
Mail list logo
