Hi John,
One way is to create an index variable that will divide your data into the
appropriate intervals. There are a number of ways to do this. Say you want
the two month version of bimonthly and you have a date variable
(raindate) for each observation like 1982-01-01.
Will it work with .xlsm files?
Best,
KW
You might try the readxl package - it's only available on github but it
reads both xlsx and xls. All going well, it should be on its way to CRAN
next week.
Hadley
On Friday, April 3, 2015, Luigi Marongiu marongiu.lu...@gmail.com wrote:
Dear
On Apr 5, 2015, at 2:40 PM, John Wasige wrote:
Thanks Jim!
Do you have an idea on how I can go about getting bi-monthly (twice a
month) results for the month with 28, 29, 30 and 31 daily observations?
Thanks for your help
raindate - seq.Date(as.Date(1982-01-01),
Thanks Jim!
Do you have an idea on how I can go about getting bi-monthly (twice a
month) results for the month with 28, 29, 30 and 31 daily observations?
Thanks for your help
John.
On Sun, Apr 5, 2015 at 11:25 PM, Jim Lemon drjimle...@gmail.com wrote:
Hi John,
One way is to create an index
Thanks for your attention Jim
Following your idea of adding one more step to construct the diagram, I used
text(spe2.rdaspe, row.names(spe2.rdaspe), pos=3, col=red,cex=0.8)
and I could add species names.
It seems that there's nothing we can do in the plot line.
Have a nice week, best regards
Many thanks everybody for your kind help.
John
On Mon, Apr 6, 2015 at 12:11 AM, David Winsemius dwinsem...@comcast.net
wrote:
On Apr 5, 2015, at 2:40 PM, John Wasige wrote:
Thanks Jim!
Do you have an idea on how I can go about getting bi-monthly (twice a
month) results for the month
Hi,
I am trying to connect points, but not in a different order than the
default value in ggplot. For example:
xx - sample(1:100,5)
yy - sample(1:100,5)
mydat - data.frame(xx,yy)
print(mydat)
ggplot(mydat,aes(xx,yy)) + geom_point() + geom_line()
I want to connect the points as they
Will this do?
ggplot(mydat,aes(xx,yy)) + geom_path()
From :
http://stackoverflow.com/questions/15706281/controlling-order-of-points-in-ggplot2-in-r
--
|
http://billyam.com || http://use-r.com ||
thanks!
On Sun, Apr 5, 2015 at 9:15 AM, billy am wickedpu...@gmail.com wrote:
Will this do?
ggplot(mydat,aes(xx,yy)) + geom_path()
From :
http://stackoverflow.com/questions/15706281/controlling-order-of-points-in-ggplot2-in-r
Hi Peter,
Thank you so much for your tips. Have a nice Easter.
Gian
Il giovedì 2 aprile 2015, peter dalgaard pda...@gmail.com ha scritto:
On 30 Mar 2015, at 17:11 , Gian Maria Niccolò Benucci
gian.benu...@gmail.com javascript:; wrote:
Dear R-usrs,
I am trying to perform a MANOVA on
Dear community,
I have daily rainfall raster data for 30 years (1982_2011). I would like to
aggregate daily to bimonthly raster data. Could somebody kindly help on how
to go about it!
Thanks for your help
--
John
[[alternative HTML version deleted]]
Someone might if they had any idea of what the data actually looked like and
what you are trying to do. The 'bimonthly' for example, is ambiguous in
English; do you mean every two months or twice a month?
Have a look at https://github.com/hadley/devtools/wiki/Reproducibility and
Dear community,
I have daily rainfall raster data for 30 years (1982_2011). I would like to
aggregate daily to bimonthly (twice a month) raster data. Could somebody
kindly help on how to go about it!
Thanks for your help
JOHN
Thanks Kane, bimonthly here means twice a month.
Thanks Bert,
The structure of the data is a raster stack with nraw=867, Ncol=995
Rgds John
On Sun, Apr 5, 2015 at 6:39 PM, Bert Gunter gunter.ber...@gene.com wrote:
See ?tapply
However, as John said, without knowing the structure of your data, it
is impossible to provide a guaranteed
Hi all,
I have a question concerning the trim and fill procedure in metafor. In STATA
it is possible to obtain the values of the added estimated effect sizes. I was
wondering if this is also possible in R and if so, how I can obtain the new
data with the added values.
I would really
See ?tapply
However, as John said, without knowing the structure of your data, it
is impossible to provide a guaranteed recipe. For example, does the
data structure contain date information? -- it would be difficult (but
not impossible depending on data structure) to aggregate by calendar
Please stop posting using HTML (as the Posting Guide warns you), and follow
John Kane's advice. Your reply below is not helping us understand as well as
you seem to think it should.
---
Jeff Newmiller
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