On 24/12/19 2:29 pm, Jim Lemon wrote:
Hi Rolf,
Following the docs back to draw.key, It looks like the ellipsis
argument is ignored. I was hoping for a brilliant solution along the
lines of:
adj=0
that could be passed down the functions like a hot potato, but was disappointed.
Thanks for
Hi Jim, Burt and all who have been so helpful - very much appreciated!
I have managed to get the code to run correctly by extending the parentheses
around the whole statement, including the &, rather than parentheses around the
two clauses on either side of the &.
It seems to have done the
Hi Rolf,
Following the docs back to draw.key, It looks like the ellipsis
argument is ignored. I was hoping for a brilliant solution along the
lines of:
adj=0
that could be passed down the functions like a hot potato, but was disappointed.
Jim
On Tue, Dec 24, 2019 at 9:26 AM Rolf Turner wrote:
Hi Kimberley,
Given the number of posts that read "I have a problem, please advise",
your concern for our mental welfare is a great Xmas present.
Jim
On Tue, Dec 24, 2019 at 10:38 AM Steinmann, Kimberly@CDPR
wrote:
>
> I am not sure how to close the thread - I hate to waste anyone's time on a
Hi Paul,
For your first question:
max(file.info(".")$mtime)
[1] "2019-12-21 21:04:19 AEDT"
As for the second, I didn't know what an AIS file was, so I googled
it. I still don't know, so I don't have a clue how to turn a string
like that into a number.
Jim
On Tue, Dec 24, 2019 at 5:14 AM Paul
Hi Kimberley,
Since you are using a loop and therefore testing one value of
v_trends_lbs at a time, the "&" in the "if" statement should be "&&".
Pinching Bert's example but using a for loop instead of ifelse:
x <- seq(-2,2,.25)
v_lbs<-rep("",length(x))
for(i in 1:length(x)) {
if(is.na(x[i]))
The title of a key seems to be horizontally centred in the key; I would
like to have it aligned with the left hand edge. I.e. I would like the
first letter of the title to have the same horizontal position as the
first letters of the text strings.
E.g. in the attached example I would like
Dear Burt, you gave a very elegant solution. Many thanks!
Jeff, I understand your solution, thank you very much for your time!
Colleague Milos, patronage is exactly what I need. I hope for your
further guidance! (Rcmdr is not enough for some purposes.)
Dear Ivan, I used your solution! It's the
WITHOUT going through your code carefully (but where is v_lbs first
defined?), maybe something like this is what you want:
> x <- seq(-2,2,.25)
> x
[1] -2.00 -1.75 -1.50 -1.25 -1.00 -0.75 -0.50 -0.25 0.00 0.25 0.50
0.75 1.00
[14] 1.25 1.50 1.75 2.00
> x <- ifelse(x>0 & x<1, '<1',
You are corresponding to a mailing list, but you need to be corresponding with
the author of the paper you are referring to. I have no idea who that is or
what the paper is that you are referring to.
On December 23, 2019 6:32:26 AM PST, Salwa El-Aty
wrote:
>
>
>Dear Sir
>I want to help me
What does the error message say?
On Mon, Dec 23, 2019, 3:33 PM Steinmann, Kimberly@CDPR <
kimberly.steinm...@cdpr.ca.gov> wrote:
> Hi - i am not super familiar with R, but need to modify my predecessor's R
> code so that if a variable is >0 and < 0.5, it will be replaced with <1. I
> have looked
Josè
Sent from Yahoo Mail on Android
On Mon, Dec 23, 2019 at 12:15 PM, Abby Spurdle wrote:
Hi Jose,Same here, I use tinn-R on a daily basis..thanks for the update and
have a merry christmas
That's awesome.
I used Tinn-R, back in 2006, when I starting learning nontrivial R
Dear Sir
I want to help me about to send the R Code of paper which title
Inference of Generalized endpoint inflated binomial regression . In . 2017
Best Regards
Salwa. A.Mousa
Sent from my Samsung device
[[alternative HTML version deleted]]
Hi - i am not super familiar with R, but need to modify my predecessor's R code
so that if a variable is >0 and < 0.5, it will be replaced with <1. I have
looked at a bunch of forum threads on the subject, but cannot seem to get
anything to work Any help at what i might be doing wrong much
Hi Jose,
That's awesome.
I used Tinn-R, back in 2006, when I starting learning nontrivial R programming.
I used it extensively, before shifting to my own (still incomplete)
programming environment.
Back then, Emacs (with ESS) had the monopoly on Linux, and Tinn-R was
leading the race on Windows.
J have just seen your follow-up post (out of tread). I don’t want to be
rude or patronizing but few caveats.
Neither R nor R help are meant to be user friendly. Learning curve is steep
but very rewarding at the end.
Problem you have can be solved in a literary hundred ways. Unfortunately,
your
Do you mean IQR? -- I don't know what ICR means.
If so, see IQR.
More generally see ?by or more generally ?tapply to obtain whatever sort of
summary you want.
e.g.
> d <-data.frame( x = runif(10), w = rep(c("a","b"),5))
> by(d$x, d$w, FUN = function(x)c(median = median(x),IQR = IQR(x)))
d$w: a
If I understand correctly you need summary by group. I would suggest
arsenal package and tableby
tab1 <- tableby(group ~ anova(var, "meansd", digits=1) + #mean and sd +
round to 1 digit + anova
kwt(var, "medianq1q3", digits=1) , #median q1 and q3 +
round to 1 digit +
The "digest" package might be what you're looking for: messages --> numerics
Or perhaps you want to create a hash in R. Search on "hashing in R" or
similar for info on this.
See ?file.info for obtaining file info, including date/time info.
Bert Gunter
"The trouble with having an open mind is
Dear friends,
Hope you are doing great. I would like to process an AIS file (which comes
in either a .txt or .csv format). The AIS file is contained in a specific
path, say C:/AISFiles/File.txt. The file contains messages like the
following:
On Mon, 23 Dec 2019 17:56:35 +0300
Medic wrote:
> I would like to split
> mydata$var
> by
> mydata$group #to get var1 and var2
There is the split() function that does exactly that (except it returns
a list instead of multiple variables)...
> And then get
> summary (var1, var2) #this is my
What Jim is alluding to is that sometimes in the process of reading in
data a small typo can mean that what was intended to be a numeric
variable is read in as a factor. So he was suggesting that you double
check that this has not happened to you.
Michael
On 23/12/2019 11:45, Neha gupta
I have
mydata$var
#this is ONE group of patients
And I would like to get
median and ICR of mydata$var.
How can I get this?
With summary (mydata$var)!
Ok!
And now I would like to get THE SAME, but for TWO group: male and
female (which are contained in the group mydata$var)
How can I get this?
Not clear what you mean by
summary (var1, var2)
? That is not a legal way to call summary. Perhaps
mt <- mtcars[,c("cyl","hp")]
mt$cyl <- factor( mt$cyl )
mtl <- split(mt[,"hp",drop=FALSE], mt$cyl)
lapply(mtl,summary)
On December 23, 2019 6:56:35 AM PST, Medic wrote:
>I have
>mydata$var
>
Thanks. I stand corrected. But...
https://shiny.rstudio.com/
Cheers,
Bert
On Mon, Dec 23, 2019 at 6:29 AM Jeff Newmiller
wrote:
> Shiny is not an app... it is a contributed R package on CRAN. Of course,
> with 15000 packages on CRAN this mailing list cannot necessarily support
> questions
?ave
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Mon, Dec 23, 2019 at 6:57 AM Medic wrote:
> I have
> mydata$var
>
> and I have
> mydata$group #two group
I have
mydata$var
and I have
mydata$group #two group
I would like to split
mydata$var
by
mydata$group #to get var1 and var2
And then get
summary (var1, var2) #this is my finite aim
How to encode it all?
__
R-help@r-project.org mailing list -- To
Hi,
A new version of Tinn-R project (6.01.01.03) was released today.
Download:
- https://nbcgib.uesc.br/tinnr/en/download
- https://sourceforge.net/projects/tinn-r/files/Tinn-R setup/
What is new:
- https://nbcgib.uesc.br/tinnr/en/download#patch
-
Shiny is not an app... it is a contributed R package on CRAN. Of course, with
15000 packages on CRAN this mailing list cannot necessarily support questions
about all of them (read the Posting Guide).
That said, this question does not seem like the use of shiny is necessarily
relevant because
Hi Jim,
Another possibility is that the values used in the initial calculation
have been read in as factors
Which calculation you are talking about? I did not use factors as variable.
Regards
On Mon, Dec 23, 2019 at 3:12 AM Jim Lemon wrote:
> Hi Neha,
> Well, that's a clue to why you are
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