As the title says, I want to apply a function (which itself returns
a function) to a list (or vector), and get a list (or vector) of
generated functions as the return value, but get unexpected result.
Anyone with an idea about the reason of this phenomenon and a correct
way to implement the
Thank you very much, though I still don't quite undertdand the
explanation :)
Nevertheless, I just found a seemingly simple (at least quiker to type)
solution after try-and-error:
eval(mapply(function(x) {x; function() x}, c(a, b)))
Wish it may help future readers.
On Thu, May 03, 2012 at
For example, prepare like this
df.0 - data.frame(x = 0, y = 0, note = 1)
df.1 - subset(df.0, note == 1)
df.2 - subset(df.0, note == 2)
Then a call to
ggplot() + aes(x = x, y = y) +
geom_point(data = df.1) + geom_point(data = df.2)
produces the error
Error in eval(expr, envir, enclos) :
Thanks, I'll post to that list if the encountered problem is just about
ggplot2.
And from the date of the issue on GitHub it seems that I might need to
manually work around the problem some more times :)
On Fri, Dec 23, 2011 at 08:10:05AM -0600, Hadley Wickham wrote:
See
Hmm, that's my fault when composing this mail, but the problem was
really encountered at that time.
Nevertheless, neither can I reproduce the problem now, perhaps I just
made another mistake at that time.
Thanks all the same, and sorry for the disturbance anyway :|
On Tue, Oct 04, 2011 at
Example:
f - function(x) { 1 + 2 * log(1 + 3 * x) + rnorm(1, sd = 0.5) }
y - f(x - c(1 : 10)); y
[1] 4.503841 5.623073 6.336423 6.861151 7.276430 7.620131 7.913338 8.169004
[9] 8.395662 8.599227
nls(x ~ a + b * log(1 + c * x), start = list(a = 1, b = 2, c = 3), trace =
TRUE)
37.22954 : 1
Ah, now I see...
Thanks very much :)
On Sat, Oct 01, 2011 at 09:27:34AM -0400, Gabor Grothendieck wrote:
On Sat, Oct 1, 2011 at 5:28 AM, Casper Ti. Vector
caspervec...@gmail.com wrote:
Its linear given c so calculate the residual sum of squares using lm
(or lm.fit which is faster) given c
Is there any way to use expression() in legend labels with ggplot2?
It seems that things like
scale_shape_manual(value = c(
x = expression(italic(x)),
y = expression(italic(y))
))
don't work.
Thanks very much :)
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Using GPG/PGP? Please get my current public key (ID: 0xAEF6A134,
Hello list, is there any R function for generating spline for implicit
functions, for example a spline for an two-column data frame where for
one value for one variable there maybe several correspondent values for
another? Many thanks.
Currently I'm using this home-made one:
spline2d -
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