-
Dr. Gerrit Eichner Mathematical Institute, Room 215
gerrit.eich...@math.uni-giessen.de Justus-Liebig-University Giessen
Tel: +49-(0)641-99-32104 Arndtstr. 2, 35392 Giessen, Germany
http://www.uni-giessen.de/eichner
on4 = Station4,
Station5 = Station5)
select.stat <- paste0("Station", c(1, 4, 5))
select.sens <- "thermometer"
sapply(Total[select.stat], function(x, sens)
x$code[x$sensor == sens], sens = select.sens)
Hth -- Gerrit
-
Hi Paul,
take a look at base R's function contour (and the Examples section
of its help page), and follow maybe the hints under "See also".
Hth -- Gerrit
-
Dr. Gerrit Eichner Mathematical Insti
Hi, James,
if I understand you correctly, maybe,
with(firstdf,
ifelse(Province %in% seconddf$Country,
Province,
Country)
)
does what you want?
Hth -- Gerrit
-
Dr. Gerrit Eichner
xph(Surv(futime, fustat) ~ age+rx+age*rx, data = ovarian)
plot(survfit(coxfit, newdata=data.frame(age=60,rx=2)))
Or do I missunderstand your question?
Hth -- Gerrit
---------
Dr. Gerrit Eichner Mathematical Institut
Hello, Elahe,
you were, of course, supposed to insert my suggested
code-snippet into you code and test it therein ...
Regards -- Gerrit
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich
Homework?
Try maybe
mutate(MinValue = min(Value[Value != 0]) )
or
mutate(MinValue = sort(unique(Value))[2])
Hth -- Gerrit
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni
Yes. :-)
Best regards -- Gerrit
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Liebig-University Giessen
Tel: +49-(0)641-99-32104 Arndtstr. 2
Dear Jeff,
read diff's help page, and you'll find out
what is wrong with your expectation.
What do think diff(df$Score) should give for
the first element in df$Score??
Hth -- Gerrit
-
Dr. Gerrit Eichner
using stripchart, but you may want to look at the
examples of function beeswarm in package beeswarm.
Hth -- Gerrit
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de
f course, then, e.g.,
do.call(paste0, data.frame(X))
would work.
Best -- Gerrit
---------
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Liebig-University Giessen
Tel:
[I forgot to keep it on the list.]
Weitergeleitete Nachricht
Betreff: Re: [R] Concatenation?
Datum: Wed, 17 Feb 2021 22:14:13 +0100
Von: Gerrit Eichner
Organisation: JLU Gießen
An: Parkhurst, David
Hi David,
checkout, e. g., base-R's
paste0(site, depth)
or, if stored
r support and the brilliant effects
package in general! :-)
Best regards -- Gerrit
-----
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Liebig-University Giessen
Tel: +49-(0)641-99-32104
.4
nloptr_1.2.2.2
[11] Matrix_1.2-18boot_1.3-25 splines_4.0.2statmod_1.4.34
lme4_1.1-23
[16] tools_4.0.2 survival_3.2-3 yaml_2.2.1 compiler_4.0.2
colorspace_1.4-1
[21] mitools_2.4 insight_0.9.5nnet_7.3-14
-----------
Hi, John,
look for the package beeswarm.
Regards -- Gerrit
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Liebig-University Giessen
Tel: +49-(0)641-99
Hi Stefano,
maybe floor(x / n) * n and ceiling(x / n) * n does what you want?
Best regards -- Gerrit
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Liebig
guess.
Regards -- Gerrit
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Liebig-University Giessen
Tel: +49-(0)641-99-32104 Arndtstr. 2, 35392 Giessen
Hi, Ana,
doesn't
udt <- unique(dt[c("chr", "pos", "gene_id")])
nrow(udt)
get close to what you want?
Hth -- Gerrit
---------
Dr. Gerrit Eichner Mathematical Institute, Room 212
g
to xlevels[[name]] <- levs where xlevels is an integer. (But that
doesn't matter anymore because my conjecture pointed to the wrong
function anyway.)
Best regards -- Gerrit
-----
Dr. Gerrit Eichner Mathemati
s_2.4 nnet_7.3-12
---------
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Liebig-University Giessen
Tel: +49-(0)641-99-32104 Arndtstr. 2, 35392 Giessen, Germany
http://www
Hi, Christofer,
try something along
len <- 5
split(Vec, rep(seq(ceiling(length(Vec)/len)), each = len))
Hth -- Gerrit
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.
rit
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Liebig-University Giessen
Tel: +49-(0)641-99-32104 Arndtstr. 2, 35392 Giessen, Germany
http://www.uni-giessen.de/eich
Hello, Jun,
try
split(df, f = factor(df$C, exclude = NULL))
For more info see ?factor, of course.
Regards -- Gerrit
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni
Don't you mean ?Rdiff ?
Hth -- Gerrit
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Liebig-University Giessen
Tel: +49-(0)641-99-32104 Arndtstr
, or wait/hope for a more knowledgeable list member to
"jump in".
Hth -- Gerrit
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Liebig-University Giesse
Am 08.06.2018 um 12:02 schrieb Martin Maechler:
Martin Maechler
on Fri, 8 Jun 2018 11:13:24 +0200 writes:
[..]
>> Thank you, Chris, for the report and
>> Gerrit for your proposed fix !!
>>
>> It looks good to me, but I will test some more (also with
>>
Hi, Chris,
had the same problem (and first thought it was my fault), but there
seems to be a typo in the code of pairs.default. Below is a workaround.
Look for two comments (starting with #) in the code to see what I
have changed to make it work at least the way I'd expect it in one of
your
Why not use as.matrix(Imp) in this case?
Regards -- Gerrit
Am 24.05.2018 um 17:04 schrieb Bert Gunter:
This is one of those instances where a less superficial knowledge of R's
technical details comes in really handy.
What you need to do is convert the data frame to a single (numeric)
Hi, Christofer,
try
print(as.numeric(x), digits = 10) # or another number of digits
to increase the printed(!) precision.
Hth -- Gerrit
Am 23.05.2018 um 12:42 schrieb Christofer Bogaso:
Hi,
Below is my simple result in R
x = "1282553.821000"
as.numeric(x)
[1] 1282554
Any idea
.
Third, just to be sure: This list is not for home work.
Two more remarks see inline below.
Hth -- Gerrit
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus
Hi, Anne,
assign Age and Bloodpressure in the correct order
to the axes in your call to plot as in:
plot(y = Age, x = BloodPressure)
abline(SimpleLinearReg1)
Hth -- Gerrit
-
Dr. Gerrit Eichner
-checking the intended name and if neccessary
changing it (somehow ...) automatically. (Have to think about that ...)
Best regards -- Gerrit
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich
m <- lmer(Reaction ~ Days + (Days | Subject), data = X)
Effect("Days", fm)
}
Hth -- Gerrit
---------
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Lieb
] colorspace_1.3-2 mgcv_1.8-22nnet_7.3-12
quantreg_5.33
---------
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Liebig-University Giessen
Tel: +49-(0)641-99-32104 Arndtstr.
ike
fm.plus.origdata <- list(fm, myair = myair)) to be able to restore
the original environemt (or at least the needed opriginal data
frame) of the time when fm was created?
Thx for any hint!
Regards -- Gerrit
---------
Dr. Gerr
the cause of your "problem". I suggest you check the structure
of m:
str(m)
I suspect you'll see that the assumption of 52 trapcatch values is
somehow wrong.
Hth -- Gerrit
---------
Dr. Gerrit Eichner Ma
Hi, Sibylle,
since you write '"mathematically" add', does
barplot(rbind(m$trapcatch, w$trapcatch))
do what you want (modulo layout details)?
Hth -- Gerrit
-
Dr. Gerrit Eichner Mathematical
t)
save(result, file = "folkeafstemning2009.Rdata")
Maybe two loops simplify this a little bit for you (not tested):
for(v in c("StedType", ))
result[[v]] <- factor(result[[v]])
for(v in c("StemmerAntal", ))
result[[v]] <- as.integer(result[[v]])
Hth -- Gerrit
---
Hello, Urs,
you may have seen Wolfgang Viechtbauer's answer already which offers
an R-technical solution, but this may leave the mathematical grounds
of linear models. See inline below for my concern and a hint.
Am 17.05.2017 um 09:12 schrieb Urs Kleinholdermann:
Dear list members,
I want to
(untested).
Hth -- Gerrit
---------
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Liebig-University Giessen
Tel: +49-(0)641-99-32104 Arndtstr. 2, 35392 Giessen, Germany
Fax: +49-(0)641-99-32109htt
Hi, Luigi,
you are probably missing a call to print() around the call to
the latticeExtra plotting function useOuterStrips() you use
inside your function printer().
Hth -- Gerrit
-
Dr. Gerrit Eichner
lp@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Hth -- Gerrit
---
Hi, Tal,
in print.default it says:
digits:
a non-null value for digits specifies the __minimum__
number of __significant__ digits to be printed in values.
Maybe this clarifies your observation.
Hth -- Gerrit
-
Dr. Gerrit
... or:
net1 <- array(0L, dim=c(5,5))
Note the difference between 0 and 0L.
Gerrit
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Liebig-Univers
Hi, Thomas,
maybe
mode(net1) <- "integer"
does what you want?
Hth -- Gerrit
-----
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Liebig-Universit
Hello, Mauricio,
maybe pwr.t2n.test() in package pwr or/and n.ttest() in package
samplesize do what you need/want.
Hth -- Gerrit
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich
how to extract various components of a formula and how to
"re-build" formulae from such single components, but I would like to
avoid that.
Thx for any hint -- Gerrit
-
Dr. Gerrit Eichner Mathematical
Hello, Elahe,
look at
?match
and check if
df2$Count[ match( Matched, df2$Serial)]
does what you want/need.
Hth -- Gerrit
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni
Hi, Matti,
use
?pnorm
and read about qnorm.
Hth -- Gerrit
On Wed, 20 Jan 2016, mviljamaa wrote:
I'm doing Normal approximation to binomial distribution.
My variables are generated by rbinom.
Here:
Hello, Dirk,
maybe I'm missing something, but to avoid your for-loop-approach doesn't
M <- M/Matrix::rowSums(M)
do what you want?
Hth -- Gerrit
-
Dr. Gerrit Eichner Mathematical Institute, Room
Hi, Petr,
from your example it's not doubtlessly clear to me sure how the sequence
of ifs should really be continued, but couldn't a nested loop help?
Something like:
for (i in 1:npks) {
plot(res[[i]]$x, res[[i]]$y, pch=20)
for (j in 1:i) {
lines(res[[i]]$x, res[[i]]$fitpk[j,], col=j,
Hi, Thanoon!
I want to simulate a vector of constants values with dimention = 200x2 and
all values of this vector are 1.
You mean "I want to _construct_ a _matrix_ of dimension 200 x 2 with all
entries equal to 1", don't you?
Homework? Take a look at
?matrix
Hth -- Gerrit
Any help
Hello, Sarah,
take a look at the online help page of the function cut() (and apply the
function to the Hunger-column).
Hth -- Gerrit
On Thu, 29 Oct 2015, Dagmar wrote:
Dear Sarah, (dear All),
Thank you for trying to help! You are right, that I want to add a column to
my dataframe with
Hello, Maicel,
if you only want to extract info from those data frames, maybe it is
enough to attach the list to the search path using attach (and afterwards
detach()); see ?attach. Otherwise the online help page of assign() might
be a starting point for you.
Hth -- Gerrit
Hi
Or
values [of] larger than 2 by 2 tables." (Similarly,
control and hybrid are not needed either here.)
Regards -- Gerrit
---------
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen
Dear Paul,
quoting the email-footer: PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html and provide commented,
minimal, self-contained, reproducible code.
So, what exactly did you try and what was the actual problem/error
message?
Besides that, have you noted
,
Paul
On Fri, Aug 28, 2015 at 8:56 AM, Gerrit Eichner
gerrit.eich...@math.uni-giessen.de wrote:
Dear Paul,
quoting the email-footer: PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html and provide commented,
minimal, self-contained, reproducible code.
So, what exactly
Hello, Xianming,
I have changed your (particular) data structure: use matrices because you
have only numeric scores and effects, use NA instead of -1 as missing
value (as usual), don't use columns for ids or row/column names (except
for the easy of reading the data structures), increase your
Hi Evans,
not many people (incl. me) are going to guess the building law for your
recursive structure from the -- in fact at first sight not so clear --
picture, but I have some comments inline below.
Hth -- Gerrit
I am trying to creat a list from a loop such that once you loop the
Hi, Ragia,
use
names( pr_sub$vector[ 1])
Regards -- Gerrit
On Tue, 23 Jun 2015, Ragia Ibrahim wrote:
Dear group,
I have the following object
pr_sub$vector[1]
14
0.07782809
class( pr_sub$vector[1])
[1] numeric
length( pr_sub$vector[1])
[1] 1
how can I separate
Hello, everyone,
aside from Rolf's hint (and Richard's warning!) you could also consider
relevel():
viagraData$dose - relevel( viagraData$dose, ref = placebo)
Hth -- Gerrit
On Fri, 5 Jun 2015, Rolf Turner wrote:
On 05/06/15 11:08, Jim Lemon wrote:
Hi James,
You can change the order of
Hi, John,
doesn't
n - your number
lapply( 1:n, rep, each = 4)
do what you need?
Hth -- Gerrit
On Sat, 18 Apr 2015, John Sorkin wrote:
Windows 7 64-bit
R 3.1.3
RStudio 0.98.1103
I am trying to generate a list of length 4n which consists of the integers 1
to n repeated in groups of
Hello, Alaios,
try
is.null( Mylist[[i]]$parameters)
It returns TRUE if your list doesn't have a component named parameters
or if that component contains NULL.
HtH -- Gerrit
On Tue, 3 Mar 2015, Alaios via R-help wrote:
Hi all,I have a list that has the following fields.
$`80`
[1]
Hie Alaiso,
try to simply apply lapply() to your data frame. It should work w/o any
further operation since data frames are lists (check with is.list()).
Hth -- Gerrit
On Wed, 25 Feb 2015, Alaios via R-help wrote:
Hi all,I would like to use an expand.grid functionality that would give
Hello, Sait,
take, for example, a look at bartlett.test(), but keep in mind that
Bartlett's test is quite sensitive to deviations from normality. Levene's
test (e.g., in leveneTest() in package car) is said to be more robust.
Hth -- Gerrit
On Thu, 8 Jan 2015, sait k wrote:
Dear Sir or
Hello, David,
take a look at the beginning of the Warning section of ?factor.
Hth -- Gerrit
Hi everybody,
I have another question (to which I could not find an answer in my r-books.
I am sure, it's not a great issue, but I simply lack of a good idea how to
solve this:
One of my variables
Hello, ron,
have you looked at the help page of qqplot and consequently tried, e.g.,
the following?
xy - qqplot( rt(300, df = 5), rt(300, df = 5),
xlim = c(-10, 10), ylim = c(0, 10))
str( xy)
Hth -- Gerrit
On Tue, 11 Nov 2014, Ron Michael wrote:
Hi,
I am some questions
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Liebig-University Giessen
Tel: +49-(0)641-99-32104 Arndtstr. 2, 35392 Giessen, Germany
Fax: +49-(0)641-99-32109http
Hello, Florian,
function na.locf() from package zoo mightdo what you want.
Hth -- Gerrit
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Liebig-University
column, not all: Something like
yourdataframe$ID - na.locf( yourdataframe$ID)
should replace the ID-column with the modified version you want.
Regards -- Gerrit
Kind regards,
Florian
Am 04.08.2014 um 11:31 schrieb Gerrit Eichner
gerrit.eich...@math.uni-giessen.de:
Hello, Florian
. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Liebig-University Giessen
Tel: +49-(0)641-99-32104 Arndtstr. 2, 35392 Giessen, Germany
Fax: +49-(0)641-99-32109http://www.uni-giessen.de/cms/eichner
datasets methods base
other attached packages:
[1] fortunes_1.5-2
loaded via a namespace (and not attached):
[1] tools_3.0.2
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni
attached packages:
[1] fortunes_1.5-2
loaded via a namespace (and not attached):
[1] grid_3.0.2 lattice_0.20-27 tools_3.0.2
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni
/2014 7:32 AM, Gerrit Eichner wrote:
Hello, everyone,
I am struggling with an Sweave-problem that didn't occur sofar (and I have
no clue what I might have changed in my system; see below). The following
example *.Rnw file's only task is (for simplicity) to output text with a
little bit of TeX-code
for the respective code chunks (which also have
results=tex, and from which I want only linebreaks in the TeX-output).
Actually, embarrassingly simple.
Thanks again -- Gerrit
On Wed, 5 Mar 2014, Duncan Murdoch wrote:
On 05/03/2014 9:29 AM, Gerrit Eichner wrote:
Thanks, Duncan,
but, sorry
Hi, Mat,
e. g., try something like
ORDER$VALUE * c( NY = 3, BER = 2, FRA = 1, WAS = 4)[ ORDER$DESTINY]
Hth -- Gerrit
On Fri, 17 Jan 2014, Mat wrote:
Hello together,
i have a little problem, to create a new column, in a data.frame.
I know i can calculate one column with as a example 2
. Unfortunatedly the line of code you suggest -
i.e.
apply( subset( d2, subset = V13:V239), 1, function( x) any( x != ))
returns the same error. Any other suggestion?
Danke schôn und auf wiederhoren
Luca
2014/1/2 Gerrit Eichner gerrit.eich...@math.uni-giessen.de
Hello, Luca,
also a happy new
Hello, Luca,
also a happy new year!
It's not quite clear to me what you want to do, but note first that the
:-operator is a short-cut for seq() with by = 1 (look at ?seq), and that
it usually (!) does not work on columns of data frames. Exception: when
used for the argument subset of
Hello, Ë®¾²Á÷Éî!
mytest-function(x,f){
sum(x*f)/sum(f)
}
cat(mytest,file=c:/mytest.R)
Error in cat(list(...), file, sep, fill, labels, append) :
argument 1 (type 'closure') cannot be handled by 'cat'
how can i write the mytest function into a file c:/mytest.R with cat
Hello, Mat,
see below.
hello together, i want to filter a data.frame. My problem is, that i
want to filter 2 numbers.
My data.frame look like this one.
No. text
1 abc
2 def
3 ee
4 ff
5 gg
I want now to filter No. 2 and 3, so my solution should be look like this
Hello, gncl dzgn,
your problem has a flavor of homework which is usually not delt with on
this list. However, a few comments:
0. The description of your problem is rather vague, in particular, the
meaning of input in the description of your conditions is unclear! (By
the way, your main
Hello, Long Vo,
take a look at the help page of split or directly at
str(Y)
They tell you that Y is a list, and list components are indexed using
[[:
mean(Y[[4]])
should do what you want.
Regards -- Gerrit
This does what I needed. However, as the output is a list object, is there
, Gerrit Eichner
gerrit.eich...@math.uni-giessen.de wrote:
Dear R-list,
I've been trying to produce a sort of an interaction plot wherein colored
stripplots and boxplots are superposed. In particular, I want the colors of
the (transparently) filled boxes to be the same as the colors of the box
borders
and would be quite grateful if somebody
could give me a hint where to look further. Or is a workaround necessary
(and available)?
Thanks a lot in advance!
Best Regards -- Gerrit
-
Dr. Gerrit Eichner
Hi, Kristi,
I have adapted the interaction plot example of function panel.average() of
the lattice package and modified the code of panel.average() to a new
function panel.loc_and_scale(). See below. (There might be a much simpler
solution, though.)
Remark on the side: I can't resist to
Alex,
it is a bit unclear what you mean by remap etc., but maybe
y0 - 880e6; y1 - 1020e6
x0 - 1; x1 - ncol(x)
y0 + (x0-1):x1 * (y1 - y0)/(x1 - (x0-1))
gives what you want.
Hth -- Gerrit
On Thu, 31 Oct 2013, Alaios wrote:
Hi everyone,
I am plotting some legend and I am using
Hello, Alaois,
if x is your vector maybe
n - length( x)
positions - trunc( quantile( seq( n), prob = 0:5/5))
x[ positions]
comes close to what you want.
Hth -- Gerrit
Hi all, I have in my code some vectors that are not of equal size. I
would like to be able for each of these vectors
Hi, Jack,
well, I disagree: What do you expect to grab out of a bucket (= data
frame) if you do not at all grab into it (indexing with an _empty_ index,
i.e. with nothing)? And changing the sign of nothing is still nothing ...
Hth -- Gerrit
On Wed, 30 Oct 2013, Jack Tanner wrote:
I'm
Hello, Vincent,
you may want to take a look at Nonparametric methods in factorial
designs by Edgar Brunner and Madan L. Puri in Statistical Papers 42, 1-52
(2001).
There is the R-package nparcomp for one-way layouts, but the paper goes
further (and mentions another software) and is maybe a
Hi, Alaios,
check out
?which
and in particular its Examples and See Also section.
Hth -- Gerrit
On Tue, 22 Oct 2013, Alaios wrote:
Hi I have a vector like that
readCsvFile$V1
[1] 30 31 32 33 34 35 36 37 38 39 310 311 312 313 314 315 316 317 318
[20] 319 320 321 20 21 22 23
just forgot to take that possibility into consideration. :(
Regards -- Gerrit
On Tue, 15 Oct 2013, Duncan Murdoch wrote:
On 15/10/2013 7:53 AM, Gerrit Eichner wrote:
Dear list subscribers,
here is a small artificial example to demonstrate the problem that I
encountered when looking
stats4_3.0.2tools_3.0.2
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Liebig-University Giessen
Tel: +49-(0)641-99-32104 Arndtstr. 2, 35392 Giessen
Hello, Catalin,
check out
?coef
Regards -- Gerrit
On Tue, 15 Oct 2013, catalin roibu wrote:
Hello all!
I have a problem with R. I want to extract regression coefficients from
summary and use it for compute the theoretical values.
How can I do that in R?
thank you!
best regards,
--
---
to give you any hint. So, PLEASE do read the
posting guide http://www.R-project.org/posting-guide.html and provide
commented, minimal, self-contained, reproducible code.
Regards -- Gerrit
On 15 October 2013 14:59, Gerrit Eichner gerrit.eich...@math.uni-giessen.de
wrote:
Hello, Catalin
Hello, Adam,
I'm rather uncertain about your goal (and consequently even more so about
how to reach it), but anyway, maybe the function match.call() with its
argument expand.dots is of some help for you. From its help page:
match.call is most commonly used in two circumstances:
To
Hi, Jannis,
maybe
plot( 1, 1, main = bquote( paste( .(a), [, .(b), ])))
comes close to what you want, but I think you may even have to use the
following to get a varying exponent really printed elevated:
a - speed
b - m * s
cc - -2
plot( 1, 1, main = bquote( paste( .(a), [,
Hello, Paulito,
first, I think you haven't received an answer yet because you did not
provide commented, minimal, self-contained, reproducible code as the
posting guide does request it from you.
Second, see inline below.
On Wed, 11 Sep 2013, Paulito Palmes wrote:
Hi,
I have a data.frame
Hello, Francesco,
these could be considered as two of the central questions in statistics in
general ... but they do not necessarily have anything to do with R.
Regards -- Gerrit
On Fri, 6 Sep 2013, Francesco Miranda wrote:
how can i calculate the probability of occurrence of an event and
-
Dr. Gerrit Eichner Mathematical Institute, Room 212
gerrit.eich...@math.uni-giessen.de Justus-Liebig-University Giessen
Tel: +49-(0)641-99-32104 Arndtstr. 2, 35392 Giessen, Germany
Fax: +49-(0)641-99-32109http://www.uni
package
just for convenience.
Regards -- Gerrit
Thank you in advance
Edouard Hardy
On Tue, Sep 3, 2013 at 11:49 AM, Gerrit Eichner
gerrit.eich...@math.uni-giessen.de wrote:
Hello, Edouard,
taking logs of A's elements (so that * turns into +, so to say), using a
left-multiplication
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