Thats the ticket! So mean is already set up to operate on columns but max and
min are not? I guess its not too important now I know ... but whats going on
in
the background that makes that happen?
Basically, this:
mean.data.frame
function (x, ...)
sapply(x, mean, ...)
environment:
Using paste(Site,Prof) when calling ave() is ugly, in that it
forces you to consider implementation details that you expect
ave() to take care of (how does paste convert various types
to strings?). It also courts errors since paste(A B, C)
and paste(A, B C) give the same result but
On Wed, Apr 27, 2011 at 4:58 AM, Dennis Murphy djmu...@gmail.com wrote:
Hi:
You could try something like
df - data.frame( expand.grid( Week = 1:52, Year = 2002:2011 ))
expand.grid already returns a data frame... You might want
KEEP.OUT.ATTRS = F though. Even it feels like you are yelling
This has the side effect of ignoring errors
and even hiding the error messages. If you
are concerned about multiple calls to on.exit()
in one function you could define a new function
like
withOptions - function(optionList, expr) {
oldOpts - options(optionList)
On Wed, Apr 27, 2011 at 3:55 PM, Justin Haynes jto...@gmail.com wrote:
I am trying to extract the shape and scale parameters of a wind speed
distribution for different sites. I can do this in a clunky way, but
I was hoping to find a way using data.table or plyr. However, when I
try I am met
Put together a list and we can see what might make sense. If we did
take this on it would be good to think about providing a reasonable
mechanism for addressing the small flaw in this function as it is
defined here.
In devtools, I have:
#' Evaluate code in specified locale.
with_locale -
If you need plyr for other tasks you ought to use a different
class for your date data (or wait until plyr can deal with
POSIXlt objects).
How do you get POSIXlt objects into a data frame?
df - data.frame(x = as.POSIXlt(as.Date(c(2008-01-01
str(df)
'data.frame': 1 obs. of 1 variable:
On Wed, Apr 20, 2011 at 6:36 PM, Dennis Murphy djmu...@gmail.com wrote:
Hi:
Perhaps you're looking for subset()? I'm not sure I understand the
problem completely, but is
do.call(rbind, lapply(database, function(df) subset(df, Symbol == 'IBM')))
or
library(plyr)
ldply(lapply(database,
Yes, it's fixed and a new version of plyr has been pushed up to cran -
hopefully will be available for download soon. In the meantime, I
think you can fix it by running library(stats) before
library(ggplot2).
Hadley
On Sun, Apr 17, 2011 at 3:51 PM, Bryan Hanson han...@depauw.edu wrote:
Is
I was trying strsplit(string,\.\.\.) as per the suggestion in Venables
and Ripleys book to (use '\.' to match '.'), which is in the Regular
expressions section.
I noticed that in the suggestions sent to me people used:
strsplit(test,\\.\\.\\.)
Could anyone please explain why I should have
On Wed, Apr 13, 2011 at 5:18 AM, Dennis Murphy djmu...@gmail.com wrote:
Hi:
Here's one approach:
strings - c(
A5.Brands.bought...Dulux,
A5.Brands.bought...Haymes,
A5.Brands.bought...Solver,
A5.Brands.bought...Taubmans.or.Bristol,
A5.Brands.bought...Wattyl,
A5.Brands.bought...Other)
Even so, this would depend on what your publisher/printer
requires in what you submit. It would be important to obtain
from them a full and exact specification of what they require
for colour printing in files submitted to them for printing.
No one else has mentioned this, but the publisher
Am I missing something obvious on how to draw multi-line plots in base graphics?
In ggplot2, I can do:
data(Oxboys, package = nlme)
library(ggplot2)
qplot(age, height, data = Oxboys, geom = line, group = Subject)
But in base graphics, the best I can come up with is this:
with(Oxboys,
On Wed, Apr 13, 2011 at 2:58 PM, Ben Bolker bbol...@gmail.com wrote:
Hadley Wickham hadley at rice.edu writes:
Am I missing something obvious on how to draw multi-line plots in
base graphics?
In ggplot2, I can do:
data(Oxboys, package = nlme)
library(ggplot2)
qplot(age, height, data
Then, can we have the ERROR message, please?
Otherwise the only explanation I can guess is that a mirror grabs the
contents of a repository exactly in the second the repository is updated and
that is unlikely, particularly if more than one mirror is involved.
Isn't one possible explanation
# plyr
plyr is a set of tools for a common set of problems: you need to
__split__ up a big data structure into homogeneous pieces, __apply__ a
function to each piece and then __combine__ all the results back
together. For example, you might want to:
* fit the same model each patient subsets of
If all you need is loess, I suspect it would be cheaper to re-write it
in C# than to get a considered legal opinion on the matter.
Hadley
On Thu, Apr 7, 2011 at 2:45 AM, Stanislav Bek
stanislav.pavel@gmail.com wrote:
Hi,
is it possible to use some statistic computing by R in proprietary
Does anyone with specific windrose experience know how to adjust the
graphic such that the data and the percent intervals are evenly spaced?
Hopefully I am making sense here
How about giving us a reproducible example?
Code is better than mere description;
code + description is best.
filelist = list.files(pattern = K*cd.txt) # the file names are K1cd.txt
.to K200cd.txt
It's very easy:
names(filelist) - basename(filelist)
data_list - ldply(filelist, read.table, header=T, comment=;, fill=T)
Hadley
--
Assistant Professor / Dobelman Family Junior Chair
On Thu, Mar 24, 2011 at 8:29 AM, Michael Bach pha...@gmail.com wrote:
Dear R users,
Given this data:
x - seq(1,100,1)
dx - as.POSIXct(x*900, origin=2007-06-01 00:00:00)
dfx - data.frame(dx)
Now to play around for example:
subset(dfx, dx as.POSIXct(2007-06-01 16:00:00))
Ok. Now for
On Thu, Mar 24, 2011 at 2:24 PM, Kevin Burnham kburn...@gmail.com wrote:
I have a data file with indicates pretest scores for a linguistics
experiment. The data are in long form so for each of 33 subjects there are
400 rows, one for each item on the test, and there is a column called
I don't doubt that R may be the most popular in terms of discussion group
traffic, but you should be aware that the traffic for SAS comprises two
separate lists that used to be mirrored, but are no longer linked
Usenet -- news://comp.soft-sys.sas (what you counted)
listserve -- SAS-L
On Thu, Mar 17, 2011 at 7:25 AM, Richard D. Morey r.d.mo...@rug.nl wrote:
I would like to assign an value to an element of a list contained in an
environment. The list will contain vectors and matrices. Here's a simple
example:
# create toy environment
testEnv = new.env(parent = emptyenv())
2) I don't want to fit data with linear model of zero intercept.
3) I dont know if I understand correctly. Im 100% sure the model for my data
should have zero intercept.
The only coordinate which Im 100% sure is correct. If I had measured quality
Y of a same sample X0 number of times I would
No. First, please use path.expand(~) for this, and it does not
necessarily mean the home directory (and in principle it might not expand at
all). In practice I think it will always be *a* home directory, but on
Windows there may be more than one (and watch out for local/roaming profile
No, defaults are evaluated in the evaluation frame of the function. That's
why you can use local variables in them, e.g. the way rgamma uses 1/rate as
a default for scale.
Oops, yes, I was getting confused with promises - non-missing
arguments are promises evaluated in the parent frame.
But
On Mon, Mar 14, 2011 at 9:41 AM, Strategische Analyse CSD Hasselt
csd...@fedpolhasselt.be wrote:
Hello,
we want to plot a proportional symbol map with ggplot. Symbols' area should
have the same proportions as the scaled variable.
Hereby an example we found on
Its useful for being able to set defaults for arguments that do not
have defaults. That cannot break existing programs.
Until the next program decides do co change those defaults and either
can't or does and you end up with incompatible assumptions. It also
make the code with the added
Hi all,
Does anyone have any advice or experience storing package settings
between R runs? Can I rely on the user's home directory (e.g.
tools::file_path_as_absolute(~)) to be available and writeable
across platforms?
Hadley
--
Assistant Professor / Dobelman Family Junior Chair
Department of
You need to specify the group aesthetic - that defines how
observations are grouped into instances of a geom.
Hadley
On Tue, Mar 15, 2011 at 8:37 AM, joeP joseph.parr...@bt.com wrote:
Hi,
This seems like there should be a simple answer, but having spent most of
the day trying to find it, I'm
The bigger issue is that R can't tell the location of an open script,
which makes it harder to create new versions of existing work
But it can. If you open a script and choose save, it will be saved to the
same place. Or do you mean an executing script? There are indirect ways to
find
Could getSrcFilename() gain a default argument so that
getSrcFilename() would by default return the path of the executing
script?
No, it needs to see a function defined in that script.
But I thought default arguments were evaluated in the parent
environment? Does that not follow for source
Well, I'd start by removing all explicit use of environments, which
makes you code very hard to follow.
Hadley
On Monday, March 14, 2011, Daniele Amberti daniele.ambe...@ors.it wrote:
I found that plyr:::daply is more efficient than base:::by (am I doing
something wrong?), below updated code
)))
res - as.timeSeries(cbind(t(res)))
stopWorkers(w)
-Original Message-
From: h.wick...@gmail.com [mailto:h.wick...@gmail.com] On Behalf Of Hadley
Wickham
Sent: 14 March 2011 12:48
To: Daniele Amberti
Cc: r-help@r-project.org
Subject: Re: [R] dataframe to a timeseries object
On Mon, Mar 14, 2011 at 9:59 AM, ONKELINX, Thierry
thierry.onkel...@inbo.be wrote:
Something like this?
my_data=read.table(clipboard, header=TRUE)
my_data$s_name - factor(my_data$s_name)
library(plyr)
ddply(my_data, .(s_name), function(x){
x$Im_looking - x$Depth +
You might try sending a reproducible example
(https://github.com/hadley/devtools/wiki/Reproducibility) to the
ggplot2 mailing list.
Hadley
On Wed, Feb 16, 2011 at 8:41 AM, Kishorenalluri
kishorenalluri...@gmail.com wrote:
Dear All,
I need the assistance to plot the staked area plot using
On Wed, Mar 9, 2011 at 3:04 PM, Dimitri Liakhovitski
dimitri.liakhovit...@gmail.com wrote:
Hello!
I have a date (a Monday):
date-20081229
mydates-as.Date(as.character(date),%Y%m%d)
What package would allow me to create a vector that starts with that
date (mydates) and contains dates for
Ok, I am very interested in what methods you plan to use that would be fit
under the description suitably analyzed for voluntary response data. From
my training and experience the only suitable thing to do with voluntary
response data is to put it through the shredder, into the recycle
Note however that I've never seen evidence for a *practical*
difference in simple cases, and also of such cases as part of a
larger computation.
But I'm happy to see one if anyone has an interesting example.
E.g., I would typically never use 0L:100L instead of 0:100
in an R script because
You can replace the previous line by:
browser(expr=(a!=old.a)
see ?browser for details.
I don't understand why you'd want to do that - using if is much more
readable to me (and is much more general!)
Hadley
--
Assistant Professor / Dobelman Family Junior Chair
Department of Statistics /
One way to implement this functionality is with a task manager callback:
watch - function(varname) {
old - get(varname)
changed - function(...) {
new - get(varname)
if (!identical(old, new)) {
message(varname, is now , new)
old - new
}
TRUE
}
You can probably do this by constructing a call to the `names-` replacement
function, but it's really bad style. Don't write R code that has external
side effects if you can avoid it. In this case, you'll almost certainly get
more maintainable code by writing your function to return a copy
It's a bit better to use xtfrm.
Hadley
On Monday, February 14, 2011, jim holtman jholt...@gmail.com wrote:
'unclass' it first(assuming that it is POSIXct)
-unclass(mytime)
On Mon, Feb 14, 2011 at 3:55 AM, JonC jon_d_co...@yahoo.co.uk wrote:
I have a problem ordering by descending magnitude
On Mon, Feb 7, 2011 at 5:54 AM, Matthew Dowle mdo...@mdowle.plus.com wrote:
Looking at the timings by each stage may help :
system.time(dt - data.table(dat))
user system elapsed
1.20 0.28 1.48
system.time(setkey(dt, x1, x2, x3, x4, x5, x6, x7, x8)) # sort by the
8 columns
Does FAQ 1.8 answer that ok ?
Ok, I'm starting to see what data.table is about, but why didn't you
enhance data.frame in R? Why does it have to be a new package?
http://datatable.r-forge.r-project.org/datatable-faq.pdf
Kind of. I think there are two sets of features data.table provides:
There's definitely something amiss with aggregate() here since similar
functions from other packages can reproduce your 'control' sum. I expect
ddply() will have some timing issues because of all the subgrouping in your
data frame, but data.table did very well and the summaryBy() function in
On Wed, Jan 26, 2011 at 5:27 AM, Dennis Murphy djmu...@gmail.com wrote:
Hi:
Here are two more candidates, using the plyr and data.table packages:
library(plyr)
ddply(X, .(x, y), function(d) length(unique(d$z)))
x y V1
1 1 1 2
2 1 2 2
3 2 3 2
4 2 4 2
5 3 5 2
6 3 6 2
The
I think I should be able to do this using the reshape function, but
I cannot get it to work. I think I need some help to understand
this...
(If I could split the variable into three separate columns splitting
by ., that would be even better.)
Use strsplit and [
Or colsplit, from reshape,
...@gmail.com [[4]h.wick...@gmail.com] On Behalf Of Hadley
Wickham [[5]had...@rice.edu]
Sent: 19 January 2011 15:11
To: Small Sandy (NHS Greater Glasgow Clyde)
Cc: [6]r-help@r-project.org
Subject: Re: [R] ggplot2, geom_hline and facet_grid
Hi Sandy,
It's difficult to know
Hi Sandy,
It's difficult to know what's going wrong without a small reproducible
example (https://github.com/hadley/devtools/wiki/Reproducibility) -
could you please provide one? You might also have better luck with an
email directly to the ggplot2 mailing list.
Hadley
On Wed, Jan 19, 2011 at
how can I perform a string operation like strsplit(x, ) on a column of a
dataframe, and put the first or the second item of the split into a new
dataframe column?
(so that on each row it is consistent)
Have a look at str_split_fixed in the stringr package.
Hadley
--
Assistant Professor /
On Mon, Jan 17, 2011 at 2:20 PM, Sean Zhang seane...@gmail.com wrote:
Dear R-Helpers,
I wonder whether there is a function which cuts a multiple dimensional array
along a chosen dimension and then store each piece (still an array of one
dimension less) into a list.
For example,
arr -
library(plyr)
# Function to sum y by A-B combinations for a generic data frame
dsum - function(d) ddply(d, .(A, B), summarise, sumY = sum(y))
See count in plyr 1.4 for a much much faster way of doing this.
Hadley
--
Assistant Professor / Dobelman Family Junior Chair
Department of Statistics
The normal distribution is a continuous distribution, i.e., the frequency
for each observed value will essentially be 1/n and not converge to the
density function. Hence, you would need to look at histogram or smoothed
densities. Rootograms, on the other hand, are intended for discrete
On Sun, Jan 16, 2011 at 5:48 AM, bill.venab...@csiro.au wrote:
Here is one way
Here is one way:
con - textConnection(
+ ID TIME OBS
+ 001 2200 23
+ 001 2400 11
+ 001 3200 10
+ 001 4500 22
+ 003 3900
exp(median(log(x)) ?
Hadley
On Sat, Jan 15, 2011 at 10:26 AM, Skull Crossbones
witch.of.agne...@gmail.com wrote:
Hi All,
I need to calculate the median for even number of data points.However
instead of calculating
the arithmetic mean of the two middle values,I need to calculate their
The data is initially extracted from an SQL database into Excel, then saved
as a tab-delimited text file for use in R.
You might also want to look at the SQL packages for R so you can skip
this manual step. I'd recommend starting with
# plyr
plyr is a set of tools for a common set of problems: you need to
__split__ up a big data structure into homogeneous pieces, __apply__ a
function to each piece and then __combine__ all the results back
together. For example, you might want to:
* fit the same model each patient subsets of
Reshape2 is a reboot of the reshape package. It's been over five years
since the first release of the package, and in that time I've learned
a tremendous amount about R programming, and how to work with data in
R. Reshape2 uses that knowledge to make a new package for reshaping
data that is much
Hi Frank,
I think you mean packagename::functionname? The three colon form is
for accessing non-exported objects. Otherwise, I think using :: vs
importFrom is functionally identical - either approach delays package
loading until necessary.
Hadley
On Mon, Jan 3, 2011 at 9:45 PM, Frank Harrell
I think you mean packagename::functionname? The three colon form is
for accessing non-exported objects.
Normally two colons suffice, but within a package you need three to
access exported but un-imported objects :)
Are you sure?
Note that it is typically a design mistake to use ‘:::’
Correct. I'm doing this because of non-exported functions in other packages,
so I need :::
But you really really shouldn't be doing that. Is there a reason that
the package authors won't export the functions?
I'd still appreciate any insight about whether importFrom in NAMESPACE
defers
It looks like you have csv files, so use read.csv instead of read.table.
Hadley
On Thu, Dec 30, 2010 at 12:18 AM, Amy Milano milano_...@yahoo.com wrote:
Dear sir,
At the outset I sincerely apologize for reverting back bit late as I was out
of office. I thank you for your guidance extended by
The Inkscape user asked if there was any way that R could be coerced to use
actual circles or paths for the points. I am not aware of a way to do this so
any input from anyone here would be greatly appreciated.
pdf(..., useDingbats = F)
Hadley
--
Assistant Professor / Dobelman Family Junior
ggplot2
ggplot2 is a plotting system for R, based on the grammar of graphics,
which tries to take the good parts of base and lattice graphics and
avoid bad parts. It takes care of many of the fiddly details
that make plotting a hassle
input - do.call(rbind, lapply(fileNames, function(.name){
+ .data - read.table(.name, header = TRUE, as.is = TRUE)
+ # add file name to the data
+ .data$file - .name
+ .data
+ }))
You can simplify this a little with plyr:
fileNames - list.files(pattern = file.*.csv)
It isn't quite convenient to read the data posted below into R
(if it was originally tab-separated, that formatting got lost) but
ddply from the plyr package is good for this: something like (untested)
d - with(data,ddply(data,interaction(UniqueID,Reason),
function(x) {
In ggplot2, by default the x-axis is in the bottom of the graph and
y-axis is in the left of the graph. I wonder if it is possible to:
1. put the x axis in the top, or put the y axis in the right?
2. display x axis in both the top and bottom?
These are on the to do list.
3. display x axis
: 01412114592)
From: h.wick...@gmail.com [h.wick...@gmail.com] On Behalf Of Hadley Wickham
[had...@rice.edu]
Sent: 01 December 2010 14:27
To: Small Sandy (NHS Greater Glasgow Clyde)
Cc: ONKELINX, Thierry; r-help@r-project.org
Subject: Re: [R] ggplot2
On Mon, Dec 6, 2010 at 3:58 AM, Sunny Srivastava
research.b...@gmail.com wrote:
Dear R-Helpers:
I am using trying to use *ddply* to extract min and max of a particular
column in a data.frame. I am using two different forms of the function:
## var_name_to_split is a string -- something like
. I am sorry if it is a basic question.
Thank you and others for your reply.
Best Regards,
S.
On Mon, Dec 6, 2010 at 5:28 PM, Hadley Wickham had...@rice.edu wrote:
On Mon, Dec 6, 2010 at 3:58 AM, Sunny Srivastava
research.b...@gmail.com wrote:
Dear R-Helpers:
I am using trying to use
However if you do:
ggplot(data=dafr, aes(x = d1, fill=d2)) + geom_histogram(binwidth = 1,
position = position_dodge(width=0.99))
The position of first bin which goes from 0-2 appears to start at about 0.2
(I accept that there is some white space to the left of this) while the
position of
You may find it easier to use a frequency polygon, geom = freqpoly.
Hadley
On Tue, Nov 30, 2010 at 2:36 PM, Small Sandy (NHS Greater Glasgow
Clyde) sandy.sm...@nhs.net wrote:
Hi
With ggplot2 I can very easily create beautiful histograms but I would like
to put two histograms on the same
res - function(x) resid(x)
ds_test$u - do.call(c, llply(mods, res))
I'd be a little careful with this, because there's no guarantee the
results will by ordered in the same way as the input (and I'd also
prefer ds_test$u - unlist(llply(mods, res)) or ds_test$u -
laply(mods, res))
In your case,
Since roxygen is a great help to document R packages, I am wondering
if there exists an approach to go back from the raw Rd files to
roxygen-documentation? E.g. turn \author{Somebody} into @author
Somebody. This sounds ridiculous, but I believe it helps in the long
term for me to maintain R
rowsum(value, paste(factor1, factor2, factor3))
That is dangerous in general, and always inefficient. Imagine factor1
is c(a, a b) and factor2 is (b c, c). Use interaction with
drop = T.
Hadley
--
Assistant Professor / Dobelman Family Junior Chair
Department of Statistics / Rice University
Where the value of exp(1) as computed by R is concerned, you have
been deceived by what R displays (prints) on screen. The default
is to display any number to 7 digits of accuracy, but that is not
the accuracy of the number held internally by R:
exp(1)
# [1] 2.718282
exp(1) - 2.718282
Hi all,
What's the equivalent to length(unique(x)) == 1 if want to ignore
small floating point differences? Should I look at diff(range(x)) or
sd(x) or something else? What cut off should I use?
If it helps to be explicit, I'm interested in detecting when a vector
is constant for the purpose
I think this does what you want (borrowing from all.equal.numeric):
all(abs((x - mean(x))) .Machine$double.eps^0.5)
with a vector of length 1 million, it took .076 seconds on a fairly old
system.
Hmmm, maybe I want:
all.equal(min(x), max(x))
?
Hadley
--
Assistant Professor / Dobelman
It's hard to know without a minimal reproducible example, but you
probably want scale_fill_gradient or scale_fill_gradientn.
Hadley
On Thu, Oct 28, 2010 at 9:42 AM, Struchtemeyer, Chris
stru...@okstate.edu wrote:
I am very new to R and don't have any computer program experience
whatsoever. I
This is on my to do list:
https://github.com/hadley/ggplot2/issues/labels/facet#issue/107
Hadley
On Thu, Oct 28, 2010 at 11:51 AM, Matthew Pettis
matthew.pet...@gmail.com wrote:
Hi All,
Here is the code that I'll be referring to:
p - ggplot(wastran.data, aes(PER_KEY, EVENTS))
(p - p +
Beware of facile comparisons of this sort -- they may be apples and nematodes.
And they also imply that the main time sink is the computation. In my
experience, figuring out how to solve the problem using takes
considerably more time than 18 / 1000 seconds, and so investing your
energy in
Note how S3 methods are dispatched only by reference to the first
argument (on the left of the operator). I think S4 beats this by
having signatures that can dispatch depending on both arguments.
That's somewhat of a simplification for primitive binary operators. R
actually looks up the method
git is where the world is headed. This video is a little old:
http://www.youtube.com/watch?v=4XpnKHJAok8, but does a good job
getting the point across.
And lots of R users are using github already:
http://github.com/languages/R/created
Hadley
--
Assistant Professor / Dobelman Family Junior
On Tue, Oct 26, 2010 at 11:55 AM, Dennis Murphy djmu...@gmail.com wrote:
Hi:
When it comes to split, apply, combine, think plyr.
library(plyr)
ldply(split(afvtprelvefs, afvtprelvefs$basestudy),
function(x) coef(lm (ef ~ quartile, data=x, weights=1/ef_std)))
Or do it in two steps:
1. What is everyone else using? The network effect is important since
you want people to be able to access your repository and you want to
leverage your knowledge of the version control system for other
projects' repositories. To that extent Subversion is the clear choice
since its used on
Or str_locate:
library(stringr)
str_locate(aabcd, bcd)
Hadley
On Mon, Oct 25, 2010 at 5:53 AM, jim holtman jholt...@gmail.com wrote:
I think what you want is 'regexpr':
regexpr(bcd, aabcd)
[1] 3
attr(,match.length)
[1] 3
On Mon, Oct 25, 2010 at 7:27 AM, yoav baranan
On Thu, Oct 14, 2010 at 11:56 AM, Joshua Wiley jwiley.ps...@gmail.com wrote:
Hi,
I do not believe you can use the save.image() function in this case.
save.image() is a wrapper for save() with defaults for the global
environment (your workspace). Try this instead, I believe it does
what you
My guess is you are using an outdated R version for which the rather new
reshape2 package has not been compiled.
I wonder if install.packages() could detect this case (e.g. by also
checking if the source version is not available), and offer a more
informative error message.
Hadley
--
Do you also know more references about variables? Unfortunately this was a
little bit short so I do not feel 100% sure I completely got it.
Try here:
http://github.com/hadley/devtools/wiki/Scoping
It's a work in progress.
Hadley
--
Assistant Professor / Dobelman Family Junior Chair
On Wed, Oct 6, 2010 at 4:05 PM, Michael Friendly frien...@yorku.ca wrote:
I'm giving a talk about some aspects of language and conceptual tools for
thinking about how
to solve problems in several programming languages for statistical computing
and graphics. I'm particularly
interested in
That is, I want to define something like the
following using an a*ply method, but aaply gives a result in which the
applied .margin(s) do not appear last in the
result, contrary to the documentation for ?aaply. I think this is a bug,
either in the function or the documentation,
but perhaps
RFF-function(qtype, qOpt,...){}
i.e., I have two args that are compulsary and the rest are optional. Now when
my user passes the function call, I need to see what optional args are
defined and process accordingly...what I have so far is..
RFF-function(qtype, qOpt,...){
mc -
I'm not sure this will solve the issue because if I move the script, I would
still have to go into the script and edit the /path/to/my/script.r, or do
I misunderstand your workaround?
I'm looking for something like:
file.path.is.here(myscript.r)
and which would return something like:
[1]
You might want to check out the plyr package.
Hadley
On Fri, Oct 1, 2010 at 6:05 AM, Werner W. pensterfuz...@yahoo.de wrote:
Hi,
I was wondering if there is an easy way to accomplish the following in R:
Often I want to apply a function, e.g. weighted.quantile from the Hmisc
package
to
Forgive me if this question has been addressed, but I was unable to find
anything in the r-help list or in cyberspace. My question is this: is there a
function, or set of functions, that will enable a script to detect its own
path? I have tried file.path() but that was not what I was
That implies you need to update your version of plyr.
Hadley
On Wed, Sep 22, 2010 at 4:10 AM, RaoulD raoul.t.dso...@gmail.com wrote:
Hi,
I am using ggplot2 to create a boxplot that summarizes a continuous
variable. This code works fine for me on one PC however when I use it on
another it
Yes, this was a little bug that will be fixed in the next release.
Hadley
On Thu, Sep 16, 2010 at 1:11 PM, Dylan Beaudette
debeaude...@ucdavis.edu wrote:
Hi,
I have been trying to use the new .parallel argument with the most recent
version of plyr [1] to speed up some tasks. I can run the
Hi Uwe,
The problem is most likely because the original poster doesn't have
the latest version of plyr. I correctly declare this dependency in
the DESCRIPTION
(http://cran.r-project.org/web/packages/reshape2/index.html), but
unfortunately R doesn't seem to use this information at run time,
Have a look at:
Computing Thousands of Test Statistics Simultaneously in R by Holger
Schwender and Tina Müller, in
http://stat-computing.org/newsletter/issues/scgn-18-1.pdf
Hadley
On Mon, Sep 13, 2010 at 4:26 PM, Alexey Ush usha...@yahoo.com wrote:
Hello,
I have a question regarding how to
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