Hi Johannes,
I set the R version using something like this in my init file:
(setq inferior-ess-r-program "C:/Program Files/R/R-4.3.1/bin/x64/Rterm.exe")
But I'm still using ESS 18.10.2 (in Vincent Goulet's Emacs
distribution) so that line might not be the right way to do it in the
version you're
> From: Woody Setzer
>
> Try changing your repository from Melpa to Melpa-stable:
>
> (add-to-list 'package-archives
> '("melpa-stable" . "https://stable.melpa.org/packages/;) t)
>
> I had a similar problem after a recent update of ESS in MELPA, but
> after I deleted ESS and
> From: "Richard M. Heiberger"
>
> ess sends spurious commands to the *R* buffer, for example
>
> > (list "base" '(("..." . "") ("deparse.level" . "1")) '("..."
> > "deparse.level" "recursive" "make.row.names" "stringsAsFactors"
> > "factor.exclude" "use.names" "fill" "idcol" "size" "z"
ng the
error messages "Symbol’s function definition is void:
ess-local-process-name" and "Error running timer
‘ess--idle-timer-function’: (void-function ess-local-process-name)"?
Thanks,
Mark Seeto
-
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> Date: Thu, 17 Sep 2020 16:34:54 -0400
> From: Vincent Goulet
> To: ess-help@r-project.org
> Subject: [ESS] Latest Emacs distributions out!
> Message-ID: <0281e8bb-019e-413d-9d10-43ad71cb4...@me.com>
> Content-Type: text/plain; charset="utf-8"
>
> Hi all,
>
> With some delay, I'm glad to
Dear R-help,
In the rms package, when using the ols function with a penalty, the
df.residual appears to always be n-1 (with n being the sample size).
That seems strange to me, but I don't have much knowledge in this
area.
Here's an example:
library(rms)
set.seed(1)
n <- 50
d <- data.frame(x1
Thanks for your reply Mehmet. I've found that the problem was that I
didn't scale the lambda value. My original example did not follow the
instruction not to give a single lambda value, but that in itself
wasn't the problem. Example shown below.
library(glmnet)
library(MASS)
set.seed(1)
n - 20
Dear R-help,
I'm having trouble understanding how glmnet converts its coefficient
estimates back to the original scale. Here's an example with ridge
regression:
library(glmnet)
set.seed(1)
n - 20 # sample size
d -
can give.
Mark Seeto
#
library(rms)
set.seed(1)
n - 100 # sample size
beta0 - 3.7
beta1 - 1.5
beta2 - 0.9
beta3 - 0.5
rate.x1 - 2
mean.x2 - 1
sd.x2 - 2
nu - 1.3
d - data.frame(x1 = rexp(n, rate = rate.x1
, ]
###
Have I misunderstood something?
Thanks,
Mark Seeto
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(gls.intercept, gls.rcs4)
Thanks,
Mark Seeto
National Acoustic Laboratories, Australia
Appears to be a definite bug, probably caused by having more than one
correlation parameter. I hope to have this fixed within 3 days.
Frank
Mark Seeto wrote
Dear R-help,
I don't understand why Gls gives
with a spline using rcs. I'm using version 3-5.0 of rms in R 2.15.0.
Thanks for any help you can give.
Mark Seeto
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plots. I'm using RGui on Windows 7. It did
not happen with R 2.13.1.
It's not a major problem, because the plots still appear to be
produced correctly, but if anyone can tell me how to fix it, I'd
appreciate it.
Thanks,
Mark Seeto
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x a.-5 y
1 00 0
2 11 1
Why does the a.-5 column name change to a..5 when another column is added?
Thanks,
Mark Seeto
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garciap wrote:
Hi to all the people,
I'm having a trouble when trying to plot a quadratic function. I have the
code:
regression-nls(Survival~beta1+beta2*PI+beta3*PI^2, data=cubs,
start=list(beta1 = 1, beta2 = 1, beta3 = 1))
plot(Survival~PI,data=cubs, ylab=Survival, xlab=PI)
Mark Seeto wrote:
garciap wrote:
Hi to all the people,
I'm having a trouble when trying to plot a quadratic function. I have the
code:
regression-nls(Survival~beta1+beta2*PI+beta3*PI^2, data=cubs,
start=list(beta1 = 1, beta2 = 1, beta3 = 1))
plot(Survival~PI,data=cubs, ylab
list. If I reply to the list, there's an option
to email the post to someone, but I don't know the person's email address.
Thanks,
Mark Seeto
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you forget to run dev.off(), as in that example.
But we don't have the
commented, minimal, self-contained, reproducible code.
the posting guide and the footer of every R message asks for.
On Sun, 12 Jun 2011, Mark Seeto wrote:
Raptorista wrote:
Now, the graph that appears is very
Raptorista wrote:
Now, the graph that appears is very nice: indeed it has a title, two
axes with their labels and all the rest;
but when I give commands
postscript(file=plot.eps, onefile=FALSE)
qqnorm (col)
to save the graph to a file plot.eps to include it in a TeX, the file
created
Thanks for your reply, Frank. I've noticed that the x.knots object doesn't
actually have to be the vector of knots. Just having x.knots - 0 or even
x.knots - a will allow predict to work.
Mark Seeto
Frank Harrell wrote:
This is a consequence of predict.ols calling predictrms which relies
as a vector like
c(-1, 0, 1) (i.e. not using quantile). Is this the intended behaviour?
The requirement that x.knots be in the workspace seems strange, given
that the knot locations are stored in ols1$Design$parms.
Thanks for any help you can give.
Mark Seeto
National Acoustic Laboratories, Australia
Is there a way to do these things without first creating new variables
in the data frame?
Thanks,
Mark Seeto
National Acoustic Laboratories
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.
Frank
Mark Seeto wrote:
Dear R help,
I'm having some trouble with model formulas for the ols function in
the rms package. I want to have two variables represented as
restricted cubic splines, and also include an interaction as a product
of linear terms, but I get an error message.
library(rms)
d
there.
Thanks,
Mark Seeto
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and provide commented, minimal, self-contained, reproducible code.
Amit Patel-7 wrote:
Hi
I have used the amelia command from the Amelia R package. this gives me a
number
of imputed datasets.
This may be a silly question, but i am not a statistician, but I am not
sure how
to combine these results to obtain the imputed dataset to usse for further
Try excluding the first column.
cor(gse20437[, 2:4])
chintan85 wrote:
Tab delimited file looks like this
Id v1 v2v3
df 56 9045
gh 87 9878
ty 897867
I used this code
[code]
gse20437 - read.csv(C:/Users//Desktop/data/GSE20437_matrix.txt,header =
, the
ordinary t interval appears to be better than the bootstrap BCA
interval. I would really appreciate any recommendations anyone can
give on when bootstrap confidence intervals should be used.
Thanks,
Mark
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National Acoustic Laboratories, Australian Hearing
(ols.imp2)
anova(fmi)
unexpectedly give the same result in the ERROR line. I would be most
grateful if anyone could explain this to me.
I need to add some more warnings. For many of the calculations, the
last imputation is used.
Frank
Thanks,
Mark
--
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Statistician
National Acoustic
.
Thanks,
Mark
--
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National Acoustic Laboratories http://www.nal.gov.au/
A Division of Australian Hearing
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Thank you for your reply Frank. I am not familiar with the contrast
test, but I'll see what I can find out about it.
Mark
Frank Harrell wrote:
On Mon, 9 Aug 2010, Mark Seeto wrote:
Hello, I have a general question about combining imputations as well
as a
question specific to the rms
of 9 gives a corrected slope of about 1.17 (corrected slope
of 1 is achieved with a penalty of about 1 or 2).
Thanks for any help/advice you can give.
Mark
--
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Statistician
National Acoustic Laboratories
A Division of Australian Hearing
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can give.
Regards,
Mark
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Statistician
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A Division of Australian Hearing
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Bill and Erik, thank you very much for your help. In addition to
solving my problem, both solutions contain other good things I didn't
know about.
Regards,
Mark Seeto
On Thu, Jun 10, 2010 at 2:44 PM, Erik Iverson er...@ccbr.umn.edu wrote:
Hello,
How does one specify a formula to lm inside
On 06/06/2010 10:49 PM, Mark Seeto wrote:
Hello,
I have a couple of questions about the ols function in Frank Harrell's
rms
package.
Is there any way to specify variables by their column number in the data
frame rather than by the variable name?
For example,
library(rms)
x1- rnorm
On 06/08/2010 05:29 AM, Mark Seeto wrote:
On 06/06/2010 10:49 PM, Mark Seeto wrote:
Hello,
I have a couple of questions about the ols function in Frank Harrell's
rms
package.
Is there any way to specify variables by their column number in the
data
frame rather than by the variable
) : '.' in formula and no 'data' argument
Thanks for any help you can give.
Regards,
Mark
--
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Statistician
National Acoustic Laboratories http://www.nal.gov.au/
A Division of Australian Hearing
126 Greville Street
Chatswood NSW 2067 Australia
P +61 2 9412 6800
F +61 2 9411 8273
Harrell says should happen.
I am either misunderstanding something or making a mistake in the code
(I'm almost 100% certain I'm not mixing up the axes). I would be most
appreciative if anyone could explain where I'm going wrong.
Thanks for any help you can provide.
Mark Seeto
Thank you very much for your help, Prof. Harrell. I was making the bad
mistake of judging the appearance of the calibration plots without
actually calculating the regression line. I was misjudging slopes of
0.8 or 0.9 as being slopes greater than 1.
Kind regards,
Mark Seeto
Mark,
Try
Hello,
I'm fairly new to R and I can't work out how to produce a double
inequality like (LaTeX) $0 \leq x \leq 1$ in the legend of a graph. If
I try
legend(50, 0.1, legend = c(expression(0 = x = 1), c(2 = x = 3)), pch =
c(1,1), col = c(2, 3))
then I get an error message unexpected '=' in
Thank you very much Duncan. I see I also had the mistake of a c
instead of expression in my question.
Mark
On Fri, Jan 22, 2010 at 7:59 AM, Duncan Murdoch murd...@stats.uwo.ca wrote:
On 21/01/2010 3:50 PM, Mark Seeto wrote:
Hello,
I'm fairly new to R and I can't work out how to produce
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