Dear Jose,
Am Montag, den 12.12.2011, 19:44 + schrieb Jose Bustos Melo:
> Hello everyone,
>
> I want make a variable selection from a dataframe, but when I build this new
> object (using cbind) the new table (which is a matrix) I lost all the
> original factor names in the variables. I get
Am Montag, den 12.12.2011, 09:41 -0500 schrieb R. Michael Weylandt :
> Why can't you just replace "temp/data" with filename (no quotes)? I'm not
> sure I get the question...
… no I am feeling silly and I do not know where I screwed up before.
Here is the full working example.
#!/usr/bin/
Dear R folks,
I have several data sets I want to process automatically using R. I
found littler [1] and thought this will do the trick.
1. Read in data file to a data frame using `scan()`.
2. Do linear regression.
3. Write the data and the coefficients back to a file.
#!/usr/bin/env r
Dear R folks,
I would like to use un-/a-/non-symmetric centered, i. e. the expectation
vanishes/is zero, distributions.
Searching for that is not that easy since all three words un-, a-,
non-symmetric seem to be common.
Do I need to create such a distribution myself by for example composing
a d
Dear R folks,
having simulation data in a vector n2off, I know that they should be
similar to a power function f [1], f(n) = n^(-1/r), r ∈ ℕ\{0}, and I
want to find the value for r best fitting the simulation data.
Furthermore I know that this is only true for big n, that means n2off(n)
~ f(n) ⇔
Dear Dennis and Steve,
Am Sonntag, den 31.07.2011, 23:32 -0400 schrieb Steve Lianoglou:
[…]
> How about trying to write the of this `f4` function below using the
> rcpp/inline combo. The C/C++ you will need to write looks to be quite
> trivial, let's change f4 to accept an x argument as a vecto
Am Montag, den 01.08.2011, 12:43 -0400 schrieb R. Michael Weylandt :
> I've only got a 20 minute layover, but three quick remarks:
>
> 1) Do a sanity check on your data size: if you want a million walks of
> a thousand steps, that already gets you to a billion integers to
> store--even at a very l
Am Sonntag, den 31.07.2011, 23:32 -0500 schrieb R. Michael Weylandt :
> Glad to help -- I haven't taken a look at Dennis' solution (which may be far
> better than mine), but if you do want to keep going down the path outlined
> below you might consider the following:
I will try Dennis’ solution ri
Am Mittwoch, den 27.07.2011, 19:59 -0400 schrieb R. Michael Weylandt :
> Some more skilled folks can help with the curve fitting, but the general
> answer is yes -- R will handle this quite ably.
Great to read that.
> Consider the following code:
>
> <<-->>
>
Am Sonntag, den 31.07.2011, 15:19 -0700 schrieb Jeffrey Dick:
> Here's an attempt using sapply:
>
> > x <- c(2, 2, 3, 3, 4, 6)
> > ys <- 1:8
> > sapply(ys, function(y) { length(which(x==y)) } )
> [1] 0 2 2 1 0 1 0 0
The last piece for my trials missing was `sapply()` which I overlooked
reading `?
Dear Sarah,
Am Sonntag, den 31.07.2011, 18:10 -0400 schrieb Sarah Goslee:
> I would use something like this:
>
> > x <- c(2,2,3,3,4,6)
> > table(x)
> x
> 2 3 4 6
> 2 2 1 1
> > x <- factor(x, levels=1:8)
> > table(x)
> x
> 1 2 3 4 5 6 7 8
> 0 2 2 1 0 1 0 0
awesome. Thank you.
Looking further I
Dear R folks,
I am sorry to ask this simple question, but my search for the right
way/command was unsuccessful.
I have a vector
> x <- c(2, 2, 3, 3, 4, 6)
Now the values of x should be considered the index of another vector
with possible greater length, say 8, and the value should be how often
Dear responders,
thank you very much for all your answers, suggestions and corrections. I
will try to give feedback and share my findings.
Am Donnerstag, den 28.07.2011, 01:56 + schrieb William Dunlap:
[…]
> You might try using sample(c(-1,1), size=length, replace=TRUE)
> instead of sign(r
Am Freitag, den 29.07.2011, 15:28 +0200 schrieb Paul Menzel:
> wanting to compare different implementations of a solution I want to
> script it to iterate over the different implementations. Is there a way
> to do this in the R shell/command line?
>
> $ more /tmp/iterf
Dear R webmasters,
my browser defaults to the charset UTF-8 and since [1] seems to be
encoded in ISO-8859-1 the umlauts are not displayed correctly. It would
be great if the encoding could be added to the header [2]. (Or the page
converted to UTF-8 and the problem would be solved for me. ;-) )
Dear Simon,
Am Freitag, den 29.07.2011, 12:32 -0700 schrieb Crock:
> i`m trying to use the plot function to show more variable-funktions in one
> graphic. so for example i would like to show Chinas Income in different
> sectors in one graphic. obviousely typing plot(ChinaIncome) the graphics are
Dear Eik,
Am Freitag, den 29.07.2011, 15:46 +0200 schrieb Eik Vettorazzi:
> how about this
> for (i in 1:2) { print( do.call(paste("f",i,sep=""),list(2, 3) )) }
>
> or using get
> for (i in 1:2) { print( get(paste("f",i,sep=""))(2, 3) ) }
works great for me. Thank you very much. Regarding searc
Dear R folks,
wanting to compare different implementations of a solution I want to
script it to iterate over the different implementations. Is there a way
to do this in the R shell/command line?
$ more /tmp/iterf.r
f1 <- function(n = 10,
l = 10)
Am Donnerstag, den 28.07.2011, 09:12 +0200 schrieb Martin Maechler:
> >>>>> "PM" == Paul Menzel
> >>>>> on Wed, 27 Jul 2011 23:53:51 +0200 writes:
[…]
> PM> So my newest suggestion is to add a comment to
>
> PM> plot(si
Dear R folks,
Am Donnerstag, den 28.07.2011, 01:36 +0200 schrieb Paul Menzel:
> I need to simulate first passage times for iterated partial sums. The
> related papers are for example [1][2].
>
> As a start I want to simulate how long a simple random walk stays
> negative, whic
Dear R folks,
I need to simulate first passage times for iterated partial sums. The
related papers are for example [1][2].
As a start I want to simulate how long a simple random walk stays
negative, which should result that it behaves like n^(-½). My code looks
like this.
8< c
Am Mittwoch, den 27.07.2011, 18:04 -0400 schrieb David Winsemius:
> On Jul 27, 2011, at 5:53 PM, Paul Menzel wrote:
> > as `plot.function` is not explicitly mentioned in `?plot`.
>
> Right, but the fact that it _is_ described as a "generic" function
> will tell th
Am Mittwoch, den 27.07.2011, 17:21 -0400 schrieb David Winsemius:
> On Jul 27, 2011, at 4:53 PM, Paul Menzel wrote:
> > Am Mittwoch, den 27.07.2011, 13:26 -0700 schrieb Bert Gunter:
> >> Paul:
> >> No such change is needed.
> >
> > Well the fact is, tha
Dear Bert,
Am Mittwoch, den 27.07.2011, 13:26 -0700 schrieb Bert Gunter:
> Paul:
> No such change is needed.
Well the fact is, that I as a beginner was looking for who I could plot
normal functions, so one more example would have helped me.
> You do not understand S3 methods.
That is probably
Dear R folks,
currently the section Examples contains the following as an example on
how to plot a “normal” function.
plot(sin, -pi, 2*pi)
Since it does not contain the argument for the function it would be
helpful to add for example the following.
## plots the graph of f(x) =
Am Mittwoch, den 27.07.2011, 14:36 -0400 schrieb David Winsemius:
> On Jul 27, 2011, at 10:12 AM, Paul Menzel wrote:
> > I am having problems getting good results when searching for R related
> > topics, that means I have not found out yet what keywords I should use
> >
Dear R folks,
I am having problems getting good results when searching for R related
topics, that means I have not found out yet what keywords I should use
to get only relevant results. Most of the time I get also MATLAB related
things and nothing related at all. The nature of this is of course t
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