Hallo Nadja
Similar as Bert I do not know how the function works. From the help page -
synth.data - is used in example. Check if your data structure is consistent
with synth.data by comparing str(synth.data) and str( INVESTMENTVOLUME).
Names of columns should be in both cases match the names in
Hallo James
Just a wild guess, are your problems connected with change of default
download method from wininet to libcurl?
Cheers
Petr
út 20. 2. 2024 v 18:24 odesílatel James Powell napsal:
>
[[alternative HTML version deleted]]
__
I am not allowed to connect to Nabble from work, sorry.
Petr
hi peter the pdf folder is in
http://r.789695.n4.nabble.com/file/n4639434/aj.pdf
--
View this message in context: http://r.789695.n4.nabble.com/help-to-
program-my-function-tp4639434p4639629.html
Sent from the R help
Hi
Specifically, since it has only a single detection indicator column
(ceneq1), it implies that within any single sample either all the
analytes
were detected, or all were not. Not what I would expect.
Don,
I have been thinking about this and wondered whether the cast format
hope both is sufficient.
@ Petr Pikal-3: in this case, there are only numerical values, but it's
a
useful hint for my other codes.
@ Petr Pikal-3 and Berend Hasselman: initializing indxind with 0's
instead
of NAs helps, it fills something in indxind now. but it does the
calculation
only
Hi
all problems solved. thank you for your help!
for the sake of completeness, here my solution:
#1) read in data:
daten-read.table('K:/Analysen/STRUCTURE/test.txt', header=TRUE,
sep=\t)
daten-as.data.frame(daten)
not needed, daten is already data frame
#2)
/packages/plan/plan.pdf
-- Bert
On Tue, Aug 7, 2012 at 1:28 AM, Petr PIKAL petr.pi...@precheza.cz
wrote:
Dear all
I need to perform some process evaluation. Sorry for not posting data
and
code - I do not have any, I ask only for pointing me to correct
direction.
Suppose I have
Probably a problem in your setting or envirenment or print function
Here is what I get
x1-64.90
x2-17.7025
c(x1,x2)
[1] 64.9000 17.7025
x-c(x1,x2)
x
[1] 64.9000 17.7025
Regards
Petr
HI
i have a little problem please help me to solve it
this is the code in R:
beta0
[1]
, Petr PIKAL petr.pi...@precheza.cz
wrote:
Dear all
I need to perform some process evaluation. Sorry for not posting data
and
code - I do not have any, I ask only for pointing me to correct
direction.
Suppose I have several connected processes P1, P2, ..., Pn. Each
process
takes
Hi
Maybe it is time for you to read some basic stuff like R intro. It seems
to me that you expect R to behave like some other language you know but
probably your expectation is wrong.
See inline
HI
i have a problem please help me to solve it:
Hi
hello, this is my script:
#1) read in data:
daten-read.table('K:/Analysen/STRUCTURE/input_STRUCTURE_tab_excl_5_282_559.txt',
header=TRUE, sep=\t)
daten-as.matrix(daten)
If there is any column with nonnumeric values it will transfer all numeric
values from daten data.frame to
Hi
please cc your post also to Rhelp list, others may give you better/quicker
answer.
HI peter
there is the function that i want to programm (joint in pdf folder).
No pdf allowed.
my data is dataexpv Ti1 265.792 26 1579.523 26
2323.704
28 68.855 28 426.076 28
Hi
Dear Jean
Thanks a lot for your help.
The reason I did not provide producible code is that my work started
with
reading in some large csv files, e.g. the data is not created by myself.
But the data is from the same data provider so I would expect to
receive
data in exactly same
Dear all
I need to perform some process evaluation. Sorry for not posting data and
code - I do not have any, I ask only for pointing me to correct direction.
Suppose I have several connected processes P1, P2, ..., Pn. Each process
takes some time and have some capacity (let say like preparing
Hi
Hi,
I appreciate your help with the segmented function. I am relatively new
to
R. I followed the introduction of the 'segmented'-package by Vito
Muggeo,
but still it does not work.
Here are the lines I wrote:
data_test-data.frame(x=c(1:10),y=c(1,1,1,1,1,2,3,4,5,6))
Hi
It is better to use dput for presenting data for others. You probably want
?merge.
Something like
merge(datuak, datuak2, by = calee_id, all.x=TRUE)
However calee_id seems to be a floating point number and it may be rounded
so you shall beware of it.
Regards
Petr
Thank you very much
Hi
OTOH I wonder why cbind gives error as OP told us
x - data.frame(x = 1:5)
y - data.frame(y = 6:15)
merge(x,y)
cbind(x,y)
Gives different results but without any error.
Regards
Petr
On Thu, Aug 2, 2012 at 4:52 PM, Ayyappa Chaturvedula
ayyapp...@gmail.com wrote:
Michael,
Thank you
Hi
Your description is quite long but almost uninformative about what you
really want.
You do not say which values you want to sum but you say it is completely
equal which value you want to add to what and what shall be the final
vector length
Based on this I would just use simple +
x-1:10
Hi
one of possible options
f- function(x, parts) split(x,rep(1:length(parts),parts))
f(9:1, c(3,2,4))
$`1`
[1] 9 8 7
$`2`
[1] 6 5
$`3`
[1] 4 3 2 1
You can also check if your parts vector agrees with x vector, if you want.
Regards
Petr
Anyone got a neat way to chop a vector up into
Hi
Something like
aggregate(DF$data, list(quarters(DF$date), format(DF$date, %Y)), mean)
Regards
Petr
Hello everybody,
I need to calculate seasonal means with temperature data for my work.
I have 70 files coming from weather stations, which looks like this for
example:
startdate -
Hi
did you find function dist? It seems that it can do directly what you
want.
Regards
Petr
Hello everyone. Like others on this list, I'm new to R, and really not
much
of a programmer, so please excuse any obtuse questions! I'm trying to
repeat a function across all possible
Hi
Hello,
It is not what happens.
Function convexhull exists in both siar and spatstat packages. As
you already load spatstat, when you are loading siar, the
convexhull in spatstat is masked by the one in siar.
Thus, when you will run convexhull function, it will be the one from
Hi
I do not have direct answer. You shall probably search ggplot2 web.
Searching legend gave me about sixty results from which you probably
could learn how to modify legend(s) according to your wish.
e.g.
http://had.co.nz/ggplot2/docs/opts.html
Regards
Petr
Dear all,
I produced the
Hi
Well, this is help list for R not for Excel, maybe you shall contact
Microsoft guys. I believe that probably easiest would be to make a simple
macro in Excel.
If you want to do merging in R you shall go through help pages for
read.xls, merge, cbind, rbind and R data import/export manual.
Hi
Dear list members,
I am trying to create a subset of a data frame based on conditions in
two
columns, and after spending much time trying (and search R-help) have
not
had any luck. Essentially, I have a data frame that is something like
this:
date-as.POSIXct(as.character(c
Hi
Hi all,
I would like create a new column in a data.frame (a1) to store 0, 1 data
converted from a factor as below.
a1$h2-NULL
for (i in 1:dim(a1)[1]) {
if (a1$h1[i]==H) a1$h2[i]-1 else a1$h2[i]-0
}
My question: is it possible to remove the loop from above code to
Hi again!
I have a question about R.
I have done gam in previous version of R with mgcv package and saved
the
workspace. This workspace contains different models and I will do
prediction
by these GAMs.
However, I install new version of R. and use the same workspace. when I
type
Hi
In new ggplot2 version following works too
p + geom_boxplot(aes(fill = factor(cyl))) +
labs(fill = Cylinders) + ylab(Miles per Gallon)+xlab(Number of
Cylinders)
Regards
Petr
Yes you can do all of the things you want.
Below is a start, to give you an idea of how to approach
Hi
I am not at all an expert in regular expressions but
gsub(^[[:punct:]]+[[:digit:]]+:, ,m)
does the output you want. Maybe by chance :-)
Regards
Petr
Hello,
I would like to substitute a substring of characters defined by a
specific
start and end sequence.
i.e. in the example matrix
Hi
It seems to me that it can be done by ggplot2 package. However I do not
understand what is three boxplots one on top of another? How could you see
the bottom boxplot when it is twice overplotted?
library(ggplot2)
p - ggplot(mtcars, aes(factor(cyl), mpg))
p + geom_boxplot(aes(fill =
Hi
Dear Sir,
We are able to read dataset in the syn.data (species:yeast) using R.But
we
want to read a new dataset using R.
We are not able to do that please tell us the procedure of reading a new
dataset of a new species.
Did you try it by similar way as you read the first dataset?
Hi
hi,R-users:
Now I plot some data with the name(aveobsdata) in column , How can I add
the
some number(e,g. the sample number) in each of the column?
plot
(aveobsdata,type='h',lwd=line_width,col=line_col,main=titleinfo,xlab=xxlab,ylab=yylab,xaxt
= n)
We do not have aveobsdata hence we
Hi
Thanks for your reply Jon.
I need to actually do more than print the name of the variable (I just
made
the example simpler). I need to manipulate var_1, var_2 etc. but setting
values of NA to 0.
Why? R has pretty strong system for handling NAs. The only exception AFAIK
is cumsum
Hi
I use R for quite a long time and as I remember I did not use such assign
paste i loop yet. Insted of such construct with polluting environment with
plenty of objects named something(i)somethingelse it is always advisable
to use lists.
When you want to shorten variables to some common
Hi
How could I select the rows of a dataset that have the maximum value in
one variable and to do this nested in another variable. It is a
dataframe
in long format with repeated measures per subject.
I was not successful using aggregate, because one of the columns has
You could do it
Hi
I have the graph plotted with x axis(-50 to 250) and y axis (-50 to
500).I
need the x axis values(-50 to 250) with spacing between two tick marks
as
1or 0.1.The graph should be wider to get enough resolution.
For the first case you shall have some special display as you will need at
I do now know how to navigate through the table.
But my question is, what kind of graphical and numerical summaries can I
make with keeping in mind that I am interested in the average working
hour
per employee?
Rather vague question without data or code, so rather vague answer.
For
PortuguĂŞs / Department
of
Portuguese Faculdade de CiĂŞncias Sociais e Humanas / Faculty of Social
Science and Humanities - UM
澳门大ĺ¦ç¤ľäĽšç§‘ĺ¦ĺŹŠäşşć–‡ĺ¦é™˘č‘ˇčŻçł»
http://www.umac.mo/fsh/ciela/staff/Marcia_Schmaltz.html (+853) 6231-2114
and 8397-8902 -Petr Pikal-3 [via R] lt;ML
Hi
both na.omit and complete cases works for me smoothly when NA is not a
valid level in factor.
If this is the case, as it seems to be, you need reset your factor levels
so that NA is not a valid level.
ex10s$dg - factor( ex10s$dg )
both commands shall work than.
Regards
Petr
Removing
Hi
Dear all
I have a 'character' vector containing mixed formats (thanks Excel!)
and I'd like to translate it into a default %Y-%m-%d Date vector.
x - c(1/3/2005, 13/04/2004, 2/5/2005, 2/5/2005, 7/5/2007,
22/04/2004, 21/04/2005, 20080430, 13/05/2003, 20080529,
NA, NA,
Hi
I can read the example you provided without much problem.
dput(head(test))
structure(list(n = 0:5, X = c(NA, NA, NA, NA, NA, NA), start = c(11185L,
39530L, 40544L, 109684L, 114629L, 118841L), X.1 = c(NA, NA, NA,
NA, NA, NA), dur = c(1L, 2L, 1L, 1L, 0L, 1L), X.2 = c(NA, NA,
NA, NA, NA, NA),
Hi
Hello,
I am trying to fit a model to some death over time data that does not
fit the criteria for the usual LD50 type models (the counts are too
large). I am using a simple linear model in an attempt to plot a nice
line
on a scatter plot and calculate some LD values to use in
Hi
Hi,
Yes, the columns are related: V1 is related to V6, V2 is related to V7
and
so on. The columns V1,V2,V3,V4,V5 contains the number of employees (in a
filling team). The columns V6,V7,V8,V9,V10 contains the number of worked
hours of the filling team.
You shall rather include your
Hi
I have a table like the following:
TABLE NO. 1
ID TIME
1325 0
1325 0
. .
. .
. .
TABLE NO. 1
ID TIME
1325 0
1325 0
. .
. .
. .
TABLE NO. 1
ID TIME
1325 0
1325 0
. .
. .
. .
TABLE NO. 1
ID TIME
1325 0
1325 0
. .
I'm not sure what you are trying to prove with that example - the
loopless
versions are massively faster, no?
In some languages loops are integral part of programming habits. In R you
can many things do with whole objects without looping - vectorisation
approach. See R-Inferno from Patrick
Hi
What is your intention?
basically one output column can be made by
cumsum(bd)
Then you can shuffle bd by let say
bd - sample(bd, 64)
and repeat cumsum for new bd.
bd-scan(blap.txt)
output-matrix(0,64,10)
for (i in 1:10) {
bd-sample(bd, 64)
cs-cumsum(bd)
output[,i]-cs
}
If you insist
Hi
Dear All,
The function I wrote can run well with the small data, but with the
large
data, the function runs very very slowly. How can I correct it? Thank
you
Your function does not run slowly, it does not run at all.
l(10,20)
Error in l(10, 20) : object 's' not found
No s object
Hi
For loops are really, really slow in R. In general, you want to avoid
them
I strongly disagree. ***Proper*** use of looping is quite convenient and
reasonably fast.
Consider
system.time( {
+ a=0
+ for (i in 1:1000) {
+ a -a+i
+ }
+ a
+ })
user system elapsed
10.220.02
And as followup
system.time(d-1000*1001/2)
user system elapsed
0.020.000.02
identical(a,b,d)
[1] TRUE
Regards
Petr
Hi
For loops are really, really slow in R. In general, you want to avoid
them
I strongly disagree. ***Proper*** use of looping is quite
Hi
On May 22, 2012, at 4:08 AM, HAOLONG HOU wrote:
Dear list,
The name of R-language is too short and is not friendly to search
engines.
Did you try it? Even with plain Google
something R will usually lead to quite good hit. Try e.g.
linear model R
Regards
Petr
Do you think
Hi
You did not provide data but I can see some problems in your code. See
inline.
I'm failing to get a for loop working. I'm sure it's something simple,
and I
have found some posts relating to it, but I'm just not understanding why
this isn't working.
I have a data frame and would
Hi
I have a dataset called raw-data . I am trying to use the following
code -
col_name-names(raw_data)
for (i in 1:(length(names(raw_data))-2))
{
tbl=table(raw_data$Pay.Late.Dummy, raw_data$col_name[i])
chisqtest-chisq.test(tbl)
}
Say the 1st column of my raw_data is
Hi
You can do it by hand and remove row/col with max number of NA values.
rem-which.max(colSums(is.na(M)))
M1-M[-rem, -rem]
rem-which.max(colSums(is.na(M1)))
M2-M1[-rem, -rem]
M2
1 2 3 4 5 7 8 10 11 12
10 143 92 134 42 123 40 107 49 93
2 143 0 77 6 99 46 47 114
Something along the lines of
dat2 - ifelse( dat1==1 , yes, no)
Another option is in this case
dat2 - c(no, yes)[dat1+1]
Regards
Petr
should do it.
John Kane
Kingston ON Canada
-Original Message-
From: s1010...@student.hsleiden.nl
Sent: Mon, 14 May 2012
Hi
On 2012-05-15 08:36, Melissa Rosenkranz wrote:
Here is an R problem I am struggling with:
My dataset is organized like this...
subject sessionvariable_x variable_y
01 11interger values
01 1
x[is.na(z)] - NA
This might send you a nasty bug if x and z are different lengths
though -- just a head's up.
Another option
x*!is.na(z)*z
Regards
Petr
Michael
On Wed, May 16, 2012 at 12:55 PM, Mintewab Bezabih
mintewab.beza...@economics.gu.se wrote:
Dear R users,
I was
Hi
I want to use the standard error values in the summary that is produced
using
coeftest, but I am getting an error code- any ideas?
See what is structure of coeftest object by
str(coeftest(lmodT_WBHO))
and from this you shall deduct how to select second column.
Regards
Petr
Hi
I had not see any answer yet but maybe there is nobody who wants to touch
the elusive object of outlier. Neither me, but here are some ideas how
one can proceed.
First of all its always up to you what is considered an outlier and how
will you deal with them.
I usually call an outlier any
Hi
how do I plot only the data below 10? everything is white for the 0-10
and
10-90 is black ..
What data below 10? I do not see any. You posted some mails before but I
do not keep all mails from R. Only those which helped me somehow.
Basically
x - sample(1:100, 100, raplace=TRUE)
x[x10]
Hi
score-read.csv(http://users.stat.umn.edu/~chen2285/hw/ACT.csv;)
score-read.csv(http://users.stat.umn.edu/~chen2285/hw/ACT.csv;)
Error in file(file, rt) : cannot open the connection
In addition: Warning message:
In file(file, rt) : unable to connect to 'users.stat.umn.edu' on port
80.
Hi
as already mentioned your data can not be deciphered. Use
dput(table1) for sending usable data.
From what you describe probably
?aggregate can be used.
But without suitable data you hardly get any advice.
Regards
Petr
Hi R user,I am struggling to figure out on how I can calculate the
Hi
what is wrong with
heatmap(as.matrix(test), col=my.colors(25))
with test from your dput
Regards
Petr
The heat map generated the correct result:
library(gplots)
arq -read.table(l)
matrix_l -data.matrix(arq)
my.colors -
colorRampPalette(c
Hi
I might be silly but if I was going to type in dput() then how should I
send the data over here?
dput(zdrz20)
outputs tou your console
structure(list(sklon = c(95, 95, 40, 40, 40, 40, 20, 20, 20,
20, 20, 20, 20), ot = c(15, 4, 10, 15, 4, 1.5, 1.5, 4, 10, 15,
4, 10, 15), doba =
Hi
arq -read.table(file)
arq_matrix -data.matrix(arq)
Are you sure that arg_matrix is numeric? Did you check it somehow?
dput(arq)
You forgot to include dput(arg) result. Without that only you know what
arg is.
arq_heatmap - heatmap(arq_matrix, Rowv = NA, Colv = NA,col =
Hi
Or you can use base function
write.table(varxls, file=some output file.xls, sep = \t, row.names =
F)
Regards
Petr
As it says, you need to supply a file name to be outputted to.
write.xls(, file = abc.xls)
Michael
On Fri, May 4, 2012 at 11:31 AM, PaulJr
Hi, Dear all,
Could you please tell me how to select specified column in dataset and
how
to do
my.data[, x]
my.data[, aa]
my.data$aa
the concentration-time profiles in R?
What is that?
Besides you could help youself a lot reading an intro to R which I believe
is in doc directory of
---
Sent from my phone. Please excuse my brevity.
Petr PIKAL petr.pi...@precheza.cz wrote:
Hi
Or you can use base function
write.table(varxls, file=some output file.xls, sep = \t, row.names
=
F)
Regards
Petr
As it says, you need to supply a file name
Hi
I wold vote aggregate
aggregate(my.df[,-1], list(pathway=my.df$pathway), mean, na.rm=T)
pathway cond.one cond.two cond.three
1pw.A 0.5 0.6NaN
2pw.B 0.4 0.90.1
3pw.C NaN 0.2NaN
Regards
Petr
Esteemed UseRs,
This
Hi
One option for substantial distinguishable range of colours is jet.colors
from matlab package.
Regards
Petr
Hi,
Thanks for the help. Extending the palette to 16 or 20 would be a big
help. The largest number of files I've had to handle in a single group
is
42 and I wouldn't expect
Hi
I would convert it to propper date format and then you can extract
anything.
dat-strptime(12/31/11 23:45, format=%m/%d/%y %H:%M)
as.Date(dat)
[1] 2011-12-31
format(dat, %H:%M)
[1] 23:45
Regards
Petr
Hello there, I was wondering if you could help me with a quick R issue.
I have a
Hi
you maybe can use mapply
If you have 2 lists
xl-list(x, x+5)
xl
[[1]]
[1] 1 2 3 4 5
[[2]]
[1] 6 7 8 9 10
yl-list(9,10)
yl
[[1]]
[1] 9
[[2]]
[1] 10
and this function
fff- function(xl,yl) (xl-yl)/yl
mapply(fff, xl, yl)
[,1] [,2]
[1,] -0.889 -0.4
[2,] -0.778
Hi!
I'm trying to do a lm() test on three objects. My problem is that R
protests
and says that the variable lengths differ for one of the objects
(Sweden.GDP.gap). But I have double checked that the number of
observations
You shall check it again. BTW How did you checked it?
are the
Hi
Dear R-community,
I am using R (V 2.14.1) on Windows 7. I have a dataset which consists of
19
variables for 91 individuals or rows. Two of my variables are Age
(adult/chick, with no NA values) and Sex (0 for females/1 for females,
with
quite a few NA values). The sex of many adult
Hi
Isn't possible just to change values in etc/Rconsole file?
## Colours for console and pager(s)
# (see rw/etc/rgb.txt for the known colours).
background = White
normaltext = NavyBlue
usertext = Red
highlight = DarkRed
You can customise it and keep your setting somewhere. With each new
Hi
If you used shorter names for your objects you will get probably more
readable advice
Is this what you wanted?
truncated_dataframe[truncated_dataframe$CLAIM_NO %in%
setdiff(truncated_dataframe$CLAIM_NO, truncated_list$CLAIM_NO),]
Regards
Petr
Hi there,
I've tried the noted solutions:
Hi
what about
rbind(a,a)
[,1] [,2] [,3] [,4]
[1,]1234
[2,]5678
[3,]1234
[4,]5678
Regards
Petr
a - matrix(1:8, 2, 4, byrow=TRUE)
a
[,1] [,2] [,3] [,4]
[1,]1234
[2,]5678
Hi
On Fri, Apr 20, 2012 at 4:42 PM, Jeff Newmiller
jdnew...@dcn.davis.ca.us wrote:
If you read the help, it talks about compiling vectors into matrices,
or
scalars into vectors. It does not say anything about combining matrices.
For the error about 14 elements, you should keep in mind
Hi
Without data it is only a guess.
I found out something strange when I used the same thing on another data
file.
In a excel file I have same data too and there I asked in a certain
column
what values where above the 7.5. Result: 206.
Now I have done the same thing in R and I get as
Hi
Your question is rather cryptic. Why the output shall be 3? What has
unique count to do with match function?
Maybe you want something what is described in switch help.
See
?switch
Regards
Petr
Hi
My code looks like this
I have two parameters x and par1. X contains values and
Hi
Hi there
is it possible that pdfs generated using the pdf() function with default
settings leads to loss of information? I was plotting copy number
changes
from Agilent 180k data in form of rectangles (rect()) while each
rectangle
represents one region of copy number change. When
Hi
Hi,
I m working on bar chart.
*Input file:*
index -5 1
index -4 3
index -3 2
index -2 10
index -1 7
index 0 2
index 1 1
barplot(t(as.matrix(i[3])), ylab= value, main = testdata,
beside=TRUE,
Hi
Hi,
I am working on dataframe and column names are multiwords but when i
read
it it become one word with space relplaced by . How can i keep
normall
spacing reading file.
for e.g.
input file
Data Test Data Out
35
5
Hi
see inline
Hello,
I've got a small dataset on box turtle shell measurements that I would
like to perform a detrended correspondence analysis on. I thought that
it
would be interesting to examine the morphometrics for each species in
the
area of overlap and in areas where neither
Hi
Any help ?
Call 999
Regards
Petr
--
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warnings-tp4550325p4551760.html
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Hi
Hello,
Is it possible to selectively display labels on a histogram?
What labels?
Like that?
x-rnorm(1)
hist(x)
hist(x, axes=F, xlab=bla, ylab=ble, main=bleble)
axis(1, at=c(-4, -1, 1, 4))
Regards
Petr
Thanks
Carol
[[alternative HTML version deleted]]
for instance this
h.lab - h$counts
h.lab[seq(2,16,2)]-NA
hist(x, labels=as.character(h.lab))
prints every second label
Regards
Petr
thanks
From: Petr PIKAL petr.pi...@precheza.cz
To: carol white wht_...@yahoo.com
Cc: r-h...@stat.math.ethz.ch r-h...@stat.math.ethz.ch
Sent: Thursday, April 12
-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
e.g. **how** did you read your file to R.
Regards
Petr
Regards,
Lämarao
- Original Message - From: Petr PIKAL
petr.pi...@precheza.cz
To: Pedro Henrique lama...@superig.com.br
Cc: r
Hi
i have a matrix like
x1 x2 x3
y1 2 34 5656
y2 34 434 342
y3 234 43 34
i want to plot these values like here
http://www.almob.org/content/2/1/12/figure/F5?highres=y
The rainbow function could calculate a colour for each value.
But how van i generate the square
Hi
You'll need to save them manually to avoid name conflicts --
save.image()
is the function to do so but you need to give a file name.
Or it is necessary have separate folder for each R session.
Regards
Petr
Michael
On Apr 10, 2012, at 7:41 AM, ya xinxi...@163.com wrote:
Hi
Hi
I have a bivariate plot of axis2 against axis1 (data below). I would
like
to use different size, type and color for points in the plot for the
point
coming from different region. For some reasons, I cannot get it done.
Below
is my code.
col - rep(c(blue, red, darkgreen), c(16, 16,
Hi
Hello,
I am a new user of R and I am trying to use the data I am reading from a
spreadsheet.
I installed the xlsReadWrite package and I am able to read data from
this
files, but how can I assign the colums into values?
E.g:
as I read a spreadsheet like this one:
Maybe with
Hi
Your post is rather screwed.
[R] how to do piecewise linear regression in R?
Maybe segmented?
Regards
Petr
Dear all,
I want to do piecewise CAPM linear regression in R:
RRiskArbâ’Rf = (1â’δ)[αMktLow+βMktLow(RMktâ’Rf)] + δ[αMkt
High
+βMkt High(RMkt â’Rf )]
where
Thanks,
anyway, using build-in R features is preferable for colours
with(data, plot(axis1, axis2, col= c(red, blue,
green)[as.numeric(data$Region)]))
legend(topright, legend=levels(data$Region), fill= c(red, blue,
green))
although sometimes can be preferable to get advantage of grid graphic
Hi
Hi R-listers,
1) I am having trouble understanding why the means I have calculated
from
Aeventexhumed (A, B, and C) are different from the means showing on the
boxplot I generated (see attached). I have added the script as to how
my
data is organized.
Maybe the difference is that
Hi
It seems to me that probably split.screen or layout is preferable if you
want specify graph for identification. But I am not an expert in this and
after some testing identification does not work well with splitted screen.
So you are probably out of luck.
Regards
Petr
Please forgive my
Michael,
First of all, thank you very much for your answer.
I've read your 2 answers, but I'm not really sure that they corresponds
to
my problem of NAs.
You shall read answers more carefully
x-rnorm(20)
x[3:4]-NA
x[12:19]-NA
x
[1] -0.30754528 0.07597988 NA NA
Hi
Can you please be more specific? Based on this input, what do you want as
a result?
set.seed(111)
dates = as.Date(sort(rnorm(10,3000,100)), origin = 2000-1-1)
dates
[1] 2007-08-01 2007-10-21 2007-12-08 2007-12-15 2008-01-29
2008-02-14 2008-02-16 2008-03-01
[9] 2008-04-02 2008-04-11
to evaluate
how many consecutive dates are within one year.
Best,
Felix
-Ursprüngliche Nachricht-
Von: Petr PIKAL [mailto:petr.pi...@precheza.cz]
Gesendet: Mittwoch, 4. April 2012 09:47
An: Fischer, Felix
Cc: r-help@r-project.org
Betreff: Odp: [R] identify time span in date
Hi
There is some mismatch in curly braces in your plotter function but when I
try to use it I get
plotter(10,3,fram=rwb,framvec=rwb$prcnt.char.depth,obj=prcnt.char.depth,form1=
+ post.f.crwn.length~shigo.av,form2=post.f.crwn.length~shigo.av-1,
+
Hi
First of all you shall change your dataset structure to list. It will help
you in future.
HI,
Need help in calling the dynamic variables
I have 2 datasets . FIrst one(mdata) is having the metadata and second
one(dataset) has got the data.
sample
*mdata *
Variable (header)
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