Hi
d<-data.frame(matrix(c("ww","ww","xx","yy","ww","yy","xx","yy","NA"),
ncol=3, byrow=TRUE))
Change character value "NA" to missing value
d[d[,3]=="NA",3]<-NA
If you want drop any unused levels of a factor just use
factor(d[,3])
[1] xx yy
Levels: xx yy
Regards
Petr
r-help-boun...@r-
Hi
r-help-boun...@r-project.org napsal dne 22.04.2011 09:19:19:
> Hello R,
>
> I would like to plot continuos function (e.g. y=x^2) without creating a
> sequence for x.
> Is there a possibility to somehow specify the range - x belongs to
> <-100,100>?
Something like
curve(x^2, -100,100)
Mayb
riate values for Windows ‘Unicode’ text files.
If the first two bytes are the Byte Order Mark ‘0xFFFE’ then these
are removed as some implementations of ‘iconv’ do not accept BOMs.
˙ţ1 looks in hex editor like that 0xFFFE so the problem is solved for now.
Thanks again
Petr
>
> --
Dear all
I have several files which claim to be *.csv (one attached, maybe it
will come through) . They can be read to Open Office without much
problem, however I can not read them into R. I tried
read.table("H2O.CSV", sep=",", dec=".")
V1
1 ˙ţ1
2
3
> read.table("H2O.CSV", sep=",", dec=".", s
Hi
Michael Bach napsal dne 19.04.2011 14:21:13:
> Petr PIKAL writes:
>
> > Hi
> >
> > r-help-boun...@r-project.org napsal dne 19.04.2011 09:46:47:
> >
> >> Dear R Users,
> >>
> >> Lets assume I have this data frame:
> >>
&
Hi
r-help-boun...@r-project.org napsal dne 19.04.2011 09:46:47:
> Dear R Users,
>
> Lets assume I have this data frame:
>
> x y z
> 1 1.00 5 0.5
> 2 1.02 5 0.7
> 3 1.04 7 0.1
> 4 1.06 9 0.4
>
> x and y columns are sorted and the values not necessarily integers. z
> values are not sorte
Hi
r-help-boun...@r-project.org napsal dne 19.04.2011 12:02:31:
> On 04/19/2011 07:39 PM, Simone Gabbriellini wrote:
> > Hello List,
> >
> > I have a data frame like:
> >
> >V130 V131 V132 V133 V134 V135 V136
> > 1 0 0 0.9 0 0.9 0 0
> > 2 0
Hi
Hi
try
colSums(is.na(data.m))
It is not in data frame but you can easily transform it if you want.
Regards
Petr
r-help-boun...@r-project.org napsal dne 19.04.2011 09:29:08:
> Dear all
>
>
>
> I have written a function to perform a very simple but useful task which
I
> do regularly. It
Hi
r-help-boun...@r-project.org napsal dne 18.04.2011 14:32:11:
> Hai,
>
> Where can i get the dataset votes.repub
> Ram
Use your favourite browser, put R votes.repub in its search facilities and
you shall be lucky enough to get it from first several hits.
If you have installed R you can star
Hi
r-help-boun...@r-project.org napsal dne 15.04.2011 16:20:23:
> Hi,
>
> I am a complete newcomer to R and although I can plot standard box-plots
I am
> struggling with this...
>
> I have two treatments - A & B, and 2 variables 1 & 2. I want to compare
> boxplots of variable 1 with variable
Hi
r-help-boun...@r-project.org napsal dne 18.04.2011 04:51:20:
> Or perhaps even more parsimoniously (by a couple of characters) -
>
> r <- c(1, 2, 3, 4, 5)
> r2<-r[-length(r)]
Maybe even shorter
head(x,-1)
Regards
Petr
>
> Min-Han
>
> On Sun, Apr 17, 2011 at 10:23 PM, Daisy Englert Duur
Hi
r-help-boun...@r-project.org napsal dne 15.04.2011 01:34:22:
> Hi everyone.
>
> I am quite frustrated that this doesn't work, as all the functions
within
> work fine by themselves. I'd also like any pointers to how to avoid
'for'
> loops in my code. I understand it's less than desirable, bu
Hi
r-help-boun...@r-project.org napsal dne 11.04.2011 09:43:03:
> Hi all,
>
> I have two matrices:
>
> G<-matrix(c(2.0, 0.5, 0.5, 0.5, 2.0, 0.5, 0.5, 0.5,2.0),3,3)
> P<-matrix(c(1.0, 0.5, 0.5, 0.5, 1.0, 0.5, 0.5, 0.5,1.0),3,3)
>
> and I want to run this equation to get a new matrix F:
>
> F =
Hi
r-help-boun...@r-project.org napsal dne 09.04.2011 19:24:38:
> I am in need of someone's help in correlating gene expression. I'm
somewhat
> new to R, and can't seem to find anyone local to help me with what I
think
> is a simple problem.
>
> I need to obtain pearson and spearman correlati
Hi
r-help-boun...@r-project.org napsal dne 08.04.2011 18:24:37:
> On 08/04/2011 9:20 AM, DEBERGH Patrick wrote:
> > hello
> >
> > I am at the very beginneing of using the R program
> >
> > I just don't understand how one can save a programfile
> >
> > For exemple, if I type in R 23+456 and want
Hi
r-help-boun...@r-project.org napsal dne 08.04.2011 09:31:44:
> Dear all,
> i have a dataset of about 400 records , with a variable that has two
levels
> 40 bad and 360 good among other variables,how do i come up with10
random
> samples that have the composition of as the main sample but
Hi
r-help-boun...@r-project.org napsal dne 06.04.2011 22:02:29:
> I have cobbled together the following logic. It works but is very
> slow. I'm sure that there must be a better r-specific way to implement
> this kind of thing, but have been unable to find/understand one. Any
> help would
Hi
r-help-boun...@r-project.org napsal dne 06.04.2011 10:48:04:
> Dear list,
>
> I have a dataframe with two column as fellow.
>
> > head(dat)
>V1 V2
> 0.15624 0.94567
> 0.26039 0.66442
> 0.16629 0.97822
> 0.23474 0.72079
> 0.11037 0.83760
> 0.14969 0.91312
>
> I want to ge
Hi
r-help-boun...@r-project.org napsal dne 06.04.2011 17:33:48:
> This is hopefully a quick question on decimal accuracy. Is any
> decimal accuracy lost when casting a numeric vector as a matrix? And
> then again casting the result back to a numeric?
>
> I'm finding that my calculation values
102
[2,]3 113
[3,]4 124
> mat[-(1:2),-(3:4)]
[,1] [,2]
[1,] 3 7
[2,]48
Which result is "correct" from your point of wiev?
Regards
Petr
>
>
> > From: Petr PIKAL
> > Subject: Odp: [R] Loop to mapply. Error
> > To: &
Hi
Well, no data so a wild guess. You want select values from matrix sr based
on values in borders[,1] and borders[,2].
If it is the case plain selection could be far better
> mat<-matrix(1:12, 4,4)
> mat
[,1] [,2] [,3] [,4]
[1,]1591
[2,]26 102
[3,]37
Hi
r-help-boun...@r-project.org napsal dne 03.02.2011 10:36:57:
>
> Hi,
>
> Peter: thank you, I have taken a look at ?approxfun but I'm not sure it
does
> what I'm after.
Hm, maybe yes. But not approxfun but approx
x1<-1:15
x2<-50:100
y1<-rnorm(15)
y2<-rnorm(51)
yy2<-approx(x2,y2)$y
yy1<-app
Hi
r-help-boun...@r-project.org napsal dne 03.02.2011 00:56:40:
>
> Thanks for the reply!
>
> This sounds great. Is there a nice way to store these 100 variable names
in
> a list without typing them all out?
Why? When you need your 42nd variable from a list lll you can just use
lll[42]
and
Hi
r-help-boun...@r-project.org napsal dne 02.02.2011 16:05:21:
>
> On Feb 2, 2011, at 9:12 AM, ADias wrote:
>
> >
> > Hi
> >
> > I have this function and this matrix:
> >
> > function(x,y) x+y/x
> >
> > m<-matrix(c(1,2,4,2,10,8),3,2)
> >
> >> m
> > [,1] [,2]
> > [1,]12
> > [2,]
Hi
r-help-boun...@r-project.org napsal dne 01.02.2011 10:20:48:
> Good morning,
>
> I have an excel spreadsheet with similarities among objects. The format
of
> the file is the following:
>
> 1st row: ,,,...,
> 2nd row: ,0,s<1,2>,s<1,3>,...,s<1,N>
> 3rd row: ,s<2,1>,0,s<2,3>,...,s<2,N>
>
> Th
Hi
r-help-boun...@r-project.org napsal dne 02.02.2011 11:14:18:
> Hi
>
> r-help-boun...@r-project.org napsal dne 31.01.2011 15:51:16:
>
> >
> >
>
>
>
>
> > >
> > >
> >
> > Hi
> >
> > thanks. I am not sure if I have understood 100% but at least I know
now
> that
> > there's a diferen
Hi
r-help-boun...@r-project.org napsal dne 01.02.2011 07:02:50:
> Hi AD,
>
> You might try the following:
>
> # data
> a <- c(2,3,5)
> b <- c(8,7) # you got this wrong ;)
>
> # option 1
> foo <- function(x) as.numeric(paste(x, sep = "", collapse = ""))
>
> # examples
> foo(a)
> # [1] 235
>
Hi
r-help-boun...@r-project.org napsal dne 31.01.2011 15:51:16:
>
>
> >
> >
>
> Hi
>
> thanks. I am not sure if I have understood 100% but at least I know now
that
> there's a diference.
>
> About this:
>
> lapsales
> Store Prod qtd
> 5 Aveiro Lapiseira 3
> 8 Coimbra
Hi
r-help-boun...@r-project.org napsal dne 31.01.2011 09:44:00:
>
>
> David Winsemius wrote:
> >
> >
> > On Jan 30, 2011, at 5:27 PM, ADias wrote:
> >
> >> dados<-
> >> data
> >> .frame
> >> (Store
> >> =
> >> c
> >> ("Setubal
> >> ","lx
> >> ","Aveiro
> >> ","Coimbra
> >> ","Aveir
Regards
Petr
>
> This I m using to draw a graph.
>
> Regards,
> Kumaraguru
>
>
> On Jan 28, 2011, at 6:47 AM, Petr PIKAL wrote:
>
> > Hi
> >
> > r-help-boun...@r-project.org napsal dne 28.01.2011 09:52:05:
> >
> >>
> >&
Hi
r-help-boun...@r-project.org napsal dne 28.01.2011 15:37:07:
> Hello,
> I have a data set with each column containing data like this:
> row column1
> 1 1.2
> 2 NA
> 3 NA
> 4 3
> 5 5
> 6 NA
> 7 1.5
> 8 NA
> 9 NA
> 10 NA
> 11 3
> 12 NA
> 13 3
> 14 NA
> 15 NA
> 16 NA
> 17 NA
>
Hi
r-help-boun...@r-project.org napsal dne 28.01.2011 09:52:05:
>
> What makes matrix to print V1, V2 as the row and col indices instead of
> numbers??
>
> cdata = read.table("ramesh.txt") #cdata is read from a file.
> c1 = cor(cdata)
>
> I am printing c1 below. I need only numbers. I dont ne
Hi
r-help-boun...@r-project.org napsal dne 25.01.2011 10:58:36:
> ooh.. I have another question.
> What if I want to add the value in the vector a to the hello each time
it
> prints.
> Here is your output
>
> a <- c(2,3,5,5,5,6,6,7)
> mapply(rep, "hello", rle(a)$lengths, USE.NAMES = FALSE)
>
>
use
> stat_summary(), for example, because it is a bit easier to plot
individual
> layers that way.
>
> HTH,
> Dennis
>
> On Mon, Jan 24, 2011 at 11:05 PM, Petr PIKAL
wrote:
>
> > Dear all
> >
> > I would like to superpose some smoothing line through
Hi
r-help-boun...@r-project.org napsal dne 25.01.2011 08:07:10:
>
> hi i have the following dataframe
>
> x y
> 1 345
> 6 NA
> 8 123
> 32 123
> 12 NA
> 6 124
> 7 NA
>
> and i want to extract the data rows which contains "NA" data, I tried
>
> subset(dataframe,y=="NA")
See
Hi
r-help-boun...@r-project.org napsal dne 24.01.2011 23:18:35:
> Thanks for the reply Erik, As you mentioned, grouping consecutive
elements
> of 'a' was my idea.
> I am unaware of any R'ish way to do it. It would be nice if someone in
the
> community knows this.
>
> The error resulting in th
Dear all
I would like to superpose some smoothing line through boxplot in ggplot
> dput(ad)
structure(list(konc.f = structure(c(1L, 1L, 1L, 1L, 2L, 2L, 2L,
2L, 3L, 3L, 3L, 3L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 6L, 6L, 6L,
7L, 7L, 7L, 7L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 3L, 3L, 3L, 3L,
4L, 4L, 4L
Hi
r-help-boun...@r-project.org napsal dne 19.01.2011 09:51:43:
>
> Hello everyone,
>
> I have a data set like this:
>
> > head( fish_transect)
> ID_TRANSECT ID_PROJECT DE_ZONE DE_LOCALITY DE_SECTOR MES
> 1 42 MB TarragonaCreixell Control I 9
> 2 42
Hi
r-help-boun...@r-project.org napsal dne 19.01.2011 00:03:10:
>
> On Jan 18, 2011, at 5:25 PM, kurt_h...@nps.gov wrote:
>
> > Greetings
> > I have a bunch of NAs in a column of categorical variables
> > designating
> > the size classes (e.g., smallest to largest: 1,2,3,4) of cave
> > cr
Hi
r-help-boun...@r-project.org napsal dne 17.01.2011 15:59:37:
> days=Sys.Date()-1:70
> price=abs(rnorm(70))
> regular=rep(c(0,0,0,0,1,0,1,0,0,1),c(7,7,7,7,7,7,7,7,7,7))
> y=data.frame(cbind(days,price,regular))
>
>
> y is like
> days price regular
> 1 14990 0.16149463 0
> 2 1
Hi
r-help-boun...@r-project.org napsal dne 18.01.2011 13:51:05:
>
> Hi,
>
> I have this character vector:
>
> A<-c("Tell me how many different letter this vector has?")
>
> Is there a way with R that it can let me know how many different letters
I
> have on this vector?
A<-c("Tell me how ma
Hi
It is rather unclear how do you want sample your data. It seems to me that
you can sample row numbers and choose sampled rows from data frame.
I probably direct output to a list ("mylist") and use
result <- lapply("mylist", GFD)
Regards
Petr
r-help-boun...@r-project.org napsal dne 17.01
Hi
r-help-boun...@r-project.org napsal dne 12.01.2011 16:16:16:
> I have a dataframe with columns "ID",'date","estimate","actual" (but
> not necessarily in that order - I do a merge somewhere and that
> somehow messes up the order of the columns).
If you have datafreme with column order a, b, c,
Hi
r-help-boun...@r-project.org napsal dne 10.01.2011 15:12:33:
> Dear all,
>
> It has been ages since I studied integration in college. Right now I
> try to recover all this kind of knowledge and then try to understand how
> integration works.
>
>
>
> Thus I am doing some first 'experim
Hi
What is wrong with my suggestion then.
> rate1
USDGBP EURO CHFAUD
1 112.05 171.52 42.71 41.50 109.55
2 112.90 168.27 42.68 41.47 102.52
3 110.85 169.03 41.86 42.84 114.91
4 109.63 169.64 44.71 43.44 122.48
5 108.08 169.29 44.14 43.69 122.12
6 111.23 169.47 44.58 42.30 12
Hi
Your code is quite complicated and I get an error
spot_returns_table <- lapply(1:nrow(trans), function(z) with(trans[z, ],
spot_trans(currency_trans=trans$currency_transacted)))
Error in if (currency_trans == "USD") { : argument is of length zero
It seems to me that you do not know what is y
Hi
r-help-boun...@r-project.org napsal dne 05.01.2011 01:26:42:
>
> Hi
>
> Suppose you have the code below. The result I get from the cat function
is
> from the avgs object. Now, I have 30 diferent objects like this and I
wish
I would stick to list and do not make 30 objects
a.g. avg.width f
il(df, n = 10) // example data//
>
> YearCountry Commodity Attribute Unit
> Value
> 1991United Kingdom Wheat, DurumTotal Supply(1000 MT) 70
> 1991United Kingdom Wheat, DurumTY Exports (1000 MT) 0
> 1991United Kingdom Wheat,
Hi
r-help-boun...@r-project.org napsal dne 05.01.2011 09:20:35:
> I'm trying use the function bwplot, but I receive a message that the
> function is not found. I charged the lattice, sm, and Hmrsc, package but
Can you please explain how one can **charge** packages? I never did it.
Besides did y
atter how exactly you will describe your data
if you fail to show any code you used and how this code failed in
delivering desired result you will get only vague responses.
Regards
Petr
>
> Regards,
>
> SNVK
>
> -Original Message-
> From: Petr PIKAL [mailto:petr.pi
Hi
r-help-boun...@r-project.org napsal dne 04.01.2011 10:35:23:
> Hi,
>
> Just installed R on a new Windows 7 machine (as admin).
>
>
> I feel quite uncomfortable knowing that the default WD when starting R
is:
>
> > getwd()
> [1] "C:/Windows/system32"
Something was set incorrectly. I belie
Hi
r-help-boun...@r-project.org napsal dne 04.01.2011 05:21:25:
> Hi All
>
> I have these questions and request members expert view on this.
>
> a) I have a dataframe (df) with five factors (identity variables) and
value
> (measured value). The id variables are Year, Country, Commodity,
Attr
Hi
r-help-boun...@r-project.org napsal dne 23.12.2010 05:13:37:
> Dear friends, hope I could be able to explain my problem through
following
> example. Please consider this:
>
>
>
> > set.seed(1)
>
> > input <- rnorm(10)
>
> > input
>
> [1] -0.6264538 0.1836433 -0.8356286 1.5952808 0.32
Hi
r-help-boun...@r-project.org napsal dne 21.12.2010 09:59:31:
> Dear all,
>
> Dear all,
>
> I am a relatively new user.
> I have an ascii file with 550 rows and 400 columns. The file contain
values
> ranging from 1 to 2000 and some values with -.
>
> I want to generate a new file where
Hi
r-help-boun...@r-project.org napsal dne 21.12.2010 11:02:07:
> Hello,
>
> I am trying to analyze sociological survey data using R. It is often
> important in survey to calculate both the actual factor sums and
> percentages (easily done with describe() ), but also the numbers and
> total perc
Hi
r-help-boun...@r-project.org napsal dne 20.12.2010 11:48:51:
> Hi,
> I have the following problem:
>
> I have a data.frame with 36 sample sites (colums) for which I have
covariates
> in 3 categories: Area, Month and River. Each Area consists of 3 rivers,
which
> were sampled over 3 month.
Hi
r-help-boun...@r-project.org napsal dne 20.12.2010 07:07:35:
> Hi,
>
> This must be an easy one but so far I haven't find a way out...
>
> I have a data frame such as:
>
> $ v1: Factor w/ 5 levels
> $ v2: Factor w/ 2 levels
> $ v3: Class 'difftime' atomic [1:]
>
> basical
Hi
r-help-boun...@r-project.org napsal dne 17.12.2010 12:41:20:
> Hi,
>
> I want to have a title for the y-axis on the right side of the plot.
> I know how to do it on the left side:
>
> > title(ylab="Title for y-axis")
>
> But how can I have the title on the right side?
See
?mtext
Regards
Hi
use melt from reshape package
> test<-data.frame(a=letters[1:3], v1=1:3, v2=5:7, v3=100:102)
> test
a v1 v2 v3
1 a 1 5 100
2 b 2 6 101
3 c 3 7 102
> melt(test)
Using a as id variables
a variable value
1 a v1 1
2 b v1 2
3 c v1 3
4 a v2 5
5 b
Hi
r-help-boun...@r-project.org napsal dne 15.12.2010 14:22:15:
> I get a list object from an iterative function. I'm trying to figure
> out the most efficient way to calculate the mean of one element, across
> all components of the overall list.
>
> I've tried
>
> output <- mean (listobject
our" "five"
>
>
> >Anyway it is maybe more about personal habits than about bad factor
> >"features"
>
> I agree with you regarding personal habits. It's not the features of
> factors. For me it's the rather inconsistent use in
Hi
r-help-boun...@r-project.org napsal dne 12.12.2010 21:00:37:
> At 12.12.2010 00:48 +0200, Tal Galili wrote:
> >Hello dear R-help mailing list,
> >
> >My question is *not* about how factors are implemented in R (which is,
if I
> >understand correctly, that factors keeps numbers and assign leve
Hi
r-help-boun...@r-project.org napsal dne 10.12.2010 15:00:12:
> Dear Mr Holtman Sir,
>
> Thanks a lot for your great solution. This certainly is helping me
achieve
> what I need to get. However, I shall be hugely thankful to you if you
can
> guide me in one respect.
>
> Sir, you have used
Hi
r-help-boun...@r-project.org napsal dne 09.12.2010 16:25:06:
> Dear useRs,
> I have two sets of data that I would like to plot in the same window,
but their
> ranges are really different, e.g.
>
> a <- c(0.2, 0.5, 0.8, 0.3, 0.4, 0.5, 0.2, 0.2, 0.3)
> b <- c(100, 2000, 800, 200, 100, 50, 4,
d to keep my
problem
> short in oder not to consume your valuable time.
>
> Regards
>
> Vince Pyne
>
>
>
> --- On Thu, 12/9/10, Petr PIKAL wrote:
>
> From: Petr PIKAL
> Subject: Re: [R] Sequence generation in a table
> To: "Vincy Pyne"
> Cc
Hi
r-help-boun...@r-project.org napsal dne 09.12.2010 12:41:47:
> Dear Sir,
>
> Sorry to bother you again. Sir, the R code provided by you gives me
following output.
>
> > yy <- lapply(c(257, 520, 110), seq, to=0, by=-100)
> > yy
> [[1]]
> [1] 257 157 57
>
> [[2]]
> [1] 520 420 320 220 120
Hi
Use par(new=TRUE)
before calling new plot
pie(rep(1,12), col=rainbow(24), radius=0.9)
par(new=TRUE)
pie(rep(1,12), col=topo.colors(24), radius=0.5)
But use piechearts only when you want to deceive your audience.
Regards
Petr
r-help-boun...@r-project.org napsal dne 08.12.2010 09:08:13:
> d
Hi
x<-rnorm(20)
max(x[x<=0])
[1] -0.1028260
x<-c(x,0)
max(x[x<=0])
min(x[x>=0])
AFAIK there is no other number fulfilling both criteria other than zero.
So if you want both criteria to be true (as your "and" suggests), just
check if there is zero.
Regards
Petr
r-help-boun...@r-project.org n
Hi
r-help-boun...@r-project.org napsal dne 06.12.2010 11:02:03:
>
> Hi,
>
> I am trying to calculate correlation coefficient for gene expression
data.
>
> Tab delimited file looks like this
>
> Id v1 v2v3
> df 56 9045
> gh 87 9878
> ty 897867
>
> I used this code
>
Hi
r-help-boun...@r-project.org napsal dne 03.12.2010 16:56:37:
>
> I solved the 1° problem with this command:
>
>
matrix2plot2[,"sensor_data"]<-as.numeric(as.character((matrix2plot2[,"sensor_data"])))
>
> In fact before the previous command I if write:
>
> str(matrix2plot2[,"sensor_data"])
Hi
r-help-boun...@r-project.org napsal dne 05.12.2010 00:19:17:
>
> year1 is the time series data set below
> 11.64
> 11.50
> 11.49
> 11.16
> 11.15
> 11.37
> 11.37
> 11.57
> 11.83
> 11.87
> 11.85
> 11.92
> 11.77
> 11.71
> 11.57
> 11.24
> 11.27
> 11.33
> 11.17
> .
>
> With a tota
Hi
If you had your variables as factors you can change levels of each factor.
levels(some.factor) <- c(0,25,50,27,100)
fac<-factor(sample(LETTERS[1:5],20, replace=TRUE) )
fac
[1] A A D A D A D A C B A A D D D B D E C B
Levels: A B C D E
levels(fac)<-1:5
fac
[1] 1 1 4 1 4 1 4 1 3 2 1 1 4 4 4
Hi
Hm. Does str(poli) revealed said explicitly that poli is data frame? I
presume that it told you that it is list. In that case you need to use
appropriate indexing, which suits structure of your list.
Regards
r-help-boun...@r-project.org napsal dne 02.12.2010 22:06:15:
>
> Simplified versi
Hi
r-help-boun...@r-project.org napsal dne 02.12.2010 17:26:20:
>
> On Dec 2, 2010, at 11:10 AM, David Lyon wrote:
>
> > Thanks David
> >
> > Do you have the url link that details the worked solution to my
> > problem:
> >
> > "that we have an extensive collection of documentation suitable for
Hi
r-help-boun...@r-project.org napsal dne 02.12.2010 16:36:09:
> Hi everyone
>
> I spent hours trying to figure this out but as a newbie I am stuck...
> can someone show me the R code for the following:
>
> If I had a tab delimited file called "file", containing 3 rows :
> 9.56 8.67 9.28
Hi
r-help-boun...@r-project.org napsal dne 30.11.2010 11:52:38:
>
> I explain better
>
> key
> index sensor1.A sensor1.B sensor2.A sensor2.B sensor3.A
> 2010-10-1 7:32:00 8NA 5NA 2
> 2010-10-3 4:33:21NA
Hi
r-help-boun...@r-project.org napsal dne 30.11.2010 10:52:35:
>
> Hi,
>
> I have this MATRIX m:
>
> key
> index sensor1.A sensor1.B sensor2.A sensor2.B sensor3.A
> 2010-10-1 7:32:00 8NA 5NA 2
> 2010-10-3 4:33:21
Hi
I am not an expert in time series but I believe you can check easily
different values for arima parameters based on ACF and PACF. To give you
better help I would need to study some literature and I believe you could
more easily do it yourself.
Best regards
Petr
r-help-boun...@r-project.org
x=[,1],y=[,2]),
What is [,1]? You shall have some data from which you wanted to extract
first and second column.
What about to look into R-intro manual to chapter 2.
Regards
Petr
>
> so how should i embedded the expression within the plot?
>
> regards,
> Pravin
>
> On Mon,
Hi
r-help-boun...@r-project.org napsal dne 29.11.2010 11:48:07:
> Hello,
>
> I am using basic plotting technique to get a graph.
> but i want to color the points plotted onto the graph depending upon few
> mathematical logics.
> values > x should be colored blue.
> values < y should be colored g
Hi
What does your teacher says about the procedures you shall use?
You shall go through help pages for ?spectrum, ?acf, ?ar and maybe some
others.
Regards
Petr
r-help-boun...@r-project.org napsal dne 29.11.2010 11:33:58:
>
> please i've a big problem.
> i've to do a econometric-quantitativ
Hi
r-help-boun...@r-project.org napsal dne 22.11.2010 16:02:20:
> Hi everyone
>
> I have a question about how to save a regression model in R and how to
> retrieve it for making predictions in a new session.
>
> To be more specific, I fitted a multilevel logistic regression model
using the
> l
Hi
r-help-boun...@r-project.org napsal dne 21.11.2010 19:31:33:
>
> I have looked into par documentation, and only setting for size of the
plot
> area was pin. But this setting sets the area as inflexible, that is no
R intro manual
Chapter 12: Graphical procedures page, 71
A typical figure is
Hi
r-help-boun...@r-project.org napsal dne 19.11.2010 16:58:01:
> PtitBleu
>
> Hello Petr,
>
> Your solution works well with my example.
> But with the function I want to use (which calls another functions), I
still
> have errors.
> I have to work on it again (but only on monday).
>
> Again
Hi
r-help-boun...@r-project.org napsal dne 19.11.2010 16:34:04:
Without going too deeply to your code, try to check na.locf function from
zoo package.
I would split your data to list according to study and subject, use
na.locf with respect to your miising value types
> x<-c(NA, 1:5)
> y<-rev(
Hi
r-help-boun...@r-project.org napsal dne 19.11.2010 15:41:08:
>
> Hello,
>
> I would like to replace a for loop with lapply in order to speed up the
> treatment of my data (I've read lapply can help to do it).
Not exactly. For loop if correctly written can be as quick as lapply. See
P.Burns
Hi
r-help-boun...@r-project.org napsal dne 18.11.2010 11:29:28:
> Alaios
> Odeslal: r-help-boun...@r-project.org
>
>
> Hello everyone.
> I have written a small function that returns a 3*n array where n is
typicall
> between 5-55.
> I issued in R
> shweights<-shadowing_weights(x,xr)
> and I
Hi
Here is one way (If I understood what you did ask).
test<-read.table("clipboard", header=T)
> test
SubID CSE1 CSE2 CSE3 CSE4 WSE1 WSE2 WSE3 WSE4
1 165626224
2 264726623
3 355555545
4
Hi
r-help-boun...@r-project.org napsal dne 13.11.2010 16:17:47:
> Re: [R] Do loop
>
> Gud evening sir ,I want do the cluster analysis algorithm in r software
can
> u guide me sir
??cluster gives you bunch of methods
>
> My mail id is :sundars...@gmail.com
>
> And I want the brief explanati
Hi
Use ave instead of tapply. It is designed for such task
Regards
Petr
r-help-boun...@r-project.org napsal dne 12.11.2010 10:49:17:
> albechan
> Odeslal: r-help-boun...@r-project.org
>
> 12.11.2010 10:49
>
> Re: [R] filling a vector with a tapply function applied to another
vector
>
>
>
Hi
r-help-boun...@r-project.org napsal dne 09.11.2010 20:25:09:
> casperyc
> Odeslal: r-help-boun...@r-project.org
>
> 09.11.2010 20:25
>
> Re: [R] how do i plot this "hist"?
>
>
> Hi all,
>
> Thank you both. The codes work perfectly.
>
> I now use
>
> barplot(t(x.m)[-1,], names.arg = x.
Hi
r-help-boun...@r-project.org napsal dne 09.11.2010 18:33:54:
> Kate Hsu
> Odeslal: r-help-boun...@r-project.org
>
> 09.11.2010 18:33
>
> Komu
>
> r-help@r-project.org
>
> Kopie
>
> Předmět
>
> [R] Question regarding to replace
>
> Dear r-users,
>
> Basically, I have a data as follow
Hi
r-help-boun...@r-project.org napsal dne 09.11.2010 10:26:09:
> "Santosh Srinivas"
> Odeslal: r-help-boun...@r-project.org
>
> 09.11.2010 10:26
>
>
> Re: [R] Creating a list to store output objects from a recursive loop
>
> Figured this out this ways I think
>
> outPut <- list(list(resul
; lll[[5]][3]
> > 13
> > 5079
> >
> > without need for writing to individual files pasting together letters
> > and numbers etc.
> >
> > There shall be R-intro document in your installation and it is worth
> > reading. It is not so big, you can m
numbers etc.
There shall be R-intro document in your installation and it is worth
reading. It is not so big, you can manage it in less then month if you
complete more than 3 pages per day.
Regards
Petr
>
> M
>
> -Original Message-
> From: Petr PIKAL [mailto:petr.
Hi
r-help-boun...@r-project.org napsal dne 04.11.2010 14:21:38:
> Hi David,
>
> I am still having troubles with that loop ...
>
> This code gives me (kinda) the name of the column/field in a data frame.
Filed
> names are form W1-W10. But there is a space between W and a number -->
"W 10",
>
Hi
r-help-boun...@r-project.org napsal dne 04.11.2010 13:28:06:
>
> Hello,
>
> I have tried to find this out some other way, but unsuccessful I have to
> try this list.
> I assume this should be quite simple.
>
> I have a dataset with 4 columns, "Sample_no", "Species", "Nitrogen",
> "Carbon" i
Hi
r-help-boun...@r-project.org napsal dne 01.11.2010 13:02:46:
>
>
>
>
>
>
>
> > To: kai...@berkeley.edu
> > From: petr.pi...@precheza.cz
> > Date: Mon, 1 Nov 2010 11:50:17 +0100
> > CC: r-help@r-project.org
> > Subject: [R] Odp: connecting points i
Hi
I remember that I did it also in base graphics but it took me some time to
find out how and it was a long time ago so.
If I remember it correctly it was some combination of graphic parameters
to set user coordinates and do not overwrite the first plot by setting
par(new=TRUE)
Regards
Petr
Hi
r-help-boun...@r-project.org napsal dne 01.11.2010 07:18:47:
>
> If I have, say, five scatter points and want to connect them together
into a
> smooth curve.
As you are not much specific about what you consider "smooth curve" here
are some options
use some model ?lm and plot predicted val
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