Hi,
I want to obtain the F test associated an ADF test
In tseries, I can obtain t t stat of Dickey fuller, it is posible to obtain
the related F test?
Many thanks in advance
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R-help@r-project.org
y a priori what is the maximum and when "stops"
there is some function in r doing something similar this?
Thans in advance to all.
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Hi all,
Have any of you instaled R on a Tablet, in this case, which Tablet. My
family wants me to gift a Tablet but I suposse R can not be instaled on a
Tablet. And my few "free" time I pass mainly trying to "improve" in R.
Can yoy tell me, if there are, wich Tablet
Hi Many Thanks to all.
dev.print(jpeg, file="test.jpeg", height=800,width=800)
Works perfectly it saves in the default directory the jpeg file.
I use RStudio.
Many Thanks.
2013/4/1 David Winsemius
>
> On Apr 1, 2013, at 9:26 AM, R. Michael Weylandt wrote:
>
> > On
Hi all if I plot a graph on R, I press on the plot Export/Save Plot as
Image
I change name on "File name:"
I select DirectoryBibliotecas\Documentos
And select Width 800 and Height 800
And finally save in format JPEG
It is posible to "type" code so that I can run m
Hello
I am trying to find an automated way of fitting a mixture of normal and
log-normal distributions to data which is clearly bimodal.
Here's a simulated example:
x.1<-rnorm(6000, 2.4, 0.6)
x.2<-rlnorm(1, 1.3,0.1)
X<-c(x.1, x.2)
hist(X,100,freq=FALSE, ylim=c(0,1.5))lines(den
Hello
I am trying to find an automated way of fitting a mixture of normal and
log-normal distributions to data which is clearly bimodal.
Here's a simulated example:
x.1<-rnorm(6000, 2.4, 0.6)x.2<-rlnorm(1, 1.3,0.1)X<-c(x.1, x.2)
hist(X,100,freq=FALSE, ylim=c(0,1.5))lines(densi
Thanks. Is there any more elegant solution? What if I don't know how many
levels of nesting ahead of time?
On Tue, Mar 12, 2013 at 8:51 AM, Greg Snow <538...@gmail.com> wrote:
> You can use the lapply or rapply functions on the resulting list to break
> each piece into a list i
Thanks. That's just an simple example - what if there are more columns and
more rows? Is there any easy way to create nested list?
Best,
Zech
On Mon, Mar 11, 2013 at 2:12 PM, MacQueen, Don wrote:
> You will have to decide what R data structure is a "tree structure". But
>
I have a data.frame object like:
> data.frame(x=c('A','A','B','B'), y=c('Ab','Ac','Ba','Bd'))
x y
1 A Ab
2 A Ac
3 B Ba
4 B Bd
how could I create a tree structure object like this:
|---Ab
A---|
_| |---Ac
|
| |---Ba
B---|
|---Bb
Thanks,
Zech
[[alternative HTML version
Learned a new trick. thanks!
Zech
On Fri, Mar 8, 2013 at 6:41 PM, William Dunlap wrote:
> Try using the combination
>plot.new() ; par(new=TRUE)
> to advance to the next position in the layout before querying par("pin").
> Be sure to actually plot something after the
Hi R users,
I find par("pin") is kind of confusing (or maybe just me?). The manual said
it will give " The current plot dimensions, (width,height), in inches."
The word "current" is the key here. I thought it would give the dimensions
of the to-be plot, but it a
Hi R users,
The margin parameter mar is measured in unit of lines, the size of which is
automatically adjusted during plotting. I am wondering how can get the size
of a line and how can I control the margin size by controlling the line
size? (I know I can use mai to control the absolute size of
Hi all,
I want to execute a loop of a program:
for (u in Timeframemin:Timeframe){}
Imagine that Timeframemin<-10
Timefram<-1
Is it posible to execute the loop but only proving from 10 to 1 but
jumping 10 each time, for example, execute for 10,20,30.to Timeframe.
Other quest
Hi all,
I´m trying to convert as a data frame (with format "date") this copied
excel column of dates (exposed below), I have tried to save them in a txt
file
tfr<-read.table("tfra.txt")
tfr<-data.frame(tfr)
I have tried several things, as date, so on, but always err
Hi all,
I want to order a series that is included on the second column in MCT.csv.
I do but R doesn´t order, could be because is a csv?
I have prove
MCT<-read.csv("MCT.csv")
a<-order(MCTor[,2],2,decreasing = FALSE)
a<-order(MCTor[,2],1,decreasing = FALSE)
or the same w
Hi JEssica
I have tried but for the moment I´m getting crazyso I let for the
future to understand for instance why the viewer doesn´t goes, and so on.
Actually I´m using "Tex Maker" and I attach code using
funtion \begin{lstlisting} so on
The only "inconvenience" i
hi i see you can create latex pdf files using eclipse and that cran r code
can be put on it direcctly. I have tried but it seems very difficult there
is an easy way step by step manual and explaining all programs and folders
needed?
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Many ThanKs to all.
2012/6/10 Bert Gunter
> On Sun, Jun 10, 2012 at 2:22 PM, arun wrote:
> > Hi Bert,
> >
> > I tried the code.
> >
> > dat2<-data.frame(dat1)
> >> do.call(order,dat2)
> > [1] 3 6 1 10 2 5 7 9 8 4
> >
> &g
Imagine I have a csv KT.csv
I want to create a new dataframe o convert KT in a matrix and create a new
matrix with each column of KT ordered by ascending order.
I have tried to make this
b<-read.csv("KT.csv")
for(i in 1:ncol(b)){
b[,i]<-sort(b[,i])
}
But it puts a message
Hi all,
I have a csv matrix "KT.csv" and it has Inf and NA
I want to calculate the mean of each row so I use
rowMeans(KT,na.rm = TRUE) but with this Inf cannot be omminted.
I´m trying to use before running rowMeans(KT,na.rm = TRUE)
KT<-range(KT,finite=TRUE)
but it doesn´t wor
Hi all
Sorry in advance
I have this txt with data and I want to plot the data with a line between
dots.
The thing is that if I run this
g<-read.table("ip.txt")
plot(g,type="l")
I have prove to attach(g) but doesn´ t work.
I know is a begginer question and sure is of
I all,
I have a matrix like this
a=
1 4
2 7
3 6
I want to create a new matrix
b=
3 6
2 7
1 4
Anyone knows if there is a "reverse" function?
I can do it with loops if no exits.
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I have it,
I have used a simply programmation using loops
I have to run the multiple lm with at least 3 variables (because it needs
at least 2 degrees of freedom).
Many Thanks
2012/5/11 Trying To learn again
> Hi all,
>
> I have I got it. I see the way on my mind. I will try
Hi all,
I have I got it. I see the way on my mind. I will try this week end and if
I get it I will send.
Thanks.
2012/5/10 Trying To learn again
> Hi all,
>
> I want to make the following:
>
> I want to run a linear regression on each column of a matrix "estima" on
&
Hi all,
I want to make the following:
I want to run a linear regression on each column of a matrix "estima" on
the correspondent column on the matrix "estima2".
You see I want to regress estima[,1] on estima2[,1] this way to all
columns
At the same time I want to make
Hi all,
I´m trying to use write function to save the output of a program (my
constructed "H" matrix)
randz<-matrix(rnorm(100),500,2000)
H<-matrix(0,500,2000)
H[1,]<-randz[1,]
for (j in 1:2000){
for (i in 2:500){
if(i<251)
H[i,j]<-0.6*H[i-1,j]+randz[i,j]
else H
Hi,
I want to plot this matrix (I attach the data), it is suposed that each
column is a different time series.
If I do
g<-read.table("dataADF.txt", header=F)
and
plot(g[,1],type="l")
it plots the first column plot if I want in a unique graph each colums of
dataA, a
Hi all,
I´m using the windows writting pad (not Notepad the simplest version). I
think there should be greater and helping note pads to help programming.
Can you suggest one?
Many thanks
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R-help@r
I´m using this version of R
R version 2.13.2 (2011-09-30)
Copyright (C) 2011 The R Foundation for Statistical Computing
ISBN 3-900051-07-0
Platform: i386-pc-mingw32/i386 (32-bit)
2012/5/5 Trying To learn again
> Hi all,
>
> I´m re-starting (as my name indicates) my little knowlegde
Hi all,
I´m re-starting (as my name indicates) my little knowlegde of CRAN R.
I made this function time before but I don´t know where is the error
because nothing appears as an error but the histogram plot doesn´t appear.
Should I install some special library to run sapply?
pru<-funct
Hi all,
I´m new using Access. I see that many things that you can do on Access you
can do on CRAN R but not on contrary.
My question is: Is there any manual with examples comparing how to do data
base analysis on access and making the same on CRAN R?
Imagine I want to compare two columns "
Hi all,
I have a matrix
a<-c(2,3,4,Inf)
> b<-as.matrix(a)
[,1]
[1,]2
[2,]3
[3,]4
[4,] Inf
> range(b, finite=TRUE)[2] (this is the maximum)
[1] 4
There is a pre-def function to extract the location (in terms of rows) of
the value in the matrix.
In my example woul
Hi all
> a<-c(2,Inf)
> max(a)
[1] Inf
>
How can I say...omit Inf?
I cannot find anything...
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PLEASE do read the posting guid
Hi all,
I have solved my question
Output<- matrix(0, length(x), 1)
for (i in 1:length(x)){
files <- paste('KT', i, '.csv', sep = '')
da1 <- read.csv(files)
Output[i,1]<-da1[1,2]
}
2011/12/14 Trying To learn again
> Hi all,
>
> I
First PRoblem solved
> read.csv("KT80.csv")
X x
1 1 0.01331361
>
I ommitt "" in calling the file name...
2011/12/14 Trying To learn again
> Hi all,
>
> I have 100 csv files always with this information (I Attach two example
> exc
Hi Michael,
First of all thanks for your response.
I do know that if I make my stimation on a single data the regression has no
sense but it will be getting sense in the growing next estimations.
I change my asking doubt.
I want to use this regressions as a first filter. Only this.
Can anyone
Hi all,
I have a time series a column vector with the ordered data so that the first
column is the first observation and so on.
The fact is that I want to run a multiple regression with only intercept.
My first task is to run the regression on the first observation (1 from 276)
and at the same
3 3
I want to now how many positions are identical between each row
in pru compared with ht.
n and m are the col and row of pru (m is the same number in pru and ht)
I tried this with loops
n<-nrow(pru)
m<-ncol(pru)
dacc2<-mat.or.vec(n, m)
for (g in 1:n){
for (j in 1:m){
if(pru[g,j]-ht
Many Thanks¡¡¡
I will try this night, I have read this I think could help me.
I´m conscient the question was badly formulated now, I will try to explain
better next time¡¡¡
On a side note: apply always accesses the function you use at least once. If
the input is a dataframe without any rows but
Hi all,
I first create a matrix/data frame called "d2" if another matrix
accomplishes some restrictions "dacc2"
da2<-da1[colSums(dacc2)>9,]
da2<-da2[(da2[,13]=24),]
write.csv(da2, file =paste('hggi', i,'.csv',sep = ''))
The thing is if finally da2 cannot get/passs the filters, it cannot writte a
Hi,
I find the solution¡¡¡
It was the 1:2
so if I put a loop for iand replace it works¡¡¡
So Many Thanks¡¡¡ Forget My doubt¡¡
2011/7/5 Trying To learn again
> Hi all,
>
> I try to exceute a function "myfun" that should use as input "input1.csv"
> and
Hi all,
I try to exceute a function "myfun" that should use as input "input1.csv"
and "input2.csv" .
Then I try to save the output dat33 on a csv file (on per each time I
execute input1..input 2 and so on). So my problem is how to finally obtain
several csv file wit
I suppose the easiest way to make this is to use loops and construct a zero
matrix to be completed each time the sequence accompleixes, don´t you?
I will try this evening¡¡¡
2011/7/2 Trying To learn again
> Hi all,
>
> I have a data matrix likein "input.txt"
>
> 8 9
Hi all,
I have a data matrix likein "input.txt"
8 9 2 5 4 5 8 5 6 6
8 9 2 8 9 2 8 9 2 1
8 9 2 5 4 5 8 5 6 4
8 9 2 5 4 5 8 5 6 6
8 9 2 8 9 2 8 9 2 1
8 9 2 5 4 5 8 9 2 2
In this example will be an 6x10 matrix (or data frame)
I want to detect how many times in a row appears this c
Hi I know that putting write(f,file="bar.txt") it should work but the txt
cannot be openned well I don ´t know exactly why.
My mai doubt is how to make this
I want to create a new matrix based on a previous matrix.
You see, If my "data" matrix accomplises this:
if(rowSums(
Hi all,
I want to create a new matrix based on a previous matrix.
You see, If my "data" matrix accomplises this:
if(rowSums(data[i,])>16|rowSums(data[i,])<28)
data[i,]= data[i,]
# if sum of rows is more than 16 and less 28 I conservate the row
#but How I say if else "remo
Hi all,
My file that worked with a thin matrix (with few rows and colums) finally
made an error but I can´t comprehed why?
valor ausente donde TRUE/FALSE es necesario (absent value TRUE/FALSE is
necessary?)
Error en if (data[i, j] - last1[1, j] != 0) data2[i, j] = 0 else { :
You recommed to
Hi all,
I have a function written by me that read a matrix (data frame) from a txt
with 4 million of rows and 13 columns.
The think is my function works with an input matrix of 100x13 and now I
tried to execute my function with the big "input file" and it is running
form the moment
6
> 3 5 5 8 8 8 8 5 5 5
> >
>
>
> On Tue, Jun 28, 2011 at 3:47 PM, Trying To learn again
> wrote:
> > Hi all,
> >
> > I have a matrix like this:
> >
> > 188556644
> > 225588666
> > 55555
> >
> > I try to r
Hi all,
I have a matrix like this:
188556644
225588666
55555
I try to read the table using read table but if I put sep="" I have seen it
expects a white space, is there a "sep" option to read this matrix so
each single number is a position of the matrix
You see thi
Hi all,
I have the next problem: I have a matrix with size 8,000,000x18. My personal
computer...blocks...so I have cut my original file into 100 different file.
I have written a function that should be run on each of this file.
So imagine
I need to read data from q1 to q100 file
data
Hi I have tried the first version, it works. BUT I have an additional
problem. I expose;
The first I solved, I tried to execute on xx data.frame but I used a matrix
wich columns I put name you see
col.names=c("Date","Time","Tip") the thing was that I didn´t er
Hi all,
I´m trying to "recuperate" old files I wrotte and I´m trying to execute on R
version 2.13.0 (2011-04-13), the thing is I execute my old file and nothing
happens...I suposse I need to install some library but there no appears no
message, no text telling "required graf
Hi all,
For several reasons I have no used CARN R in monthsI have an idea and I
want to retry to learn CRAN R.
I know I need to formulate more "intelligent" questions but I will expose
and if someone can help me I would be very gratefull I promise to try to
learn again
The
lumns that contain this pre-requisite.
2010/10/4 Trying To learn again
> Hi all,
>
> I´ve been ill and I have lost a lot of time without seen the pc.
>
> I want you to help if you can if you want.
>
> Only I need an initial guide. I´ve been out a lot of time and I need a
>
Hi all,
I´ve been ill and I have lost a lot of time without seen the pc.
I want you to help if you can if you want.
Only I need an initial guide. I´ve been out a lot of time and I need a hope.
Is only for "joby" purposes.
The problem:
I want to simulate each of the posible combin
Hi all,
I wanto to run a plot about the levels of a variable parting on an ols
regression. The regression in done on the rate of return of the variable.
Imagine R_{t}=a+b*R_{t-1}
So If P, the "estimated" price would be P_{t}=P_{t-1}*R_{t}
Imagine that I obtain lm fitted valu
Hi many thank¡¡¡
I promise work hard¡¡¡
Today I ´ve been very busy but I will wake up tomorrow on 5:00 to see what
you have suggested I need work harder but working and having a children (1,5
years is very exhaust
2010/7/28 Greg Snow
> In addition to the arrows function, look at
Hi I want to plot an x,y plot something like an scatter plot.
I always have the same doubt, were is the last point of my file?
Imagine it is a time series so I want the last point to indicate with an
arrow (but athomatically if posible).
Someone knows if it is posible?
Could it be posible to
Hi all,
I have 35 years, I have been working since I exit from University. I have
returned to make a phd...I´m fortunatelly I´m working so unfortunatelly I
have few time to study (I have also a baby with 16 months).
I´m trying to use R but sometimes it gets very difficult.
I´m trying to put
Hi,
Anyone please help installing RODBC?
Cumprimentos,
Joao Vaz
Product Engineer
QPT Product Engineering
Qimonda Portugal S.A.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Vaz Joao (QPT TO EPA
Hi,
I have R version 2.8.1 running on Windows 2000 and can't seem to be able to
install package RODBC. I've tried reinstalling R but that wasn't successful.
Can some one please help?
This is the command I'm using and the subsequent error message:
> install.packages(&
I have R version 2.8.1 running on Windows 2000 and can't seem to be able to
install package RODBC. I've tried reinstalling R but that wasn't successful.
Can some one please help?
This is the command and the subsequent error message:
> install.packages("RODBC", .L
Hi,
Sorry, just one correction: the error message that appears is:
Warning: unable to access index for repository
http://ftp5.gwdg.de/pub/misc/cran/bin/windows/contrib/2.8
Cumprimentos,
Joao Vaz
Product Engineer
QPT Product Engineering
Qimonda Portugal S.A
Hi,
I'm running R version 2.8.1 on Windows and I'm having quite a lot of trouble
just to install package RODBC.
When I run command install.packages("RODBC"), the following error message
appears:
Warning: unable to access index for repository
http://cran.pt.r-project.org
Reason, I need to do this in awk and not R:
Let's say 'x' is the tabular representation of a sparse contingency table
> x
x10 x11 x12 x13 x14 x15 x16 x17 x18 x19 Freq
10 0 0 2 2 2 0 2 0 2 54
51 0 0 2 2 2 0 2 1 21
61 0
Can anyone point out why this is not working?
y<-read.table(pipe(' awk '{ n = $1; sub( ".*" $1 " " ,"") ; while ( n-- )
print }' temp.txt '))
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x11 2 3
1 0 0 0
2 0 0 0
3 0 0 0
Now, I do can do the following to get the sparse representation 'y' for the
table above:
> idx<-2
> y<-as.data.frame.table(xtabs(~.,data[,idx:(idx+4)]))
> y<-y[y$Freq>0,]
> z<-sort(y$Freq,
I have a matrix y:
> dimnames(y)
$x93
[1] "1" "2"
$x94
[1] "0" "1" "2"
.. so on (there are other dimensions as well)
I need to access a particular dimension, but a random mechanism tells me
which dimension it would. So, s
Neat! Thanks.
On 10/5/07, Deepayan Sarkar <[EMAIL PROTECTED]> wrote:
>
> On 10/5/07, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
> > I have an application that would generate a cross-tabulation in array
> > format in R. In particular, my application would give me a
I have an application that would generate a cross-tabulation in array
format in R. In particular, my application would give me a result
similar to that of :
array(5,c(2,2,2,2,2))
The above could be seen as a cross-tabulation of 5 variables with 2
levels each (could be 0 and 1). In this case, the
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