Geoff,
I think you could write an if loop to solve this.
You could write:
for(i in 1:num_obs){
if(DAYS[i]=='Monday'){
DF$DAYS.BETWEEN[i]<-1
}
}
Where 'num_obs' is the total number of temperature observations you have.
This would only be correct if you had no missing data on Fridays. Also, if
Didn't mean to snub you guys, Hugo and David. I didn't see your posts
before. Thanks for the advice.
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I knew it would be something simple. Thanks for catching that, Martyn.
Billy
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Hi all,
This is a very basic question, but I just can't figure out why R is handling
a loop I'm writing the way it is.
Here is the script I have written:
grid_2_series<-function(gage_handle,data_type,filename)
series_name<-paste(gage_handle,data_type,sep="_")
data_grid<-read.table(file=paste(fi
One thing I should have mentioned before is that "pds_gagehandles" is a
character vector that contains the site names that I am interested in. An
example of a site name is "saho".
So with with the paste function, I am trying to get R to assign a variable
with the site name followed by "_potwy".
Hi all,
I am attempting to run through a large set of data and sort events by the
water year (1 Oct - 30 Sep) in which they occurred.
I have no problem doing this for each individual site I am looking at (so my
problem is not with most of the code, just one minor thing), but when I try
to loop
Hi all,
I am trying to write a script that will compute Kendall's tau for a 75 time
series (using the Kendall package) and will then write the tau and p values
from the Kendall test to a text file table that can be read into Excel.
I am having no problem calculating Kendall's tau and the associat
#x27;
and on and on..
Does anyone know what might be causing this error? Or is there a way
for me to see what line in the code results in an error?
Thanks again.
Billy
Philipp Pagel-5 [via R] wrote:
On Fri,
Mar 25, 2011 at 06:42:49AM -0700, armstrwa wrote:
> When I atte
Hi all,
When I attempt to run a script, I keep getting the error message shown
below. I have seen from searching that the "Use of save versions prior to 2
is deprecated" could be an error resulting from a permissions problem, but I
have been unable to find anything describing the "file has magnic
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
Thanks, Petr. Your insight has helped me out a lot.
Billy
Petr Savicky-2 [via R] wrote:
On Mon, Mar 21, 2011 at 02:28:32PM -0700, armstrwa wrote:
> Hi all,
>
> Forgive me for this basic q
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
Thank you very much, Peter. That does make it clearer.
Billy
Peter Ehlers [via R] wrote:
On
2011-03-21 14:16, armstrwa wrote:
> Hi,
>
> I am running a correlation analysis on a temporal
Hi all,
I am trying to write a script that will automate the task of running a
Kendall's Tau correlation test on 75 time series that I am interested in.
The code I have written is:
for(i in 1:length(gagehandles)){
dates<-get(paste(gagehandles[i],"_amsd",sep=""))
q<-get(paste(gagehandles[i],"_a
Hi all,
Forgive me for this basic question. I've been doing some research and
haven't been able to figure out how to best do this yet.
I have 75 variables defined as vector time series. I am trying to create a
script to automate calculations on each of these variables, but I wasn't
sure how to
Hi,
I am running a correlation analysis on a temporal dataset. I was wondering
if you would receive the same tau and p values running the function:
MannKendall(x), where x is the dependant variable that changes with time
as you would running:
Kendall(d,x), where x is the exact same dataset a
r formula, you've got them
backwards from what you've said you're trying to model.
armstrwa wrote:
Yeah, I did look at the
help(loess) page, but I wasn't really sure what to do with that. I was
inputting it as:
> test<-loess(date ~ q,data.frame(
Yeah, I did look at the help(loess) page, but I wasn't really sure what to do
with that. I was inputting it as:
> test<-loess(date ~ q,data.frame(date,q),span=0.5)
> test
Call:
loess(formula = date ~ q, data = data.frame(date, q), span = 0.5)
Number of Observations: 96
Equivalent Number of Para
Hi,
I am trying to create a loess smooth from hydrologic data. My goal is to
create a smooth line that describes discharge at a certain point in time. I
have done this using the 'lowess' function and had no problem, but I'm
having some difficulty with loess. I am inputting the date ('date') and
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