Hello,
I have a data frame with 400 columns and wanted to filter character columns
with "$" in it.For example: > x <- c("$5", "$89", "$10", "$34") > y <-
c(1:4)> My.Data <- data.frame (x,y)> My.Data x y1 $5 12 $89 23 $10 34 $34 4
I want to detect the columns with $ and remove the $ from t
Hi,
I have the below function which returns confidence intervals. I wanted to pass
different sample sizes through the function, but for some reason it's not
working. n <- seq(from=40, to=300, by=2o)
I was also wondering how I can return a plot for different sample sizes.
plot(m~d, main="
format="%B-%d-%y" )
idx <- grepl( "^(0[1-9]|1[0-2])[0-9]{2}[0-9]{2}$", dta$DtStr, perl=TRUE )
dta$Dt[ idx ] <- as.Date( dta$DtStr[ idx ], format="%m%d%y" )
idx <- grepl( "^([1-9]|1[0-2])/[0-9]{1,2}/[0-9]{2}$", dta$DtStr, perl=TRUE
)
dta$Dt[ idx ] &l
Hi Christoph,
There is "," between dates.Many thanks. Best,Farnoosh
On Wednesday, June 28, 2017 9:05 PM, Christoph Puschmann
wrote:
Hey,
Are all the dates connected? So no comma or space btw?
Regards,
Christoph
> On 29 Jun 2017, at 2:02 pm, Farnoosh Sheikhi via R-h
Hi,
I have a data set with various date formats in one column and not sure how to
unify it.Here is a few formats:
02091702/22/170221201703/17/160015-08-239/2/1500170806May-2-201522-March-2014
I tried parse_date_time from lubridate library but it failed.Thanks so much.
Best,Farnoosh
[[a
Hi,
I have a data set like below:
Subject<- c("2", "2", "2", "3", "3", "3", "4", "4", "5", "5", "5",
"5")dates<-c("2011-01-01", "2011-01-01", "2011-01-03" ,"2011-01-04",
"2011-01-05", "2011-01-06" ,"2011-01-07", "2011-01-07", "2011-01-09"
,"2011-01-10" ,"2011-01-11" ,"2011-01-11")deps<-
blockquote, div.yahoo_quoted { margin-left: 0 !important; border-left:1px
#715FFA solid !important; padding-left:1ex !important; background-color:white
!important; }
Hi
I have a data set like below and wanted to create a new date variable by
extracting the dates for specific departments.I wa
Hi there,
I have a data set like below and wanted to create a new date variable by
extracting the dates for specific departments.I want to extract the dates for
departments CC, DD, FF, put it in a new column and repeat it for other unique
IDs.
Subject<- c("2", "2", "2", "3", "3", "3", "4", "4"
Hi all,
I have two data sets similar like below and wanted to merge them with variable
"deps". As this is a sample data with small sample size, I don't have any
problem using command merge. However, the actual data set has ~60,000
observations with a lot of repeated measures. For example, for a
g) keep_rows<-c(keep_rows,rowindex)
}
final<-matrix(unlist(lapply(df[keep_rows,],as.character)),ncol=3)
I find it terribly hard to ignore puzzles.
Jim
On Wed, Mar 30, 2016 at 10:52 AM, Farnoosh Sheikhi via R-help
wrote:
> Hello,
> I have a data set similar to below and I wanted to
Hello,
I have a data set similar to below and I wanted to keep the observations after
the first occurrence of these department: "B", "D", "F".For example for ID=2,
the observation with deps=B and anything after will be kept in the data. For
ID=3, observations with deps=D and anything after will
Hello,
I'm trying to get the distances between two Zipcode variables, but for some
reason I get this error:
"matching was not perfect, returning what was found.Error: no such index at
level 1"
Here is my code:
library(ggmap)mapdist(data$Zip.A, data$Zip.B, mode = "driving")
The Zip codes are all
13L, 8706L, 4049L, 5877L,
>>> 1375L, 2223L, 3423L), date = structure(c(4L, 3L, 2L, 1L, 7L,
>>> 6L, 5L), .Label = c("05/12/11", "06/05/11", "07-Dec-11",
>>> "19-Dec-11", "01/22/2011", "10/19/2011", "31/12/20
-7L),
class = "data.frame")SampleData
Thanks for your help:).
On Wednesday, July 29, 2015 1:50 PM, Sarah Goslee
wrote:
On Wed, Jul 29, 2015 at 2:45 PM, farnoosh sheikhi v
Hi Arun,
Hope all is well with you. I have a data with a column for date.The date format
is mixed. There are date values with Month/Day/Year format and values with
Day/Month/Year format.I don't know how to unify it.I really appreciate your
help.Thanks.
[[alternative HTML version dele
2� 1� 0� 0
� � 2:� 2� � 3� 0� 1� 1
On Wednesday, February 11, 2015 5:47 PM, farnoosh sheikhi
wrote:
Hi Arun,
I have a data set that look s like below. I wanted to get a difference in dates
for each unique ID and record it as a new X and have binary input for each one.
ID� Date
1� � � �
7;), type='l', col=1:3, ylab='X',
> xlab='TIME')
> legend('bottomright', inset=.05, legend=LETTERS[1:3], pch=1, col=1:3)
> A.K.
>
> On Friday, December 5, 2014 5:45 PM, farnoosh sheikhi
> wrote:
>
>
>
> Hi Arun,
>
> I hope you a
quot;,"AL MIGUEL","ALV",
"Farnoosh Sheikhi", "D Art", "Rob K Kim")
do.call(rbind,lapply(str_split(str_replace_all(str1,perl('(?<= )([A-Za-z]+)$'),
",\\1"),","),function(x) {x1 <- str_trim(x); if(length(
You are the best. Thanks tons:))
Regards, Farnoosh Sheikhi
On Thursday, February 27, 2014 10:37 PM, arun wrote:
Hi Farnoosh,
YOu can try:
DataA$percent <- with(DataA,round((Var2/sum(Var2))*100,2))
library(ggplot2)
ggplot(DataA,aes(x=Var1,y=percent))+geom_bar(stat="identity&q
, etc.
I want to create a data set in R based on this story.
I really appreciate any help and direction.
Regards, Farnoosh Sheikhi
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RE TIER 2 10
#2 2 AETNA EPO Group1 110
#3 3 BLUE CARD INTE Group1 2
#4 4 BLUE CROSS AUTO Group1 25
#5 5 BLUE CROSS CA Group1 33
#6 6 LOCKHEED Group2 40
A.K.
On Wednesday, February 19, 2014 6:03 PM, farnoosh sh
Perfect. Thank you so much.
Regards, Farnoosh Sheikhi
On Thursday, February 13, 2014 2:16 PM, arun wrote:
Hi Farnoosh,
If I understand it correctly,
dat <-read.table(text="Var1
Great>5
great
'less great<2'
'approx great11'",sep="",head
Thanks:)
Regards, Farnoosh Sheikhi
On Thursday, February 13, 2014 1:29 PM, arun wrote:
Sorry, the library should be
library(reshape2)
On Thursday, February 13, 2014 4:27 PM, arun wrote:
HI Farnoosh,
You can use ?dcast()
library(plyr)
dcast(DataA,ID~Var1,value.var="Var2&qu
Thanks a lot. That worked perfectly.
Best,Farnoosh Sheikhi
Sent: Wednesday, August 28, 2013 10:37 AM
Subject: Re: list to data frame
If the expected result is data.frame()
as.data.frame(t(as.data.frame(lapply(dat1,sum# would be data.frame. But,
not
Thanks a lot. That works great.
I have another question, I will send you another email.
Best,Farnoosh Sheikhi
Cc: R help
Sent: Monday, August 26, 2013 12:06 PM
Subject: Re: Loop for converting character columns to Numeric
Hi,
Suppose you created a
Thanks for the code. It was so simple and worked perfectly.
I really appreciate it.
Best,Farnoosh Sheikhi
Cc: R help
Sent: Wednesday, August 14, 2013 11:56 AM
Subject: Re: changing colnames
Hi,
You could try:
dat1<- read.table(text="
X1,X2,X3
Thanks a lot Arun.
I like the do.call command a lot. So easy to use and fast:-)
Best,Farnoosh Sheikhi
Cc: R help
Sent: Monday, July 29, 2013 1:58 PM
Subject: Re: Aggregate
Hi,
You could try:
dat1<- read.table(text="
ID Group1
1 1
1
te x2 x1 x3
56 25-Jun-01 10 2 126
56 29-Oct-01 10 2 140
56 18-Mar-02 10 2 445
56 6-Jun-03 10 2 224
56 16-Jan-04 NA NA
58 10-Jan-02 10.8 1 715
58 26-Dec-03 10.8 1 NA
Best,Farnoosh Sheikhi
[[alternative HTML version deleted]]
Hi,
I want to simulate from Markov Chain Discrete Algorithm and my transition
matrix is:
The probability transition matrix
trans = matrix(c(0.8,0.05,0.05,0,
0.05,0.80,0.055,
0.05,0.05,0.81, 0, 0.05, 0.095, 0, 0.81), ncol=4, byrow=TRUE);
The Initiate Values are
Thanks a lot.
That worked:-)
Cc: R help
Sent: Sunday, April 21, 2013 7:32 AM
Subject: Re: Excluding observations
Hi Farnoosh,
set.seed(25)
Data.All.Var<- data.frame(ID= sample(LETTERS[1:10],25,replace=TRUE),
value=rnorm(25),stringsAsFactors=FALSE)
set.seed
New[3,] &
x2[i,2]< x1New[4,] ,]; x4<-x2[i,][nrow(x3)>0];merge(x3[,1:2],x4) }))}))
dataNew2$Date.Accident<-format(dataNew2$Date.Accident,"%d-%b-%y")
library(plyr)
res<-join(rbind(dataNew1,dataNew2),DataB,by=c("ID","Date.Accident"),type="rig
00 1
Thanks.
Best,Farnoosh Sheikhi
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and provide
!!!
I'm wondering if there is something wrong in my codes .
Thanks a lot and happy holidays!
Best,Farnoosh Sheikhi
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P
olumn my lab or procedures
start.
I really appreciate your help.
Thanks.
Best,Farnoosh Sheikhi
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PLEASE do read the posting
Thank you so much.
It worked very well:)
Best,Farnoosh Sheikhi
Cc: R help
Sent: Wednesday, December 12, 2012 12:59 PM
Subject: Re: Subset of Data
Hi Farnoosh,
Try this:
set.seed(151)
mat1<-matrix(sample(1:400,100,replace=TRUE),ncol=20)
set.seed
mydata) ???
step(fit0, scope=list(lower=fit0, upper=fit.final), data=mydata,
direction="forward")
step(fit.final, scope=list(lower=fit.final, upper=fit0), data=mydata,
direction="backward")
Best,Farnoosh Sheikhi
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___
thanks dear. method 2 worked very fast since my data is very big.
Thanks a lot. :-)
Best,Farnoosh Sheikhi
Cc: R help
Sent: Monday, November 12, 2012 6:15 PM
Subject: Re: for loop
HI,
You can do this in many ways:
dat1<-read.table(text="
med1,m
Hi,
I have a R output that looks as follow:
Rad:0
Rad1:2
Rad3:3
I want to make a new matrix that looks like : sample size is 2400
Variable n11 n12
Rad 0 2400-0=2400
Rad1 2 2400-2
Rad3 3 2400-3
Thanks a lot for your time and help:)
Best,Farnoosh Sheikhi
I'm using Revolution R Enterprise.
This command worked perfectly.
Thank you so much for your help and time:-)
Best,Farnoosh Sheikhi
Cc: R help
Sent: Wednesday, November 7, 2012 10:47 AM
Subject: Re: [R] pivot table
HI,
Could you tell me which version
Hi there,
Thanks forhelping. I really appreciate it.
The only thing is I get this error: "Error in gsub("[\\_]", ".", paste0("Lab",
colnames(res2)[-1])) :
could not find function "paste0""
Thanks.
Best,Farnoosh Sheikhi
___
It worked beautifully.
Thank you so much:-)
Best,Farnoosh Sheikhi
Cc: R help
Sent: Tuesday, November 6, 2012 2:44 PM
Subject: Re: [R] pivot table
Hi,
Is this okay?
library(reshape2)
dat1<-read.table(text="
ID Diag Proc DOB Gender
a
Hi there,
Thanks a lot for your help, but Proc doesn't show in the result.
I also want to assign 1 and 0 instead of the name of variables.
Thanks a lot.
Best,Farnoosh Sheikhi
Cc: R help
Sent: Tuesday, November 6, 2012 1:42 PM
Subject: Re: [R] pivot
Lab3.A
a 11 1000
b 0 1001 0
Thanks a lot:)
Best,Farnoosh Sheikhi
Cc: R help
Sent: Tuesday, November 6, 2012 2:44 PM
Subject: Re: [R] pivot table
Hi,
Is this okay?
library(reshape2)
dat1<-read.table(text="
ID Dia
diag1
I want to reformat this data to :
ID diag1 diag 2 diag 3.. diagx proc1 proc2 proc3... procx DOB Gender
a1011 20F
Thanks a lot for your help and time.
Best,Farnoosh Sheikhi
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Thanks a lot. Is count command in package COUNT? I'm having a hard fine to fine
this package.
Thanks again:)
Best,Farnoosh Sheikhi
Cc: R help
Sent: Tuesday, October 23, 2012 2:07 PM
Subject: Re: [R] frequency
Hi,
Try this:
dat1<-read.table(t
hanks a lot.
Best,Farnoosh Sheikhi
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and provide comm
form.
When I put odds.ratio=as.matrix(odds.ratio), my plot shows the numbers.
I really appreciate your help.
Thanks.
Best,Farnoosh Sheikhi
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Hi,
I have a column of DOB in mm/dd/. I want to convert this format to age.
Thanks a lot.
Best,Farnoosh Sheikhi
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PLEASE
50 100 0.9647998
>
Best,Farnoosh Sheikhi
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an
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