corboot$t
t is a matrix of the bootstrap replicates.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of David Parkhurst
Sent: Thursday, March 06, 2014 12:28 PM
To: r-help@r-project.org
Subject: [R] Another question about bootstrapping cor
When I use the fix that Arun K. provided to my earlier example, I wonder
how to find out where in the 999 bootstrap repetitions the value for the
actual data fits.
Here is the fixed code:
x <- 1:15
y <- c(2,4,1,3,5, 7,6, 9,10,8, 14, 13, 11, 15, 12)
x[3] <- NA; x[11] <- NA; x[8] <- NA
y[2] <- NA
Thank you Ahmadou,
I got an error when I change fill to colour:
> p + geom_point(aes(size = ACE, colour = ACE)) + theme_bw() +
+ scale_size(to = c(3, 15), name = "Número de especies", breaks = c(10,
40, 70, 100, 130, 160, 190, 220, 250)) +
+ scale_colour_gradientn(name = 'Número de especies',
Hi all
Just as Pierre pointed out, i used rgeos instead of gpclib (the licence is
less restrictive even though i'm still students). A since the last release
the rgeos package seems to work well.
I'm really disapointed by the fact that some packages (e.g adehabitatMA
which is great thank's M. Caleng
Hi all,
2011/4/4 Felipe Carrillo :
> Manuel:
> As far as I know one needs gpclibPermit() in order to fortify
> see this:
> Note: polygon geometry computations in maptools
> depend on the package gpclib, which has a
> restricted licence. It is disabled by default;
> to enabl
Manuel:
As far as I know one needs gpclibPermit() in order to fortify
see this:
Note: polygon geometry computations in maptools
depend on the package gpclib, which has a
restricted licence. It is disabled by default;
to enable gpclib, type gpclibPermit()
I am going to guess
Thank you very much Felipe,
Did you see the solution from ahmadou dicko?
He doesn´t use gpclibPermit()
I have another option but I cannot get the right fill for the id.
See attached map.
ai_biotica = readOGR(dsn="C:/ProyectosRespacial/ICE/SIG_Biotica_PHED",
layer="AI_BIOTICA_010411_CRTM05")
Manuel:
I changed your variable names from x to 'long' and y to 'lat' on the
riqueza_out.csv file.
The code below should do what you want. Also, since the legend title is kind of
long, I broke it
down into three lines so you can see more plot area. I am cc'ing the other
groups so more people
use
thank you. I need learn it, after that, maybe I can understant it well.
thank Nikhil
Nikhil Kaza-2 wrote:
>
> You need dim(cor.matrix)[1]
>
> Following might be better instead of a loop, to to get the row ids of
> a matrix
>
> (which(cor.matrix >=0.95) %/% dim(cor.matrix)[1])+1
>
> for co
my programe is below:
a=c(1,2,1,1,1); b=c(1,2,3,4,1); c=c(3,4,3,3,3); d=c(1,2,3,5,1);
e=c(1,5,3,5,1)
data.f=data.frame(a,b,c,d,e)
origin.data<-data.f
cor.matrix<-cor(origin.data)
origin.cor<-cor.matrix
m<-0
for(i in 1:(cor.matrix[1]-1))
{
for(j in (i+1):(cor.matrix[2]))
{
if (cor.matri
nden: donderdag 23 juli 2009 14:25
Aan: r-help@r-project.org
Onderwerp: [R] Another question on gplot
I am getting following strange error :
library(sn)
library(ggplot2)
dat1 <- as.matrix(rsn(1000, 0, 1, 0))[,1]
ggplot() + geom_histogram(aes(x = dat1, y = ..density.., fill =
..count..))
+
I am getting following strange error :
library(sn)
library(ggplot2)
dat1 <- as.matrix(rsn(1000, 0, 1, 0))[,1]
ggplot() + geom_histogram(aes(x = dat1, y = ..density.., fill = ..count..))
+
xlab("Distribution") + scale_y_continuous("")
Error: No data for layer
Can anyone please
How about you starting threads with something that suggest what you are
looking for:
Like "adding collumns in stata (gen or egen)".
On Sun, Mar 29, 2009 at 10:50 PM, minben wrote:
> I want to add a colume to a data frame by some rules, in stata the
> command is "gen" or "egen" ,but what is it
I want to add a colume to a data frame by some rules, in stata the
command is "gen" or "egen" ,but what is it in R?
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I have one other question regarding the nnet package in R:
What is the value of the step size (often referred to as "eta") for
the gradient descent function?
I dont see anywhere in the API where this value can be modified.
Thanks,
-Colin
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