="glm", ...)
where you want it to make the call
glm(...)
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Message-
> From: Simon Kiss [mailto:sjk...@gmail.com]
> Sent: Thursday, December 19, 2013 1:49 PM
> To: William Dunlap
> Cc: Dennis Murph
Hi there: Just to tie this altogether.
Here is the final function
f<- function (modelType, responseName, predictorNames, data, ..., envir =
parent.frame())
{
call <- match.call()
call$formula <- formula(envir = envir, paste(responseName, sep = " ~ ",
nd as.name() would
make a hash of it as we saw in the original portion of this question.
>
> Bill Dunlap
> Spotfire, TIBCO Software
> wdunlap tibco.com
>
>
>> -Original Message-
>> From: David Winsemius [mailto:dwinsem...@comcast.net]
>> Sent: Thursda
sem...@comcast.net]
> Sent: Thursday, December 19, 2013 11:31 AM
> To: William Dunlap
> Cc: Simon Kiss; r-help@r-project.org
> Subject: Re: [R] Help using mapply to run multiple models
>
>
> On Dec 19, 2013, at 11:10 AM, William Dunlap wrote:
>
> >>>
Bill Dunlap
>> Spotfire, TIBCO Software
>> wdunlap tibco.com
>>
>>
>>> -Original Message-
>>> From: Simon Kiss [mailto:sjk...@gmail.com]
>>> Sent: Thursday, December 19, 2013 10:56 AM
>>> To: William Dunlap
>>> Cc: D
gt; Bill Dunlap
> Spotfire, TIBCO Software
> wdunlap tibco.com
>
>
>> -Original Message-
>> From: Simon Kiss [mailto:sjk...@gmail.com]
>> Sent: Thursday, December 19, 2013 10:56 AM
>> To: William Dunlap
>> Cc: Dennis Murphy; r-help@r-project.org
>> Subject: Re
> Sent: Thursday, December 19, 2013 10:56 AM
> To: William Dunlap
> Cc: Dennis Murphy; r-help@r-project.org
> Subject: Re: [R] Help using mapply to run multiple models
>
> Hello Bill, that is fantastic and it's quite a bit above what I could write.
> Is there a way to
>
Hello Bill, that is fantastic and it's quite a bit above what I could write. Is
there a way to make the model type an argument to the function so that you can
specify whether one is running glm, lm and such?
I tried to modify it by inserting an argument modelType below, but that doesn't
work.
Y
r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf
> Of Simon Kiss
> Sent: Wednesday, December 18, 2013 9:11 AM
> To: Dennis Murphy
> Cc: r-help@r-project.org
> Subject: Re: [R] Help using mapply to run multiple models
>
> Dennis, how would your
Folks:
1. Haven't closely followed the thread. I'm responding only to Simon's post.
2. ?formula ## Especially note the use of "."
So just make an appropriately constructed data frame for the data
argument of glm:
## example
> df <- data.frame(y=rnorm(9),x1=runif(9), x2=1:9)
> glm(y~.,data=df)
Dennis, how would your function be modified to allow it to be more flexible in
future.
I'm thinking like:
> f <- function(x='Dependent variable', y='List of Independent Variables',
> z='Data Frame')
> {
>form <- as.formula(paste(x, y, sep = " ~ "))
>glm(form, data =z)
> }
I tried that t
Thanks! that works, more or less. Although the wonky behaviour of mapply that
David pointed out is irritating. I tried deleting the $call item from the
models produced and passing them to stargazer for reporting the results, but
stargazer won't recognize the results even though the class is expl
On Dec 17, 2013, at 5:53 PM, Simon Kiss wrote:
> I think I'm missing something. I have a data frame that looks below.
> sample.df<-data.frame(var1=rbinom(50, size=1, prob=0.5), var2=rbinom(50,
> size=2, prob=0.5), var3=rbinom(50, size=3, prob=0.5), var4=rbinom(50, size=2,
> prob=0.5), var5=r
I think I'm missing something. I have a data frame that looks below.
sample.df<-data.frame(var1=rbinom(50, size=1, prob=0.5), var2=rbinom(50,
size=2, prob=0.5), var3=rbinom(50, size=3, prob=0.5), var4=rbinom(50, size=2,
prob=0.5), var5=rbinom(50, size=2, prob=0.5))
I'd like to run a series of
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