Re: [R] How to take out the content of character string

2010-03-15 Thread jq81
Thank you all so much for the help! -- View this message in context: http://n4.nabble.com/How-to-take-out-the-content-of-character-string-tp1587004p1592886.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing

Re: [R] How to take out the content of character string

2010-03-11 Thread Thomas Lumley
On Wed, 10 Mar 2010, Henrique Dallazuanna wrote: On Wed, Mar 10, 2010 at 7:50 PM, Thomas Lumley tlum...@u.washington.edu wrote: On Wed, 10 Mar 2010, baptiste auguie wrote: Hi, it's generally considered a bad practice but try this, eval(parse(text=AA)) library(fortunes) fortune(106) HTH,

Re: [R] How to take out the content of character string

2010-03-10 Thread baptiste auguie
Hi, it's generally considered a bad practice but try this, eval(parse(text=AA)) library(fortunes) fortune(106) HTH, baptiste On 10 March 2010 07:46, jq81 jingqia...@gmail.com wrote: My question is represented by the following example. For example, I have a character string a, which is

Re: [R] How to take out the content of character string

2010-03-10 Thread Thomas Lumley
On Wed, 10 Mar 2010, baptiste auguie wrote: Hi, it's generally considered a bad practice but try this, eval(parse(text=AA)) library(fortunes) fortune(106) HTH, baptiste On 10 March 2010 07:46, jq81 jingqia...@gmail.com wrote: My question is represented by the following example. For

Re: [R] How to take out the content of character string

2010-03-10 Thread Henrique Dallazuanna
On Wed, Mar 10, 2010 at 7:50 PM, Thomas Lumley tlum...@u.washington.edu wrote: On Wed, 10 Mar 2010, baptiste auguie wrote: Hi, it's generally considered a bad practice but try this, eval(parse(text=AA)) library(fortunes) fortune(106) HTH, baptiste On 10 March 2010 07:46, jq81

[R] How to take out the content of character string

2010-03-09 Thread jq81
My question is represented by the following example. For example, I have a character string a, which is defined as AA=list(x=1, y=2) I want to take out the content of AA by using some function, so that I can obtain the following expression automatically. list(x=1, y=2) Does anyone know how