Please, please do not use html formatted mail.
It is clearly requested by the mailing list
The code of your last mail is a mess and when replying it becomes even more of
a mess.
I told you to do
siml[g,] - optm(perm=20)
See the comma after g.
and not what you are now doing with
Dear R Users,
I created a function which returns a value every time it's run (A
simplified toy example is attached on this mail).
For example spat(a,b,c,d) # run the first time and it gives you ans1=
10, perm=1 ;
run the second time and gives you ans2= 7, perm=2 etc
I store both the
Is this what you want? I was not clear on your algorithm, but is looks
like you wanted descending values:
testx -
+ function(n, verbose = FALSE)
+ {
+ mat - cbind(optA = sample(n, n, TRUE), perm = seq(n))
+ if (verbose){
+ cat(***starting matrix\n)
+ print(mat)
+ }
+
Hi all are there any R packages that include circular stats similar to
Oriana (http://www.kovcomp.co.uk/oriana/newver4.html)?
I am interested in looking at annual patterns of bat activity where data
will have date/times and relative abundance values for each Date.
I would like to have a
On 05/27/2013 10:28 AM, Neotropical bat risk assessments wrote:
Hi all are there any R packages that include circular stats similar to
Oriana (http://www.kovcomp.co.uk/oriana/newver4.html)?
I am interested in looking at annual patterns of bat activity where data
will have date/times and
Hello, James,
see my comments inline.
... Main issue/question: In R the nparLD ANOVA-type Test showed a
significant p-value for diel period, no effect of season, and no
interaction between diel period and season. But a post-hoc Wilcoxon
Signed-Rank Test did NOT find a significant difference
1:51 PM
Subject: [R] R help: Batch read files based on names in a list
*
I am currently reading in a series of files, applying the same functions to
them one at a time, and then merging the resulting data frames e.g.:
MyRows - c(RowA, RowB, RowC)File1_DF -
read.delim(DirectoryToFiles
*
I am currently reading in a series of files, applying the same functions to
them one at a time, and then merging the resulting data frames e.g.:
MyRows - c(RowA, RowB, RowC)File1_DF -
read.delim(DirectoryToFiles\\File1_Folder\\File1.txt,
stringsAsFactors=FALSE, check.names=FALSE)File1_DF
On Wed, 15 May 2013, Jonathan Dry dry...@gmail.com writes:
*
I am currently reading in a series of files, applying the same functions to
them one at a time, and then merging the resulting data frames e.g.:
MyRows - c(RowA, RowB, RowC)File1_DF -
Hi,
I'm trying to analyze repeated measurements of body temperature data
collected from 7 randomly chosen subjects (e.g. turtles). I am using R,
along with the nparLD package to test for an effect of diel period (fixed
factor: day or night) and season (sub-plot fixed factor: spring, summer,
fall)
Hi Arun,
I am still facing trouble as I can see the data output is identical for
all rows when I am using this merge function. It seems that since in my
data2 which I have provided I have not given you the exact genes I have.
There are likely to be repeatations of ID in both the files but the
Hi Vivek,
May be this helps:
set.seed(35)
dat1- cbind(ID=1:8,
as.data.frame(matrix(sample(1:50,8*7,replace=TRUE),ncol=7)))
set.seed(38)
dat2- cbind(ID= sample(1:20,8,replace=FALSE),
as.data.frame(matrix(sample(1:50,8*33,replace=TRUE),ncol=33)))
colnames(dat2)[-1]-gsub(V,X,colnames(dat2)[-1])
HI Arun,
My data sets are as in the provided files. I am providing the sample files.
I guess this will give a better idea to the type of working I want to do
with the two files and the kind or script am trying to write. Hope you can
give me some suggestions regarding this. I am new to R so having
HI,
Assuming that out_dat.txt is the output you expected.
dat1- read.table(data1.txt,header=TRUE,stringsAsFactors=FALSE)
dat2- read.table(data2.txt,header=TRUE,stringsAsFactors=FALSE)
out_dat- read.table(out_data.txt,header=TRUE,stringsAsFactors=FALSE)
out_dat2-merge(dat1[,1:4],dat2,by=ID)
This comes up regularly. Type ?print.survfit and look at the comments there under
value.
Terry T.
- begin included message
Hi,
I'm not sure if this is the proper way to ask questions, sorry if not. But
here's my problem:
I'm trying to do a bootstrap estimate of the
Hi,
I'm not sure if this is the proper way to ask questions, sorry if not. But
here's my problem:
I'm trying to do a bootstrap estimate of the mean for some survival data.
Is there a way to specifically call upon the rmean value, in order to store
it in an object? I've used
Thank you Jason! actually, there have been two solutions and one is yours
setting row.names=F works great, additionally what Ive been having problems
with is the European version of Word 2010. Apparently it sets delimiters of
; instead of , as in the English/USA version. This is something
On 3/26/2013 7:21 AM, Kerry wrote:
Thank you Jason! actually, there have been two solutions and one is yours
setting row.names=F works great, additionally what Ive been having problems
with is the European version of Word 2010. Apparently it sets delimiters of
; instead of , as in the
On R 2.15.2 and ArcGIS 9.3.1, it works for me in ArcCatalog but you have to
follow the particulars here:
http://webhelp.esri.com/arcgisdesktop/9.3/index.cfm?TopicName=Accessing_delimited_text_file_data
For example:
write.table(test, '***.tab', sep = '\t', row.names = F)
The extension .tab and
Good morning to you all,
Sorry for taking your time from your research and
teaching schedules.
If you have a non-stationary univariate time Series
data that has the transformation:
Say; l.dat-log (series)
d.ldat-diff (l.dat, differences=1)
and you fit say arima model.
predit.arima-predict
If you just want point forecasts, it's simple:
Let your original series be X_t, t=1, ..., N.
Let Y_t = log(X_t).
Let Z_t = Y_t - Y_{t-1}, t = 2, ..., N.
Fit your model and forecast, obtaining Z-hat__1, ..., Z-hat_10.
Then Y-hat_{N+1} = Y_N + Z-hat_1, Y-hat_{N+2} = Y-hat_{N+1} + Z-hat_2,
.,
I just saw a message from David Winsemius, responding to an inquiry
from Carol White:
On Jan 28, 2013, at 9:06 PM, carol white wrote:
Should I understand that this message was received?
It's always possible to check the Archives for this question.
This prompted me to ask about a problem
The searchable archives may lag, and apparently do. The main list
archive is here:
https://stat.ethz.ch/pipermail/r-help/
and is complete. That's the one to check if you wish to know whether
something made it to the list.
If you go to the r-help listinfo link in the mailing list footer, you
are
On 01/30/2013 10:28 AM, Sarah Goslee wrote:
The searchable archives may lag, and apparently do. The main list
archive is here:
https://stat.ethz.ch/pipermail/r-help/
and is complete. That's the one to check if you wish to know whether
something made it to the list.
If you go to the r-help
-- ___ Paul K. Musingila University of
Hasselt, I-Biostat, Diepenbeek, Belgium Mobile: +254-724-423532,
+32-48-637-4558 E-mail: paul.musing...@student.uhasselt.be,
pmusing...@gmail.com Skype: pmusingila When darkness overtakes the
godly, light will come bursting
Hi,
I have explored many of the R packages that construct Bayesian trees including
the tgp, bart, BMA and maptree packages. I have also searched through some
other packages but they do not seem to be suitable for the type of analysis I
need to do. I need to construct Bayesian CART that have
I don't know of one. If building your own you could use rpart with the maxdepth=1 as
the tool to find the best split at each node.
Terry Therneau
On 12/20/2012 05:00 AM, r-help-requ...@r-project.org wrote:
Hi,
I've searched R-help and haven't found an answer. I have a set of data from
Hi,
I am new to R. I am trying to regroup data frame using multiple constrains.
for example
data frame: data
value class percent
15526 36 4.6875
15527 62 85.9375
15527 82 32.4564
15528 36 70.3125
15528 62 9.375
15528 82 74.6875
I need to regroup
On Nov 23, 2012, at 1:14 PM, prasmas wrote:
Hi,
I am new to R. I am trying to regroup data frame using multiple
constrains.
for example
data frame: data
value class percent
15526 36 4.6875
15527 62 85.9375
15527 82 32.4564
15528 36 70.3125
15528 62
Hello,
Like the following?
dat - read.table(text=
value class percent
15526 36 4.6875
15527 62 85.9375
15527 82 32.4564
15528 36 70.3125
15528 62 9.375
15528 82 74.6875
, header = TRUE)
per70 - dat$percent 70
split(dat, list(dat$class, per70))
Hope this helps,
Rui Barradas
Em 23-11-2012
, 2012 7:40 PM
Subject: Re: [R] R help..subsetting data frame that meeting multiple
criteria
On Nov 23, 2012, at 1:14 PM, prasmas wrote:
Hi,
I am new to R. I am trying to regroup data frame using multiple
constrains.
for example
data frame: data
valueclasspercent
1552636
and 1 to a and b.
row.names(mat1)-gsub(1,b,gsub(0,a,row.names(mat1)))
row.names(mat1)
#[1] 36_a 62_b 82_a 36_b 62_a 82_b 72_a 72_a
Hope it helps.
A.K.
- Original Message -
From: prasmas prasad...@gmail.com
To: r-help@r-project.org
Cc:
Sent: Friday, November 23, 2012 4:14 PM
Subject: [R] R
74.6875
A.K.
- Original Message -
From: David Winsemius dwinsem...@comcast.net
To: prasmas prasad...@gmail.com
Cc: r-help@r-project.org
Sent: Friday, November 23, 2012 7:40 PM
Subject: Re: [R] R help..subsetting data frame that meeting multiple criteria
On Nov 23, 2012, at 1:14 PM
Hi the list,
I have some basic questions about writing a package. On which list shall I
post them?
Theoretically, I am supposed to post them on r-devel, but all the questions on
this list are very
advance questions, not basic ones... So I don't know what to do.
Christophe
--
Christophe
On Nov 5, 2012, at 11:24 AM, Christophe Genolini cgeno...@u-paris10.fr wrote:
Hi the list,
I have some basic questions about writing a package. On which list shall I
post them?
Theoretically, I am supposed to post them on r-devel, but all the questions
on this list are very
advance
Hi,
I am trying to add a column of numbers to a data frame in R with multiple
conditions.
Here is a simplified example df:
[A] [B] [C] [D] [E]
[1] 1 X 90 88
[2] 1 Y 72 70
[3] 1 Z 67 41
[4] 2 X 74 49
[5] 2 Y 42 50
[6] 2 Z 81 56
[7] 3 X 92 59
[8] 3 Y 94 80
[9] 3 Z 80 82
I would like column [E]
Hi Libby,
You had an accumulation of small errors, from an extra ) to an unclear
understanding of how indexing works in R. Also, you shouldn't call
your dataframe df, or use square brackets in column names.
That said, what about:
sampledata - structure(list(A = c(1L, 1L, 1L, 2L, 2L, 2L, 3L,
Gertken libb...@utexas.edu
Cc: r-help@r-project.org
Sent: Thursday, October 4, 2012 4:03 PM
Subject: Re: [R] R help - Adding a column in a data frame with multiple
conditions
Hi Libby,
You had an accumulation of small errors, from an extra ) to an unclear
understanding of how indexing works in R
Hello Amelie,
I don't have an answer to your question, but I just wanted to point out
this page I noticed recently (
http://hlplab.wordpress.com/2009/05/07/multinomial-random-effects-models-in-r/),
which might be helpful.
I'm also interested in figuring out how to do a multinomial glmm, so if
Hi there,
I have subscribed to R-help but am not sure how to view or post questions? I
think this is the right way.
I am planning on doing a multivariate regression investigating the relationship
between depression (a continuous variable) and social support variables (mostly
continuous, some
On Sun, Aug 12, 2012 at 10:58 PM, Louise Cowpertwait
louisecowpertw...@gmail.com wrote:
Hi there,
I have subscribed to R-help but am not sure how to view or post questions? I
think this is the right way.
Indeed!
I am planning on doing a multivariate regression investigating the
Hi
I'm trying to increase the memory limit but Im facing this problem
Error: unexpected symbol in C:\\Program
Files\\R\\R-2.15.0\\bin\\i386\\Rgui.exe --max-mem-size=500M
Hope you can help me out
Thank You
[[alternative HTML version deleted]]
There seem to be too many quotes in your error message... the path and name of
the program should be quoted, the argument should not (or should be separately
quoted).
500M isn't especially large these days... be sure to check your existing
(default) value using the memory.limit() function
Please continue to include the r-help list in the conversation... you will most
likely get your solution quicker.
Why do you have double backslashes? That is needed within R, but not at the
command line or in a shortcut.
On Sun, Aug 5, 2012 at 4:49 PM, Douglas Karabasz
doug...@sigmamonster.com wrote:
I have a xts object made of daily closing prices I have acquired using
quantmod.
Here is my code:
library(xts)
library(quantmod)
library(lubridate)
# Gets SPY data
getSymbols(SPY)
# Subset Prices
On Mon, Aug 6, 2012 at 4:30 PM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
On Sun, Aug 5, 2012 at 4:49 PM, Douglas Karabasz
doug...@sigmamonster.com wrote:
I have a xts object made of daily closing prices I have acquired using
quantmod.
Here is my code:
library(xts)
I have a xts object made of daily closing prices I have acquired using
quantmod.
Here is my code:
library(xts)
library(quantmod)
library(lubridate)
# Gets SPY data
getSymbols(SPY)
# Subset Prices to just closing price
SP500 - Cl(SPY)
# Show day of the week for each date using 2-6
Hello,
Inline
Em 31-07-2012 02:59, Wellington Silva escreveu:
Ok,
This really helped.
You've probably noticed, I'm a begginer using R.
And when you said that you tried with rnorm and the counts were not zero,
where did you use the rnorm?
Where the runif is, in its stead use
matrix(
Hello,
Glad it helped.
E fico à espera do relatório.
Rui Barradas
Em 31-07-2012 14:40, Wellington Silva escreveu:
Rui,
This is a cientific initiation program.
The idea is to develop a code which can simulate data and calculate the ARL
later.
*So, a little bit later yesterday night, after
Hi,
I'm Wellington from Brazil and I have the following issue:
I've been working on a project a for a while, and I'm having trouble in
using the loop (for)
I need to read a column (c1), and for each value of this column, I need to
check if it's within the control limits
So, I was
Hello,
Your code example doesn't make much sense, it needs decrypting. Let's see,
for(k in 1:length(c1)){
if(c1[k] lcl | c1[k] ucl) {do something}
}
If this is it, then you can completely avoid the loop:
i1 - c1 lcl | c1 ucl # create an index vector
out.of.control - c1[ i1 ]
Hello,
Try the following.
# make up some data
dds - 1e3
nc - 10
xss - data.frame(matrix(runif(nc*dds, min=-1, max=1), ncol=nc))
names(xss) - paste0(xs, 1:10)
# two functions with descriptive names
getControlLimits - function(x, L = 3){
mu - mean(x)
sigma - sd(x)
c(lcl = mu -
Hi,
I'm using write.table() to export dataframe to Excel. All works fine except
that I want to export the variable labels instead of variable names.
I can see the labels in the R consol using attr(), but I just don't know how
to use the labels instead of the names.
Thanks,
François
hi
would you please remove my email from the mailing list.
thanks in advance
Sebastien
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
https://stat.ethz.ch/mailman/listinfo/r-help
at the bottom…
On 16.07.2012, at 10:52, Sébastien Morant wrote:
hi
would you please remove my email from the mailing list.
thanks in advance
Sebastien
[[alternative HTML version deleted]]
__
On 16/07/2012, r-help-requ...@r-project.org
r-help-requ...@r-project.org wrote:
--
Message: 77
Date: Mon, 16 Jul 2012 10:48:39 +0100
From: Rui Barradas ruipbarra...@sapo.pt
To: e-letter inp...@gmail.com
Cc: r-help@r-project.org
Subject: Re: [R] histogram of
http://www.ncbi.nlm.nih.gov/pubmed/21418051 for the full reference.
I don't have an electronic copy, but I do have that issue of Biometrics
in my office. I'll have a copy sent over.
Terry
On 07/10/2012 04:08 PM, r-help-requ...@r-project.org wrote:
Send R-help mailing list submissions to
Hi guys
i need some help to build choropleth.
Basically i am trying to colour regions on the map by population.
I possess the shape file of the country, and also the population data,
however, i am having trouble to create the plot, below is my code:
population=read.csv(nz2.csv)
population
Hello,
You can find some hints there:
http://geography.uoregon.edu/geogr/topics/index.html
Regards
Le 12/06/28 14:26, iverson a écrit :
Hi guys
i need some help to build choropleth.
Basically i am trying to colour regions on the map by population.
I possess the shape file of the country,
On 06/28/2012 03:26 PM, iverson wrote:
Hi guys
i need some help to build choropleth.
Basically i am trying to colour regions on the map by population.
I possess the shape file of the country, and also the population data,
however, i am having trouble to create the plot, below is my code:
While lm() is a linear modeling, the constraints make it easier to solve with a
nonlinear
tool. Both my packages Rvmmin and Rcgmin (I recommend the R-forge versions as
more
up-to-date) have bounds constraints and masks i.e., fixed parameters.
I am actually looking for example problems of this
Rich,
The documentation for cenboxplot states that the second argument must be
logical and not integer. the function cenboxplot substitutes synthetic
values for censored values using ros, hence the error message from the ros
method.
I also do not understand how you expect group = 'SO4' to
] On
Behalf Of Alex Roth
Sent: Wednesday, May 02, 2012 4:01 PM
To: r-help@r-project.org
Subject: [R] R help!
Hello there, I was wondering if you could help me with a quick R issue.
I have a data set where one of the columns has both date and time in it, e.g.
12/31/11 23:45 in one cell. I want
On May 3, 2012, at 14:05 , Nutter, Benjamin wrote:
So long as x is a character vector, I tend to use the following for this
problem.
x - c(12/31/11 23:45, 1/1/12 2:15)
x.split - strsplit(x, )
x.date - sapply(x.split, function(y) return(y[1]))
x.time - sapply(x.split, function(y) if
Hi
I would convert it to propper date format and then you can extract
anything.
dat-strptime(12/31/11 23:45, format=%m/%d/%y %H:%M)
as.Date(dat)
[1] 2011-12-31
format(dat, %H:%M)
[1] 23:45
Regards
Petr
Hello there, I was wondering if you could help me with a quick R issue.
I have a
Hello there, I was wondering if you could help me with a quick R issue.
I have a data set where one of the columns has both date and time in
it, e.g. 12/31/11 23:45 in one cell. I want to use R to split this
column into two new columns: date and time.
One of the problems with splitting here is
Hi Alex,
Here is one way:
s - 12/31/11 23:45
strsplit(s, )[[1]]
# [1] 12/31/11 23:45
*
HTH,
Jorge.-
*
On Wed, May 2, 2012 at 4:00 PM, Alex Roth wrote:
Hello there, I was wondering if you could help me with a quick R issue.
I have a data set where one of the columns has both date and
On 02-05-2012, at 22:00, Alex Roth wrote:
Hello there, I was wondering if you could help me with a quick R issue.
I have a data set where one of the columns has both date and time in
it, e.g. 12/31/11 23:45 in one cell. I want to use R to split this
column into two new columns: date and
Hard to say.. your example is not reproducible. (Study the Posting Guide
mentioned at the end of every message on this list.)
A stab in the dark might be that z$dt is a factor and needs to be converted to
character first. Use the str function to study your data.
I will be out of the office Apr 26-27, 2012 with limited or no email
access.
For immediate help, please call the JPSM main number,
301-314-7911.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
Yes, the (start, stop] formalism is the easiest way to deal with time
dependent data.
Each individual only needs to have sufficient data to describe them, so
for if id number 4 is in house 1, their housemate #1 was eaten at time
2, and the were eaten at time 10, the following is sufficient
Hello,
When i run the code below from Weibull distribution with 30% censoring by using
optim i get an error form R, which states that
Error in optim(start, fn = z, data = q, hessian = T) :
objective function in optim evaluates to length 25 not 1
can somebody help me remove this error. Is my
On 16-04-2012, at 07:04, Christopher Kelvin wrote:
Hello,
When i run the code below from Weibull distribution with 30% censoring by
using optim i get an error form R, which states that
Error in optim(start, fn = z, data = q, hessian = T) :
objective function in optim evaluates to
-project.org r-help@r-project.org
Subject: [R] R-Help: Censoring data
Message-ID:
1334314483.27693.yahoomail...@web65408.mail.ac4.yahoo.com
Content-Type: text/plain; charset=iso-8859-1
Hello,
?I want to estimate weibull parameters with 30% censored data. I have below
the code
Hello,
I want to estimate weibull parameters with 30% censored data. I have below the
code for the censoring
but how it must be put into the likelihood equation to obtain the desire
estimate is where i have a problem with,
can some body help?
My likelihood equation is for a random type-I
Hello,
can i implement this as 10% censored data where t gives me failure and x
censored.
Thank you
p=2;b=120
n=50
set.seed(132);
r-sample(1:50,45)
t-rweibull(r,shape=p,scale=b)
t
set.seed(123);
cens - sample(1:50, 5)
x-runif(cens,shape=p,scale=b)
x
Chris Guure
Researcher,
Institute for
On 11-Apr-2012 16:28:31 Christopher Kelvin wrote:
Hello,
can i implement this as 10% censored data where t gives me
failure and x censored.
Thank you
p=2;b=120
n=50
set.seed(132);
r-sample(1:50,45)
t-rweibull(r,shape=p,scale=b)
t
set.seed(123);_
cens - sample(1:50, 5)_
Hello,
I wish to censor 10% of my sample units of 50 from a Weibull distribution.
Below is the code for it.
I will need to know whether what i have done is correct and if not, can i have
any suggestion to improve it?
Thank you
p=2;b=120
n=50
r=45
t-rweibull(r,shape=p,scale=b)
On Apr 10, 2012, at 11:48 PM, Christopher Kelvin wrote:
Hello,
I wish to censor 10% of my sample units of 50 from a Weibull
distribution. Below is the code for it.
I will need to know whether what i have done is correct and if not,
can i have any suggestion to improve it?
Thank you
I have a 11*1562 set of data. I want to regress using ols all combination of
the ten variables on the eleventh. Store the results of the t test of each
regression and the r2 to compare which combination is better. the
combination can use any amount o variables. How can I do that in R?
--
View
This is, more often that not, statistically speaking a bad idea:
you're likely to get a false positive (https://xkcd.com/882/)
But it sounds like something along these lines should work for you to
get the models :
x - data.frame(rnorm(50), rnorm(50), rnorm(50), rnorm(50))
m - vector(list,
On 2012-04-07 08:27, kebrab67 wrote:
I have a 11*1562 set of data. I want to regress using ols all combination of
the ten variables on the eleventh. Store the results of the t test of each
regression and the r2 to compare which combination is better. the
combination can use any amount o
Hi,
I have a polynomial of 2n^2-5n+3 and I have my n values going up in powers of 2
i.e. n=2,4,8,16…..
I wanted to fit this curve to the function A*n*log2(n) +B*n where A and B are
to be found.
How would i do this?
Thank you
Jaymin
__
This sounds a little bit like homework (since you know the actual
model), so I'll just point you in the right direction:
I'd do something like:
n - 2^(1:10)
y - 2*n^2 - 5*n + 3
dtf - data.frame(y = y, n=n)
lm( **, data = dtf)
The * should be replaced by a formula object: to find
Q #1: yesterday:
A: 1. Restructure your database with NoSQL. See MongoDB.org.
2. Choose application language with which to work (and get Driver)
and write your code.
3. R package - rmongodb.
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This posting is only to celebrate that R-help-es (R-help for Spanish
Speakers) have reached 500
members!
(and to thank Patricia for doing the bulk of admin work).
Kjetil
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:)
congratulations!
On Tue, Mar 13, 2012 at 08:59:56AM -0600, Kjetil Halvorsen wrote:
This posting is only to celebrate that R-help-es (R-help for Spanish
Speakers) have reached 500
members!
(and to thank Patricia for doing the bulk of admin work).
Kjetil
On Fri, 2012-03-09 at 12:00 +0100, r-help-requ...@r-project.org wrote:
A note on standard errors: ?S(t) +- std is a terrible confidence
interval. ?You will be much more accurate if you use log
scale. ?(Some
argue for logit or log-log, in truth they all work well.) ? If n is
large
On Sat, Feb 18, 2012 at 06:00:53PM -0500, li li wrote:
Dear all,
I need to generate numbers from multivariate normal with large dimensions
(5,000,000).
Below is my code and the error I got from R. Sigma in the code is the
covariance
matrix. Can anyone give some idea on how to take care of
Petr,
Thanks for the help. That certainly makes sense and solves my current
problem. But, in general, for arbitrary covariance matrix (instead of the
special equi-correlation case), it there a way to generate numbers from
multivariate normal when the dimension is very high?
Thanks.
Actually I still get an error for the case of equal correlation.
Below is the code
m - 10
n - 500
m1 - 0.5*m
mu - c(rep(2, m1), rep(0, m-m1))
rho - 0.5
x.mod1 - matrix(rnorm(n*m, sd=sqrt(1-rho)), nrow=n, ncol=m)+rnorm(n,
sd=sqrt(rho))+t(replicate(n,mu))
Error: cannot allocate vector of
On Feb 19, 2012, at 16:53 , li li wrote:
Petr,
Thanks for the help. That certainly makes sense and solves my current
problem. But, in general, for arbitrary covariance matrix (instead of the
special equi-correlation case), it there a way to generate numbers from
multivariate normal when
On Feb 19, 2012, at 11:46 AM, li li wrote:
Actually I still get an error for the case of equal correlation.
No. You need to read the error message for meaning.
Below is the code
m - 10
n - 500
m1 - 0.5*m
mu - c(rep(2, m1), rep(0, m-m1))
rho - 0.5
x.mod1 - matrix(rnorm(n*m,
On Sat, Feb 18, 2012 at 06:00:53PM -0500, li li wrote:
Dear all,
I need to generate numbers from multivariate normal with large dimensions
(5,000,000).
Hi.
I am replying to your first email, since the other did not arrive
to my folder, possibly filtered out by a spam filter. I see them
at
Folks:
Perhaps I am naive, ignorant, or foolish, but this whole discussion
seems rather ridiculous. What possible relation to reality could a
multivariate normal of the size requested have? Even for simulation,
it seems like nonsense.
Cheers,
Bert
On Sun, Feb 19, 2012 at 11:35 AM, Petr Savicky
On 20/02/12 09:55, Bert Gunter wrote:
Folks:
Perhaps I am naive, ignorant, or foolish, but this whole discussion
seems rather ridiculous. What possible relation to reality could a
multivariate normal of the size requested have? Even for simulation,
it seems like nonsense.
Right on, bro'!!!
Dear all,
I need to generate numbers from multivariate normal with large dimensions
(5,000,000).
Below is my code and the error I got from R. Sigma in the code is the
covariance
matrix. Can anyone give some idea on how to take care of this error. Thank
you.
Hannah
m - 500
Hi Petr,
You advice options(scipen=20) gave me the expected result and fix the
problem.
Thanks a lot!
Gian
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PLEASE do read
dear:
i want to know how to get a survival curve of the Cox proportional risk
regression, thank you.
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Le lundi 13 février 2012 à 19:48 +0800, 丁飞 a écrit :
dear:
i want to know how to get a survival curve of the Cox proportional risk
regression, thank you.
See the relevant part of the Survival Task View here:
http://cran.r-project.org/web/views/Survival.html
And more specifically, see the
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