[R] solving equation consisting of factorials

2010-10-30 Thread Shant Ch
Hi, I was trying to solve for m such that, choose(n-1,k-1)+choose(n-2,k-1)+...+choose(n-m+1,k-1) - ck=0 ck is calculated by the way given in the code. Now I solved for m using uniroot but the error messages appeared. n-30 k=3 alpha-0.05 nk-choose(n,k);

Re: [R] solving equation consisting of factorials

2010-10-30 Thread David Winsemius
On Oct 30, 2010, at 9:55 AM, Shant Ch wrote: Hi, I was trying to solve for m such that, choose(n-1,k-1)+choose(n-2,k-1)+...+choose(n-m+1,k-1) - ck=0 ck is calculated by the way given in the code. Now I solved for m using uniroot but the error messages appeared. n-30 k=3 alpha-0.05

[R] Solving equation

2010-05-01 Thread Shant Ch
Hello, I want to solve: x*(3^x)*log(4)-x*log(4/3)-(3^x)+1=0 for x. I used the following code, uniroot(function(x) x*(3^x)*log(4)-x*log(4/3)-(3^x)+1, lower = -2, upper = 2, tol = 0.001 ) While using this I am getting the following error. Can anyone please help me out. Error in

Re: [R] Solving equation

2010-05-01 Thread Berend Hasselman
Shant Ch wrote: I want to solve: x*(3^x)*log(4)-x*log(4/3)-(3^x)+1=0 for x. I used the following code, uniroot(function(x) x*(3^x)*log(4)-x*log(4/3)-(3^x)+1, lower = -2, upper = 2, tol = 0.001 ) While using this I am getting the following error. Can anyone please help me out. Error

Re: [R] Solving equation

2010-05-01 Thread David Winsemius
On May 1, 2010, at 3:28 AM, Berend Hasselman wrote: Shant Ch wrote: I want to solve: x*(3^x)*log(4)-x*log(4/3)-(3^x)+1=0 for x. I used the following code, uniroot(function(x) x*(3^x)*log(4)-x*log(4/3)-(3^x)+1, lower = -2, upper = 2, tol = 0.001 ) While using this I am getting the

Re: [R] Solving equation

2010-05-01 Thread Berend Hasselman
David Winsemius wrote: On May 1, 2010, at 3:28 AM, Berend Hasselman wrote: Shant Ch wrote: I want to solve: x*(3^x)*log(4)-x*log(4/3)-(3^x)+1=0 for x. I used the following code, uniroot(function(x) x*(3^x)*log(4)-x*log(4/3)-(3^x)+1, lower = -2, upper = 2, tol = 0.001 )

Re: [R] Solving equation

2010-05-01 Thread Peter Ehlers
On 2010-05-01 7:13, Berend Hasselman wrote: David Winsemius wrote: On May 1, 2010, at 3:28 AM, Berend Hasselman wrote: Shant Ch wrote: I want to solve: x*(3^x)*log(4)-x*log(4/3)-(3^x)+1=0 for x. I used the following code, uniroot(function(x) x*(3^x)*log(4)-x*log(4/3)-(3^x)+1, lower