I am sorry for my careless. I forgot implementing the last code
corresponding to setting y-axis. Thanks Mark Leeds and all guys.
2013/1/22 hp wan
> Thanks. This time the x-axis works well but the y-axis is missing.
>
> 2013/1/22 Mark Leeds
>
>> Hi Hp: I decided to use axis because names.arg
Thanks. This time the x-axis works well but the y-axis is missing.
2013/1/22 Mark Leeds
> Hi Hp: I decided to use axis because names.arg wasn't working very well.
> Below is
> an improvement and I'm sure, given enough effort, it can be improved much
> more. But
> atleast below will get you start
Hi Hp: I decided to use axis because names.arg wasn't working very well.
Below is
an improvement and I'm sure, given enough effort, it can be improved much
more. But
atleast below will get you started.
breaks=c(-1.55,-1.50,-1.45,-1.40,-1.35,-1.30,-1.25,-1.20,-1.15,-1.10,-1.05,-1.00,-0.95,-0.90,-0.
Hi: if you mean that you want the labels to be the strings "-1.55", "-1.50"
etc then you
can use the names.arg argument for that. You can create a vector of
character strings
binstrings = c("-1.55","-1.50", )
or just convert your data to strings using as.character. Then, in the call
to barpl
But the x-axis of barplot is still not what I want. The xlab is breaks, not
-1.55,-1.50,,0.55.
2013/1/22 Mark Leeds
> Hi Hp: I'm not sure what you want. Below looks slightly better but if you
> want the x-axis
> to have better labels, then there is a names.arg argument to barplot. see
> ?bar
Hi Hp: I'm not sure what you want. Below looks slightly better but if you
want the x-axis
to have better labels, then there is a names.arg argument to barplot. see
?barplot.
I don't know what each of the bins represents but if you want to include
all of those zeros then I don't think there's any w
Ok, that is no problem.
2013/1/22 Mark Leeds
> let me look at but it's probably best to send to the whole list because
> there are many
> people on it way more knowledgable than myself. I'm ccing the list and
> hope you
> don't mind. my fault for replying privately initially.
>
>
>
> On Mon, Jan
let me look at but it's probably best to send to the whole list because
there are many
people on it way more knowledgable than myself. I'm ccing the list and hope
you
don't mind. my fault for replying privately initially.
On Mon, Jan 21, 2013 at 7:36 PM, hp wan wrote:
> Thanks for your reply!
>
On 13-01-21 5:18 PM, hp wan wrote:
Hi All,
When carrying out hist(samples,breaks=50,probability=TRUE), the column
values are considerably greater than 1, which seams very unreasonable. The
plot is attached.
I think the column value of the hist plot should correspond to
x$counts/sum(x$counts)
Hi All,
When carrying out hist(samples,breaks=50,probability=TRUE), the column
values are considerably greater than 1, which seams very unreasonable. The
plot is attached.
I think the column value of the hist plot should correspond to
x$counts/sum(x$counts)
(x=hist(samples,breaks=50,probabilit
10 matches
Mail list logo
